Develop Reference

Unable to see the source of the problem with the code for sending data to PHP file

I am very sorry to appear much ignorant but I have experienced this problem for long and I am now completely unable to understand why my JQuery function is not working.
I need this code to send data to PHP file which I am sure its working. I have tried to code everything with php but I have found there are place that I will have to include ajax.
$(document).ready(function(){
$('#sending').on('submit', function(event){
event.preventDefault();
if(($('#receiver_id1').val() == '0') && ($('#receiver_id2').val() == '0') && ($('#receiver_id3').val() == '0'))
{
alert("Please fill in the recipient!");
return false;
}
else if($.trim($("#message").val()) == '')
{
alert("You cannot send an empty message.");
return false;
}
else if($('#subject').val() == '')
{
var retVal = confirm("Are you sure to send a message without a subject?");
if( retVal == true ) {
var receiver_id1 = $('#receiver_id1').val();
var receiver_id2 = $('#receiver_id2').val();
var receiver_id3 = $('#receiver_id3').val();
var receiver_name1 = $('#receiver_id1').text();
var receiver_name2 = $('#receiver_id2').text();
var receiver_name3 = $('#receiver_id3').text();
var from_user_name = '<?php echo $from_user_name;?>';
var from_user_id = '<?php echo $from_user_id;?>';
var subject = $('#subject').val();
var message = $('#message').val();
$.ajax({
url:"messaging.php",
type:"POST",
data:{receiver_id1:receiver_id1, receiver_id2:receiver_id2, receiver_id3:receiver_id3, receiver_name1:receiver_name1, receiver_name2:receiver_name2, receiver_name3:receiver_name3, subject:subject, message:message},
success:function(data)
{
$('#receiver_id1').val("0");
$('#receiver_id2').val("0");
$('#receiver_id3').val("0");
$('#subject').val("");
$('#message').val("");
var employee_id = $(this).attr("id");
$.ajax({
url:"select.php",
type:"post",
data:{employee_id:employee_id},
success:function(data){
$('#employee_detail').html(data);
$('#popup').modal("show");
}
});
},
error: function(jqxhr, status, exception) {
alert('Exception:', exception);
}
});
} else {
return false;
}
} else
{
var receiver_id1 = $('#receiver_id1').val();
var receiver_id2 = $('#receiver_id2').val();
var receiver_id3 = $('#receiver_id3').val();
var receiver_name1 = $('#receiver_id1').text();
var receiver_name2 = $('#receiver_id2').text();
var receiver_name3 = $('#receiver_id3').text();
var from_user_name = '<?php echo $from_user_name;?>';
var from_user_id = '<?php echo $from_user_id;?>';
var subject = $('#subject').val();
var message = $('#message').val();
$.ajax({
url:"messaging.php",
type:"POST",
data:{receiver_id1:receiver_id1, receiver_id2:receiver_id2, receiver_id3:receiver_id3, receiver_name1:receiver_name1, receiver_name2:receiver_name2, receiver_name3:receiver_name3, from_user_name:from_user_name, from_user_id:from_user_id, subject:subject, message:message},
success:function(data)
{
$('#receiver_id1').val("0");
$('#receiver_id2').val("0");
$('#receiver_id3').val("0");
$('#subject').val("");
$('#message').val("");
var employee_id = $(this).attr("id");
$.ajax({
url:"select.php",
method:"post",
data:{employee_id:employee_id},
success:function(data){
$('#employee_detail').html(data);
$('#popup').modal("show");
}
});
},
error: function(jqxhr, status, exception) {
alert('Exception:', exception);
}
});
}
});
});
I really need help. I absolutely need this script to work. Thanks in advance.

Send blob image to php

I've created a dynamic upload and I want to send each blob to server after the images are cropped.
The problem is that it's sent only the last append and I don't know why.
var g = 0;
for(var j = 1;j <= boxno;j++) //boxno = 4 pics (I can have as much as I want)
{
input = $("#input"+j);
if(input.val().length !== 0)//check if input has any values
{
pcanvas = $("#pcanvas"+j)[0];
context = pcanvas.getContext("2d");
formData = new FormData($(this)[0]);
var blob = dataURLtoBlob(pcanvas.toDataURL('image/png'));
formData.append("pcanvas_"+g+"[]", blob);
g++;
}
}
var info = {
userid:userId,
username:userName,
picNr: g
}
formData.append("info[]", info["userid"]);
formData.append("info[]", info["username"]);
formData.append("info[]", info["picNr"]);
$.ajax({
url: "/send.php",
type: "POST",
data: formData,
contentType: false,
cache: false,
processData: false,
success: function(data) {
console.log(data);
},
error: function(data) {
console.log("error");
},
complete: function(data) {}
});
function dataURLtoBlob(dataURL) {
var BASE64_MARKER = ';base64,';
if (dataURL.indexOf(BASE64_MARKER) == -1) {
var parts = dataURL.split(',');
var contentType = parts[0].split(':')[1];
var raw = decodeURIComponent(parts[1]);
return new Blob([raw], {
type: contentType
});
}
var parts = dataURL.split(BASE64_MARKER);
var contentType = parts[0].split(':')[1];
var raw = window.atob(parts[1]);
var rawLength = raw.length;
var uInt8Array = new Uint8Array(rawLength);
for (var i = 0; i < rawLength; ++i) {
uInt8Array[i] = raw.charCodeAt(i);
}
return new Blob([uInt8Array], {
type: contentType
});
}
Now if I send using this method is sent only "pcanvas3", the last loop. But If I put $.ajax inside the loop is working, but I don't want this, because I want to add into my db and is adding 4 times the same results (also I create new folder for a specific upload, so if I add inside the loop $.ajax it creates 4 folders)
Here is my php.
$id = $_POST['info'][0];
$username = $_POST['info'][1];
$picNr = $_POST['info'][2];
$shuffledid = str_shuffle($id);
$uniqueid = $id.$shuffledid;
$path = $_SERVER['DOCUMENT_ROOT'].'/_user/_tests/en/'.$uniqueid;
if(!file_exists($path))
{
mkdir($path,0755);
}
for($g = 0; $g <= $picNr; $g++)
{
$virtualbg = imagecreatetruecolor(400,410);
$tmp_file = $_FILES['pcanvas_'.$g]['tmp_name'][0];
$pic = imagecreatefrompng($tmp_file);
list($width,$height,$type) = getimagesize($tmp_file);
imagecopyresampled($virtualbg,$pic, 0,0,0,0, 400,410,$width,$height);
imagejpeg($virtualbg,$path.'/pic_'.$g.'.jpg');
imagedestroy($pic);
imagedestroy($virtualbg);
}
As you can see I'm passing through each "pcanvas_0,1,2,3,4" but only the last one it gets the tmp_files.
What I'm doing it wrong? I think the problem is on my append. I've tried to append something else to the formData("pcanvas.. and it works but my blob is not appended.
Thank you!

View is not passing the model to controller - ASP.Net MVC

This is a basic passing of values from view to controller, but this does not seek to work.When I click the update button that functions to update the record in the database, the values from view, does not correctly pass the values to controller. Upon putting debugger in the javascript, the each variables were able to correctly got its values and evn the object where they are stored.
What could possible the reason for this problem?
here's the button onclick event code in Javascript.
$('#updatePrescription').click(function () {
debugger;
ValidateFields();
var drugListIsEmpty = CheckDrugList();
var error = $(".text-danger").length;
if (error == 0 && !drugListIsEmpty) {
debugger;
var prescription = [];
var template = {};
template.templateName = $("#prescriptionTemplateName").val();
template.templateTypeId = $('input[name=templateTypeId]:checked').val();
template.prescriptionTemplateItemList = [];
template.instructionId = $('.instruction').val();
template.frequencyId = $('.frequency').val();
template.day = $('.inputDays').val();
template.quantity = $('.inputQuantity').val();
template.dispenseLocationId = $('.selectDispenseLocation').val();
template.statusId = $('.status').val();
//template.categoryId = $('.templateCategory').filter(":visible").last().val();
template.templateId = $('#prescriptionTemplateId').val();
//if (template.categoryId == null) {
// template.categoryId = 0;
//}
var x = 0;
$('#tblPrescriptionSaveTemplateBody tr').each(function (key, value) {
debugger;
var row = $(this).closest('tr');
var next_row = $(row).next();
var drugId = $(value).find('.drugId').val();
var dosage = $(value).find('.inputDosage').val();
var dosageUnitId = $(value).find('.selectUnitId').val();
var statusId = "41";
var remarks = $(value).find('.inputDescription').val();
var groupId = $(value).find('.inputGroupNo').val();
var unit = $(value).find('.selectUnitId').val();
var prescriptionTemplateItemId = $(value).find('.prescriptionTemplateItemId').val();
x++;
var obj = {
// templateId: prescriptionTemplateId,
prescriptionTemplateId: template.templateId,
prescriptionTemplateItemId: prescriptionTemplateItemId,
drugId: drugId,
dosage: dosage,
dosageUnitId: dosageUnitId,
instructionId: template.instructionId,
frequencyId: template.frequencyId,
day: template.day,
quanitity: template.quantity,
unit: unit,
remarks: remarks,
dispenseLocationId: template.dispenseLocationId,
groupId: groupId,
statusId: template.statusId
}
template.prescriptionTemplateItemList.push(obj);
//prescription.push(obj)
})
$.ajax({
type: 'POST',
url: '/WestMedicinePrescriptionTemplate/UpdateTemplate',
dataType: 'json',
contentType: 'application/json',
data: JSON.stringify(template),
success: function (data) {
ShowNotificationMessage(data.notification);
window.location.href = '/WestMedicinePrescriptionTemplate/Index';
}
});
}
});
This is expected to pass the result of model in parameter "newtemplate" in the controller, but it results to null
public ActionResult UpdateTemplate([FromBody] PrescriptionTemplateVM newtemplate)
{
int empId = Convert.ToInt32(HttpContext.Session.GetInt32("EmployeeId"));
var notif = "Update Failed.";
try
{
if (ModelState.IsValid)
{
bool updateSuccessful = _prescription.UpdatePrescriptionTemplateAndItems(newtemplate, empId);
if (updateSuccessful)
{
notif = "Update Successful.";
}
}
}
catch (Exception ex)
{
notif = ex.Message;
}
return Json(new { notification = notif });
}
What could be the problem in the code

do like this:
[HttpPost]
public ActionResult UpdateTemplate(PrescriptionTemplateVM newtemplate)
You need to make sure that you are using the same variables names that you defined in PrescriptionTemplateVM
and dont convert the data to Json. do like this:
$.ajax({
type: 'POST',
url: '/WestMedicinePrescriptionTemplate/UpdateTemplate',
dataType: 'json',
contentType: 'application/json',
data: {newtemplate: template},
success: function (data) {
ShowNotificationMessage(data.notification);
window.location.href =
'/WestMedicinePrescriptionTemplate/Index';
}
});

JS insertHtml without focus?

I have some code written in PHP with textarea input field. I also have a JS code that inserts html code into field:
$('form textarea#response').ready(function() {
function populateGet() {
var obj = {}, params = location.search.slice(1).split('&');
for(var i=0, len=params.length;i<len;i++) {
var keyVal = params[i].split('=');
obj[decodeURIComponent(keyVal[0])] = decodeURIComponent(keyVal[1]);
}
return obj;
}
var test = populateGet();
var ticid;
for(var key in test) {
if(Object.prototype.hasOwnProperty.call(test, key)) {
var val = test[key];
ticid = val;
}
}
$('form select#cannedResp').val('original');
var fObj = $(this).closest('form');
var $url = 'ajax.php/tickets/'+ticid+'/canned-resp/original.json';
$.ajax({
type: "GET",
url: $url,
dataType: 'json',
cache: false,
success: function(canned){
console.log('dupa');
//Canned response.
var box = $('form textarea#response'),
redactor = box.data('redactor');
if(canned.response) {
if (redactor){
redactor.insertHtml(canned.response);
}else{
box.val(box.val() + canned.response);
box.blur();
}
//if (redactor)
//redactor.observeStart();
}
//Canned attachments.
var ca = $('.attachments', fObj);
if(canned.files && ca.length) {
var fdb = ca.find('.dropzone').data('dropbox');
$.each(canned.files,function(i, j) {
fdb.addNode(j);
});
}
document.getElementById('focustest').focus();
}
})
.done(function() { })
.fail(function() { });
});
The problem is that execution of above code (redactor.insertHtml(canned.response);) causes focus on the textarea. The code is executed on page load.
Is there any way I can insert the content into field without causing the focus to placed on this field?
Thank you in advance and best regards
Tom

Loading data from controller to chart Jquery/ MVC/ C#

I have the following controller code to return chart data to jquery.
UPDATE: I have modified the code as suggested, but still getting error.
public JsonResult GetLeaveDataForPieChart(int user_id)
{
List<EmployeeLeaveHeader> elh1 = new List<EmployeeLeaveHeader>();
List<ChartEvent> ch = new List<ChartEvent>();
elh1 = itlbg1.EmployeeLeaveHeaders.Where(f => f.Employee_ID == user_id).ToList();
foreach (var item in elh1)
{
ChartEvent ce = new ChartEvent();
ce.value = (item.leaveAvailable * 100).ToString();
ce.color = item.CompanyLeaves.LeaveTypes.color;
ce.highlight = "#ffffff";
ce.label = item.CompanyLeaves.LeaveTypes.typeDescription + " Leave Available";
ch.Add(ce);
ChartEvent ce1 = new ChartEvent();
ce1.value = (item.leaveTaken * 100).ToString();
ce1.color = item.CompanyLeaves.LeaveTypes.color_light;
ce1.highlight = "#ffffff";
ce1.label = item.CompanyLeaves.LeaveTypes.typeDescription + " Leave Taken";
ch.Add(ce1);
}
return Json(ch, JsonRequestBehavior.AllowGet);
}
I need to retrieve data in jquery so that it is in the required format to be passed to pie data.
(document).ready(function () {
user_id = $("#user_id_1").text();
$.ajax({
url: '/Leave/GetLeaveDataForPieChart/',
cache: false,
data: { user_id: user_id },
type: "GET",
datatype: "json",
success: function (data) {
alert(data);
var pieChartCanvas = $("#pieChart").get(0).getContext("2d");
var pieChart = new Chart(pieChartCanvas);
var PieData = $.each(data, function (idx, obj) {
var leave = new Object();
leave.value = obj.value;
leave.color = obj.color;
leave.highlight = obj.highlight;
leave.label = obj.label;
alert(leave);
return leave;
});
var pieOptions = {
//pie options..
};
pieChart.Doughnut(PieData, pieOptions);
}
});
Can anyone explain how to convert the json data to javascript object to be passed to the pie chart?

Here is how you parse JSON string into object.
var jsonObject = JSON.parse(jsonString);
here is how you use jquery to fetch the data and use it for your chart
$.ajax({
url: '/<Controller>/GetLeaveDataForPieChart/',
cache: false,
data: { user_id: <UserID> },
type: "GET",
success: function (data, textStatus, xmlHttpRequest) {
data = JSON.parse(data);
//....
//....
//Chart
//....
//....
//....
}
});