Before anyone marks this as a duplicate, I have looked at many sites and am currently using this one - jQuery - passing value from one input to another for guidance, yet no result... I am trying to pass a value from one input in one form to another input in a 'table'. I have put it in a table because of a very weird reason - it does not display a Sparql value when in a form only displays in a table so the input was placed in a table. My code is below:
Form
<form onclick="txtFullName.value = txtFirstName.value +'_'+ txtLastName.value">
First name : <input type="text" name="txtFirstName" value="#ViewBag.FirstName"/> <br><br>
Last name : <input type="text" name="txtLastName" value="#ViewBag.LastName" /> <br><br>
Full name : <input type="text" id="txtFullName" name="txtFullName"> <br><br />
<input id="submit12" type="button" value="Submit">
</form>
Table
<table id="results">
<Full name:
<br>
<input id="userInput" type="text" name="fullname" ${userJson.userId == ''?'': 'disabled'} value="#ViewBag.DisplayName">
<br>
<input id="submit" type="submit" value="Submit">
</table>
JQUERY
$('#submit12').on('click', function (e) { //Form submit
$('#userInput').change(function () {
$('txtFullName').val($(this).val());
});
});
I am trying to display the txtFullName into userInput input when pressing submit but right now only the `txtFullName' is displayed when pressing submit. Also the submit is the submit button in the FORM.
Anymore info needed let me know:)
You need to change the onclick to action on the form if you are trying to use submit button. The other way is to use input type button instead of submit:
So:
$(document).ready(function() {
$('#submit12').on('click', function (e) {
console.log('test');
$("#txtFullName").val($("#txtFirstName").val() + '_' + $("#txtLastName").val());
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
First name : <input type="text" id="txtFirstName" value="First"/> <br><br>
Last name : <input type="text" id="txtLastName" value="Last" /> <br><br>
Full name : <input type="text" id="txtFullName" name="txtFullName"> <br><br />
<input id="submit12" type="button" value="Submit">
</form>
If you want to display txtFullName into userInput, simply do something like this:
$('#submit12').on('click', function (e) { //Form submit
$('#userInput').val($('#txtFullName').val());
});
And why do you need change function there , if yo need changes when click submit.
Edit your JQuery like this:
$('#submit12').on('click', function (e) { //Form submit
$('#userInput').change(function () {
$('#txtFullName').val($(this).val());
});
});
$('#submit').on('click', function () { //Form submit
$('#userInput').val($('#txtFullName').val());
});
I don't clearly understand why you do it but It can fix your code.
It is not entirely clear what the two buttons do, but the operation itself is really very simple. See comments inline for explanations:
// Wait until the DOM is loaded and all elements are avaialble
window.addEventListener("DOMContentLoaded", function(){
// Get references to the DOM elements you'll need
var theForm = document.getElementById("frmTest");
var txtFirstName = document.getElementById("txtFirstName");
var txtLasttName = document.getElementById("txtLastName");
var txtFulltName = document.getElementById("txtFullName");
var txtUserInput = document.getElementById("txtUserInput");
var btn1 = document.getElementById("btnSubmit1");
var btn2 = document.getElementById("btnSubmit2");
// Function to join names together
function combine(){
txtFullName.value = txtFirstName.value + '_' + txtLastName.value;
}
// Set event handlers
frmTest.addEventListener("click", combine);
btn1.addEventListener("click", combine);
});
<!-- Keep you JavaScript out of your HTML -->
<form id="frmTest">
First name : <input type="text" id="txtFirstName" name="txtFirstName" value="#ViewBag.FirstName">
<br><br>
Last name : <input type="text" id="txtLastName" name="txtLastName" value="#ViewBag.LastName" >
<br><br>
Full name : <input type="text" id="txtFullName" name="txtFullName"> <br><br />
<input id="btnSubmit1" type="button" value="Combine Names">
<table id="results">
<Full name:
<br>
<input id="txtUserInput" type="text" name="fullname" ${userJson.userId == ''?'': 'disabled'} value="#ViewBag.DisplayName">
<br>
<input id="btnSubmit2" type="submit" value="Submit">
</table>
</form>
Related
How can I know which form I clicked? Is it possible with a button class instead of buttons with id?
$(document).ready(function () {
$(".form-buttons").click(function () {
//I only want the form which corresponds to the button I clicked
var formDates = $(form).serialize()
alert ("You clicked "+formDates)
})
})
<form id="form1">
<input type="text" value="date1" name="name1"/>
<input type="text" value="date2" name="name2"/>
<input type="text" value="date3" name="name3"/>
<button type="button" class="form-button"></button>
</form>
<form id="form2">
<input type="text" value="date4" name="name1"/>
<input type="text" value="date5" name="name2"/>
<input type="text" value="date6" name="name3"/>
<button type="button" class="form-button"></button>
</form>
Yes use class instead of id for similar elements. Please try this.
Note: form-button is the class name in your HTML and not form-buttons
$(document).ready(function () {
$(".form-button").click(function () {
var formDates = $(this).closest('form').serialize();
alert ("You clicked "+formDates)
})
})
I think you be looking for
$('.form-button').on('click', function () {
alert($(this).parents('form').attr('id')); // Check the ID of the form clicked
});
something Maybe Like mentioned above.
You can get the name of the element by using the this keyword which refer, in a DOM event, to the cibled element :
$(document).ready(function () {
$(".form-buttons").click(function () {
alert('You clicked the form' + this.parentElement.getAttribute('id'));
})
})
You can do this in a few different ways. You can traverse up the DOM and see which form is used or -and this is my favorite- you can submit the form!
Solution 1: Traversing up the DOM
<script>
$(document).ready(function () {
$(".form-button").click(function () {
var clicked_form = $(this).parent();
var formDates = clicked_form.serialize();
alert ("You clicked "+formDates);
})
})
</script>
</head>
<body>
<form id="form1">
<input type="text" value="date1" name="name1"/>
<input type="text" value="date2" name="name2"/>
<input type="text" value="date3" name="name3"/>
<button type="button" class="form-button"></button>
</form>
<form id="form2">
<input type="text" value="date4" name="name1"/>
<input type="text" value="date5" name="name2"/>
<input type="text" value="date6" name="name3"/>
<button type="button" class="form-button"></button>
</form>
</body>
Solution 2: Submit the form
You already are using the form, so why not submit it? Change the buttons to input elements with type submit and intercept the submit event, like this. This is how I think it should be done. It is also better for user experience because the user can just submit the form by pressing enter.
<script>
$(document).ready(function () {
$("form").on('submit', function (e) {
e.preventDefault();
var formDates = $(this).serialize()
alert ("You clicked "+formDates)
})
})
</script>
</head>
<body>
<form id="form1">
<input type="text" value="date1" name="name1"/>
<input type="text" value="date2" name="name2"/>
<input type="text" value="date3" name="name3"/>
<input type="submit" class="form-button"></input>
</form>
<form id="form2">
<input type="text" value="date4" name="name1"/>
<input type="text" value="date5" name="name2"/>
<input type="text" value="date6" name="name3"/>
<input type="submit" class="form-button"></input>
</form>
</body>
Check this fiddle on how I would do it.
https://jsfiddle.net/xtfeugav/
Simple use
$("form").submit(function(e) {
to listen for every submit on all the forms you have. To get the ID of the form you use
var formid = $(this).attr('id');
I used e.preventDefault(); to prevent the form don't update the page.
Remember to use <input type="submit" value="Submit"> on your forms to make this work.
Its a simple code, hope it helps.
I created three separate forms and gave each of these forms an id. After the user presses next, the current form fades out and the second form fades in. After the user presses next again, the second form then fades out and the next form fades in. Inside the third form I included a submit button that should submit all my data to my database.
I am having issues passing the information through the three different forms and was wondering if anyone had any ideas on how I could more easily accomplish this.
Sample code:
<form id ="1">
<input type = "text"/>
</form>
<form id = "2">
<input type="checkbox"/>
</form>
<form id = "3" action ="upload.php">
<input type = "file">
<input type = "submit">
</form>
EDIT* adding more info: Once the user presses submit, the information passed in from form 1 and form 2 should both be posted into upload.php. I am not sure how to accomplish that so far.
You can solve this issue by using single form like below.
<form id ="1" action ="upload.php">
<div class="first-form">
<input type = "text"/>
</div>
<div class="second-form">
<input type="checkbox"/>
</div>
<div class="third-form">
<input type = "file">
<input type = "submit">
</div>
</form>
there are three div with different class. You must hide and show the div not the form.
If you want to do with normal php without ajax, try this.
<form id ="1">
<input type="text" name="form1" />
</form>
<form id = "2">
<input type="checkbox" name="form2"/>
</form>
<form id = "3" action="file.php" method="post">
<input type = "text" name="form3">
<input type = "submit" id="sub">
</form>
Script
$(document).on("click", "#sub", function () {
$('#1 :input').not(':submit').clone().hide().appendTo('#3');
$('#2 :input').not(':submit').clone().hide().appendTo('#3');
return true;
});
You can use jQuery's serialize function to achieve this:
Your html file:
<form id="1">
<input type="text" name="name" />
</form>
<form id="2">
<input type="checkbox" name="chk" />
</form>
<form id="3">
<input type="file" name="file">
<input type="submit">
</form>
Add this script (an AJAX way):
<script>
$(document).ready(function(){
$("#3").submit(function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: "upload.php",
data: $('#1, #2, #3').serialize(),
success: function(res) {
if(res==="Success"){
alert("Success!!!");
}
}
});
});
});
</script>
UPDATE
As #Santosh Patel suggests, I too suggest the same, to enclose form contents inside div. But since you have come up with a design, I suggested you jQuery.
I would have to input fields like this
<form>
<input type="text" id="keyword" placeholder="XXX">
<input type="text" id="state" placeholder="XXX">
<button type="submit" id="submit">Submit</button>
</form>
On click of the submit I would like to send them to a new page with the value of the input appended to the url with query string.
http://www.link.com/page?keyword=XYXYX&state=XZXX
Here is my start thinking but was thinking .serialize() can handle this better than this example
var keywordVal = $("#keyword").val();
var stateVal = $("#state").val();
$( "form" ).on( "submit", function() {
event.preventDefault();
location.href='http://www.link.com/page?keyword=' + keywordVal + '&state=' + stateVal
});
let me know if i am approaching it the right way..
You don't need JavaScript to do this.
Simply add an action attribute with the URL and set the method attribute to GET (this will append the named field values as a query string).
<form action="<yourURL>" method="GET">
<input type="text" id="keyword" name="keyword" placeholder="XXX">
<input type="text" id="state" name="state" placeholder="XXX">
<button type="submit" id="submit">Submit</button>
</form>
NOTE: You'll need name attributes on your fields.
Fiddle: http://jsfiddle.net/pjh7wkj4/
No need any jQuery/javascript to do that, form tag is providing those functionality. Adding action and method (GET) attributes will give you the results what you expect.
<form action="<target_url>" method="GET">
<input type="text" id="keyword" name="keyword" placeholder="XXX">
<input type="text" id="state" name="state" placeholder="XXX">
<button type="submit" id="submit">Submit</button>
</form>
I'm making a html5 application which require all fields to be filled in before the submit button can be clicked.
What I want to do now is give an alert if a textbox is not filled in, the problem is that my submit button is disabled until all fields are filled in, so I can't really add an alert to that button.
Any idea's on how to solve this?
I want it so that after filling in the final textbox the submit button becomes available without first having to click on it.
Note that the 'required' does not work.
I have the following code:
HTML:
<form id="winForm">
<p>
<input type="text" id="name" name="name" required />
</p>
<p>
<input type="text" id="vorname" name="vorname" required />
</p>
<p>
<input type="text" id="email1" name="email1" required />
<label id="atteken" >#</label>
<input type="text" id="email2" name="email2 " required />
<textarea id="fullemail" name="fullemail"></textarea>
</p>
<p>
<input type="text" id="telefon" name="telefon" onclick="generateFullAdress()" required />
</p>
<p>
<input type="text" id="firma" name="firma" required />
</p>
<p>
<input type="submit" id="submitBtn" onclick="sendTheMail()" value=" ">
</button><div id="loading"><img src="images/loadingBar.gif" id="load"></img></div>
</p>
</form>
Jquery/JS
<script type="text/javascript">
function generateFullAdress() {
document.getElementById('fullemail').value =
document.getElementById('email1').value + '#' +
document.getElementById('email2').value;
}
</script>
<script>
var $input = $('input:text'),
$register = $('#submitBtn');
$register.attr('disabled', true);
$input.keyup(function() {
var trigger = false;
$input.each(function() {
if (!$(this).val()) {
trigger = true;
}
});
if(trigger) {
$register.attr('disabled',true);
}else {
$register.removeAttr('disabled');
}
});
</script>
Help would greatly be appreciated.
Thanks!
If you have a form as such:
<form id="form">
...
</form>
You can use the following jQuery code to do something before the form is submitted:
$(function() {
$('#form').submit(function() {
// DO STUFF
return true; // return false to cancel form action
});
});
OR
perform the samething with the onsubmit event like
<form action="youraction" onsubmit="validatefunction" method="post">
This is my demo cord.
<input type="text" id="my_input1" />
<input type="text" id="my_input2" />
<input type="text" id="total" />
<input type="button" value="Add Them Together" onclick="doMath();" />
<script type="text/javascript">
function doMath()
{
// Capture the entered values of two input boxes
var my_input1 = document.getElementById('my_input1').value;
var my_input2 = document.getElementById('my_input2').value;
// Add them together and display
var sum = parseFloat(my_input1) + parseFloat(my_input2);
document.getElementById('total').value=sum;
}
I want to work this function when my_input2 is enter it's value. Just like onclick method for button is there any event to set value to total tetxfeild after key release event?
<script type="text/javascript">
$(document).ready(function () {
$("#my_input2").blur(function () {
var sum = parseInt($("#my_input1").val()) + parseInt($("#my_input2").val());
$("#total").val(sum);
});
});
</script>
<div>
<input type="text" id="my_input1" />
<input type="text" id="my_input2" />
<input type="text" id="total" />
<input type="button" value="Add Them Together" />
</div>
And also u should frame ur question correctly bcz u have added code in button click and asking us it should work after leaving textbox
Put onkeyup() on second input field this will fire your function.
Something like that:
<input type="text" id="my_input2" onkeyup="doMath();" />
try this
<input type="text" id="my_input2" onchange="doMath();" />