Develop Reference

How to make .toggle from .animate

I have hamburger menu that comes in with an animation. When I click again on hamburger menu (after I have already escaped from the menu), the menu appears without animation.
I assume it is caused by .animate - I need to make .toggle
$(document).ready(function() {
$("#openMenu").click(function() {
$("#main").toggle(200);
$("#menuSection").toggle(200);
$(".menu").animate({ left: "2%" });
});
});
CSS:
.menu {
height: 100px;
width: 0px;
background-color: #450a5a;
display: flex;
position: absolute;
left: -50%;
cursor: pointer;
pointer-events: none;
transition: all 0.5s;
}

I assume that you click again on the #openMenu element to trigger menu closing animation when it's opened. Calling .animate that you have in your code again, after .menu element's style it already set to left: 2%; will not change anything. You have to implement code that will trigger either "out" animation or "in" animation depending on whether or not the menu is opened.
$(document).ready(function() {
$("#openMenu").click(function() {
$("#main").toggle(200);
$("#menuSection").toggle(200);
var menu = $(".menu");
if (menu.css("left") == "2%") { //if the "in" animation was already performed
menu.animate({ left: "0%" }); //revert back to normal
} else {
menu.animate({ left: "2%" }); //perform "in" animation
}
});
});

Div flickers on hover

I have read a lot of the questions on here but can't find one that fixes this. I have programmed a div to follow my cursor. I only want it to appear when the cursor is over #backgroundiv. I have got it working but it sometimes randomly flickers on chrome and disappears entirely on firefox. Even more randomly is it sometimes appears to work and then starts flickering. I have tried a variety of things from hover to mouseenter/mouseover but nothing seems to work.
What I want is for #newdot to appear when the cursor is over #backgroundiv and then follow the cursor around the div. Any help would be much appreciated.
//hide dot when leaves the page
$(document).ready(function() {
$("#backgroundiv").hover(function() {
$("#newdot").removeClass("hide");
}, function() {
$("#newdot").addClass("hide");
});
});
//div follows the cursor
$("#backgroundiv").on('mousemove', function(e) {
//below centres the div
var newdotwidth = $("#newdot").width() / 2;
$('#newdot').css({
left: e.pageX - newdotwidth,
top: e.pageY - newdotwidth
});
});
//tried below too but it doesn't work
/*$(document).ready(function(){
$("#backgroundiv").mouseenter(function(){
$("#newdot").removeClass("hide");
});
$("#backgroundiv").mouseout(function(){
$("#newdot").addClass("hide");
});
}); */
#backgroundiv {
width: 400px;
height: 400px;
background-color: blue;
z-index: 1;
}
#newdot {
width: 40px;
height: 40px;
background-color: red;
position: absolute;
z-index: 2;
}
.hide {
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="newdot"></div>
<div id="backgroundiv"></div>

There is not issue but a logical behavior, when you hover on the blue div you trigger mouseenter so you remove the class and you see the red one BUT when you hover the red one you trigger mouseleave from the blue div thus you add the class and you hide the red one. Now the red is hidden you trigger again the mouseenter on the blue div and you remove the class again and the red div is shown, and so on ... this is the flicker.
To avoid this you can consider the hover on the red box to make the red box appear on its hover when you lose the hover from the blue one.
$(document).ready(function() {
$("#backgroundiv").hover(function() {
$("#newdot").removeClass("hide");
}, function() {
$("#newdot").addClass("hide");
});
});
//div follows the cursor
$("#backgroundiv").on('mousemove', function(e) {
//below centres the div
var newdotwidth = $("#newdot").width() / 2;
$('#newdot').css({
left: e.pageX - newdotwidth,
top: e.pageY - newdotwidth
});
});
#backgroundiv {
width: 400px;
height: 400px;
background-color: blue;
z-index: 1;
}
#newdot {
width: 40px;
height: 40px;
background-color: red;
position: absolute;
z-index: 2;
}
.hide {
display: none;
}
/* Added this code */
#newdot:hover {
display: block;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="newdot">
</div>
<div id="backgroundiv">
</div>

About draggable elements in jquery

I don't have much experience with jQuery.
I have 4 li elements and a draggable block. When I drag from green to blue, first I need my dragging block to stand behind blue and not go out from the borders of the container, meaning that my draggable element must be always snap into the container.
When my draggable element stand behind blue, the background color must be changed from brown to red.
Can anybody help me? Because I don't really know how to do this. All what I have at this moment is: JSFiddle
HTML
<div id="container" class="ui-widget-header">
<div id="draggable" class="ui-widget-content"></div>
<ul id="menu">
<li id="menuElement1"></li>
<li id="menuElement2"></li>
<li id="menuElement3"></li>
<li id="menuElement4"></li>
</ul>
</div>
CSS
body {
background-color: brown;
}
#container {
position: relative;
}
#menu,
#draggable {
position: absolute;
top: 0;
left: 0;
}
#draggable {
width: 100px;
height: 150px;
}
#menu {
margin-left: -40px;
}
ul li {
display: block;
float: left;
padding: 50px;
}
#menuElement1 {
background-color: green;
}
#menuElement2 {
background-color: blue;
}
#menuElement3 {
background-color: black;
}
#menuElement4 {
background-color: red;
}
#container {
height: 150px;
width: 100%;
background-color: gray;
JQuery
$(function() {
$( "#draggable" ).draggable({ snap: ".ui-widget-header" });
});

Here's an updated fiddle
You'd do well to read this article on Droppable from the jQuery docs. Basically you were half way there, you need to make an element (the blue box, with id #menuElement2) droppable to provide a target for a draggable element
$('#menuElement2').droppable({
drop: function( event, ui ) {
//Do something here...
}
});
Within the drop function (this fired when the block is dropped on the target) you need to perform your action.
$('body').css({'background-color': 'red'});
This adds a custom css rule to the body that changes the colour, again check out the jQuery docs - search for 'jQuery css'.
Hope this helps :)
Update: I just updated the fiddle again to make it revert back to brown when you change selection - not sure if you wanted this but it can be easily removed by commenting out the css change within the drag function.

Toggling a slide out menu

So I'm in the process of making a slide out menu on my site. It slides out on click, but how can I set it up so on another click it will slide back in?
Pretty simple source code right now:
$(document).ready(function() {
$("#menuicon").click(function() {
$("nav ul, .content").animate({left: "-15%"}, 1000);
});
});
Thanks in advance!

Check this simple Slide Out menu.
DEMO http://jsfiddle.net/yeyene/TLtqe/1/
$('a').on('click',function() {
if($('#website').css('left')=='0px'){
$('#website').animate({left: '-30%'}, 1000);
}else{
$('#website').animate({left:0}, 1000);
}
});

You may be able to just use the toggle() function in place of click, but I'm not a big fan of toggle. The below solution incorporates a class as well, but this is how I'd do it:
$(document).ready(function() {
$("#menuicon").click(function(e) {
var menuicon = $(e.target);
if (!menuicon.hasClass('open'){
menuicon.addClass('open');
$("nav ul, .content").animate({left: "-15%"}, 1000);
} else {
menuicon.removeClass('open');
$("nav ul, .content").animate({left: "0"}, 1000);
}
});
});
I would also incorporate a 'working' class on there to prevent double clicks, but that may be more than you need with your project.
EDIT:
Little extra tidbit that I use quite a bit, if you have complex menu options that involve a few different objects (like an anchor, with an img and a span inside, or some other elements in it) you can pair e.target with the jquery 'closest()' function to be sure you're always selecting the anchor and not one of its children.
var clicked = $(e.target).closest('a');
This is pretty helpful if you're trying to also fetch any attribute values from your clicked objects, using this you know for certain that your selection will always be the 'a' (rather than e.target returning a child img or something), and you can work from there.

Use the jquery slidetoggle instead!
E.g, $(document).ready(function() { $("#menuicon").click(function() { $("nav ul, .content").slideToggle(1000); }); }); instead of animate!

Couldn't you use something like this?
$(document).ready(function() {
$(".nav_button").click(function () {
$(".top.mini_nav").slideToggle();
});
});
I'm using this here -> DEMO
And this is the CSS I use for that button
.top.mini_nav {
display: none;
top: 20px;
left: 20px;
margin-bottom: 60px;
position: relative;
}
.top.mini_nav a:hover {
background-color: #F8F8F8;
}
.nav_button {
position: relative;
width: 40px;
height: 40px;
left: 40px;
display: block;
color: white;
background-color: #2898F2;
font-size: 20px;
font-weight: bold;
text-align: center;
line-height: 39px;
cursor: pointer;
top: 20px;
border-radius: 5px;
-webkit-transform: rotate(90deg);
-moz-transform: rotate(90deg);
-ms-transform: rotate(90deg);
-o-transform: rotate(90deg);
transform: rotate(90deg);
}
.nav_button:hover {
background-color: #D0A624;
}
You will probably want something cleaner - but this works fine so far for me.

I realized that I just needed to make a variable that would set itself to true/false depending on if it was open.
var open = false;
$(document).ready(function() {
$("#menuicon").click (function() {
if (!open){
$(".content, nav ul").animate({left: "-=15%"}, 1000);
open = true;
} else {
$(".content, nav ul").animate({left: "+=15%"}, 1000);
open = false;
}
});
});
Thanks for all the help guys!

jquery slide hidden menu from left can't configure js

So I've been working on this for a while, I've tried many examples found here on stackoverflow, and then starting reading up on js/jquery for most of the day, but am still having trouble with this.
Basically I was able to create a hidden menu item that slides on to screen when clicked, and I was able to change the button used to open in by toggling the class, and send it back.
But after the first time through that process when I try to open it again, it opens and then closes automatically.
I built a jsfiddle, but have done it wrong as it's not working the same as on my site.
fiddle: http://jsfiddle.net/VpnrV/1/
site: http://ericbrockmanwebsites.com/dev4/
code - html:
<div id="dashboard">
<nav id="access">
<div class="open"></div>Here's a bunch of content representing the nav bar.
</nav>
</div> <!-- dashboard -->
css:
#dashboard {
font-size:30px;
float:left;
position: absolute;
right: -653px;
z-index: 100;
}
#access {
display: block;
float: right;
margin: 10px auto 0;
width:730px;
}
.open {
background: #cabd32 url(images/open.png) top left no-repeat;
float:left;
padding:13px 30px 16px;
}
.close {
background: #cabd32 url(images/close.png) top left no-repeat;
float:left;
padding:13px 30px 16px;
}
my laughable js:
$(document).ready(function() {
$('.open').click(function() {
$('#dashboard').animate({ right: '0' });
$(this).toggleClass('close');
$('.close').click(function() {
$('#dashboard').animate({right: '-653'});
}
);
});
Any help is greatly appreciated!

You are actually binding the class .close to multiple callback every time you click the button.
you can try this:
$('.open').bind('click',function(){
$('#dashboard').stop().animate(
{
right: $(this).hasClass('close') ? '-653px' : '-400px'
});
$(this).toggleClass('close');
});
Having stop() infront of animate() will cancel the current animation and do the next animation without queueing multiple animations up.

You can actually do this in one click event. All this does is every time you click open it looks for the close class, if it's there, close the menu, if not open it. Then toggle the close class:
$(document).ready(function () {
$('.open').on("click", function () {
if ($(this).hasClass('close')) {
$('#dashboard').animate({
right: '-653'
});
} else {
$('#dashboard').animate({
right: '0'
});
}
$(this).toggleClass('close');
});
});
I don't know if this is the most effecient but it works for your example. I updated it as well: http://jsfiddle.net/VpnrV/3/