This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 6 years ago.
I want alphabetical pagination in php. I have a code, but some problem is there. When I click any alphabet, in address bar selected alphabet shows, but data starting from selected alphabet not shows.
I have database testing
table name: tbl_student
atrributes are: student_id, student_name, student_phone
and my code is:
<?php
$connect = mysqli_connect('localhost', 'root', '', 'testing');
$char = '';
if(isset($_GET["char"]))
{
$char = $_GET["char"];
$char = preg_replace('#[^a-z]#i', '', $char);
$query = "SELECT * FROM tbl_student WHERE student_name LIKE '$char%'";
}
else
{
$query = "SELECT * FROM tbl_student ORDER BY student_id";
}
$result = mysqli_query($connect, $query);
?>
<!DOCTYPE html>
<html>
<head>
<title> Alphabetic Pagination</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.0/jquery.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
</head>
<body>
<br /><br />
<div class="container" style="width:1100px;">
<div class="table-responsive">
<div align="center">
<?php
$character = range('A', 'Z');
echo '<ul class="pagination">';
foreach($character as $alphabet)
{
echo '<li>'.$alphabet.'</li>';
}
echo '</ul>';
?>
</div>
<table class="table table-bordered">
<tr>
<th width="20%">ID</th>
<th width="50%">Student Name</th>
<th width="30%">Student Phone</th>
</tr>
<?php
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
?>
<tr>
<td><?php echo $row["student_id"]; ?></td>
<td><?php echo $row["student_name"]; ?></td>
<td><?php echo $row["student_phone"]; ?></td>
</tr>
<?php
}
}
else
{
?>
<tr>
<td colspan="3" align="center">Data not Found</td>
</tr>
<?php
}
?>
</table>
</div>
</div>
</body>
The problem is that you have used character as variable names in url and char in $_GET[] array.
Either
Change $_GET["char"] to $_GET["character"] `
Or
Change
<li>'.$alphabet.'</li>
to
<li>'.$alphabet.'</li>
Related
My goals is to make filter for loading posts from 1 week ago, 1 month ago and two inputs from date from and date to ( if one of them is empty to be filled with current date( y-m-d h:m:s ) format
This is all i tried and could have made it to work, every answer is much appreciated, thank you
Tl:dr
Select filter for week ago, month ago
From date - to date ( if one of those is empty then use current date )
Index.php
<?php
$connect = mysqli_connect("localhost", "root", "", "testing");
$query = "SELECT * FROM tbl_order ORDER BY order_id desc";
$result = mysqli_query($connect, $query);
?>
<!DOCTYPE html>
<html>
<head>
<title>Webslesson Tutorial | Ajax PHP MySQL Date Range Search using jQuery DatePicker</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.0/jquery.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />
<script src="http://code.jquery.com/ui/1.10.3/jquery-ui.js"></script>
<link rel="stylesheet" href="http://code.jquery.com/ui/1.11.4/themes/smoothness/jquery-ui.css">
</head>
<body>
<br /><br />
<div class="container" style="width:900px;">
<h2 align="center">Ajax PHP MySQL Date Range Search using jQuery DatePicker</h2>
<h3 align="center">Order Data</h3><br />
<div class="col-md-3">
<input type="text" name="from_date" id="from_date" class="form-control" placeholder="From Date" />
</div>
<div class="col-md-3">
<input type="text" name="to_date" id="to_date" class="form-control" placeholder="To Date" />
</div>
<div class="col-md-5">
<input type="button" name="filter" id="filter" value="Filter" class="btn btn-info" />
</div>
<div style="clear:both"></div>
<br />
<div id="order_table">
<table class="table table-bordered">
<tr>
<th width="5%">ID</th>
<th width="30%">Customer Name</th>
<th width="43%">Item</th>
<th width="10%">Value</th>
<th width="12%">Order Date</th>
</tr>
<?php
while($row = mysqli_fetch_array($result))
{
?>
<tr>
<td><?php echo $row["order_id"]; ?></td>
<td><?php echo $row["order_customer_name"]; ?></td>
<td><?php echo $row["order_item"]; ?></td>
<td>$ <?php echo $row["order_value"]; ?></td>
<td><?php echo $row["order_date"]; ?></td>
</tr>
<?php
}
?>
</table>
</div>
</div>
</body>
</html>
<script>
$(document).ready(function(){
$.datepicker.setDefaults({
dateFormat: 'yy-mm-dd'
});
$(function(){
$("#from_date").datepicker();
$("#to_date").datepicker();
});
$('#filter').click(function(){
var from_date = $('#from_date').val();
var to_date = $('#to_date').val();
if(from_date != '' && to_date != '')
{
$.ajax({
url:"filter.php",
method:"POST",
data:{from_date:from_date, to_date:to_date},
success:function(data)
{
$('#order_table').html(data);
}
});
}
else
{
alert("Please Select Date");
}
});
});
</script>
And filter.php
<?php
//filter.php
if(isset($_POST["from_date"], $_POST["to_date"]))
{
$connect = mysqli_connect("localhost", "root", "", "testing");
$output = '';
$query = "
SELECT * FROM tbl_order
WHERE order_date BETWEEN '".$_POST["from_date"]."' AND '".$_POST["to_date"]."'
";
$result = mysqli_query($connect, $query);
$output .= '
<table class="table table-bordered">
<tr>
<th width="5%">ID</th>
<th width="30%">Customer Name</th>
<th width="43%">Item</th>
<th width="10%">Value</th>
<th width="12%">Order Date</th>
</tr>
';
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td>'. $row["order_id"] .'</td>
<td>'. $row["order_customer_name"] .'</td>
<td>'. $row["order_item"] .'</td>
<td>$ '. $row["order_value"] .'</td>
<td>'. $row["order_date"] .'</td>
</tr>
';
}
}
else
{
$output .= '
<tr>
<td colspan="5">No Order Found</td>
</tr>
';
}
$output .= '</table>';
echo $output;
}
?>
Use something like this to make sure that you are getting the correct format from your datepicker:
$("#from_date").datepicker({ dateFormat: 'yy-mm-dd' }).val();
Make PHP variables to use in your query for the date:
$fromDate = !empty($_POST['from_date']) ? "'".mysqli_escape_string($_POST["from_date"])."'" : "CURDATE()";
$toDate = !empty($_POST["to_date"]) ? "'".mysqli_escape_string($_POST["to_date"])."'" : "CURDATE()";
$query =
"SELECT *
FROM tbl_order
WHERE order_date
BETWEEN $fromDate
AND $toDate";
NOTE: You should also add some logic in there to make sure that the from_date does not end up being before the to_date.
NOTE 2: This answer is making the assumption that you have not set up PDO. Always make sure to avoid SQL injection attacks in some way. Any values coming from the front end are unsafe and subject to SQL injection. PDO would be preferable, but escaping will work.
You can try casting your $_POST using CAST function to convert values to date.
$query = "SELECT * FROM tbl_order
WHERE order_date
BETWEEN CAST('".$_POST["from_date"]."' AS DATE)
AND CAST('".$_POST["to_date"]."' AS DATE)";
You can read about it on MySQLTutorial .
Also I recommend you to escape variables when working with database :-) Always expect user is up to no good.
hi guys how can i create a validation so that when i import a csv file it will not give me a error offset(intentionally reduced the csv file column)
i got the code https://www.webslesson.info/2016/10/import-csv-file-data-into-mysql-database-using-php-ajax.html
here is the code in index.php
<?php
$connect = mysqli_connect("localhost", "root", "", "db");
$query = "SELECT * FROM tbl_employee ORDER BY id desc";
$result = mysqli_query($connect, $query);
?>
<!DOCTYPE html>
<html>
<head>
<title>Webslesson Tutorial | Import CSV File Data into MySQL Database using PHP & Ajax</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.0/jquery.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />
<script src="https://cdn.datatables.net/1.10.12/js/jquery.dataTables.min.js"></script>
<script src="https://cdn.datatables.net/1.10.12/js/dataTables.bootstrap.min.js"></script>
<link rel="stylesheet" href="https://cdn.datatables.net/1.10.12/css/dataTables.bootstrap.min.css" />
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
</head>
<body>
<br /><br />
<div class="container" style="width:900px;">
<h2 align="center">Import CSV File Data into MySQL Database using PHP & Ajax</h2>
<h3 align="center">Employee Data</h3><br />
<form id="upload_csv" method="post" enctype="multipart/form-data">
<div class="col-md-3">
<br />
<label>Add More Data</label>
</div>
<div class="col-md-4">
<input type="file" name="employee_file" style="margin-top:15px;" accept=".csv"/>
</div>
<div class="col-md-5">
<input type="submit" name="upload" id="upload" value="Upload" style="margin-top:10px;" class="btn btn-info" />
</div>
<div style="clear:both"></div>
</form>
<br /><br /><br />
<div class="table-responsive" id="employee_table">
<table class="table table-bordered">
<tr>
<th width="5%">ID</th>
<th width="25%">Name</th>
<th width="35%">Address</th>
<th width="10%">Gender</th>
<th width="20%">Designation</th>
<th width="5%">Age</th>
</tr>
<?php
while($row = mysqli_fetch_array($result))
{
?>
<tr>
<td><?php echo $row["id"]; ?></td>
<td><?php echo $row["name"]; ?></td>
<td><?php echo $row["address"]; ?></td>
<td><?php echo $row["gender"]; ?></td>
<td><?php echo $row["designation"]; ?></td>
<td><?php echo $row["age"]; ?></td>
</tr>
<?php
}
?>
</table>
</div>
</div>
</body>
</html>
<script>
$(document).ready(function(){
$('#upload_csv').on("submit", function(e){
e.preventDefault(); //form will not submitted
$.ajax({
url:"import.php",
method:"POST",
data:new FormData(this),
contentType:false, // The content type used when sending data to the server.
cache:false, // To unable request pages to be cached
processData:false, // To send DOMDocument or non processed data file it is set to false
success: function(data){
if(data=='Error1')
{
alert("Invalid File");
}
else if(data == "Error2")
{
alert("Please Select File");
}
else if(data != 'Error1' && data != 'Error2')
{
$('#employee_table').html(data);
alert("Data Import Successfully");
}
}
})
});
});
</script>
and here is for import.php
<?php
if(!empty($_FILES["employee_file"]["name"]))
{
$connect = mysqli_connect("localhost", "root", "", "db");
$output = '';
$allowed_ext = array("csv");
$tmp = explode(".", $_FILES["employee_file"]["name"]);
$extension = end($tmp);
if(in_array($extension, $allowed_ext))
{
$file_data = fopen($_FILES["employee_file"]["tmp_name"], 'r');
fgetcsv($file_data);
while($row = fgetcsv($file_data))
{
$id = mysqli_real_escape_string($connect, $row[0]);
$name = mysqli_real_escape_string($connect, $row[1]);
$address = mysqli_real_escape_string($connect, $row[2]);
$gender = mysqli_real_escape_string($connect, $row[3]);
$designation = mysqli_real_escape_string($connect, $row[4]);
$age = mysqli_real_escape_string($connect, $row[5]);
$query = "
INSERT INTO tbl_employee
(id,name, address, gender, designation, age)
VALUES ('$id','$name', '$address', '$gender', '$designation', '$age')
";
mysqli_query($connect, $query);
}
$select = "SELECT * FROM tbl_employee ORDER BY id DESC";
$result = mysqli_query($connect, $select);
$output .= '
<table class="table table-bordered">
<tr>
<th width="5%">ID</th>
<th width="25%">Name</th>
<th width="35%">Address</th>
<th width="10%">Gender</th>
<th width="20%">Designation</th>
<th width="5%">Age</th>
</tr>
';
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td>'.$row["id"].'</td>
<td>'.$row["name"].'</td>
<td>'.$row["address"].'</td>
<td>'.$row["gender"].'</td>
<td>'.$row["designation"].'</td>
<td>'.$row["age"].'</td>
</tr>
';
}
$output .= '</table>';
echo $output;
}
else
{
echo 'Error1';
}
}
else
{
echo "Error2";
}
?>
i put all the code so that every one can try it too.
Thanks for answer
Can anyone help me with this? I just want to print this table using javascript print mode. But how? Using also the print view in the web style. I really appreciate any help. Thank you in advance. :)
Here's my code.
<?php
if(isset($_POST['search'])) {
$valueToSearch = $_POST['valueToSearch'];
$query = "SELECT * FROM dailytimerecord WHERE CONCAT(Dtrec_ID, TimeIn, TimeOut) LIKE '%".$valueToSearch."%'";
$search_result = filterTable($query);
} else {
$query = "SELECT * FROM dailytimerecord";
$search_result = filterTable($query);
}
function filterTable($query) {
$connect = mysqli_connect("localhost", "root", "", "alqdb");
$filter_Result = mysqli_query($connect, $query);
return $filter_Result;
}
?>
<!DOCTYPE html>
<html>
<head>
<title>PHP HTML TABLE DATA SEARCH</title>
<style>
table,tr,th,td {
border: 1px solid black;
}
</style>
</head>
<body>
<form method="post">
<input type="text" name="valueToSearch" placeholder="Value To Search"><br><br>
<input type="submit" name="search" value="Filter"><br><br>
<input type="button" name="print" value="Print"><br><br>
<table>
<tr>
<th>Name</th>
<th>Dtrec_ID</th>
<th>Date</th>
<th>Time In</th>
<th>Time Out</th>
</tr>
<?php while($row = mysqli_fetch_array($search_result)):?>
<tr>
<td></td>
<td><?php echo $row['Dtrec_ID'];?></td>
<td><?php echo date("F j, Y", strtotime($row['TimeIn']));?></td>
<td><?php echo date("h:i, A", strtotime($row['TimeIn']))?></td>
<td><?php echo date("h:i, A", strtotime($row['TimeOut']));?></td>
</tr>
<?php endwhile;?>
</table>
</form>
</body>
</html>
I need to upload selected image but I don't have any idea to make it. Anyone could help me on this problem? Included code below. Thank you for helping in advance.
Test.php
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<script>
function myFunction1(isChecked2){
$('.chckbox1').change( function() {
var isChecked2 = this.checked;
if(isChecked2) {
$(this).parents("tr:eq(0)").find(".product_img").prop("disabled",false);
} else {
$(this).parents("tr:eq(0)").find(".product_img").prop("disabled",true);}
})};
</script>
</head>
<body>
<form method="post" action="UPDATE.php">
<div class="row">
<div class="col-xs-4">
<table id="simple-table" class="table table-striped table-bordered table-hover">
<thead>
<tr>
<th class="center">Select</th>
<th class="center">Product Image</th>
<th class="center">New Image</th>
</tr>
</thead>
<tbody>
<?php
//connect to database
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
//select table from database
mysql_select_db("MBTR", $con);
$result = mysql_query("SELECT * from maray_product_img WHERE product_id='P100044'");
//query resutl
$countrow = 1;
//read result
while($row = mysql_fetch_array($result))
{
$img_id=$row['img_id'];
$p_id = $row['product_id'];
$product_img_name = $row['product_img_name'];
$product_img = $row['product_img'];
$product_img_path = $row['product_img_path'];
//$product_quantity = $row['product_quantity'];
?>
<tr>
<td class="center" style="vertical-align:middle"> <input name="img_id[]" type="checkbox" id="check[]" class="chckbox1 ace" value="<?php echo $img_id;?>" onclick="myFunction1(this)"/><span class="lbl red"><input type="hidden" name="product_id[<?php echo $img_id;?>]" value="<?php echo $p_id;?>"></span><input type="hidden" name="product_img_name[<?php echo $img_id;?>]" value="<?php echo $product_img_name;?>"></td>
<td class="center"><img src="<?php echo $row['product_img_path'];?>" width="60" height="60"></td>
<td class="center" style="vertical-align:middle"><input type="file" name="product_img[<?php echo $img_id;?>]" id="product_img[]" class="product_img form-control" disabled></td>
</tr>
<?php
$countrow++;
}
?>
</tbody>
</table>
</div><!-- /.span -->
</div><!-- /.row -->
<button type="submit" name="submit">Update</button>
</form>
</body>
</html>
UPDATE.php
<?php
error_reporting(E_ALL & ~E_NOTICE);
include ("dbconfig.php");
require_once('auth.php');
$product_img_name=$_FILES["product_img"]["name"];
if((isset($_POST['img_id'])))
{
$rand = rand(5,987897899);
foreach($_POST["img_id"] as $imgId)
{
//$product_img_name= $_POST['product_img_name'][$imgId];
$tmpName = $_FILES['product_img_name']['tmp_name'][$imgId];
$imagetmp=addslashes (file_get_contents($tmpName));
$name=basename($_FILES['product_img_name']['name'][$imgId]);
$t_name=$_FILES['product_img']['tmp_name'][$imgId];
$dir='upload';
$new_name= date('dmY')."_".$product_code."_".$rand."_".$name;
if(move_uploaded_file($t_name,$dir."/".$new_name))
{
$query = mysql_query("UPDATE maray_product_img set product_img_name='$imagename',
product_img_path='upload/$imagename', product_img='$imagetmp' where img_id='$imgId' LIMIT 1");
echo "<script>alert ('Successfull! Data has been changed.')</script>";
echo "<script>window.location = 'test.php'</script>";
}
else
{
echo "<script>alert ('Failed to update. Please try again')</script>";
}
}
}
?>
Hope experts can help me on this. I'm new to PHP. Some of the code which I got from others. Really need help. Thank you in advance.
This question already has answers here:
undefined index text fields php database?
(2 answers)
Closed 8 years ago.
how exactly ajax jquery working. i am new in ajax and jquery.
i want to delete row my using ajax.
index.php
<head><link rel="stylesheet" type="text/css" href="css/style.css"></head>
<h1>Login Here</h1>
<form name="f1" action="login.php" method="post">
<table border="1">
<tr><td>username</td><td><input type="text" name="t1"></td>
</tr>
<tr><td>password</td><td><input type="password" name="t2"></td></tr>
<tr><td><input type="submit" value="login"></td>
<td class="error"><?php if(isset($_GET['wrong_detial'])){
echo "RE-ENTER username and password !! "; }?>
</td>
</tr>
</table>
</form>
login.php
<head>
<script type="text/javascript" src="jquery.js"></script>
<link rel="stylesheet" type="text/css" href="css/style.css">
<script type="text/javascript">
function del() {
var info = 'id=' + id;
$.ajax({
type: 'get',
url: 'delete.php',
success: function (result) {
$("#div1").html(result);
}
});
return false;
}
</script>
</head>
<?php
include "db/db.php";
$user=$_POST['t1'];
$pass=$_POST['t2'];
$result=mysql_query("select * from registor where username='$user' and password='$pass' ")or die(mysql_error());
$row=mysql_fetch_row($result);
?>
<h1>Welcome Mr. <?php echo $user;?></h1>
<?php
if(!$user == $row[1] || !$pass ==$row[2]){ //if username or password not matched with database
header("location:account.php?wrong_detial");
}
else{
if($user == 'admin'){ //if admin login
?>
<table border="1">
<tr><td>User ID</td><td>Username</td><td>Password</td><td>Email-ID</td><td>delete</td></tr>
<?php
$admin_result=mysql_query("select * from registor");
while($admin_db=mysql_fetch_row($admin_result)){
?>
<tr>
<td><?php echo $admin_db[0];?></td>
<td><?php echo $admin_db[1];?></td>
<td><?php echo $admin_db[2];?></td>
<td><?php echo $admin_db[3];?></td>
<td id="div1">
Delete <!-- Deleting single record-->
</td>
</tr>
<?php
}
?>
</table>
<?php }
?>
delete.php
<?php
include "db/db.php";
if($_GET['delete']){
$drop=$_GET['delete'];
}
$result=mysql_query("delete from registor where username='$drop'");
if($result){
echo "deleted";
}
?>
what is the solution of this.
is there better way to delete record from database using ajax jquery.
Missing end curly braces in login.php for else block.
</table>
<?php }
?>
should be
</table>
<?php }
}
?>