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Basically, the "rec" variable is correctly filled, but it's not happening with the "email" variable . Why?
This is my code:
<textarea id="q" name="q"></textarea>
<button onclick='alert(rec);'>Click</button>
<a id="email" href="#" target="_blank">Email</a>
<script>
var rec;
var email;
$("#q").keyup(function() {
rec = $('#q').val();
email = 'www.corriere.it/' + rec;
$('email').attr("href", email);
});
</script>
https://jsfiddle.net/wvsc93d4/3/
You're not using the selector correctly, try:
$('#email').attr("href",email);
You're missing the # selector:
$('#email').attr("href",email);
Related
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
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Closed 2 years ago.
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i don't understand why it doesn't send what they put in the input box to local storage
<body>
<input id="name">
<button onclick="bob()">
save
</button>
</body>
<script>
const person = document.getElementByid("name");
window.localStorage.setItem('user', JSON.stringify(person));
</script>
You need to use the value property to get what the user entered.
function bob() {
const person = document.getElementById("name");
window.localStorage.setItem('user', person.value);
}
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Closed 3 years ago.
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js code :
...
let wr = $('div[class="topstory-content-wrapper last"]');
console.log(wr.html());
...
error: throw new SyntaxError("Malformed attribute selector: " + selector);
^
SyntaxError: Malformed attribute selector: class = topstory-content-wrapper last
Try to write your selector in the next way:
const wr = $('div.topstory-content-wrapper.last');
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Closed 4 years ago.
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I'm trying to make an alert, that prints the value of a variabile, here is my attempt.
var username = prompt("I'm LaunchBot, what's your name?");
var print = alert() ;
alert() is a function. It take a parameter between the parenthesis. So just insert your variable username between them:
var username = prompt("I'm LaunchBot, what's your name?");
alert(username) ;
As suggested in the comment alert() doesn't return anything so do not add a variable assignment before.
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Closed 6 years ago.
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This part of javascript code works on my home computer, but doesn't at work. Also, my colleague tested it and it doesn't work on her home computer?!
function klikNaX(x, y, z) {
var u = document.getElementById(z);
var u2;
u2 = u.style.backgroundColor;
document.getElementById("test").innerHTML = (z + " " + u2);
}
The problem seems to be with this part
u.style.backgroundColor;
Its not a problem of style.backgroundColor, instead please check if 'u' is a valid node and not undefined.
And try setting a color to u.style.backgroundColor = 'green'
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Closed 7 years ago.
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This code should working, but I have no idea why it is not working at all.
HTML:
<p><input type="file" size="50"></p>
<p><input type="button" value="test" onclick="test()"></p>
JavaScript:
test = function() {
console.dir(document.querySelector('input[type="file"]').value);
var a = document.querySelector('input[type="file"]').vaule;
console.dir(a);
};
The first console.dir can successfully display the selected file filename
whereas I store it in var a is return undefined, whats happended?
fiddle: jsfiddle.net/eb5tuo7o
With the console log you're using .value but when you're storing it you've misspelled it as .vaule.
test = function() {
console.dir(document.querySelector('input[type="file"]').value);
var a = document.querySelector('input[type="file"]').value;
console.dir(a);
};
There is no such thing as "vaule"
You can access html elements value by using
document.querySelector('input[type="file"]').value;
And if you are using jquery it's even simpler
$("input[type=file]").val();