Develop Reference

Inserting into Mysql form php with Ajax without reload page

I have this jQuery AJAX code that into Mysql form php. It works without reloading the page. The problem is that it When the user enters something into the form, then clicks submit, I would like to use php and ajax (with jquery). But it do not print the string in alert() . Can someone please show me how this can be achieved?
HTML :
<form id="students" method="post">
<div class="row">
<input name="a[]" value="" type="text" >
<input name="b[]" value="" type="text" >
</div>
<div class="row">
<input name="a[]" value="" type="text" >
<input name="b[]" value="" type="text" >
</div>
<input type="submit" value="submit" id="submitbutton" class="insert"/>
</form>
<script type="text/javascript">
$('#students').submit(function(){
event.preventDefault();
$.ajax({
type: 'POST',
url: 'ajax_insert.php',
data: $('#students').serialize(),
dataType: 'JSON',
success: function(data) {
alert('form has been posted successfully');
}
});
});
</script>
and ajax_insert.php :
$a1=$_POST['a'];
$b1=$_POST['b'];
//$query_values = array();
$index=0;
foreach($a1 as $s){
$sql = "INSERT INTO test_data(a,b) VALUES('$s','".$b1[$index]."')";
$result = mysql_query($sql);
if($result)
{
echo "1";
}
$index++;
}

$('#students').submit(function(event){
event.preventDefault();
$.ajax({
type: 'POST',
url: 'ajax_insert.php',
data: $('#students').serialize(),
dataType: 'JSON',
success: function(data) {
alert('form has been posted successfully');
}
});
check official document here and learn how to use event.preventDefault();

You probably have to event.preventDefault(); in the submit event callback :
$('#students').submit(function(){
event.preventDefault();
$.ajax({
type: 'POST',
url: 'ajax_insert.php',
data: $('#students').serialize(),
dataType: 'JSON',
success: function(data) {
alert('form has been posted successfully');
}
});
});

You need return valid json when use dataType: "json" in $.ajax call
Or you can use dataType: "html" without rewriting php code
Update (examples of code, that should work):
in HTML:
<script type="text/javascript">
$('#students').submit(function(e){
e.preventDefault();
$.ajax({
type: 'POST',
url: 'ajax_insert.php',
data: $('#students').serialize(),
dataType: 'JSON',
success: function(data) {
if(data.result == 1) {
alert('form has been posted successfully');
} else {
alert(data.error);
}
}
});
});
</script>
ajax_insert.php
$a1=$_POST['a'];
$b1=$_POST['b'];
//$query_values = array();
$index=0;
$errors = array();
foreach($a1 as $s){
$sql = "INSERT INTO test_data(a,b) VALUES('$s','".$b1[$index]."')";
$result = mysql_query($sql);
if(!$result)
{
$errors[] = "\"$sql\"";
}
$index++;
}
if(!empty($errors)) {
echo json_encode(array('result'=>0,'error'=>"Error executing following queries: \n".implode("\n", $errors)));
} else {
echo json_encode(array('result'=>1));
}

How to echo value input type text when use ajax upload?

How to echo value input type text when use ajax upload ?
This is my code for upload file to dir attachments_files and it's work good.
But i have some issue. I want to know how to echo value from id="username_uploader" in upload.php using php ?
i tried to use like this
echo $_POST['username_uploader'];
but not work. Please help me .
index.php
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<input id="username_uploader" type="text" name="username_uploader" value="test_user"/>
<input id="attachment_file_input_id" type="file" name="sortpic" onchange="test_fn()"/>
<div id="demoajax"></div>
<script>
function test_fn () {
var file_data = $('#attachment_file_input_id').prop('files')[0];
var form_data = new FormData();
form_data.append('file', file_data);
$.ajax({
url: 'upload.php',
dataType: 'text',
cache: false,
contentType: false,
processData: false,
data: form_data,
type: 'post',
success: function(php_script_response){
alert("upload success");
$('#demoajax').append(php_script_response);
}
});
};
</script>
upload.php
<?php
if ( 0 < $_FILES['file']['error'] ) {
echo 'Error: ' . $_FILES['file']['error'] . '<br>';
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"], "attachments_files/" .$_FILES["file"]["name"]);
echo $_POST['username_uploader'];
}
?>

You need to include the username_uploader value in the FormData you send, as you currently omit it. Try this:
var form_data = new FormData();
form_data.append('file', file_data);
form_data.append('username_uploader', $('#username_uploader').val());
It would also be better practice for your PHP code to return JSON, that way you don't need to worry about the formatting or whitespace in the returned value. Here's a complete example:
function test_fn () {
var form_data = new FormData();
form_data.append('file', $('#attachment_file_input_id').prop('files')[0]);
form_data.append('username_uploader', $('#username_uploader').val());
$.ajax({
url: 'upload.php',
type: 'POST',
dataType: 'json',
cache: false,
processData: false,
data: form_data,
success: function(response){
alert("upload success");
$('#demoajax').append(response.uploader);
}
});
};
<?php
if (0 < $_FILES['file']['error']) {
echo json_encode(array('error' => 'Error: ' . $_FILES['file']['error'] . '<br>'));
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"], "attachments_files/" .$_FILES["file"]["name"]);
echo json_encode(array('uploader' => $_POST['username_uploader']));
}
?>

why ajax post method return empty alert box when i tried to return data from controller file in codeigniter

This is my ajax function
$(function(){
$("#myform").submit(function(){ //i want to get data from my form after submittingit
dataString = $("#myform").serialize();
alert(dataString);
$.ajax({
type: "POST",
url: "<?php echo base_url(); ?>index.php/customer/viewCustomerData",
data: dataString,
success: function(data){
alert(data);
}
});
return false;
});
});
this is my controller class function
function viewCustomerData(){
if($_POST){
$name = $_POST['name'];
return 'name';
}
else {
return false;
}
}
other thing is i tried to alert data string taken from form serialize, but it also empty. I want to return data set from database after sending key word from javascript file. i tried if the javascript file connect correctly with my controller function. so i tried to return some value and display it using alert box. but it gives empty result.

This is better way to submit a form with ajax
$(document).on("submit", "#myform", function(event)
{
event.preventDefault();
$.ajax({
url: "<?php echo base_url(); ?>index.php/customer/viewCustomerData"
type: "POST",
data: new FormData(this),
processData: false,
contentType: false,
success: function (data, status)
{
alert(data);
},
error: function (xhr, desc, err)
{
}
});
});

try this
$(function(){
$("#myform").submit(function(){
dataString = $("#myform").serialize();
alert(dataString);
$.ajax({
type: "POST",
url: "<?php echo base_url(); ?>index.php/customer/viewCustomerData",
data: dataString,
cache: false,
datatype: 'json',
success: function(data){
alert(data.result);
}
});
});
});
in controller
function viewCustomerData(){
if($this->input->post('name'){
$result = $this->input->post('name');
} else {
$result = false;
}
header('Content-Type: application/json');
echo json_encode(array('result' => $result));
}

you cant alert $("#myform").serialize(); because this is an object instead of alert it try console.log($("#myform").serialize();)
then open browser console and see what is printed
$.ajax({
type: "POST",
url: "<?php echo base_url(); ?>index.php/customer/viewCustomerData",
data: dataString,
})
.done(function( data ) {
if ( console && console.log ) {
console.log( "Sample of data:", data);
}
});

javascript button ajax and php

I have a small question, which I guess in my opinion will sound stupid. I have actually this code
<script type="text/javascript">
$(document).ready(function(){
var email_value = prompt('Please enter your email address');
if(email_value !== null){
//post the field with ajax
$.ajax({
url: '="/new/cfolder.php',
type: 'POST',
dataType: 'text',
data: {data : email_value},
success: function(response){
//do anything with the response
console.log(response);
}
});
}
});
</script>
I would like to link it to my button which does this
<form action="/new/cfolder.php" method="post">
</font><input type="submit" value="Create Vdisk" class="myButton6" onClick="function()">
<br></form>
Is it actually possible to do this? thank you for any answer.

<script type="text/javascript">
$(document).ready(function(){
$(document).on('click', '.myButton6', function(){
var email_value = prompt('Please enter your email address');
//post the field with ajax
if(email_value.length > 0){
$.ajax({
url: '/new/cfolder.php',
type: 'POST',
dataType: 'text',
data: {data : email_value},
success: function(response){
alert(response);
}
});
}
)};
});
</script>
try that way

// this is the id of the form
$("#idForm").submit(function() {
var url = "path/to/your/script.php"; // the script where you handle the form input.
$.ajax({
type: "POST",
url: '="/new/cfolder.php',
data: $("#idForm").serialize(), // serializes the form's elements.
success: function(data)
{
alert(data); // show response from the php script.
}
});
return false; // avoid to execute the actual submit of the form.
});
give your form an id
<form id="idForm" action="/Same/path/as/your/ajax/" method="post">
</font><input type="submit" value="Create Vdisk" class="myButton6" onClick="function()">
<br></form>

Yes of course you can do this . Like this code and you will have to include jquery1.9.0.js or above.
<script type="text/javascript">
$(document).ready(function(){
$("#myButton6").click(fuction(){
var email_value = prompt('Please enter your email address');
if(email_value !== null){
//post the field with ajax
$.ajax({
url: '/new/cfolder.php',
type: 'POST',
dataType: 'text',
data: {data : email_value},
success: function(response){
//do anything with the response
console.log(response);
}
});
}
});
});
</script>
I would like to link it to my button which does this
</font><input type="submit" value="Create Vdisk" class="myButton6" id="myButton6">
<br>

jquery ajax post email field

I'm not sure why I'm not able to post the content of email field,
here is my code.
<html>
<head>
<title></title>
<script src="//code.jquery.com/jquery-1.11.2.min.js"></script>
</head>
<body>
<input type="text" id="email" name="email">
<input type="button" id="submit" name="submit" value="submit">
</body>
<script type="text/javascript">
$(document).ready(function () {
$('#submit').click(function (event) {
var email = $('#email').val();
console.log(email),
$.ajax({
url: 'db.php',
type: 'POST',
data: 'email=' + 'email',
success: function (data) {
console.log(data);
}
})
});
});
</script>
</html>
backend file "db.php"
<?php
$email = $_POST['email'];
echo "$email";
I'm able to console.log email, and displays correctly, before it gets submitted to db.php.
console log returns "email" only.
Not sure whats wrong, your help is highly appreciated.
Thanks

You are sending string "email", while you want to send a variable value:
$.ajax({
url: 'db.php',
type: 'POST',
data: 'email=' + email, // or data: {email: email}
success: function (data) {
console.log(data);
}
});

Use this it will help
<script type="text/javascript">
$(document).ready(function () {
$('#submit').click(function (event) {
var email = $('#email').val();
console.log(email),
$.ajax({
url: 'db.php',
type: 'POST',
data: {email: email},
success: function (data) {
console.log(data);
}
})
});
});
</script>