Develop Reference

Detecting return on input vs button click in reactive form

I'm building a reactive form in Angular with 3 submit buttons on it.
<form [formGroup]="sessionForm" (submit)="submitSession($event)">
<div class="row">
<label>
<span>Title</span>
<input type="text" formControlName="title" [class.required]="markRequired.indexOf('title') >= 0">
</label>
</div>
... more fields ...
<div *ngIf="!admin" class="row">
<button type="submit" (click)="setBtnClicked('submit')" class="btn btn-primary">Submit</button>
</div>
<div *ngIf="admin" class="row">
<button type="submit" (click)="setBtnClicked('save')" class="btn btn-primary">Save</button>
<button type="submit" (click)="setBtnClicked('approve')" class="btn btn-success">Save and approve</button>
<button type="submit" (click)="delete($event, false)" [hidden]="confirmDelete" class="btn btn-danger">Delete</button>
<button type="submit" (click)="delete($event, true)" [hidden]="!confirmDelete" class="btn btn-danger">Are you sure?</button>
</div>
<div [hidden]="!showSuccess" class="msgBox msgBox-success">Your session has been submitted! It will need to be approved before it is listed.</div>
</form>
On each button, I've attached a (click) handler which triggers a function to track which button is hit:
setBtnClicked(value) {
this.btnClicked = value;
}
However, when someone hits return on an input, I notice that the value of this.btnClicked is equal to the first button in the form.
I'm not sure how to track when a user hits return or when they hit the button, so I can respond differently, or if my structure is wrong. I'd like to trigger the submitSession function on any submit, be it return or button. I did try adding a formControl to the buttons, but that failed.

Because you're using a form, pressing enter on an input should run the submitSession() method tied to the form, but it's possible it's defaulting to the first submit button on the form. Maybe removing the submitSession() as well as the type="submit" from the buttons will prevent a form submission based on enter. That way the user would need to actually click a button to trigger something.
Also in the methods where you pass the event in, the following code would detect if it was triggered by an enter key press.
if (event.keyCode === 13) {
console.log('you just clicked enter');
}

How to submit form data in ajax using enter in the keyboard

I am creating a comment functionality and below are my code so far.
html
<form action="http://website.com/transaction_items/add_comment" class="" id="form-comment" role="form" method="post" accept-charset="utf-8">
<input type="hidden" name="checklists_item_id" value="6" style="display:none;">
<input type="hidden" name="user_id" value="1" style="display:none;">
<div class="input-group col-xs-12">
<input type="text" name="comment" value="" class="form-control" id="comment-input" placeholder="Enter your comments..">
<span class="input-group-btn">
<button class="btn btn-default" id="doc-comment" type="button">Post</button>
</span>
</div>
</form>
jQuery
This function is called when document is ready.
function comment () {
$('#doc-comment').click(function (e) {
var form_id = '#' + $(this).parents('form').attr('id');
// submit data from the form
submit.send(form_id);
});
}
The problem:
Using the button <button class="btn btn-default" id="doc-comment" type="button">Post</button> to submit data work fine, but
if I use enter in the keyboard, submit.send(form_id); will not do its function, instead the default form submission will execute.
How can I use ajax if use enter in the keyboard to submit form data?

nutshell
$("#form-comment").on('submit', function(evt) {
evt.preventDefault();
// do your ajax stuff here
});
you can then toss the onclick button listener.. as this will handle the button submit as well

There are more ways to submit a form then simply pressing the submit button.
You need to:
Use the forms submit method
Keep the form from doing the full submit.
-
// This will catch the *enter* as well as the submit button
$("#form-comment").on('submit', function(evt) {
evt.preventDefault();
// You can then submit the form via ajax and update things as needed.
});
IF you are going to use a button you should at least do a
<button type="button">...</button>
which behaves differently.

$("#form-comment").keyup(function (e) { // On pressing enter
if (e.keyCode == 13) {
// put your ajax code here
}
});
You may have to disable the default Enter event for the form submit button as well depending on your browser.
So in the Jquery Button click function make sure you have something like
event.preventDefault();

Hide form on submit with Angular JS

Trying to wrap my head around some Angular items and working thru a tutorial to edit and learn.
Clicking the below button shows the below form. How do I reverse this once the form is submitted? Meaning hiding the form on submit until the button is clicked once more.
<button ng-click="addNewClicked=!addNewClicked;" class="btn btn-sm btn-primary">
<i class="fa fa-plus"></i>Add Task
</button>
Basically, the form appears, I enter something and submit, but would like the form to dissapear upon submit? Thinking something to do with ng-hide, but can I do this using only Angular? Or do I need to do something with javascript/css?
<div id="addForm" class="margin-full-5">
<form ng-init="addNewClicked=false; " ng-if="addNewClicked" id="newTaskForm" class="add-task">
<div class="form-actions">
<div class="input-group">
<input type="text" class="form-control" name="comment" ng-model="taskInput" placeholder="Add New Task" ng-focus="addNewClicked">
<div class="input-group-btn">
<button class="btn btn-default" type="submit" ng-click="addTask(taskInput)">
<i class="fa fa-plus"></i> Add Task
</button>
</div>
</div>
</div>
</form>

You can also achieve this using a combination of Angular form's attribute $submitted, ng-hide and ng-submit
<form name="myForm" ng-hide="myForm.$submitted" ng-submit="submit()">
<button>Submit</button>
</form>
Read about it here: https://docs.angularjs.org/api/ng/type/form.FormController

Somewhere in your view.
<button ng-click="showTheForm = !showTheForm">Add a Task</button>
<form ng-show="showTheForm" ng-submit="processForm()">
<button>Submit</button>
<button type="button" ng-click="showTheForm = false">Cancel</button>
</form>
Somewhere in your controller
$scope.processForm = function() {
// execute something
$scope.showTheForm = false;
}

Your form is displaying IF the addNewClicked value evaluates to true, which occurs when you click the add task button. If you want the form to disappear on submit, you just need to make the onClick to that button change your addNewClicked to false.
AngularJS Docs for Ng-If

You can do that by using ng-show/ng-hide as per example below :
<form ng-init="addNewClicked=false; " ng-if="addNewClicked" ng-hide="hideform" id="newTaskForm" class="add-task">
and modify the submit method to make the hideform = true;
$scope.addTask = function(input){
... your things
$scope.hideform = true;
}
You can also do the same using jQuery :
$("#newTaskForm").hide();

This should do the trick:
$scope.addTask = function(taskInput) {
...
$scope.addNewClicked = false;
}

You could use ng-show as you can see in this jsfiddle
This will show and hide the div element based on clicking the button. When the button is clicked it will toggle the boolean, hence acting as an on/off switch for ng-show

Form won't submit due to button's conflicting interests

My website has a simple form that is linked with MailChimp. The problem is that the form's submit button has conflicting interests, specifically, there's javascript email-field validation code that
is requiring the button to have type="submit" written in the button code. But if I include type=submit, it prevents my form from submitting to MailChimp.
Here is the button code in 2 forms. The first is the form which allows javascript error validation to work but submission to MailChimp to NOT work (notice the type)
<button class='buttonmain' type="submit" >Submit Form</button>
The second form does not have type="submit" and so js validation won't work, but it will submit to MailChimp:
<button class='buttonmain'>Submit Form</button>
Here's the full form
<form id="form-signup_v1"
name="form-signup_v1"
method="POST"
action="http://mysite.us10.list-manage.com/subscribe/post"
>
<!-- MailChimp Code -->
<input type="hidden" name="u" value="g02362223cdaf329adf5">
<input type="hidden" name="id" value="32da65235dba0">
<div class="errorstyle">
<div class="field">
<div class="ui left labeled input">
<input id="MERGE0"
name="MERGE0"
placeholder="My Email Address"
type="text"
data-validation="[EMAIL]">
<div class="ui corner label">
<i class="asterisk icon">*</i>
</div>
</div>
</div>
</div>
<button class='buttonmain' type="submit" >Submit</button>
</form>
and here's the script for validating the e-mail field.
Notice how it calls on "submit".
<script>
$('#form-signup_v1').validate({
submit: {
settings: {
inputContainer: '.field'
},
callback: {
onBeforeSubmit: function (node) {
myBeforeSubmitFunction(':D', ':)', node);
},
onSubmit: function (node) {
console.log('#' + node.id + ' has a submit override.');
//node.submit();
}
}
},
debug: true
});
function myBeforeSubmitFunction(a, b, node) {
console.log(a, b);
$(node).find('input:not([type="submit"]), select, textarea').attr('readonly', 'true');
$(node).append('<div class="ui active loader"></div>');
}
$('#prefill-signup_v1').on('click', function () {
var form = $(this).closest('form');
form.find('#signup_v1-name').val('John Doe');
form.find('#signup_v1-username').val('RocketJoe');
form.find('#signup_v1-password').val('test123');
form.find('#signup_v1-password-confirm').val('test123');
form.find('#signup_v1-email').val('test#test.test');
form.find('#signup_v1-email-confirm').val('test#test.test');
});
</script>
How do I combine the 2 button code forms I posted at the beginning, so that the form IS validated with js and also submits to MC?
Thanks so much!

I solved it myself doing the following:
Changing the script to include:
function myBeforeSubmitFunction(a, b, node) {
document.getElementById("form-signup_v1").submit();

using javascript to modify form action submits form without doing submit

I have an HTML form that I submit after changing the action with some javascript. Two different buttons can do the submit.
The interesting thing is that I was trying to debug it and inserted an alert after changing the action and before submitting the form. The form is submitted without the alert ever being displayed. To make sure it's actually performing the javascript, I added an alert before changing the action. That alert displays; the alert after changing the action does not.
<form name='FormSelect' method='post' action='Undefined'>
...
<button onclick="SubmitForm('class')">Submit</button>
...
<button onclick="SubmitForm('student')">Submit</button>
...
</form>
<script type="text/javascript">
function SubmitForm(target){
alert("Action 1: " + document.FormSelect.action);
if (target=="class") {
document.FormSelect.action = "ClassAction.php";
} else {
document.FormSelect.action = "StudentAction.php";
}
alert("Action 2: " + document.FormSelect.action);
// document.FormSelect.submit();
}
</script>
Is that the expected sequence of events?

Any button placed inside form element will cause submit action. To prevent this you can add type="button" to button elements, or make you submit callback return false;
<button type="button" onclick="SubmitForm('class')">Submit</button
see http://jsfiddle.net/yD2Uu/

As the others have already pointed out the form will be submitted anyway if you don't cancle the event. I want to suggest a JavaScript free solution to your problem.
<button formaction="ClassAction.php">Submit</button>
<button formaction="StudentAction.php">Submit</button>
It's not supported in IE < 10 though. But you can still use your function as a fallback then, just a bit more elegant ;)
function SubmitForm(button){
button.form.action = button.formaction;
}

A better solution is to give the buttons a name each and submit to Action.php and let the server get the value of the named button
$student = filter_var($_POST["student"], FILTER_SANITIZE_STRING); // php5 cleaning
when you have
<form method="post" action="Actions.php">
<input type="submit" name="student" value="John Doe" />
<input type="submit" name="student" value="Jane Doe" />
<input type="submit" name="student" value="Whatever Doe" />
</form>
Otherwise if you must
Try this
<form method='post' action='Undefined'>
...
<input type="button" value="Class" onclick="SubmitForm(this)" />
...
<input type="button" value="Student" onclick="SubmitForm(this)"/>
...
</form>
<script type="text/javascript">
var actions = {
"class":"ClassAction.php",
"student":"StudentAction.php"
}
function SubmitForm(button){
button.form.action = actions[button.value];
button.form.submit();
}
</script>

Thanks to Yauhen Vasileusky's example, I started removing code between my 1st & 2nd alerts and found that the problem seems to be the following IF statement:
if (document.FormSelect.FormName.value.substr(0,19)=="ObservationRequest_" || document.FormSelect.FormName.value=="StudentReg2013rx" || document.FormSelect.FormName.value=="Toddler Update Form v3rx")
{
document.FormSelect.action = "GenerateXDP.php";
}
When I remove it, both alerts are displayed. So the answer to my question is that changing the action does not submit the form; it was some other error in my code that made it appear as if that was the case.