Develop Reference

on button click with confirm alert box, query submitting on cancel also

i have created a button to remove data from database. The button code looks like the following:
<form method="post">
<button name="remove" onclick="myFunction()" style="margin-left: -15%; border-radius: 15px;" class="button button2">Remove</button>
</form>
i have given an alert confirm box to proceed or cancel the button click.
function myFunction() {
confirm("Do you want to remove?!");
}
now after the button click, if i do cancel or if i do ok, both are executing the query. the cancel button is not cancelling the click. can anyone please tell what is wrong here.

Way 1:
you can use this:
<button name="remove" onclick="return confirm('Are you sure?')" style="margin-left: -15%; border-radius: 15px;" class="button button2">Remove</button>
the return is very important
WAY 2:
function myFunction() {
if (confirm('Are you sure?')) {
//Do SomeThing...!
}
}
NOTE:
You can use the Sweet Alert

You need to validate the confirm response
function myFunction() {
if (confirm("Do you want to remove?!")) {
//do stufff here...
console.log('success')
} else {
console.log('cancel')
}
}
<button name="remove" onclick="myFunction()"class="button button2">Remove</button>

Make sure you do preventDefault because your delete button is inside the form
document.getElementById("uniqueId").addEventListener("click", function(event){
event.preventDefault();
if(confirm("Msg")){
//do something
}
});
<form method="post">
<button name="remove" id="uniqueId" style=" border-radius: 15px;" class="button button2">Remove</button>
</form>
Make sure that every button have a unique id

Two Html buttons for two different functions

I have a form which has two Options, Submit and Overwrite.
It looks like this:
[ INPUT FIELD ]
[Submit] [Overwrite]
The Overwrite Button only appears when the value already is in the Database.
The HTML Code is:
<input type="text" name="target" id="target">
<button id="submit" name="submit" type="submit" class="btn btn-primary"> Submit </button>
<button id="overwrite" name="overwrite" type="submit" class="btn btn-primary"> Overwrite </button>
The JS Code is:
if(!problem){
data = "submit=save";
jQuery('#overwrite').click(function(){
$(this).toggleClass('selected');
if( $(this).hasClass('selected') ){
data+="&overwrite=on";
console.log( "overwrite=on" );
}
});
sendToBean(href, data);
jQuery.each(langs, function(i, lang){
sendToBean(href, data);
});
}
}
If I only have the Submit button, it works.
If I only have the Overwrite button, it works.
But if I have both, the Overwrite button wont work anymore.
Does anyone have a solution to this problem?

put retrun false in the anonymous callback function will do the trick. since you declare that the button is a submit button
if(!problem){
data = "submit=save";
jQuery('#overwrite').click(function(){
$(this).toggleClass('selected');
if( $(this).hasClass('selected') ){
data+="&overwrite=on";
console.log( "overwrite=on" );
}
return false;
});
sendToBean(href, data);
jQuery.each(langs, function(i, lang){
sendToBean(href, data);
});
}
}

When you click the submit button the page will be refreshed and the overwrite will return to the initial format and the selected will disappear, Try to change the input type to button :
<button id="overwrite" name="overwrite" type="button" class="btn btn-primary"> Overwrite </button>
Hope this helps.

Remove <input type=""> for Overwrite button you may use <button>
Overwrite

<input type="text" name="target" id="target">
<input type="submit" id="btnSubmit" name="btnSubmit" class="btn btn-primary" value="submit"/>
<input type="submit" id="btnOverwrite" name="btnOverwrite" class="btn btn-primary" value="Overwrite"/>
$(document).ready(function(){
$("#btnOverwrite").unbind("click").bind("click",function(e){
e.preventDefault();
alert("overwrite called");
});
$("#btnSubmit").unbind("click").bind("click",function(e){
e.preventDefault();
alert("submit called");
})
});
Review fiddle
https://jsfiddle.net/dipakchavda2912/rwdakvyg/

Event on ok cancel button in JavaScript

I am stuck with a small issue.
<input class="btn btn-home" type="submit" name="discard" id="discard" onclick="return confirm('Are you sure you want to discard changes?')" alt="Discard" value="Discard Changes"/>
$('document').ready(function(){
var subm = "";
$('input[type="submit"]').click(function(e) {
subm = e.target.id;
if(subm == 'discard')
window.location = "http://www.weblink.com/manager.php";
})
});
When user click on button a confirmation box will appear with ok cancel. When user click on ok it will redirect to other page and if user click on cancel then it will stay on this page.
Problem is it is redirecting if user click on cancel. I don't want to redirect the page if cancel button clicked.

Two problems here:
You're trying to combine inline and external JS, which is always a bit messy
You're not suppressing the native behaviour of submit buttons, which is to submit a form (which I assume you have in your HTML, even though it's not shown). In fact, you don't even need the button to be of type submit.
HTML:
<button class="btn btn-home" name="discard" id="discard">Discard Changes</button>
JS:
$('#discard').on('click', function(evt) {
evt.preventDefault(); //don't submit the form, which a button naturally does
if (confirm('Are you sure you want to discard changes?'))
location.href = 'http://www.weblink.com/manager.php'; //redirect only on confirm
});

Put confirm dialog inside onsubmit listener instead. No need to use click listener.
<form onsubmit="return confirm('whatever your confirmation message')">
<input class="btn btn-home" type="submit" name="discard" value="Discard Changes"/>
</form>

You need to remove the inline script,
and the modification to the code should be something like the below -
$('document').ready(function()
{
var subm = "";
$('input[type="submit"]').click(function(e) {
var isConfirmed = confirm('Are you sure you want to discard changes?');
if(isConfirmed){
subm = e.target.id;
if(subm == 'discard'){
window.location = "http://www.weblink.com/manager.php";
}
}
});
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input class="btn btn-home" type="submit" name="discard" id="discard" alt="Discard" value="Discard Changes"/>

Enable submit button with javascript

First, i have a code that i need to know if the user has clicked on one submit button, then, i need one function to enable another submit button that is disabled by disabled="disabled".
Here's my noob function (Needs improves, does not work).
:
<script>
function EnableSend() {
if(document.getElementById("Submit_Facebook").click(); {
document.getElementById("submit").disabled = false; }
}
</script>
And now the code:
1 - Disabled Submit: (Will be enabled after user click on Submit_Facebook submit button).
<input id="submit" name="submit" type="submit" value="" disabled="disabled">
2 - Other submit that will make the disabled submit enabled.
<form method="post" class="button" action="<?=$PHP_SELF;?>"">
<input id="Submit_Facebook" name="Submit_Facebook" type="submit" value=""onclick="EnableSend()">
</form>
3 - Php part
<?php
if (isset($_POST['Submit_Facebook'])) {
echo "<script>alert('You now can proceed to step two.');</script>";
echo '<script type="text/javascript"language="javascript">window.open("#");</script>';
exit;
}?>
Well, my english is not that good, but if you guys need any detail just contact me, thanks for your attention.

jsFiddle
<input id="submit" name="submit" type="submit" value="send" disabled="disabled">
<input id="Submit_Facebook" name="Submit_Facebook" type="submit" value="" onclick="EnableSend();">
<script type="text/javascript">
function EnableSend() {
document.getElementById("submit").disabled = false;
}
</script>

You got to remove disabled attribute from input.
Something like this:
var EnableSend = function(){
$( "#submit" ).removeAttr('disabled');
};

html form with multiple submitbuttons

I have 2 submit buttons in an HTML form.
How can I know which submit button has triggered the JavaScript function?
<script language="javascript" type="text/javascript">
function verifyData(formdata) {
// Here I want to know from which submit button this function is triggered
// I can't use type button instead of submit
// I can't use onclick handler
// I can't use JQuery.. I want to do only with javascript
}
</script>
<form onsubmit="verifyData(this);" method="post">
<input type="submit" value="submit1">
<input type="submit" value="submit2">
</form>
<button value="delete row" id="but1" onclick="disps()">delete row</button>
I want to do different actions based on the different submit buttons clicked.

It is not possible to check the button clicked through the onsubmit event. Instead move the call to verifyData() to the onclick handler of each button. Use return in the onclick call to cancel submission if false is returned by verifyData()
<script language="javascript" type="text/javascript">
function verifyData(button) {
// validate
switch (button.value) {
case "submit1":
// do somehting
break;
case "submit2":
// do somehting
break;
// ...
};
// submit the form
return true;
}
</script>
<form method="post">
<input type="submit" value="submit1" onclick="return verifyData(this);">
<input type="submit" value="submit2" onclick="return verifyData(this);">
</form>

How about putting an onclick event handler on both buttons which will set a variable to say which button was clicked?
like so:
<script language="javascript" type="text/javascript">
function verifyData(formdata) {
alert(btnClicked);
// Here I want to know from which submit button this function is triggered
// I can't use type button instead of submit
}
var btnClicked = 0;
function setSubmit(which) {
btnClicked = which; return true;
}
</script>
<form onsubmit="verifyData(this);" method="post">
<input type="submit" value="submit1" onclick="return setSubmit(1);">
<input type="submit" value="submit2" onclick="return setSubmit(2);">
</form>

Are you allowed to use the jQuery library?
If you can using this you can easily bind to each submit button based on an id.
For example:
<form id="form1" method="post">
<input type="submit" value="submit1" id="submit1">
<input type="submit" value="submit2" id="submit2" >
</form>
<script type="text/javascript">
$("#submit1").click(function(e)
{
// Do stuff when 1 is clicked.
$("#form1").submit();
});
$("#submit2").click(function(e)
{
// Do stuff when 2 is clicked.
$("#form1").submit();
});
</script>
you could also have the buttons as a type of button to avoid any issues, but you should be able to simply return false; to stop the button of type submit from... submitting

Here is how I would do it... Firstly I would use jQuery so you must include that in your document like this:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"></script>
It would also mean your HTML can be simplified to:
<form method="post">
<input type="submit" value="submit1"/>
<input type="submit" value="submit2"/>
</form>
Then you can use jQuery:
<script>
// When the document is ready
$(function(){
// Action performed when a submit button in the form is clicked
$("form[type='submit']").click(function(e){
// Get the value attribute
var val = $(this).val(),
validation_has_passed = false;
// If it is submit1
if(val == "submit1") {
// Validate submit 1
validation_has_passed = true;
// If it is submit2
} else if(val == "submit2") {
// Validate submit 2
validation_has_passed = true;
}
// If all validation is OK submit the form
if(validation_has_passed === true) {
$("form").submit();
}
// Ensure pressing these buttons doesn't submit the form
e.preventDefault();
});
});
</script>