its been 2 days that im stuck with this error i can see the data that i post but the next page do not load
when i submit i get http://localhost:8000/android/www/login1.html?username=**********&password=****************&action=SignIn
thanks for ur help.
<script type="text/javascript">
$(document).ready(function() {
$('button[type=submit]').submit(function () {
var username = $('input[name=username]').val();
var password = $('input[name=password]').val();
$.ajax({
type: "POST",
url: "http://localhost/server1/login1.php",
data: $('#login').serialize(),
dataType: 'json',
success:function(json){
if(json.status === 'success') {
alert('Tout est bon');
window.location.href="TestPorteur.html";
}
else{
window.location.href="ResetPassword.html";
}
}
/* */
});
return false;
});
});
</script>
<div class="login-bottom" id="login">
<form id="form" >
<div class="text">
<input type="text" placeholder="Numéro Téléphone" id="username" name="username" />
<span class="men"></span>
<div class="clear"> </div>
</div>
<div class="text">
<input type="password" placeholder="Password..." id="password" name="password" />
<span class="pass"></span>
<div class="clear"> </div>
</div>
<div class="remember">
<div class="remember-top">
Mot de passe oublié?
</span>
</div>
<div class="send">
<button type="submit" id="action" name="action" value="SignIn">Sign In</button>
</div>
<div class="clear"> </div>
</div>
</form>
</div>
<?php
header('Access-Control-Allow-Origin: *');
include('conn.php');
if(isset($_POST["username"])&& isset($_POST["password"])){
$password = $_POST['password'];
$username = $_POST['username'];
echo"Veuillez remplir les champs";
}
$sql7="select * from utilisateur WHERE username='$username'";
$result=mysqli_query($conn, $sql7);
while($result1 = mysqli_fetch_array($result)){
$var=$result['password'];}
if($password!='$var'){
$status="passworderrone";
echo json_encode(['status' => $status]);
}
if($password=='$var'){
$vari='11';
function getRemoteIp(){
if( !ini_get('register_globals') ) {
return $_SERVER['REMOTE_ADDR'];
} else {
return #$REMOTE_ADDR;
}
return "";
}
$ip = getRemoteIp();
$sql2="select * from session WHERE username='$username'";
$usrname=mysqli_query($conn, $sql2);
while($result = mysqli_fetch_array($usrname)){
$vari=$result['username'];
}
if('$vari'==$username){
$status= "dejainscris";
echo json_encode(['status' => $status]);
$sql3 = "INSERT INTO session (username, tps_connx, tcpip)
VALUES ('$username',NOW(),'$ip')";
$res3=mysqli_query($conn, $sql3);
}
else {$status="premiereinscription";
echo json_encode(['status' => $status]);
}
}
?>
There are two things you can do to fix this.
Remove type=submit from button and in JS instead of catching submit event, you should catch click event.
<button id="action" name="action" value="SignIn">Sign In</button>
and in JS you should look for click event.
$('button#action').click(function () {
The reason for this type=submit directly submit the form. So first that needs to be checked, then look for click event and do your thing.
Second way to do this is that instead of catching submit event on button, look for submit event on form because it is meant for forms.
so your JS should
$('#form').submit(function (e) {
e.preventDefault();
...
Related
I'm trying to log in and then redirect to a custom page, based on user type. My problem is that when I'm pressing the login button, on the console I get that that I have a Undefined array key pageType, and I don't understand why... If I'm for example on teacher page, I set $_SESSION['pageType'] = 'teacher';
This my login.html page:
<img class="wave" src="img/wave.png">
<div class="container_main" onsubmit="redirect();">
<div class="img">
<img src="img/bg.svg">
</div>
<div class="login-content">
<form onsubmit="redirect();">
<img src="img/avatar.svg">
<h2 class="title">Quiz Website</h2>
<div class="input-div one">
<div class="i">
<i class="fas fa-user"></i>
</div>
<div class="div">
<input type="text" class="input" id="enterID" placeholder="Username">
</div>
</div>
<div class="input-div pass">
<div class="i">
<i class="fas fa-lock"></i>
</div>
<div class="div form-group">
<input id="password" type="password" class="form-control" placeholder="Password" value="" required/>
</div>
</div>
Don't have an account?
<div class="form-group">
Trouble logging in?
</div>
<input type="submit" class="btn" value="Login" onclick="login();" readonly >
<div class="error-message" id="errorMessage"></div>
</form>
</div>
</div>
</html>
This is checklogin.js:
function login() {
var enterID = document.getElementById("enterID").value;
var password = document.getElementById("password").value;
if ((password != "") && (enterID != "")) {
var info = "?enterID=" + enterID + "&password=" + password;
$.ajax
({
type: "GET",
async: true,
url: "php/login.php" + info,
success: function (respond) {
if (respond == "admin") {
window.location.href = "page/admin-system-management.php";
} else if (respond == "student") {
window.location.href = "page/student-dashboard.php";
} else if (respond == "teacher") {
window.location.href = "page/teacher-dashboard.php";
} else {
document.getElementById("errorMessage").innerText = respond;
}
}
});
}
else {
document.getElementById("errorMessage").innerText = "Please fill in all the fields.";
}
}
function redirect() {
$.ajax
({
type: "GET",
async: true,
url: "php/redirect.php",
success: function (respond) {
if (respond != "not logged.") {
if (respond == "admin") {
window.location.href = "page/admin-system-management.php";
} else if (respond == "student") {
window.location.href = "page/student-dashboard.php";
} else if (respond == "teacher") {
window.location.href = "page/teacher-dashboard.php";
}
}
console.log(respond)
}
});
}
And this is my redirect.php file:
<?php
if (session_status() == PHP_SESSION_NONE) {
session_start();
}
if (isset($_SESSION["type"])){
if ($_SESSION["type"] != $_SESSION["pageType"]){
$alert_message = "You cannot access this page using your account!";
$link = "../login.html";
echo "<script type='text/javascript'>alert('$alert_message'); window.setTimeout(function(){ if ('".$_SESSION["type"]."'=='admin'){ window.location.href = '../page/admin-system-management.php';} else if ('".$_SESSION["type"]."'=='student'){ window.location.href = '../page/student-dashboard.php';} else if ('".$_SESSION["type"]."'=='teacher'){ window.location.href = '../page/teacher-dashboard.php';} }, 0);</script>";
}
} else {
$alert_message = "Your login period has expired! Please login again!";
$link = "../login.html";
echo "<script type='text/javascript'>alert('$alert_message'); window.setTimeout(function(){ window.location.href = '$link'; }, 0);</script>";
}
?>
What I suspect is that the redirect() function it's not even loaded, so that's why I think I'm getting this error... Sometimes I'm seeing ,,XHR failed loading: GET"
I modified a code in order to have another login.html page, this is my old login.html code:
<body class="jumbotron vertical-center" onload="redirect();">
<div class="container login-container">
<div class="row">
<div class="col-md-4 login-form mx-auto">
<h3>Login</h3>
<h6>Don't have an account? Register</h6>
<form>
<div class="error-message" id="errorMessage"></div>
<div class="form-group">
<input id="enterID" type="text" class="form-control" placeholder="Your User ID *" value="" required/>
</div>
<div class="form-group">
<input id="password" type="password" class="form-control" placeholder="Your Password *" value="" required/>
</div>
<div class="form-group">
<input class="btn btn-block btn-primary" value="Login" onclick="login();" readonly />
</div>
<div class="form-group">
Trouble logging in?
</div>
</form>
</div>
</div>
</div>
</body>
Inside redirect() function add this line at the start.
This will stop the forms default action of redirecting/refreshing the page
event.preventDefault();
Then your redirect function / respond variable should work
If you return this from php it will be ignored by javascript
echo "<script type='text/javascript'>code here\</script>";
To make your redirect.php easier to debug output the data as a json encoded array instead of a string that way you can view/test more data.
inside redirect.php try add this code straight after the session_start() line just as a first test
$data = [
'session' => $_SESSION,
'response' => 'place your response here',
];
echo json_encode($data);
exit;
Ok here is the update i think you need.
redirect.php
<?php
if(!session_id()) {
session_start();
}
// you can change this line to this once you have debugged your code - $data = [];
$data = ['session' => $_SESSION];
// place code here to get the user type from the database
// then use $_SESSION['type'] = '{database response}';
if(!isset($_SESSION['type']))
{
$_SESSION['type'] = null;
}
switch($_SESSION['type']) {
case 'admin':
header('Location: /page/admin-system-management.php'); // this is the php way to redirect
break;
case 'student':
header('Location: /page/student-dashboard.php');
break;
case 'teacher':
header('Location: /page/teacher-dashboard.php');
break;
default:
$data['alert_message'] = 'Your login period has expired! Please login again!';
}
echo json_encode($data);
exit;
?>
Javascript redirect function
function redirect() {
$.ajax
({
type: "GET",
async: true,
url: "php/redirect.php",
success: function (response) {
console.log(response);
if(response.alert_message) {
alert(response.alert_message);
}
}
});
}
I simply want to submit my form to the same page with ajax without page refresh. So my below code submits the form but $_POST values are not picked ... Am I submitting it properly. I don't get any error but I think my form is not submitting.
html form
<form action="" id="fixeddonation" name="fixeddonation" method="post">
<input type="hidden" class="donerProject" name="donerProject" value="test">
<input type="hidden" class="donersubProject" id="donersubProject" name="donersubProject" value="general">
<input type="hidden" class="donerLocations" id="donerLocations" name="donerLocations" value="general">
<input type="hidden" class="donationpagetype" name="donationpagetype" value="general">
<input type="hidden" class="projectadded" id="projectadded" name="projectadded" value="1">
<input type="hidden" value="302" id="pageid" name="pageid">
<div class="classsetrepet generalfixshow fullrow row fixed-page">
<div class="col-6 text-right">
<div class="prize">Fixed Amount £</div>
</div>
<div class="col-6">
<input type="text" id="oneoffamt" name="oneoffamt" class="oneoffamt validatenumber">
<span class="amt_error"></span>
</div>
</div>
<br>
<div class="row">
<div class="col-6"></div>
<div class="col-6">
<input type="submit" id="submit_gen_one" class="btn-block" value="submit" name="submit_gen_one">
</div>
</div>
</form>
Ajax code
jQuery('#fixeddonation').on('submit', function (e) {
e.preventDefault();
jQuery.ajax({
type: 'post',
url: 'wp-admin/admin-ajax.php',
data: jQuery('#fixeddonation').serialize(),
success: function (data) {
alert(data);
alert('form was submitted');
jQuery('#collapse2').addClass('in').removeAttr('aria-expanded').removeAttr('style'); jQuery('#collapse1').removeClass('in').removeAttr('aria-expanded').removeAttr('style');
}
});
return false;
});
Add a correct value to the action tag of your form and try this:
<script>
$(document).ready(function() {
var form = $('#fixeddonation');
form.submit(function(ev) {
ev.preventDefault();
var formData = form.serialize();
$.ajax({
method: 'POST',
url: form.attr('action'),
data: formData
}) .done(function(data) {
alert(data);
});
});
}); // end .ready()
</script>
Don't need return false as you already called preventDefault() first thing
First create Template
<?php
/* Template Name: Test */
get_header();
?>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js" type="text/javascript"></script>
<div id="primary" class="content-area">
<main id="main" class="site-main">
<p class="register-message" style="display:none"></p>
<form action="#" method="POST" name="testregister" class="register-form">
<fieldset>
<label><i class="fa fa-file-text-o"></i> Register Form</label>
<input type="text" name="firstname" placeholder="Username" id="firstname">
<p id="firstname-error" style="display:none">Firstname Must Be Enter</p>
<input type="email" name="email" placeholder="Email address" id="email">
<p id="email-error" style="display:none">Email Must Be Enter</p>
<input type="submit" class="button" id="test" value="Register" >
</fieldset>
</form>
<script type="text/javascript">
jQuery('#test').on('click',function(e){
e.preventDefault();
var firstname = jQuery('#firstname').val();
var email = jQuery('#email').val();
if (firstname == "") {
jQuery('#firstname-error').show();
return false;
} else {
jQuery('#firstname-error').hide();
}
if (email == "") { jQuery('#email-error').show(); return false; }
else { jQuery('#email-error').hide(); }
jQuery.ajax({
type:"POST",
url:"<?php echo admin_url('admin-ajax.php'); ?>",
data: {
action: "test",
firstname : firstname,
email : email
},
success: function(results){
console.log(results);
jQuery('.register-message').text(results).show();
},
error: function(results) {
}
});
});
</script>
</main><!-- #main -->
</div><!-- #primary -->
after that create a function (function.php in wordpress)
add_action('wp_ajax_test', 'test', 0);
add_action('wp_ajax_nopriv_test', 'test');
function test() {
$firstname = stripcslashes($_POST['firstname']);
$email = stripcslashes($_POST['email']);
global $wpdb;
$q = $wpdb->prepare("SELECT * FROM wp_test WHERE email='".$email."' ");
$res = $wpdb->get_results($q);
if(count($res)>0)
{
echo "Email Allready Register ";
}
else
{
$user_data = array(
'firstname' => $firstname,
'email' => $email
);
$tablename = $wpdb->prefix.'test'; // if use wordpress
$user_id= $wpdb->insert( $tablename,$user_data );
echo 'we have Created an account for you';
die;
}
}
I'm very new to ajax, and I'm trying to make a login script that doesn't require a page reload - it's working well except I attempt to set a session variable on the processing page, but no session variable is set.
My form:
<div class="form-bottom">
<form role="form" class="login-form">
<div class="form-group">
<label class="sr-only" for="username">Username</label>
<input type="text" name="username" placeholder="Username..." class="form-username form-control" id="username">
</div>
<div class="form-group">
<label class="sr-only" for="password">Password</label>
<input type="password" name="password" placeholder="Password..." class="form-password form-control" id="password">
</div>
<input type="submit" id="submit" class="btn" style="width:100%;background-color:lightblue;" value="Log In" id="login"/>
</form>
<? echo $_SESSION['Name']; ?>
</div>
My ajax:
<script type="text/javascript" >
$(function() {
$("#submit").click(function() {
var username = $("#username").val();
var password = $("#password").val();
var dataString = 'username='+ username + '&password=' + password;
if(username=='' || password=='')
{
$('.success').fadeOut(200).hide();
$('.error').fadeOut(200).show();
}
else
{
$.ajax({
type: "POST",
url: "ajax/login.php",
data: dataString,
success: function(){
$('.success').fadeIn(200).show();
$('.error').fadeOut(200).hide();
window.setTimeout(function () {
location.href = "index.php";
}, 3000);
}
});
}
return false;
});
});
</script>
My php script:
include('./static/config.php');
if (session_status() == PHP_SESSION_NONE) {
session_start();
}
if(isset($_POST)) {
$username = mysqli_real_escape_string($con, $_POST['username']);
$password = mysqli_real_escape_string($con, $_POST['password']);
$sql = "SELECT Name FROM techs WHERE Username='$username' AND Password='$password'";
$result = mysqli_query($con, $sql);
$exists = mysqli_num_rows($result);
if($exists == 1) {
$row = mysqli_fetch_assoc($result);
$_SESSION['Name'] = $row['Name'];
}
}
I was able to get it working the way I wanted it to.
Form:
<div id="box">
<div class="row">
<div class="col-sm-6 col-sm-offset-3 form-box">
<div class="form-top">
<div class="form-top-left">
<h3>Log-in</h3>
<span id="error" class="error"></span>
</div>
<div class="form-top-right">
<i class="fa fa-key"></i>
</div>
</div>
<div id="box" class="form-bottom">
<form class="login-form" action="" method="post">
<div class="form-group">
<label class="sr-only" for="username">Username</label>
<input type="text" name="username" placeholder="Username..." class="form-username form-control" id="username">
</div>
<div class="form-group">
<label class="sr-only" for="password">Password</label>
<input type="password" name="password" placeholder="Password..." class="form-password form-control" id="password">
</div>
<input type="submit" id="login" class="btn" style="width:100%;background-color:lightblue;" value="Log In" id="login"/>
</form>
</div>
</div>
</div>
</div>
AJAX Code:
<script src="js/jquery.min.js"></script>
<script src="js/jquery.ui.shake.js"></script>
<script>
$(document).ready(function() {
$('#login').click(function()
{
var username=$("#username").val();
var password=$("#password").val();
var dataString = 'username='+username+'&password='+password;
if($.trim(username).length>0 && $.trim(password).length>0)
{
$.ajax({
type: "POST",
url: "ajax/login.php",
data: dataString,
cache: false,
beforeSend: function(){ $("#login").val('Connecting...');},
success: function(data){
if(data)
{
window.setTimeout(function () {
location.href = "index.php";
}, 3000);
}
else
{
$('#box').shake();
$("#login").val('Login')
$("#error").html("<span style='color:#cc0000'>Error:</span> Invalid username and password. ");
}
}
});
}
return false;
});
});
</script>
PHP (ajax/login.php):
<?php
include("../static/config.php");
session_start();
if(isSet($_POST['username']) && isSet($_POST['password']))
{
// username and password sent from Form
$username=mysqli_real_escape_string($con,$_POST['username']);
$password=mysqli_real_escape_string($con,$_POST['password']);
$result=mysqli_query($con,"SELECT Name FROM techs WHERE Username='$username' and Password='$password'");
$count=mysqli_num_rows($result);
$row=mysqli_fetch_array($result,MYSQLI_ASSOC);
// If result matched $myusername and $mypassword, table row must be 1 row
if($count==1)
{
$_SESSION['Name']=$row['Name'];
echo $row['Name'];
}
}
?>
Since you've stated you're very new to Ajax, you start off pretty well.
There are however a couple of things to know how this works.
You want to avoid a page refresh, yet you don't print out any responses because you're not returning anything in the ajax request. You instead set a session variable which will show up at the next page request (so a refresh)
$.ajax({
type: 'POST',
url: 'ajax/login.php',
data: { username: $("#username").val(), password: $("#password").val() },
success: function (data) {
$('.form-bottom').html(data); // here we replace the form with output of the ajax/login.php response.
}
});
And for the PHP side of things:
$sql = "SELECT Name FROM techs WHERE Username='$username' AND Password='$password'";
if(($result = mysqli_query($con, $sql)) != false){ // always verify if your query ran successfully.
if(mysqli_num_rows($result)){ // or compare with == 1, but assuming a username is unique it can only be 1 so it equals to true.
echo mysqli_fetch_assoc($result)['name']; // index, columns, etc should always be lower cased to avoid confusion.
// Obviously you can store it in a session
// But for now just output the data so we can use it as our response.
// json is very usefull with sending large amounts of data.
}
}
The idea of Ajax is that you can request an update, but you need to update your page with javascript manually in order to make it work.
I think you forget to start the session.So start the session at the top of your script. Hope it will help.
session_start();
include('./static/config.php');
if(isset($_POST)) {
$username = mysqli_real_escape_string($con, $_POST['username']);
$password = mysqli_real_escape_string($con, $_POST['password']);
$sql = "SELECT Name FROM techs WHERE Username='$username' AND Password='$password'";
$result = mysqli_query($con, $sql);
$exists = mysqli_num_rows($result);
if($exists == 1) {
$row = mysqli_fetch_assoc($result);
$_SESSION['Name'] = $row['Name'];
}
}
3 things you could try:
On the page where you are trying to set the session variable you would have to use proper php opening tags like <?php
Second thing is that you would have to put a value in your session like $_SESSION['hello'] = 'hello';
Third thing, on every page where you handle your session you would have to call <?php session_start(); ?> for it to work.
Goodluck!
i am trying to send some values from html form to php page.
here in the form i have some values which are hidden.and one text field which its value has to be passed to php page.
index.php:
<?php
if ($login->isUserLoggedIn() == true){
?>
<div class="panel panel-default">
<div class="panel-heading"><h4>Invite friend</h4></div>
<div class="panel-body">
<form action="friend-invite.php" method="get">
<div class="col-md-4 col-lg-4">
<label class="control-label" for="friend">Enter email address</label>
<input type="email" class="form-control" name="friendemail" id="friendemail" placeholder="sam#uncle.com" required><br>
<?php
echo '<input type="hidden" name="invitename" value="'.$_SESSION["user_name"].'">' ;
echo '<input type="hidden" name="invite-url" value="'.$_SERVER['REQUEST_URI'].'">';
echo '<input type="hidden" class="invite-product" name="invite-product-name">';
?>
<input type="submit" name="submit" value="Invite" class="btn btn-primary">
</div>
</form>
<div class="mail-message"></div>
</div>
</div>
<?php
}else{
}?>
friend-invite.php:
<?php
include('_header.php');
$user_email = $_GET['friendemail'];
$invited_by = $_GET['invitename'];
$invite_link = $_GET['invite-url'];
$product_name = $_GET['invite-product-name'];
if (isset($user_email, $invited_by, $invite_link, $product_name)){
sendInvitation($user_email,$invited_by,$invite_link,$product_name);
} else {
echo "Are you trying to do something nasty??";
}
function sendInvitation($user_email,$invited_by,$invite_link,$product_name)
{
$mail = new PHPMailer;
if (EMAIL_USE_SMTP) {
$mail->IsSMTP();
$mail->SMTPAuth = EMAIL_SMTP_AUTH;
if (defined(EMAIL_SMTP_ENCRYPTION)) {
$mail->SMTPSecure = EMAIL_SMTP_ENCRYPTION;
}
$mail->Host = EMAIL_SMTP_HOST;
$mail->Username = EMAIL_SMTP_USERNAME;
$mail->Password = EMAIL_SMTP_PASSWORD;
$mail->Port = EMAIL_SMTP_PORT;
$mail->IsHTML(true);
} else {
$mail->IsMail();
}
$mail->From = EMAIL_VERIFICATION_FROM;
$mail->FromName = $invited_by;
$mail->AddAddress($user_email);
$mail->Subject = SHOP_INVITE;
$link = $invite_link;
$mail->Body = $invited_by." ".FRIEND_INVITE_PRODUCT."<a href='".$link."'>".$product_name."</a>";
if(!$mail->Send()) {
$this->errors[] = MESSAGE_VERIFICATION_MAIL_NOT_SENT . $mail->ErrorInfo;
return false;
} else {
return true;
}
}
?>
AJAX function:
$(function () {
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'get',
url: 'invite-friend.php',
data: $('form').serialize(),
success: function () {
$(".mail-message").html('<div class="alert alert-success"><strong>Success!</strong> Indicates a successful or positive action.</div>');
}
});
});
});
the friend-invite.php page is getting the values that has been passed to it and check if the values has been set, if it has been set then it will call the php function sendInvitation() with the parameters. now all these things are happening pretty good.but i want to do it through AJAX. how can i do that.
You forgot to give your hidden fields an id:
echo '<input type="hidden" name="invitename" id="invitename" value="'.$_SESSION["user_name"].'">' ;
...
Change your index.php as:
<?php
if ($login->isUserLoggedIn() == true){
?>
<div class="panel panel-default">
<div class="panel-heading"><h4>Invite friend</h4></div>
<div class="panel-body">
<form action="">
<div class="col-md-4 col-lg-4">
<label class="control-label" for="friend">Enter email address</label>
<input type="email" class="form-control" name="friendemail" id="friendemail" placeholder="sam#uncle.com" required><br>
<?php
echo '<input type="hidden" name="invitename" value="'.$_SESSION["user_name"].'">' ;
echo '<input type="hidden" name="invite-url" value="'.$_SERVER['REQUEST_URI'].'">';
echo '<input type="hidden" class="invite-product" name="invite-product-name">';
?>
<input type="button" id="btn-submit" name="submit" value="Invite" class="btn btn-primary" />
</div>
</form>
<div class="mail-message"></div>
</div>
</div>
<?php
}else{
}?>
And change AJAX function as:
$(function () {
$('#btn-submit').on('click', function (e) {
e.preventDefault();
$.ajax({
type: 'get',
url: 'invite-friend.php',
data: $('form').serialize(),
success: function () {
$(".mail-message").html('<div class="alert alert-success"><strong>Success!</strong> Indicates a successful or positive action.</div>');
}
});
});
});
We do not need a submit button in form if we using AJAX.
Dude you are simply making your code complex ... you are doing form submit + ajax submit .I think there you are going wrong.
Just try these:
Remove action="friend-invite.php" from your form tag and try . if this does not help than make your button input type button or use button tag. just try all these it should work.
If all this does not work than give id and name to your form ,,and use to submit as:
$(function() {
$("#form_id").on("submit", function(event) {
Try all these
Html5 login button not responding when submit button is clicked. The below was built with remember me features but the button does nothing when clicked. Any help will be appreciated and below is the efforts so far. Thanks
<script src="jquery-1.9.1.js"></script>
<script>
$(function() {
if (localStorage.chkbx && localStorage.chkbx != '') {
$('#remember_me').attr('checked', 'checked');
$('#username').val(localStorage.usrname);
$('#pass').val(localStorage.pass);
} else {
$('#remember_me').removeAttr('checked');
$('#username').val('');
$('#pass').val('');
}
$('#remember_me').click(function() {
if ($('#remember_me').is(':checked')) {
// save username and password
localStorage.usrname = $('#username').val();
localStorage.pass = $('#pass').val();
localStorage.chkbx = $('#remember_me').val();
} else {
localStorage.usrname = '';
localStorage.pass = '';
localStorage.chkbx = '';
var userdata= "username="+username+"&pass="+pass+"&remember_me="+remember_me;
$("#loader").show();
$("#loader").fadeIn(400).html('<img src="loader.gif" align="absmiddle"> <span class="loading">Checking your details please be patient</span>');
$.ajax({
type:"post",
data:userdata,
url:"signin.php",
cache:false,
success:function(msg){
$("#loader").hide();
$('.error').fadeIn(200).html(msg);
}
});
}
});
});
</script>
<div class="container">
<form class="form-signin">
<h2 class="form-signin-heading">Please sign in</h2>
<input type="text" class="input-block-level" placeholder="username" id='username'>
<input type="password" class="input-block-level" placeholder="Password" id="pass">
<label class="checkbox">
<input type="checkbox" value="remember-me" id="remember_me"> Remember me
</label>
<button class="btn btn-large btn-primary" type="submit">Sign in</button>
</form>
</div>
<?php
require("db_pdo.php");
$username=strip_tags($_POST["username"]);
$pass=strip_tags($_POST["pass"]);
$remember_me=strip_tags($_POST["remember_me"]);
$statement = $db->prepare('
SELECT * FROM members
WHERE username = :username
AND password = :password AND remember_me = :remember_me
');
$statement->execute(array(
':usernameu' => $username,
':password' => $pass,
':remember_me' => 'remember_me'));
if ($row = $statement->fetch()) {
$user=$pid=htmlentities($row['fullname'], ENT_QUOTES, "UTF-8");
echo "Welcome Mr/Mrs <b>".$user."</b> <font color=pink>you are signed in successfully. <br>Redirecting in 2 seconds</font> <img src=loader.gif>";
echo '<script>
window.setTimeout(function() {
window.location.href = "welcome.html";
}, 2000);
</script>';
}else{
echo '<font color=red size=2><b>Either of your details is wrong. You are trying to use login accounts that belongs to another
person</b></font>';
}
?>