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Clear data form submit button php

I have a form and I want, when I click on submit button, that all data input will clear. My script below is not working:
<!-- language: lang-js -->
jQuery(document).ready(function($) {
$('.product_submit button').on('click', function(event) {
event.preventDefault();
$('span.loadding').html('<i class="fa fa-spin fa-refresh" aria-hidden="true"></i>');
var data_form = $("#form-product").serialize();
$.ajax({
type: 'post',
url: location,
data: data_form,
success: function(resulf) {
var errors = $(resulf).find('#alert_order').html();
var html = $(resulf).find('#add-to-order-success').html();
if (html) {
$('#add-to-order-success').html(html);
$(".myform")[0].reset();
}
if (errors) {
$('#add-to-order-success').html(errors);
}
$('span.loadding').html('<i class="fa fa-check" aria-hidden="true"></i>');
}
})
})
});
<!-- language: lang-html -->
<div class="form-add-cart">
<form method="post" action="" id="form-product" name="myform">
<table>
<tbody>
<tr>
<td width="40%">
<?php _e('Họ và tên:','wow'); ?>
</td>
<td width="60%"><input type="text" name="name_order" value="<?php echo $current_user->display_name; ?>" size="40" class="wpcf7-form-control wpcf7-text" aria-invalid="false" required></td>
</tr>
<tr>
<td width="40%">
<?php _e('Điện thoại:','wow'); ?>
</td>
<td width="60%"><input type="text" name="phone_order" value="" class="wpcf7-form-control wpcf7-text" aria-invalid="false" required></td>
</tr>
<tr>
<td width="40%">
<?php _e('Sản phẩm :','wow'); ?>
</td>
<td width="60%"><input type="text" name="product_order" value="<?php the_title(); ?>" class="wpcf7-form-control wpcf7-text" aria-invalid="false" required></td>
</tr>
</tbody>
</table>
<div class="product_submit">
<button type="submit" class="wpcf7-form-control wpcf7-submit">
<?php _e('Gửi','wow'); ?> <span class="loadding"></span>
</button>
</div>
<input type="hidden" name="id_product" value="<?php echo $post->ID; ?>">
<input type="hidden" name="add_product_to_order" value="<?php echo $post->ID; ?>">
</form>
</div>

Hi I think the problem is that you didn't include class="myform" in your form.
As you can see, you are applying to the reset() class myform.
$(".myform")[0].reset();
You can alternatively set an id to it like id="myidform"
and then use it in you jquery
$("#myidform")[0].reset();

unable to submit form data using ajax?

i am very new to php and have no idea of javascript, have done all js work using tutorials.Also tried to use existing solutions from stackoverflow, but no success !
What i am trying to do is trying to update database values using 'submit' button on the basis of values called from 'select option'.
Problem is that no data is getting updated in DB after i click on submit button (on viewtest.php), I have also tried to add the 'update.php' to form action.
Here's the screenshot of viewtest.php
here's my code:
viewtest.php
<form method="POST" action="">
<table border="1px"><tr> <td>
<select required name="tstname" id="test" onChange="fetch_ques()">
<option> Select Test Name</option>
<?php
$res=mysqli_query($connection,"select * from test_detail");
while($row=mysqli_fetch_array($res))
{
?>
<option value="<?php echo $row["test_name"]; ?>">
<?php echo
$row["test_name"]; echo' - - ['. $row['test_category'].']'; ?> </option>
<?php
}
?>
</select>
</div>
<td>
<div id="qnos"><select></select></div></td></tr>
<tr><td colspan="2" align="center">
<input type="submit" name="btnSubmit" id="vform" value="Update Question"> </td></tr>
</form>
</table>
<div id="ques"></div>
<script type="text/javascript">
function fetch_ques()
{
var xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","getq.php?
tstnm="+document.getElementById("test").value,false); // function id
xmlhttp.send(null);
document.getElementById("qnos").innerHTML=xmlhttp.responseText; // div id
}
function display_ques()
{
var xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","displayq.php?
qnos="+document.getElementById("quesdd").value,false);
xmlhttp.send(null);
document.getElementById("ques").innerHTML=xmlhttp.responseText;
}
</script>
<script type="text/javascript">
$(document).ready(function()
{
$("#vform").submit(); (function()
// document.getElementById("vform").submit();(function()
{
location.href='update.php?
qno='+$("#quesno").val()+'&qn='+$("#ques").val()+'&c1='+$("#a1").val()+'&c2='+$
("#a2").val()+'&c3'+$("#a3").val()+'&c4='+$("#a4").val()+'&cr='+$("#cr").val();
});
});
</script>
<?php
if(isset($_GET['st']) && $_GET['st'] !== "")
{
echo"updated";
}
else echo "Error: ".mysqli_errno();
?>
displayq.php //Used to fetch data in select menu
<?php
include '../connect.php';
$quesno=$_GET["qnos"];
if($quesno!="")
{
$qry=mysqli_query($connection,"select * from quesadd where quesid='$quesno'");
echo "<table name='ques'>";
while($ftc=mysqli_fetch_array($qry))
{
?>
<form method="POST" action="">
<table name="ques">
<tr><td align="center" colspan="2"> <!-- // Comment <input type="submit" name="submit" id="upq" value="Update Question">--></td> </tr>
<tr> <td align="center"> <b> Question : <input type="text" id="quesno" value="<?php echo $ftc["quesid"];?>" disabled></b></td>
<td> <textarea name="ques" id="ques" cols="100" rows="3" placeholder="Please Input The Question Here !"> <?php echo $ftc['ques'];?></textarea> </td> </tr>
<tr> <td width="25%" align="center" colspan="2"> <br> <b>Choices</b> </td> </tr>
<tr> <td align="center" colspan="2"><b>1.</b> <input type="text" id="a1" name="a1" value="<?php echo $ftc['c1'];?>"> </td> </tr>
<tr> <td align="center" colspan="2"><b>2.</b> <input type="text" id="a2" size="20px" name="a2" value="<?php echo $ftc['c2'];?>"> </td> </tr>
<tr> <td align="center" colspan="2"><b>3.</b> <input type="text" id="a3" size="20px" name="a3" value="<?php echo $ftc['c3'];?>"> </td> </tr>
<tr> <td align="center" colspan="2"><b>4.</b> <input type="text" id="a4" size="20px" name="a4" value="<?php echo $ftc['c4'];?>"> </td> </tr>
<tr> <td align="center" colspan="2"><b><font color="maroon">Correct Answer</font></b> <input type="text" size="20px" id="cr" name="correct" value="<?php echo $ftc['answer'];?>"> </td> </tr>
</table>
</form>
<?php
}
echo "</table>";
}
?>
</tr> </td>
</table>
</form>
update.php //Used to update question by getting values from 'viewtest.php'
<?php
include '../connect.php';
$qn=$_GET['qno'];
$qname=$GET['qn'];
$a1=$GET['c1'];
$a2=$GET['c2'];
$a3=$GET['c3'];
$a4=$GET['c4'];
$acr=$GET['cr'];
$update=mysqli_query($connection,"update quesadd SET ques='$qname',
c1='$a1',c2='$a2',c3='$a3',c4='$a4',answer='$acr' where quesid='$qn' ");
if($update==true)
{
header('location:viewtest.php?st=true');
}
?>

I can see multiple problems, don't know if all the problems will go away but it will help.
$("#vform").submit(); (function()
The line above says if a <form> with the id="vform" has been submitted, execute this function. Your form does not have an id so it will never trigger. One other problem is that the function is not part of the trigger. It should be something like
$("#vform").submit(function()
The complete code could look like:
<script type="text/javascript">
$(document).ready(function(){
$("#vform").submit(function(e){
e.preventDefault();
location.href='update.php?qno='+$("#quesno").val()+'&qn='+$("#ques").val()+'&c1='+$("#a1").val()+'&c2='+$("#a2").val()+'&c3'+$("#a3").val()+'&c4='+$("#a4").val()+'&cr='+$("#cr").val();
return false;
});
});
</script>

Use AJAX to submit your form and refresh/redirect the page with javascript.
viewtest.php
<?php
include '../connect.php';
?>
<form method="POST" action="">
<table border="1px">
<tr>
<td>
<select required name="tstname" onchange="display_ques()" id="test">
<option> Select Test Name</option>
<?php
$res = mysqli_query($connection, "select * from test_detail");
while ($row = mysqli_fetch_array($res)) {
?>
<option value="<?php echo $row["test_id"]; ?>">
<?php echo
$row["test_name"];
echo ' - - [' . $row['test_category'] . ']'; ?> </option>
<?php
}
?>
</select>
</td>
<td>
<div id="qnos">
<select>
<!-- put code here for showing question id/number -->
</select></div>
</td>
</tr>
<tr>
<td colspan="2" align="center">
<input type="submit" name="btnSubmit" id="vform" value="Update Question"></td>
</tr>
</table>
</form>
<div id="ques"></div>
<h1 id="status"></h1>
<!-- jQuery -->
<script src="https://code.jquery.com/jquery-3.2.1.min.js"></script>
<script>
function display_ques() {
var xmlhttp = new XMLHttpRequest();
xmlhttp.onreadystatechange = function () {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("ques").innerHTML = xmlhttp.responseText;
}
};
xmlhttp.open("GET", "displayq.php?qnos=" + document.getElementById("test").value, true);
xmlhttp.send(null);
}
function fetch_ques() {
var xmlhttp = new XMLHttpRequest();
xmlhttp.open("GET", "getq.php?tstnm = " + document.getElementById("test").value, false); // function id
xmlhttp.send(null);
document.getElementById("qnos").innerHTML = xmlhttp.responseText; // div id
}
$(document).ready(function () {
$('#vform').on('click', function (e) {
e.preventDefault();
var data = $('form#update').serialize();
$.post('update.php', data, function (response) {
// response is the data returned from php echo json_encode(['results' => true/false]), from update.php
var res = JSON.parse(response);
if (res.results == true) {
$('#status').html('Data was updated');
} else {
$('#status').html('Error occured while trying to update data.');
console.log(response);
}
});
});
});
</script>
I have given your form and id to be able to serialize it using jQuery and I have also added a hidden input to hold the id of the current question.
displayq.php
<?php
include '../connect.php';
$quesno = $_GET["qnos"];
if($quesno != "") : ?>
<form id="update" method="POST" action=""> <!-- added an id to the form -->
<table name="ques">
<?php
$qry = mysqli_query($connection,"select * from quesadd where quesid='$quesno'");
while($ftc = mysqli_fetch_array($qry)) : ?>
<tr><td align="center" colspan="2"> <!-- // Comment <input type="submit" name="submit" id="upq" value="Update Question">--></td> </tr>
<tr> <td align="center"> <b> Question : <input type="text" id="quesno" value="<?php echo $ftc["quesid"];?>" disabled></b></td>
<td> <textarea name="ques" id="ques" cols="100" rows="3" placeholder="Please Input The Question Here !"> <?php echo $ftc['ques'];?></textarea> </td> </tr>
<!-- added this hidden input to hold the question number -->
<input type="text" id="quesno" name="quesno" value="<?php echo $ftc["quesid"];?>" hidden>
<tr> <td width="25%" align="center" colspan="2"> <br> <b>Choices</b> </td> </tr>
<tr> <td align="center" colspan="2"><b>1.</b> <input type="text" id="a1" name="a1" value="<?php echo $ftc['c1'];?>"> </td> </tr>
<tr> <td align="center" colspan="2"><b>2.</b> <input type="text" id="a2" size="20px" name="a2" value="<?php echo $ftc['c2'];?>"> </td> </tr>
<tr> <td align="center" colspan="2"><b>3.</b> <input type="text" id="a3" size="20px" name="a3" value="<?php echo $ftc['c3'];?>"> </td> </tr>
<tr> <td align="center" colspan="2"><b>4.</b> <input type="text" id="a4" size="20px" name="a4" value="<?php echo $ftc['c4'];?>"> </td> </tr>
<tr> <td align="center" colspan="2"><b><font color="maroon">Correct Answer</font></b> <input type="text" size="20px" id="cr" name="correct" value="<?php echo $ftc['answer'];?>"> </td> </tr>
<?php endwhile; ?>
</table>
</form>
<?php endif; ?>
Then in your update.php you can access the values using $_POST
<?php
include '../connect.php';
$qn = trim($_POST['quesno']);
$qname = trim($_POST['ques']);
$a1 = trim($_POST['a1']);
$a2 = trim($_POST['a2']);
$a3 = trim($_POST['a3']);
$a4 = trim($_POST['a4']);
$acr = trim($_POST['correct']);
$sql = "update quesadd SET ques='$qname', c1='$a1',c2='$a2',c3='$a3',c4='$a4',answer='$acr' where quesid='$qn'";
if (mysqli_query($connection, $sql)) {
// returning data to jQuery, as response
// jQuery will parse this as json {results: true}
echo json_encode(['results' => true]);
} else {
// returning data to jQuery, as response
// jQuery will parse this as json {results: false}
echo json_encode(['results' => false]);
}

get values from query string (table tr td) foreach line into jquery ui dialog

i have some code, see:
<script>
$$.ready(function() {
// Profile Dialog
$( "#user-dialog" ).dialog({
autoOpen: false,
modal: true,
width: 400,
open: function(){ $(this).parent().css('overflow', 'visible'); $$.utils.forms.resize() }
}).find('button.submit').click(function(){
var $el = $(this).parents('.ui-dialog-content');
if ($el.validate().form()) {
$el.dialog('close');
}
}).end().find('button.cancel').click(function(){
var $el = $(this).parents('.ui-dialog-content');
$el.find('form')[0].reset();
$el.dialog('close');;
});
$('#user-table').on('click', '.open-user-dialog', function(){
$( "#user-dialog" ).dialog( "open" );
return false;
});
});
</script>
<table id="user-table">
<thead>
<tr>
<th>id</th>
<th>name</th>
<th>action</th>
</tr>
</thead>
<tbody>
<?php
$sql = "SELECT id,user_name FROM users";
if ($result = $verbindung->query($sql)) {
while ($row = $result->fetch_assoc()) {
?>
<tr>
<td><?php echo $row["id"];?></td>
<td><?php echo $row["user_name"];?></td>
<td>
<button class="open-user-dialog"><img src="img/icons/packs/fugue/16x16/bullet_go.png"/> view</button>
</td>
</tr>
<?php }} ?>
</tbody>
</table>
<div style="display: none;" id="user-dialog" title="user view">
<form action="">
<div class="row">
<label>
<strong>User details</strong>
</label>
<div>
<input type="text" id="user_id" value="<?php echo $id; ?>">
<input type="text" id="user_name" value="<?php echo $user_name; ?>">
</div>
</div>
</form>
<div class="actions">
<div class="left">
<button class="grey cancel">cancel</button>
</div>
<div class="right">
<input id="submit" onclick="userFunction()" type="button" value="go">
</div>
</div>
</div>
How i get my details from table to my jquery dialog?
the dialog is working fine, but i dont get the values $row['id'] and $row['user_name'] to display in my jquery dialog.
What I also try, I do not get the data in my dialog to be able to process them further.
How i can pass $row['id'] and $row['user_name'] for each line to my dialog?
Can someone Help me?

Firstly you add Php code in Php tags.You don't write if and while in php.
<table>
<thead>
<tr>
<th>id</th>
<th>name</th>
<th>action</th>
</tr>
</thead>
<tbody>
<?php
if ($result = $verbindung->query($sql)) {
while ($row = $result->fetch_assoc()) {
?>
<tr>
<td><?php echo $row["id"];?></td>
<td><?php echo $row["user_name"];?></td>
<td>
<button class="open-user-dialog"><img src="img/icons/packs/fugue/16x16/bullet_go.png"/> view</button>
</td>
</tr>
<?php }} ?>
</tbody>
</table>
<div style="display: none;" id="user-dialog" title="user view">
<form action="">
<div class="row">
<label>
<strong>User details</strong>
</label>
<div>
<input type="text" id="user_id" value="<?php echo $id; ?>">
<input type="text" id="user_name" value="<?php echo $user_name; ?>">
</div>
</div>
</form>
<div class="actions">
<div class="left">
<button class="grey cancel">cancel</button>
</div>
<div class="right">
<input id="submit" onclick="userFunction()" type="button" value="go">
</div>
</div>
try this

jQuery function run just in first row

I already fetched all values from database into table
foreach ( $result as $print ) {
?>
<form method="post">
<tr>
<td>Edit</td>
</tr>
<tr>
<div class="edit-box1">
<input id="idd" type="text" readonly="readonly" value="<?php echo $idd; ?>" name="status111">
<input type="submit" value="GO" name="edit-go">
</div>
</tr>
</form>
}
And this is the jQuery code:
jQuery(document).ready(
function() {
jQuery("#edit-btn").click(function() {
jQuery("#idd").prop("readonly", false);
});
});
The problem is that I got 20 rows and my edit button just run on my first row.
How can I make my jQuery run on all rows ?

This will be your HTML
$cnt=0;
foreach ( $result as $print ) {
?>
<form method="post">
<tr>
<td><a href="#" class="edit-button" id='<?php echo $cnt;?>'>Edit</a></td>
</tr>
<tr>
<div class="edit-box1">
<input id="idd<?php echo $cnt;?>" type="text" readonly="readonly" value="<?php echo $idd; ?>" name="status111">
<input type="submit" value="GO" name="edit-go">
<?php $cnt++; ?>
</div>
</tr>
</form>
}
This will be your jquery code
<script>
jQuery(document).ready(
function() {
jQuery(".edit-button").click(function() {
jQuery("#idd"+$(this).attr("id")).prop("readonly", false);
});
});
</script>
Hope this will work surely.

Id cannot be used more than once, use class instead, try this code:
<?php foreach($result as $print): ?>
<form method="post" class="form">
<tr>
<td>Edit</td>
</tr>
<tr>
<div class="edit-box1">
<input class="idd" type="text" readonly="readonly" value="<?php echo $idd; ?>" name="status111">
<input type="submit" value="GO" name="edit-go">
</div>
</tr>
</form>
<?php endforeach; ?>
<script>
jQuery(document).on('click','.edit-btn',function(){
jQuery(this).closest('.form').find('.idd').prop('readonly',false);
});
</script>

1 ) all id convert class
2) Use method removeAttr("readonly")
<tr>
<td>Edit</td>
</tr>
<input class="idd" type="text" readonly="readonly" value="<?php echo $idd; ?>" name="status111">
And you can use $(".idd").removeAttr("readonly")
$(document).ready(function(){
$(".edit-btn").click(function(){
$(".idd").removeAttr("readonly");
$(".idd:first").focus();
})
})
Example :
<html>
<head>
<meta charset="utf-8">
</head>
<body>
<tr>
<td>Edit</td>
</tr>
<input type="text" class="idd" readonly>
<input type="text" class="idd" readonly>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script>
$(document).ready(function(){
$(".edit-btn").click(function(){
$(".idd").removeAttr("readonly");
$(".idd:first").focus();
})
})
</script>
</body>
</html>

Submit button not working because of formating

I have been working to get this code working for a little while and finally got it to work by implementing two codes together. Except the formatting of it does not let my submit button work. My submit button acts a save by updating all data entered into the textboxes in a sql database. So this button is absolutely necessary. Please let me know what I'm doing wrong.
<?php
mysql_connect("localhost", "username", "password")or die("cannot connect");
mysql_select_db("databas")or die("cannot bselect DB");
$sql="SELECT * FROM test";
$result=mysql_query($sql);
// Count table rows
$count=mysql_num_rows($result);
?>
<html>
<head>
<link rel="shortcut icon" href="../../favicon.ico">
<link rel="stylesheet" type="text/css" href="css/normalize.css" />
<link rel="stylesheet" type="text/css" href="css/styles.css" />
<link rel="stylesheet" type="text/css" href="css/component.css" />
<script src="javafile.js"></script>
</head>
<body>
<div class="component">
<table class="overflow-y">
<thead>
<tr>
<th width="16%" align="center" id="box_header2" style='width:10%'><button class="logout">Log out</button> Name</th>
<th width="16%" align="center" id="box_header2" style='width:10%'>Job Code</th>
<th width="16%" align="center" id="box_header2" style='width:10%'>Date</th>
<th width="14%" align="center" id="box_header2" style='width:20%'>Address</th>
</tr>
</thead>
<tbody>
<tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<form action="update3.php" method="post" name="form1">
<tbody>
<tr>
<th>
<input name="name[]" type="text" id="Name" value="<? echo $rows['Name'];?>">
</th>
<td>
<input name="job[]" type="text" id="Job" value="<? echo $rows['Job']; ?>">
</td>
<td>
<input name="date[]" type="text" id="Date" value="<? echo $rows['Date']; ?>">
</td>
<td>
<input name="address[]" type="text" id="Address" value="<? echo $rows['Address']; ?>">
</td>
<td>
<input name="id[]" type="hidden" value="<? echo $rows['ID']; ?>">
</td>
</tr>
</tbody>
<?php
}
?>
<tr>
</tr>
</tbody>
<tbody>
<tr>
<td>
<input type="submit" name="Submit" value="Save">
</td>
</tr>
</tbody>
</table>
</td>
</tr>
</form>
</table>
<?php
mysql_close();
?>

try this hope it works for you :
<input name="name[]" type="text" id="Name" value='<?php echo $rows["uname"];?>'>

Please, put the <form> tag before the while loop, otherwise you'll have as many opened forms as rows in the query's result set.