I have div2(height 20px vertical align centre) inside div1(100px) and div2 having anchor tag.
On hover of div1 I am showing hand pointer, but also want on click anywhere in div1 area it should navigate to anchor tag url. Please refer Image for more detail
.test:hover {
cursor: pointer;
cursor: hand;
}
<div class="test" style="height:100px">
<div style=" position: relative; top: 50%; transform: translateY(-50%);">
Pawan Kotak
</div>
</div>
If the outer 'div' should behave like an anchor, just reorder the elements like this:
<a href="myAnchor.tld">
<div id="div1">
<div id="div2"></div>
</div>
</a>
You don't have to mess around with jQuery, if your markup could simply be structured the way it actualy works.
try with following way
$(div1).on("click",function(){
window.location = $(this).find("a").attr("href");
});
this is just a wayout.
Assuming your div id's to be div1 and div2 here is a solution.
$('#div1').on('click',function(){
$(this).find('a').trigger('click');
});
The script will attach a click event to the div1 and when ever user clicks this div it finds the a tag with in it $(this).find('a') and triggers a click event on that anchor tag.
you can also grow your anchor tag (there are several methods/approaches)
.test {
background-color: red;
}
.test a {
cursor: hand;
background-color: blue;
display: block;
line-height: 100px;
}
<div class="test" style="height:100px">
<div style=" position: relative; top: 50%; transform: translateY(-50%);">
Pawan Kotak
</div>
</div>
Related
I have 3 questions about my jQuery study today.
Why my jQuery code not have the animation effect as it should be? for example, .slideUp() and .slideDown(), my code shows something strange instead of slideUp animation.
I understand, the .hide() or .slideUp() function is only to HIDE the div box, not DELETE them, however, in my code, why the position of other div boxes changed after a DIV .hide()? Shouldn't it stay at their original position as the DIV box is still there, just HIDED?
How can I achieve to let other DIVs stay at the original position, when one DIV box has been hided?
$(document).ready(function() {
$('#panel1').slideUp(1000).delay(1500).slideDown(1000);
});
.panel {
display: inline-block;
width: 80px;
height: 60px;
border: 1px solid green;
position: relative;
top: 20px;
margin-left: 45px;
border-radius: 5px;
}
.panelTop {
height: 30px;
background-color: blue;
color: white;
text-align: center;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<div class="panels">
<div id="panel1" class="panel">
<div class="panelTop">#panel1</div>
<div class="panelBottom">content</div>
</div>
<div id="panel2" class="panel">
<div class="panelTop">#panel2</div>
<div class="panelBottom">content</div>
</div>
<div id="panel3" class="panel">
<div class="panelTop">#panel3</div>
<div class="panelBottom">content</div>
</div>
<div id="panel4" class="panel">
<div class="panelTop">#panel4</div>
<div class="panelBottom">content</div>
</div>
</div>
For your first question
Why my jQuery code not have the animation effect as it should be? for
example, .slideUp() and .slideDown(), my code shows something strange
instead of slideUp animation.
The .slideUp() method animates the height of the matched elements. Means it animates height so it reaches 0 (or, if set, to whatever the CSS min-height property is). See here for reference. That is exactly what is happening to your first box it is decreasing in height.
Afterwards the display style property is set to none to ensure that the element no longer affects the layout of the page.
What display none does ?
display:none means that the tag in question will not appear on the
page at all
Now for second and third question
I understand, the .hide() or .slideUp() function is only to HIDE the
div box, not DELETE them, however, in my code, why the position of
other div boxes changed after a DIV .hide()? Shouldn't it stay at
their original position as the DIV box is still there, just HIDED?
How can I achieve to let other DIVs stay at the original position,
when one DIV box has been hided?
The .hide() and .slideUp()function they both add display:none to your tag element. Means they are gone now
Now what can you do to let them stay there, But hidden from view ?
You can use visibility or opacity property instead rather than using display
property.
For example: visibility: hidden; will just hide it from the view.
Will update your fiddle in order to demonstrate it in a while. Hope this will help you. Please feel free to ask if not clear. Thank you.
$(document).ready(function() {
setInterval(function(){
$('#panel1').slideUp(1000).delay(500).slideDown(1000);
}, 3000);
});
.outer-div
{
position: relative;
display: inline-block;
min-height: 1px;
margin-right: 15px;
margin-left: 15px;
width: 130px;
height: 90px;
}
.panel {
border: 1px solid green;
margin-left: 45px;
border-radius: 5px;
position:absolute;
top:0;
width: 100%;
}
.panelTop {
height: 30px;
background-color: blue;
color: white;
text-align: center;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<div class="panels">
<div class="outer-div">
<div id="panel1" class="panel">
<div class="panelTop">#panel1</div>
<div class="panelBottom">content</div>
</div>
</div>
<div class="outer-div">
<div id="panel2" class="panel">
<div class="panelTop">#panel2</div>
<div class="panelBottom">content</div>
</div>
</div>
<div class="outer-div">
<div id="panel3" class="panel">
<div class="panelTop">#panel3</div>
<div class="panelBottom">content</div>
</div>
</div>
<div class="outer-div">
<div id="panel4" class="panel">
<div class="panelTop">#panel4</div>
<div class="panelBottom">content</div>
</div>
</div>
</div>
You should use display:flex on .panels, that solves your first question.
For second question you should use visibility or opacity.
With current code you are removing it, although it is called hide() it is equivalent to CSS display:none; which doesn't keep space of element.
Although you actually don't need to set visibility in your case because sliding it up will hide element and down show.
Something like this:
$('#panel1').animate({
top: -62 // 60 is height of element plus 2px of borders
}, 1000).delay(1500).animate({
top: 0
}, 1000);
Also you have to change CSS a bit.
Add this to your CSS:
.panels {
display: flex;
overflow: hidden;
margin-top: 20px;
}
And from .panel remove top: 20px;
Full example is here https://jsfiddle.net/_jakob/cphptby3/1/
I have two Div's next to each other, wrapped in a container Div which has the display:flex-attribute. Now I have this kind of tricky issue where I need to be able to click on one element inside the div which then shows a previously hidden div, which also is placed inside the container. When the hidden div is visible, the container of course expands BUT I need the container NOT to expand and I cannot place the hidden div outside the container. I have the following example code:
HTML:
<div id="container">
<div class="content">
<div class="top">
This is the top
</div>
<div class="bottom">
This is the bottom - click me
</div>
<div class="expand">
This is hidden content
</div>
</div>
<div class="content right">
This is the right content
</div>
</div>
The CSS:
#container {
width: 100%;
display: flex;
}
.content {
float: left;
width: 49%;
border: 1px solid;
}
.top, .bottom {
height:100px;
}
.top {
background: #ddd;
}
.bottom {
background: #eee;
}
.right {
background: #e9e9e9
}
.expand {
display:none;
background: #999;
}
I have made JSFIDDLE - So the hidden div should be outside the container when its visible - can someone help me out?
adding position: absolute; to the .expand div pushes the div outside of the box
https://jsfiddle.net/4724m90k/
I am working on an effect here, I will post the code as well, but here is the basic premise. I have a div containing 2 divs and one hidden div called test. When I click the containing div I want the hidden div (which is called "test") to animate only for the containing div I clicked. Right now it is opening on every single div because of how I have the code written, I am thinking I have to use "this" in order to get it to open correctly the way I want it, but I am not sure how to use it in this instance
TLDR: I want to toggle class .open on the div .test when I click the div .workImg (or workBlock), currently it is opening on every .workImg, I want it to only open on the one I click. I am very stumped, I think I need to use $(this) in here somewhere to target just the one I am clicking but cannot figure out how to apply that since all of my class names are the same...
HTML:
<div class="workCont">
<div class="workBlock">
<div class="workImg">
<div class="test"></div>
<img src="/assets/images/piece1.jpg" />
</div>
<div class="workName">Project</div>
</div>
<div class="workBlock">
<div class="workImg">
<div class="test"></div>
<img src="/assets/images/piece1.jpg" />
</div>
<div class="workName">Project</div>
</div>
<div class="workBlock break">
<div class="workImg">
<div class="test"></div>
<img src="/assets/images/piece1.jpg" />
</div>
<div class="workName">Project</div>
</div>
</div>
CSS:
.workCont {
width:1024px;
margin: $center;
overflow:hidden;
.workBlock {
float:left;
margin-left:17px;
&:nth-child(3n+1) {
margin-left:0;
}
&:nth-child(1n+1) {
margin-top:33px;
}
.workImg {
background:#151515;
width:330px;
height:201px;
display:inline-block;
position: relative;
}
.test {
position: absolute;
z-index:100;
width: 0px;
height: 0px;
-webkit-transition-duration: 1s;
-webkit-transition-property: all;
-webkit-transition-timing-function: ease-in-out;
text-align: center;
background: white;
color: white;
font-family: sans-serif; /* Just 'cos */
}
.test.open {
transform: scale(50, 50);
top: 0px;
left: 0px;
width: 1000px;
height: 1000px;
clear:both;
}
.workName {
text-align:center;
margin-top:17px;
}
}
}
jQuery:
$(document).ready(function(){
$(".workImg").click(function() {
$(".test").toggleClass("open");
});
});
use $(this)
$(document).ready(function(){
$(".workImg").click(function() {
$(this).find(".test").toggleClass("open");
});
});
I created a notecard image where i overlayed multiple images on top of it. These are elements of the notecard. I want it so that when I hover over the notecard, I can completely change the contents on the notecard image (overlaying new things onto the notecard).
So right now, I have this right now:
<div style="position:relative;">
<a href="#games">
<img id "image_a" a" src="images/card_normal.png" onmouseover "this.src rc 'images/hover/card_hover.png';" ;" onmouseout "this.src rc 'images/card_normal.png';" ;" style="position: absolute; top: 0; left: 0;"/>
<img id "image_b" b" src="images/category_icons/icon_games.png" style="position: absolute; top: 10px; left: 40px;"/>
<img id "image_c" c" src="images/category_titles/title_games.png" style="position: absolute; top: 160px; left: 40px;"/>
</a>
</div>
Where the notecard changes into a "hovered" version, but I am unable to change anything else. I want it so that whenever the mouse pointer is in the notecard (including if its on other elements inside the notecard), the contents change. I want to completely scrap the contents of it (so the title and icon) and change it so I can add text and overlay new images.
How can I do this in JS/HTML/etc?
If the two versions (hover/non-hover) are significantly different (and you want a no-js solution), you could have two divs, one set to hide, one set to show. Then on-hover, you change their visibility. Fiddle.
<div class="card">
<div class="no-hover">
stuff you want to show when the user is just looking
</div>
<div class="on-hover">
stuff you want to show when the user hovers
</div>
</div>
CSS:
.no-hover {
display: block;
}
.on-hover {
display: none;
}
.card:hover > .on-hover {
display: block;
}
.card:hover > .no-hover {
display: none;
}
It's extra HTML elements, but might be easier to maintain.
Based on your comment to Learner's answer, here is an example of the idea you are describing:
HTML:
<div class="outer">
<div class="inner"></div>
<div class="inner"></div>
<div class="inner"></div>
<div class="inner"></div>
</div>
CSS:
.outer {
width: 304px;
height: 304px;
background-color: black;
}
.inner {
float: left;
width: 150px;
height: 150px;
background-color: red;
border: 1px solid black;
display: none;
}
.outer:hover .inner {
display: block;
}
DEMO
If you are trying to achieve something like this:
http://spoonfedproject.com/wp-content/uploads/demo/jquery-slide-hover/index.htm
Here's your solution:
http://www.robertkuzma.com/2011/01/jquery-animated-swap-div-content-on-hover-effect/
I'm using JavaScript with HTML and I have a page that includes multiple iframes. I want to be able to blur some of these iframse (not hide then) so that users can see what is inside these frames but cannot click on them or type in them.
Is there a way to do this?
iframe.contents().find('body').blur()
Something like this may be what you want: http://jsfiddle.net/Paulpro/xcWcn/1/
HTML:
<div id="frame1-blocker" class="frame-blocker"></div>
<iframe id="frame1" src="http://google.com" style="width: 500px; height: 300px; padding: 0px; border: 0px;"/>
CSS:
.frame-blocker{
background-color: rgba(0,0,0,0.5);
position: absolute;
width: 500px;
height: 300px;
}
I would suggest positioning a transparent DIV over each "blurred" iFrame to prevent clock events propagating downward. iFrame tags themselves do not to my knowledge provide the functionality you want.
And for what it's worth, "blur" in Web parlance refers to moving the text cursor outside of a control!
Here is a demo of a way using an overlay within the iframe:
#hidden {
display: none;
}
iframe {
width: 200px;
height: 200px;
}
a {
color: #f00;
text-decoration: underline;
cursor: pointer;
}
<div>
<a class="activate" rel="1">Active Test 1</a><br/>
<a class="activate" rel="2">Active Test 2</a><br/>
<a class="activate" rel="3">Active Test 3</a>
</div>
<iframe id="test1"></iframe>
<iframe id="test2"></iframe>
<iframe id="test3"></iframe>
<div id="hidden">
<div id="overlay" style="display: none; position: absolute; left: 0; top: 0; z-index: 100; background-color: #000;"></div>
<div>
http://www.yahoo.com/
</div>
</div>
$('iframe').each(function(){
$(this).contents().find('body').append($('#hidden').html());
});
$('div a.activate').click(function(){
$('iframe[id^=test]').contents().find('#overlay')
.css('height','200px')
.css('width','200px')
.fadeTo('fast', 0.5);
$('iframe#test'+this.rel).contents().find('#overlay')
.css('height','0')
.css('width','0')
.fadeTo('fast', 1);
});
http://jsfiddle.net/ZTpXa/