I want to split string http://some.com/\,brabra,400,500 into ['http://some.com/\,brabra', 400, 500]
I already tried this, but error because lookbehind is not support in js.
'http://some.com/\,brabra,400,500'.split(/(?<!\\),/g)
Any other ideas to do this?
You may use matching approach with (?:[^,\\]+|\\.)+:
match(/(?:[^,\\]+|\\.)+/g)
See the regex demo
Details: the (?:[^,\\]+|\\.)+ matches 1 or more occurrences ((?:...)+) of a 1+ characters other than , and \ (with [^,\\]+) or (|) any escaped sequence (\\.)
var s = "http://some.com/\\,brabra,400,500"
console.log(s.match(/(?:[^,\\]+|\\.)+/g));
Or a workaround if the comma to be split with is always followed with a digit:
split(/,(?=\d)/)
See this regex demo
var s = "http://some.com/\\,brabra,400,500"
console.log(s.split(/,(?=\d)/));
A classic, if slightly inelegant approach for such problems is to replace some characters with a magic token, then put them back later:
str
.replace("\\,", "DONT_SPLIT_HERE")
.split(',')
.map(part => part.replace("DONT_SPLIT_HERE", "\\,")
you can use simulate positive lookaheads with reversing the string:
String.prototype.reverse = function() {
return this.split("").reverse().join("");
}
Array.prototype.reverseElements = function() {
var ar = [];
for (var i = 0; i < this.length; i++) {
if (typeof this[i] === 'string')
ar[i] = this[i].reverse();
else {
//Do something if not a String
}
}
return ar;
}
var str = "http://some.com/\,brabra,400,500";
var ar = str.reverse().split(/,(?!\\)/).reverse().reverseElements();
console.log(ar);
Note: The Regex works here, but not in the snippet.
Related
I want to remove all special characters except space from a string using JavaScript.
For example,
abc's test#s
should output as
abcs tests.
You should use the string replace function, with a single regex.
Assuming by special characters, you mean anything that's not letter, here is a solution:
const str = "abc's test#s";
console.log(str.replace(/[^a-zA-Z ]/g, ""));
You can do it specifying the characters you want to remove:
string = string.replace(/[&\/\\#,+()$~%.'":*?<>{}]/g, '');
Alternatively, to change all characters except numbers and letters, try:
string = string.replace(/[^a-zA-Z0-9]/g, '');
The first solution does not work for any UTF-8 alphabet. (It will cut text such as Привіт). I have managed to create a function which does not use RegExp and use good UTF-8 support in the JavaScript engine. The idea is simple if a symbol is equal in uppercase and lowercase it is a special character. The only exception is made for whitespace.
function removeSpecials(str) {
var lower = str.toLowerCase();
var upper = str.toUpperCase();
var res = "";
for(var i=0; i<lower.length; ++i) {
if(lower[i] != upper[i] || lower[i].trim() === '')
res += str[i];
}
return res;
}
Update: Please note, that this solution works only for languages where there are small and capital letters. In languages like Chinese, this won't work.
Update 2: I came to the original solution when I was working on a fuzzy search. If you also trying to remove special characters to implement search functionality, there is a better approach. Use any transliteration library which will produce you string only from Latin characters and then the simple Regexp will do all magic of removing special characters. (This will work for Chinese also and you also will receive side benefits by making Tromsø == Tromso).
search all not (word characters || space):
str.replace(/[^\w ]/, '')
I don't know JavaScript, but isn't it possible using regex?
Something like [^\w\d\s] will match anything but digits, characters and whitespaces. It would be just a question to find the syntax in JavaScript.
I tried Seagul's very creative solution, but found it treated numbers also as special characters, which did not suit my needs. So here is my (failsafe) tweak of Seagul's solution...
//return true if char is a number
function isNumber (text) {
if(text) {
var reg = new RegExp('[0-9]+$');
return reg.test(text);
}
return false;
}
function removeSpecial (text) {
if(text) {
var lower = text.toLowerCase();
var upper = text.toUpperCase();
var result = "";
for(var i=0; i<lower.length; ++i) {
if(isNumber(text[i]) || (lower[i] != upper[i]) || (lower[i].trim() === '')) {
result += text[i];
}
}
return result;
}
return '';
}
const str = "abc's#thy#^g&test#s";
console.log(str.replace(/[^a-zA-Z ]/g, ""));
Try to use this one
var result= stringToReplace.replace(/[^\w\s]/g, '')
[^] is for negation, \w for [a-zA-Z0-9_] word characters and \s for space,
/[]/g for global
With regular expression
let string = "!#This tool removes $special *characters* /other/ than! digits, characters and spaces!!!$";
var NewString= string.replace(/[^\w\s]/gi, '');
console.log(NewString);
Result //This tool removes special characters other than digits characters and spaces
Live Example : https://helpseotools.com/text-tools/remove-special-characters
dot (.) may not be considered special. I have added an OR condition to Mozfet's & Seagull's answer:
function isNumber (text) {
reg = new RegExp('[0-9]+$');
if(text) {
return reg.test(text);
}
return false;
}
function removeSpecial (text) {
if(text) {
var lower = text.toLowerCase();
var upper = text.toUpperCase();
var result = "";
for(var i=0; i<lower.length; ++i) {
if(isNumber(text[i]) || (lower[i] != upper[i]) || (lower[i].trim() === '') || (lower[i].trim() === '.')) {
result += text[i];
}
}
return result;
}
return '';
}
Try this:
const strippedString = htmlString.replace(/(<([^>]+)>)/gi, "");
console.log(strippedString);
const input = `#if_1 $(PR_CONTRACT_END_DATE) == '23-09-2019' #
Test27919<alerts#imimobile.com> #elseif_1 $(PR_CONTRACT_START_DATE) == '20-09-2019' #
Sender539<rama.sns#gmail.com> #elseif_1 $(PR_ACCOUNT_ID) == '1234' #
AdestraSID<hello#imimobile.co> #else_1#Test27919<alerts#imimobile.com>#endif_1#`;
const replaceString = input.split('$(').join('->').split(')').join('<-');
console.log(replaceString.match(/(?<=->).*?(?=<-)/g));
Whose special characters you want to remove from a string, prepare a list of them and then user javascript replace function to remove all special characters.
var str = 'abc'de#;:sfjkewr47239847duifyh';
alert(str.replace("'","").replace("#","").replace(";","").replace(":",""));
or you can run loop for a whole string and compare single single character with the ASCII code and regenerate a new string.
I want to remove all special characters except space from a string using JavaScript.
For example,
abc's test#s
should output as
abcs tests.
You should use the string replace function, with a single regex.
Assuming by special characters, you mean anything that's not letter, here is a solution:
const str = "abc's test#s";
console.log(str.replace(/[^a-zA-Z ]/g, ""));
You can do it specifying the characters you want to remove:
string = string.replace(/[&\/\\#,+()$~%.'":*?<>{}]/g, '');
Alternatively, to change all characters except numbers and letters, try:
string = string.replace(/[^a-zA-Z0-9]/g, '');
The first solution does not work for any UTF-8 alphabet. (It will cut text such as Привіт). I have managed to create a function which does not use RegExp and use good UTF-8 support in the JavaScript engine. The idea is simple if a symbol is equal in uppercase and lowercase it is a special character. The only exception is made for whitespace.
function removeSpecials(str) {
var lower = str.toLowerCase();
var upper = str.toUpperCase();
var res = "";
for(var i=0; i<lower.length; ++i) {
if(lower[i] != upper[i] || lower[i].trim() === '')
res += str[i];
}
return res;
}
Update: Please note, that this solution works only for languages where there are small and capital letters. In languages like Chinese, this won't work.
Update 2: I came to the original solution when I was working on a fuzzy search. If you also trying to remove special characters to implement search functionality, there is a better approach. Use any transliteration library which will produce you string only from Latin characters and then the simple Regexp will do all magic of removing special characters. (This will work for Chinese also and you also will receive side benefits by making Tromsø == Tromso).
search all not (word characters || space):
str.replace(/[^\w ]/, '')
I don't know JavaScript, but isn't it possible using regex?
Something like [^\w\d\s] will match anything but digits, characters and whitespaces. It would be just a question to find the syntax in JavaScript.
I tried Seagul's very creative solution, but found it treated numbers also as special characters, which did not suit my needs. So here is my (failsafe) tweak of Seagul's solution...
//return true if char is a number
function isNumber (text) {
if(text) {
var reg = new RegExp('[0-9]+$');
return reg.test(text);
}
return false;
}
function removeSpecial (text) {
if(text) {
var lower = text.toLowerCase();
var upper = text.toUpperCase();
var result = "";
for(var i=0; i<lower.length; ++i) {
if(isNumber(text[i]) || (lower[i] != upper[i]) || (lower[i].trim() === '')) {
result += text[i];
}
}
return result;
}
return '';
}
const str = "abc's#thy#^g&test#s";
console.log(str.replace(/[^a-zA-Z ]/g, ""));
Try to use this one
var result= stringToReplace.replace(/[^\w\s]/g, '')
[^] is for negation, \w for [a-zA-Z0-9_] word characters and \s for space,
/[]/g for global
With regular expression
let string = "!#This tool removes $special *characters* /other/ than! digits, characters and spaces!!!$";
var NewString= string.replace(/[^\w\s]/gi, '');
console.log(NewString);
Result //This tool removes special characters other than digits characters and spaces
Live Example : https://helpseotools.com/text-tools/remove-special-characters
dot (.) may not be considered special. I have added an OR condition to Mozfet's & Seagull's answer:
function isNumber (text) {
reg = new RegExp('[0-9]+$');
if(text) {
return reg.test(text);
}
return false;
}
function removeSpecial (text) {
if(text) {
var lower = text.toLowerCase();
var upper = text.toUpperCase();
var result = "";
for(var i=0; i<lower.length; ++i) {
if(isNumber(text[i]) || (lower[i] != upper[i]) || (lower[i].trim() === '') || (lower[i].trim() === '.')) {
result += text[i];
}
}
return result;
}
return '';
}
Try this:
const strippedString = htmlString.replace(/(<([^>]+)>)/gi, "");
console.log(strippedString);
const input = `#if_1 $(PR_CONTRACT_END_DATE) == '23-09-2019' #
Test27919<alerts#imimobile.com> #elseif_1 $(PR_CONTRACT_START_DATE) == '20-09-2019' #
Sender539<rama.sns#gmail.com> #elseif_1 $(PR_ACCOUNT_ID) == '1234' #
AdestraSID<hello#imimobile.co> #else_1#Test27919<alerts#imimobile.com>#endif_1#`;
const replaceString = input.split('$(').join('->').split(')').join('<-');
console.log(replaceString.match(/(?<=->).*?(?=<-)/g));
Whose special characters you want to remove from a string, prepare a list of them and then user javascript replace function to remove all special characters.
var str = 'abc'de#;:sfjkewr47239847duifyh';
alert(str.replace("'","").replace("#","").replace(";","").replace(":",""));
or you can run loop for a whole string and compare single single character with the ASCII code and regenerate a new string.
My string contains some of the special characters that needs to be escaped with (\) double backslash before the string. My piece of code below:
var data = "abckdef)ghijkl)-8-mno-3-(pqrstuvw-1-xyz)-5-thiaa-1-aza-";
var iChars = "!##$%^&*()+=-[]\\\';,./{}|\":<>?~_";
for (var i = 0; i < data.length; i++) {
if (iChars.indexOf(data.charAt(i)) != -1) {
console.log("Your string has special characters. \nThese are not allowed.");
return false;
}
}
Expected Result would be:
abckdef\)ghijkl\)\-8\-mno\-3\-\(pqrstuvw\-1\-xyz\)\-5\-thiaa\-1\-aza\-
Above code finds the special characters in my string, but I wanted to add (\\) before every occurrences of the special characters. Any help on this?
Use a regex replacement:
Match:
/[!##$%^&*()+=\-[\]\\';,./{}|":<>?~_]/
Replace to:
\$&
>>> data.replace(/[!##$%^&*()+=\-[\]\\';,./{}|":<>?~_]/g, "\\$&")
... "abckdef\)ghijkl\)\-8\-mno\-3\-\(pqrstuvw\-1\-xyz\)\-5\-thiaa\-1\-aza\-"
Regex:
([!##$%^&*()+=\[\]\\';,./{}|":<>?~_-])
Replacement string:
\$1
DEMO
> var data = "abckdef)ghijkl)-8-mno-3-(pqrstuvw-1-xyz)-5-thiaa-1-aza-";
undefined
> var result = data.replace(/([!##$%^&*()+=\[\]\\';,./{}|":<>?~_-])/g, "\\$1");
undefined
> console.log(result);
abckdef\)ghijkl\)\-8\-mno\-3\-\(pqrstuvw\-1\-xyz\)\-5\-thiaa\-1\-aza\-
Try this plug and play function.
var data = "abckdef)ghijkl)-8-mno-3-(pqrstuvw-1-xyz)-5-thiaa-1-aza-";
function escapeSpecialCaseChar(text) {
return text.replace(/[-[\]{}()*+?.,\\^$|#\s]/g, '\\$&');
}
console.log(escapeSpecialCaseChar(data));
Do you want to escape anything other than alphanumeric character then make it simple
Find what :([^a-zA-Z0-9])
Replacement: \\$1
regex101 demo
Sample code:
var re = /([^a-zA-Z0-9])/g;
var str = 'abckdef)ghijkl)-8-mno-3-(pqrstuvw-1-xyz)-5-thiaa-1-aza-';
var subst = '\\$1';
var result = str.replace(re, subst);
output: (same as expected)
abckdef\)ghijkl\)\-8\-mno\-3\-\(pqrstuvw\-1\-xyz\)\-5\-thiaa\-1\-aza\-
I have found a way to remove repeated characters from a string using regular expressions.
function RemoveDuplicates() {
var str = "aaabbbccc";
var filtered = str.replace(/[^\w\s]|(.)\1/gi, "");
alert(filtered);
}
Output: abc
this is working fine.
But if str = "aaabbbccccabbbbcccccc" then output is abcabc.
Is there any way to get only unique characters or remove all duplicates one?
Please let me know if there is any way.
A lookahead like "this, followed by something and this":
var str = "aaabbbccccabbbbcccccc";
console.log(str.replace(/(.)(?=.*\1)/g, "")); // "abc"
Note that this preserves the last occurrence of each character:
var str = "aabbccxccbbaa";
console.log(str.replace(/(.)(?=.*\1)/g, "")); // "xcba"
Without regexes, preserving order:
var str = "aabbccxccbbaa";
console.log(str.split("").filter(function(x, n, s) {
return s.indexOf(x) == n
}).join("")); // "abcx"
This is an old question, but in ES6 we can use Sets. The code looks like this:
var test = 'aaabbbcccaabbbcccaaaaaaaasa';
var result = Array.from(new Set(test)).join('');
console.log(result);
var RegTxt = "$f1$='test' AND f2='test2'";
alert(RegTxt.match(/\'[^\']*'/g))
returns the match correctely i:e 'test','test2' but how can i remove the single quote in the match.
This would be quite simple if JavaScript supported negative lookbehinds:
/(?<=').*?(?=')/
But unfortunately, it doesn't.
In cases like these I like to abuse String.prototype.replace:
// btw, RegTxt should start with a lowercase 'r', as per convention
var match = [];
regTxt.replace(/'([^']*)'/g, function($0, $1){
match.push($1);
});
match; // => ['test', 'test2']
Here is a crude solution to your problem.
var match = RegTxt.match(/\'[^\']*'/g)
match = match.substring(1, match.length - 2);
Trivial approach:
RegTxt.replace(/'/g, "")
using your regex:
RegTxt.replace(/\'([^\']*)'/g, "$1")
var matches = str.match(regex);
var newMatches = [];
for( i in matches )
{
var word = matches[i];
newMatches.push( word.substring(1,word.length-1))
}
newMatches will now contain the array you need.