I have multiple images in a HTML document and I want them to render unique values when they are clicked (in some retrievable way). I have tried having them as form elements, like so:
<form id="myform" method="post" action="">
<input type="hidden" name="action" value="submit" />
<div class="flex-item"><input type="image" name="submit" value="alt1" alt="alt1" src="images/<?php echo $data[$counter] ?>"></div>
<div class="flex-item"><input type="image" name="submit" value="alt2" alt="alt2" src="images/<?php echo $data[$counter+1] ?>"></div>
</form>
In this case I would like to access the POST data with PHP, something like:
if (isset($_POST['action'])) {
echo '<br />The ' . $_POST['submit'] . ' button was pressed';
}
But this doesn't work, as it's the image input type, which doesn't seem to be able to send data. I have tried using a button with the image as background, but this way I would have to adapt the size of each image to make it fit in the button (which I want to avoid, as I have many images).
I know I could use an image as a submit button with Javascript, but as I said, information about which image has been clicked also needs to be available somehow. Any ideas about the best solution?
HTML / CSS - Only way.
Set up the CSS to hide the radio buttons:
.hidden {
display: none !important;
}
In your form, use radio buttons to track which image is selected. Put the image inside of a label that is "for" the relevant radio button . Be sure to put whatever info you want in PHP inside the value attribute of the radio buttons:
<form method="post" name="myForm">
<div>
<input type="radio" name="image" value="image1" id="image1" class="hidden">
<label for="image1"><img src="path-to-your-image.jpg"></label>
</div>
<div>
<input type="radio" name="image" value="image2" id="image2" class="hidden">
<label for="image2"><img src="path-to-your-other-image.jpg"></label>
</div>
<div>
<input type="submit" name="save" value="Save Image Selection">
</div>
</form>
If you need the form to submit when they click an image, then add this bit of javascript:
<script>
// No-conflict-mode-safe document ready function (waits until page is loaded to run, which ensures radio buttons are available to bind to)
jQuery(function($) {
// Hide / suppress the submit button
$('input[type="submit"]').closest('div').hide();
// Bind to change event for all radio buttons
$('input[type="radio"]').on('change', function() {
// Submit the form ("this" refers to the radio button)
$(this).closest('form').submit();
});
});
</script>
Then, when you submit this form, in your PHP you'd be able to do this:
$image = $_POST[ 'image' ]; // 'image' is the name of the radio buttons
var_dump( $image );
// Will result in "image1" or "image2", etc - whatever "value" you assigned to the radio buttons
When you use your code, you get the submit param (because of the button's attribute name) in your $_POST object. The value will be the value attribute.
So you can check this like this:
<form id="myform" method="post" action="">
<input type="hidden" name="action" value="submit" />
<div class="flex-item"><input type="image" name="submit" value="alt1" alt="alt1" src="images/img1"></div>
<div class="flex-item"><input type="image" name="submit" value="alt2" alt="alt2" src="images/img2"></div>
</form>
<?php
if (isset($_POST['submit'])) {
if ($_POST['submit'] == 'alt1') {
echo 'alt1 clicked';
// First button clicked
}
else {
echo 'alt2 clicked';
// second button clicked
}
}
?>
Related
I have written a comment system in PHP. Currently, the editor is on the top of the page:
<form method="POST" id="comment_form" enctype="multipart/form-data">
<input type="text" name="comment_name" id="comment_name" value="<?php echo $user ?>" placeholder="User" />
<textarea name="comment_content" id="comment_content" placeholder="Comment" rows="5"></textarea>
<input type="hidden" name="comment_id" id="comment_id" value="" />
<input type="submit" name="submit" id="save" class="btn" value="Send" />
</form>
Each comment look like that (simplified):
<div class="comment">
<b><?php echo $row["user"] ?></b>
<div>
<?php echo $row["comment"] ?>
</div>
<button type="button" class="btn reply" id="'.$row["comment_id"].'">Reply</button>
</div>
An small javascript function sets the focus on the editor when the Reply button is clicked:
$(document).on('click', '.reply', function(){
var comment_id = $(this).attr("id");
$('#comment_id').val(comment_id);
$('#comment_name').focus();
});
});
I would like that editor to open below any Reply button when one of the buttons is clicked.
I guess that adding the editor code after each comment with a "display: none" attribute is not the best solution.
Would you please help me to achieve that ?
If I understand correctly you want one form for all comments, rather than duplicating the form HTML inside every comment.
In which case you need to move it in the DOM via JavaScript. You don't show any attempt at this but it might look something like this:
$(document).on('click', '.reply', function() {
$('#comment_form').insertAfter(this); //<-- move form
var comment_id = $(this).attr("id");
$('#comment_id').val(comment_id);
$('#comment_name').focus();
});
Note also that your JS is syntactically invalid as you have double });.
I am developing a facial recognition system. When i capture image with my webcam the url is loaded into a text box in a form. Now i want the form to submit and process the php if it is submnitted. Here is my form
<form action="<?php echo $_SERVER["PHP_SELF"];?>" method="post" enctype="multipart/form-data" id="frmsubmit">
<input type="text" class="form-control input-sm" id="imgsrc" name="imgsrc">
<input type="submit" value="AUTHENTICATE" class="btn btn-primary" data-loading-text="Loading..." name="send" id="submit">
</form>
AND MY JAVASCRIPT
<script language="JavaScript">
webcam.set_api_url( 'present.php' );
webcam.set_quality( 100 ); // JPEG quality (1 - 100)
webcam.set_shutter_sound( true ); // play shutter click sound
webcam.set_hook( 'onComplete', 'my_completion_handler' );
function take_snapshot(){
// take snapshot and upload to server
document.getElementById('upload_results').innerHTML = '<h1>Uploading Image To Database...</h1>';
webcam.snap();
}
function my_completion_handler(msg) {
document.getElementById("imgsrc").value=msg;
// extract URL out of PHP output
if (msg.match(/(http\:\/\/\S+)/)) {
// show JPEG image in page
document.getElementById('upload_results').innerHTML ="<div class='alert alert-success fade in'> <i class='icon-remove close' data-dismiss='alert'></i> <strong>Success!</strong>Image Captured And Uploaded Successfully </div>";
document.getElementById('upload_img').innerHTML ="<img src="+msg+" class=\"images\">";
// reset camera for another shot
webcam.reset();
document.getElementById('frmsubmit').submit();
}
else {alert("PHP Error: " + msg);
}
}
</script>
AND PHP CODE
if(isset ($_POST["send"]))
{
Use submit button click trigger for example
document.getElementById("submit").click();
you are using document.getElementById('frmsubmit').submit(); but you don't have any form with this id but you have submit button with id submit. so this code will work for you.
if you give the form an id
<form action="someaction" method="post" id="someform">
You can trigger the submit event with jQuery
$('#someform').trigger('submit');
or
$('#someform').submit();
Try this...
$('#imgsrc').on('change', function(){
$(this).parent().submit();
})
You can add the attribute onchange to the text box
onchange="this.form.submit()"
I want to create a piece of javascript code which doesn't allow the user to submit the form unless at least one event has been checked from the list of checkboxes within a span tag. how would this be done?
Form Name
<form id="bookingForm" name"form1" action="#" method="get">
Span class which echos all the events along with a checkbox at the end of the printed event
<span class='chosen'><input type='checkbox' name='event[]' onclick='checkTerms();' value='{$event['eventID']}' title='{$event['eventPrice']}' /></span>
Submit button code
<input type="submit" name="submit" value="Make booking" id="sub1" disabled=disable />
function checkCheckboxes() {
if (document.querySelector('input[name="event\\[\\]"]:checked') == null) {
document.getElementById('sub1').disabled = 'disabled';
} else {
document.getElementById('sub1').removeAttribute('disabled');
}
}
Change the onclick attribute of the checkboxes to:
onclick="checkCheckboxes(); checkTerms();"
I am trying to show or hide div after submitting an action. so let say I have textarea and I put "example" there then checked the checkbox. after submitting, the "receipt.php" page must display "example" , and if I unchecked the checkbox and submit, the receipt.php page must hide the "example". I tried searching similar to my problem but I really don't have idea how to solve it. I have this code so far but i dont have any codes in "receipt.php" since I really don't have idea. pls help me
<form method ="POST" action ="receipt.php">
<textarea name ="comment"></textarea><br>
<input type="checkbox" id="checkbox" value ="1" >Show this comment in receipt<br>
<input type ="submit" value ="Print">
</form>
You don't need the server response to recognize if the checkbox was checked unless you have some validation on server side. If using JQuery, you can do this:
$('#checkbox').change(function(){
$('#your_div').toggle();
});
If you want to rely on what your server says you need to return something to your ajax call.
for example {response: true/false}
In Html:-
<form method ="POST" action ="receipt.php">
<textarea name ="comment"></textarea><br>
<input type="checkbox" name="reciept-chk" id="checkbox" value = "1" >Show this comment in receipt<br>
<input type ="submit" value ="Print">
</form>
In receipt.php:
<?php
..//recept.php
if(isset($_POST['reciept-chk'])){
// Write Code example here
}
?>
If you want to validate it client side before posting your value in receipt.php then
you can simply validate by piece of jquery.
$(document).ready(function(){
$('#checkbox').change(function(){
if ($('#checkbox').is(':checked')) {
$("#exampleDiv").show();
} else {
$("#exampleDiv").hide();
}
});
});
Please avoide toggle() as it deprecated in 1.8
Here is the code you'll need in your unique PHP file :
<form method="POST">
<textarea name="comment">
<?php (isset($_POST['checkbox1']) && $_POST['checkbox1'] == '1') ? echo "Example"; : echo ""; ?>
</textarea>
<br>
<label for="checkbox1">Show this comment in receipt</label>
<input type="checkbox" id="checkbox1" name="checkbox1" value="1" />
<br>
<input type="submit" value="Print" />
</form>
Replace what you want in place of "Example".
If you are using javascript only, you might try something like this:
<script>
function show(){
if(form.toggledisplay.checked == false){
document.getElementById('example').style.display = "none";
}
else{
document.getElementById('div').style.display = "block";
}
}
</script>
<form method = "POST" action="receipt.php" onsubmit="show()">
<textarea name = "comment"></textarea><br>
<input type="checkbox" name="toggledisplay" id="checkbox" value = "1" >Show this comment in receipt<br>
<input type = "submit" value = "Print">
</form>
<div id="example" style="display:none;">This is the div you want to show</div>
If you are populating the contents of the div from the receipt.php file, you could make a post request to it, when the onsubmit() function is fired and fill the contents of the div like:
document.getElementById('div').innerHTML = "Result from the get/post request"
Hope this points you in the right direction.
I have a page which has lot of post data in the url.
For example,
www.test.com/test.php?userid='tester'&name=test&so on
The above page has a form that has something like this:
<?
$set=get_value_set;
if($set ==1) {
$set_value="SET";
} else {
$set_value="UNSET";
}
?>
<form name="test">
<input type="text" readonly="READONLY" value="<? echo $user_id; ?>">
<input type="submit" value="Email" name="submit_user">
<input type="submit" value="<? echo $set_value; ?>" name="submit_user">
<?
function setuser()
{
//sets the value
}
function email_user()
{
//sets the value
}
?>
there are two buttons above, when I click on email, i want the value of email button to be passed to the email_user function and do some proceesing there. Similar thing when I click on the set button.
NOTE:But in both cases above, I want the form to remain in the same page with the same post data in the url, but I also want the page to be refreshed so that the set button can have a value of Set or Unset depending on the database update.
Is this possible?
I would start to remove the submit action of each button and change them to
<input type="button" class="btn-Email" value="Email" name="submit_user" />
<input type="button" class="btn-Other" value="<? echo $set_value; ?>" name="submit_user" />
and then, using jQuery, you can easily process each click and submit the form
$(function() {
$(".btn-Email").click(function() {
// append anything you want
var but_email_value = $(this).val(), // or $(".btn-Email").val()
btn_other_value = $(".btn-Other").val();
$("form").submit();
});
$(".btn-Other").click(function() {
// append anything you want
var but_other_value = $(this).val(), // or $(".btn-Other").val();
btn_email_value = $(".btn-Email").val();
$("form").submit();
});
});
change your HTML
<form id="test" name="test">
...
<button onclick="email_user();">Email</button>
<button onclick="setuser();"><? echo $set_value; ?></button>
</form>
your functions should submit the form for you:
document.getElementById("test").submit();