Sorry folk, I know that my question asked many guys in different form, but I'm disappointed to find a decision my problem.
function testAjax(){
var result = "";
$.ajax({
type: "POST",
dataType: 'jsonp',
url: "https://api.novaposhta.ua/v2.0/json/",
data: {
"modelName": "Address",
"calledMethod": "getCities",
"methodProperties": {},
"apiKey": "6f94a6391cb5134ee68ddb7924de2a3d"
},
success: function(msg) { result = msg }});
return result;
}
var kor = testAjax();
console.log(kor);
I need to take out data from the ajax request and assign this data to a global variable. But function testAjax returns nothing. I think testAjax returns nothing because it's an async request to server and completes later than return result.
My question - how do I take out a value from $.ajax() and assign this value to a global variable? I tried googling and try decide this problem, but ...
Yes, your hunch is correct - the function is returning result as an empty string because the success handler is called later when the server response is returned. If you wish to do something specific when the response comes in, do so in the success response handler like so:
...
success: function(msg) {
// now you have the response so do something with it
console.log(msg);
}
...
most of the time the logic go inside the success function, whatever you will do with the response do it inside the success function.I think you may bay more time for the code structure and the flow of data inside your app.
good luck
Related
I am trying to put a url from an ajax response into a variable in jquery.
I have written the following code:
var thumb = $.ajax({
dataType: 'json',
url: 'https://www.googleapis.com/books/v1/volumes?q=isbn:' + isbn,
success: function(response){
return $(response).volumeInfo.imageLinks.thumbnail;
}}).responseText;
It was my understanding from looking at other answers that I must add .responseText at the end, or the code will continue without waiting for the ajax response.
However, thumb variable remains undefined.
I tried implementing the following solution with relevant changes (As I am passing only one ISBN at a time, there shouldn't be an array. The response should contain only one imageLinks.thumbnail url), but I cannot seem to catch the response correctly.
I looked into other answers, especially this one, but I am still not clear about how to reach the ajax response.
$.ajax is asynchronous, meaning the code will execute completely and the success callback will be fired at a later time.
var thumb is evaluated immediately. Do some reading on "callbacks" and "promises" to get more familiar with this topic.
A solution to your issue is:
function setThumbnail(thumbnail){
// this will evaluate later, when the ajax returns success
console.log('thumbnail gotten!');
var thumb = thumbnail; // do something with in in this function
}
$.ajax({
dataType: 'json',
url: 'https://www.googleapis.com/books/v1/volumes?q=isbn:' + isbn,
success: function(response){
setThumbnail($(response).volumeInfo.imageLinks.thumbnail);
}
});
// This line will evaluate immediately and carry on
console.log('ajax executed');
I threw in some logs for you to help you understand the order of execution here.
I would also note that $(response) looks odd to me, without testing it I think it should probably be just response.volumeInfo....
console.log(response) in the success callback to make sure you understand what data you are getting back.
Im trying to sort this around, im making an ajax requests of get type, and the page will be returning many responses, OK is one of those, is the page returns OK then I need to proceed for form submitting, else I need to halt the form submission, but Im unable to access the data out side of the function, it is available inside the fall back function alone, is it due to asynchronous mannerism?, can some one assist me to get out of this?
$.get('ajax.html',function(data){
//some code here
});
if(data == 'ok'){return true; } else {return false;}
$.get fires an asynchronous request, and the execution of you program continues. So in your case data is available only after the ajax call finishes and only inside your callback function. You need to do whatever you want to do with data inside your callback function.
You need to re-arrange you code to do something like:
$.get('ajax.html', function (data) {
if(data === 'OK') {
// do what you need to do in this case
}
});
// at this point there's no data
No, you are accessing data which is not a variable available.
How about assigning it to another variable?
var resp = "";
get('ajax.html', function (data) {
resp = data;
});
if(resp == "OK") {alert(1);}
alternatively you can go use asyn false
$.ajax({
url: url,
type: "GET",
async: false,
data: data,
success: function(ret) {
//alert(ret);
resp = data;
}
});
alert(resp);
Cheers!
I am wondering is these is any way to access the results of a jquery ajax call in the form a traditional var set to function fashion. For example consider:
function getPoints(){
//An array of JSON objects
var Points;
$.ajax({
url: "js/retrievePointsDataJson.php",
dataType:'json',
type: 'POST',
}).done(function(data){
//console.log(data);
Points.append(data);
});
console.log(Points);
return Points;
}
The commented out console.log show the array of json objects whereas the outer one does not. Now, i have tries this:
var Points = $.ajax({ ...});
And i see the response text within a larger object, but am unsure how to access the responseText. console.log(Points.responseText) yields an undefined variable.
Is this possible with this approach? Here is another question that received a check mark with a similar issue.
I have another solutions, which is the encapsulate my code within the done() function and i will have access to all my data. I was just curious if what i am attempting to do is even doable.
Thank you.
yes it is possible, however, you must wait for the request to be complete before doing so. However, since you can't effectively force the return to wait until the data exists, you're only options are to return a deferred object instead, or re-write the function in such a way that allows it to accept a callback.
function getPoints(){
return $.ajax({
url: "js/retrievePointsDataJson.php",
dataType:'json',
type: 'POST'
});
}
getPoints().done(function(data){
console.log(data);
});
or
function getPoints(callback){
return $.ajax({
url: "js/retrievePointsDataJson.php",
dataType:'json',
type: 'POST',
success: callback
});
}
getPoints(function(data){
console.log(data);
});
Because the Ajax call is done asynchronously you shouldn't return it from the outside function. This would require that you somehow block until the asynchronous call completes. Instead you could pass in a callback function to the getPoints function that will handle the logic of using the points.
function getPoints(callback){
$.ajax({
url: "js/retrievePointsDataJson.php",
dataType:'json',
type: 'POST',
}).done(function(data){
callback(data);
});
}
The asynchronous nature of ajax can make things harder if your used to imperative programming, but it will make your user interface much more responsive.
The log you're calling in the outer function is working with an undefined variable because the function is asynchronous. You can't return it from getPoints because it won't have finished. Any work with the Points variable needs to happen inside the callback (the function passed to done).
I try to manipulate a variable inside a function. But it seems to forget the values once I exit the function, eventhough the variable is declared outside the function.
The essential code:
var posts = {};
// Perform a data request
// skjutsgruppens-page
$.oajax({
url: "https://graph.facebook.com/197214710347172/feed?limit=500",
*SNIP*
success: function(data) {
$.extend(posts, data);
}
});
// Gruppen
$.oajax({
url: "https://graph.facebook.com/2388163605/feed?limit=500",
*snip*
success: function(data) {
$.extend(posts, data);
}
});
The oajax retrievies data from facebook. I want to make a variable that contains the data from both oajax methods.
The actual code: http://eco.nolgren.se/demo/resihop/#
The issue is likely that the success function executes at an arbitrary time in the future--unless you specifically access posts after you know the success function has executed, you will receive undefined results, completely dependent on function and access timing.
The best approach is to handle this correctly by doing necessary work inside in the success function, or use something like jQuery's .when function.
I hope this is not too much of a newbe question but I've been pulling my hair out for a while now so thought I'd give in and ask for my first piece of advice on here.
I'm trying to read an external xml file using javascript / jQuery / ajax and place the retrieved data into an array so that I can then reference it later.
So far I seem to be doing everything right upto the point I put the data into the array but then I'm struggling to to read the data anywhere other than inside the function where I create it. Why am I not able to access the Array from anywhere other than in that function?
Here is my code...
Please help!!
$.ajax({
type: "GET",
url: "data.xml",
dataType: "xml",
success: do_xmlParser
});
function do_xmlParser(xml)
{
var myArray = new Array();
$(xml).find("tag").each(function ()
{
myArray.push($(this).find("innerTag").text());
});
console.log("inside "+myArray); // This outputs the array I am expecting
return myArray; // is this right???
}
console.log("outside: "+myArray); // This does NOT output the array but instead I get "myArray is not defined"
You're defining do_xmlParser as a callback to an asynchronous function (success of the jquery ajax call). Anything you want to happen after the ajax call succeeds has to occur within that callback function, or you have to chain functions from the success callback.
The way you have it now, the actual execution of code will go:
ajax -> file being requested -> console.log ->
file transfer done -> success handler
If you're doing some critical stuff and you want the call be to synchronous, you can supply the
async : false
setting to the ajax call. Then, you should be able to do something like this:
var myArray = [],
do_xmlParser = function (xml)
{
$(xml).find("tag").each(function ()
{
myArray.push($(this).find("innerTag").text());
});
};
$.ajax({
type: "GET",
url: "data.xml",
dataType: "xml",
success: do_xmlParser,
async: false
});
console.log("outside: " + myArray);
The async option doesn't work for cross-domain requests, though.
NOTE
I don't recommend doing this. AJAX calls are supposed to be asynchronous, and I always use the success callback to perform all of the processing on the returned data.
Edit:
Also, if you're into reading... I'd recommend jQuery Pocket Reference and JavaScript: The Definitive Guide (both by David Flanagan).
look close and you will see. You are actually firing up an array that dosen't exist. You have declared myArray inside function. Try do something like this.
console.lod("outside :"+do_xmlParser(xml)); // I think that when you merge a string and an array it will output only string, but I can be wrong.