I've been trying hours to figure this out without any luck. Would be grateful if someone could point me to the right direction.
The problem is that the RegExp Object is totally ignoring the \b and \s Metacharacters.
var orOperator = 'or';
var term = 'ipsum';
var str = 'lorem or ipsum or ipsumal';
var regex = new RegExp('(\\s)\\b' + orOperator + '\\s' + term + '\\b', 'gi');
console.log(regex);
str = str.replace(regex, '');
While the resulting regex should be
/(\s)\bor\sipsum\b/gi
I keep getting this one instead (with Metacharacters stripped) and I don't know why
/(s)orsipsum/gi
You can also use String.raw tag function (more on MDN) — it'll ignore (not process) any escape sequences aka metacharacters and allow substitutions:
var orOperator = 'or';
var term = 'ipsum';
var str = 'lorem or ipsum or ipsumal';
var regexStr = String.raw`(\s)\b${orOperator}\s${term}\b`;
var regexFlags = 'gi';
var regex = new RegExp(regexStr, regexFlags);
console.log(regex);
str = str.replace(regex, '');
and result is
/(\s)\bor\sipsum\b/gi
'lorem or ipsumal'
As #YizhengShen and #CasimiretHippolyte suggested in the comments, 4 backslashes for each Metacharacter did the trick.
var regex = new RegExp('(\\\\s)\\\\b' + orOperator + '\\\\s' + term + '\\\\b', 'gi');
Related
var str = "Demo Docs Version 1.0.1";
var got = str.split(" ").splice(-1)[0]
str = str.replace(got, "testing");
console.log(str);
I can replace last word if there is space in between but how can i replace my last word when there _ in string ?
var str = "Demo-Docs-Version-1-0-1";
var got = str.split(" ").splice(-1)[0]
str = str.replace(got, "testing");
console.log(str);
What about this?
str = str.replace(/(?!.*(\s|_)).*/, "testing")
I want to add a closing bracket to the math expression within the string
var str = "solve this now Math.sqrt(345+6 is good but Math.sin(79 is better.";
var patt1 = /\((d+)/g;
var result = str.match(patt1);
document.getElementById("demo").innerHTML = result;
The match patter displays (345 and (79. Without changing the content, how can I add a closing bracket so the string look like;
var str = " solve this now Math.sqrt(345)+6 is good but Math.sin(79) is better.
Use negative lookahead assertion.
var str = "solve this now Math.sqrt(345+6 is good but Math.sin(79 is better.";
console.log(str.replace(/(\(\d+)\b(?!\))/g, "$1)"))
(\(\d+) capture \( and one or more digits
(?!\)) only if the match wasn't followed by closing brace )
Check if the an opening brace if followed by numbers, but not by its closing brace after numbers
var str = "solve this now Math.sqrt(345+6 is good but Math.sin(79 is better.";
var output = str.replace( /\([\d]+(?!=\))/g, r => r + ")");
Output
solve this now Math.sqrt(345)+6 is good but Math.sin(79) is better.
Demo
var str = "solve this now Math.sqrt(345+6 is good but Math.sin(79 is better.";
var output = str.replace(/\([\d]+(?!=\))/g, r => r + ")");
console.log(output);
You can include . to allow decimals as well
var str = "solve this now Math.sqrt(345.5+6 is good but Math.sin(79.33 is better (232.";
var output = str.replace( /\(\d+(\.(\d)+)?(?!=\))/g, r => r + ")");
Output
solve this now Math.sqrt(345.5)+6 is good but Math.sin(79.33) is better (232).
Demo
var str = "solve this now Math.sqrt(345.5+6 is good but Math.sin(79.33 is better (232.";
var output = str.replace( /\(\d+(\.(\d)+)?(?!=\))/g, r => r + ")");
console.log(output);
I am using a regular Expression for a glosary function on a website, but it can not "handle" special charters as æ, ø and å. The regEx is as follows:
var re = new RegExp("\\b" + pat + "\\b", "g");
How can i modify the RegEx above to handle special charters?
You may use the solution from here:
function getWholeWords(input, word) {
var pL = "a-zA-Z\\xAA\\xB5\\xBA\\xC0-\\xD6\\xD8-\\xF6\\xF8-\\u02C1\\u02C6-\\u02D1\\u02E0-\\u02E4\\u02EC\\u02EE\\u0370-\\u0374\\u0376\\u0377\\u037A-\\u037D\\u037F\\u0386\\u0388-\\u038A\\u038C\\u038E-\\u03A1\\u03A3-\\u03F5\\u03F7-\\u0481\\u048A-\\u052F\\u0531-\\u0556\\u0559\\u0561-\\u0587\\u05D0-\\u05EA\\u05F0-\\u05F2\\u0620-\\u064A\\u066E\\u066F\\u0671-\\u06D3\\u06D5\\u06E5\\u06E6\\u06EE\\u06EF\\u06FA-\\u06FC\\u06FF\\u0710\\u0712-\\u072F\\u074D-\\u07A5\\u07B1\\u07CA-\\u07EA\\u07F4\\u07F5\\u07FA\\u0800-\\u0815\\u081A\\u0824\\u0828\\u0840-\\u0858\\u08A0-\\u08B2\\u0904-\\u0939\\u093D\\u0950\\u0958-\\u0961\\u0971-\\u0980\\u0985-\\u098C\\u098F\\u0990\\u0993-\\u09A8\\u09AA-\\u09B0\\u09B2\\u09B6-\\u09B9\\u09BD\\u09CE\\u09DC\\u09DD\\u09DF-\\u09E1\\u09F0\\u09F1\\u0A05-\\u0A0A\\u0A0F\\u0A10\\u0A13-\\u0A28\\u0A2A-\\u0A30\\u0A32\\u0A33\\u0A35\\u0A36\\u0A38\\u0A39\\u0A59-\\u0A5C\\u0A5E\\u0A72-\\u0A74\\u0A85-\\u0A8D\\u0A8F-\\u0A91\\u0A93-\\u0AA8\\u0AAA-\\u0AB0\\u0AB2\\u0AB3\\u0AB5-\\u0AB9\\u0ABD\\u0AD0\\u0AE0\\u0AE1\\u0B05-\\u0B0C\\u0B0F\\u0B10\\u0B13-\\u0B28\\u0B2A-\\u0B30\\u0B32\\u0B33\\u0B35-\\u0B39\\u0B3D\\u0B5C\\u0B5D\\u0B5F-\\u0B61\\u0B71\\u0B83\\u0B85-\\u0B8A\\u0B8E-\\u0B90\\u0B92-\\u0B95\\u0B99\\u0B9A\\u0B9C\\u0B9E\\u0B9F\\u0BA3\\u0BA4\\u0BA8-\\u0BAA\\u0BAE-\\u0BB9\\u0BD0\\u0C05-\\u0C0C\\u0C0E-\\u0C10\\u0C12-\\u0C28\\u0C2A-\\u0C39\\u0C3D\\u0C58\\u0C59\\u0C60\\u0C61\\u0C85-\\u0C8C\\u0C8E-\\u0C90\\u0C92-\\u0CA8\\u0CAA-\\u0CB3\\u0CB5-\\u0CB9\\u0CBD\\u0CDE\\u0CE0\\u0CE1\\u0CF1\\u0CF2\\u0D05-\\u0D0C\\u0D0E-\\u0D10\\u0D12-\\u0D3A\\u0D3D\\u0D4E\\u0D60\\u0D61\\u0D7A-\\u0D7F\\u0D85-\\u0D96\\u0D9A-\\u0DB1\\u0DB3-\\u0DBB\\u0DBD\\u0DC0-\\u0DC6\\u0E01-\\u0E30\\u0E32\\u0E33\\u0E40-\\u0E46\\u0E81\\u0E82\\u0E84\\u0E87\\u0E88\\u0E8A\\u0E8D\\u0E94-\\u0E97\\u0E99-\\u0E9F\\u0EA1-\\u0EA3\\u0EA5\\u0EA7\\u0EAA\\u0EAB\\u0EAD-\\u0EB0\\u0EB2\\u0EB3\\u0EBD\\u0EC0-\\u0EC4\\u0EC6\\u0EDC-\\u0EDF\\u0F00\\u0F40-\\u0F47\\u0F49-\\u0F6C\\u0F88-\\u0F8C\\u1000-\\u102A\\u103F\\u1050-\\u1055\\u105A-\\u105D\\u1061\\u1065\\u1066\\u106E-\\u1070\\u1075-\\u1081\\u108E\\u10A0-\\u10C5\\u10C7\\u10CD\\u10D0-\\u10FA\\u10FC-\\u1248\\u124A-\\u124D\\u1250-\\u1256\\u1258\\u125A-\\u125D\\u1260-\\u1288\\u128A-\\u128D\\u1290-\\u12B0\\u12B2-\\u12B5\\u12B8-\\u12BE\\u12C0\\u12C2-\\u12C5\\u12C8-\\u12D6\\u12D8-\\u1310\\u1312-\\u1315\\u1318-\\u135A\\u1380-\\u138F\\u13A0-\\u13F4\\u1401-\\u166C\\u166F-\\u167F\\u1681-\\u169A\\u16A0-\\u16EA\\u16F1-\\u16F8\\u1700-\\u170C\\u170E-\\u1711\\u1720-\\u1731\\u1740-\\u1751\\u1760-\\u176C\\u176E-\\u1770\\u1780-\\u17B3\\u17D7\\u17DC\\u1820-\\u1877\\u1880-\\u18A8\\u18AA\\u18B0-\\u18F5\\u1900-\\u191E\\u1950-\\u196D\\u1970-\\u1974\\u1980-\\u19AB\\u19C1-\\u19C7\\u1A00-\\u1A16\\u1A20-\\u1A54\\u1AA7\\u1B05-\\u1B33\\u1B45-\\u1B4B\\u1B83-\\u1BA0\\u1BAE\\u1BAF\\u1BBA-\\u1BE5\\u1C00-\\u1C23\\u1C4D-\\u1C4F\\u1C5A-\\u1C7D\\u1CE9-\\u1CEC\\u1CEE-\\u1CF1\\u1CF5\\u1CF6\\u1D00-\\u1DBF\\u1E00-\\u1F15\\u1F18-\\u1F1D\\u1F20-\\u1F45\\u1F48-\\u1F4D\\u1F50-\\u1F57\\u1F59\\u1F5B\\u1F5D\\u1F5F-\\u1F7D\\u1F80-\\u1FB4\\u1FB6-\\u1FBC\\u1FBE\\u1FC2-\\u1FC4\\u1FC6-\\u1FCC\\u1FD0-\\u1FD3\\u1FD6-\\u1FDB\\u1FE0-\\u1FEC\\u1FF2-\\u1FF4\\u1FF6-\\u1FFC\\u2071\\u207F\\u2090-\\u209C\\u2102\\u2107\\u210A-\\u2113\\u2115\\u2119-\\u211D\\u2124\\u2126\\u2128\\u212A-\\u212D\\u212F-\\u2139\\u213C-\\u213F\\u2145-\\u2149\\u214E\\u2183\\u2184\\u2C00-\\u2C2E\\u2C30-\\u2C5E\\u2C60-\\u2CE4\\u2CEB-\\u2CEE\\u2CF2\\u2CF3\\u2D00-\\u2D25\\u2D27\\u2D2D\\u2D30-\\u2D67\\u2D6F\\u2D80-\\u2D96\\u2DA0-\\u2DA6\\u2DA8-\\u2DAE\\u2DB0-\\u2DB6\\u2DB8-\\u2DBE\\u2DC0-\\u2DC6\\u2DC8-\\u2DCE\\u2DD0-\\u2DD6\\u2DD8-\\u2DDE\\u2E2F\\u3005\\u3006\\u3031-\\u3035\\u303B\\u303C\\u3041-\\u3096\\u309D-\\u309F\\u30A1-\\u30FA\\u30FC-\\u30FF\\u3105-\\u312D\\u3131-\\u318E\\u31A0-\\u31BA\\u31F0-\\u31FF\\u3400-\\u4DB5\\u4E00-\\u9FCC\\uA000-\\uA48C\\uA4D0-\\uA4FD\\uA500-\\uA60C\\uA610-\\uA61F\\uA62A\\uA62B\\uA640-\\uA66E\\uA67F-\\uA69D\\uA6A0-\\uA6E5\\uA717-\\uA71F\\uA722-\\uA788\\uA78B-\\uA78E\\uA790-\\uA7AD\\uA7B0\\uA7B1\\uA7F7-\\uA801\\uA803-\\uA805\\uA807-\\uA80A\\uA80C-\\uA822\\uA840-\\uA873\\uA882-\\uA8B3\\uA8F2-\\uA8F7\\uA8FB\\uA90A-\\uA925\\uA930-\\uA946\\uA960-\\uA97C\\uA984-\\uA9B2\\uA9CF\\uA9E0-\\uA9E4\\uA9E6-\\uA9EF\\uA9FA-\\uA9FE\\uAA00-\\uAA28\\uAA40-\\uAA42\\uAA44-\\uAA4B\\uAA60-\\uAA76\\uAA7A\\uAA7E-\\uAAAF\\uAAB1\\uAAB5\\uAAB6\\uAAB9-\\uAABD\\uAAC0\\uAAC2\\uAADB-\\uAADD\\uAAE0-\\uAAEA\\uAAF2-\\uAAF4\\uAB01-\\uAB06\\uAB09-\\uAB0E\\uAB11-\\uAB16\\uAB20-\\uAB26\\uAB28-\\uAB2E\\uAB30-\\uAB5A\\uAB5C-\\uAB5F\\uAB64\\uAB65\\uABC0-\\uABE2\\uAC00-\\uD7A3\\uD7B0-\\uD7C6\\uD7CB-\\uD7FB\\uF900-\\uFA6D\\uFA70-\\uFAD9\\uFB00-\\uFB06\\uFB13-\\uFB17\\uFB1D\\uFB1F-\\uFB28\\uFB2A-\\uFB36\\uFB38-\\uFB3C\\uFB3E\\uFB40\\uFB41\\uFB43\\uFB44\\uFB46-\\uFBB1\\uFBD3-\\uFD3D\\uFD50-\\uFD8F\\uFD92-\\uFDC7\\uFDF0-\\uFDFB\\uFE70-\\uFE74\\uFE76-\\uFEFC\\uFF21-\\uFF3A\\uFF41-\\uFF5A\\uFF66-\\uFFBE\\uFFC2-\\uFFC7\\uFFCA-\\uFFCF\\uFFD2-\\uFFD7\\uFFDA-\\uFFDC";
var rx = RegExp("(?:^|[^_0-9" + pL + "])(" + word + ")(?![_0-9" + pL + "])", "ig"); // Build the regex (might be moved out from the function)
var words = [];
while ((m = rx.exec(input)) !== null) {
words.push(m[1]); // Add an occurrence
}
return words;
}
var word = "æøå";
var input = "æøå, AæøåZ, BæøåY, and æøå!";
document.body.innerHTML = "<pre>" + JSON.stringify(getWholeWords(input, word), 0, 4) + "</pre>";
Or a regex that will look for a word only if it is enclosed with whitespace/start/end of the string:
var re = new RegExp("(?:^|\\s)(" + pat.replace(/[-\/\\^$*+?.()|[\]{}]/g, '\\$&') + ")(?!\\S)", "g");
and grab Group 1 value.
I have the following bit of code :
var stringToMatch = "De$mond. \(blah)";
var pattern = "^" + stringToMatch;
var regex = new RegExp(pattern, "i");
return regex.test("testing De$mond.");
Now I need to escape stringToMatch before using it in pattern
A solution I found here suggest this method if I understand correctly :
var stringToMatch = "De$mond. \(blah)";
stringToMatch = stringToMatch.replace(/[\-\[\]\/\{\}\(\)\*\+\?\.\\\^\$\|]/g, "\\$&");
var pattern = "^" + stringToMatch;
var regex = new RegExp(pattern, "i");
return regex.test("testing De$mond.");
Why can't I simply escape all of the characters in stringToMatch instead?
e.g.
var stringToMatch = "De$mond. \(blah)";
var stringToMatchAsArrayOfChars = [];
for (var i = 0; i < stringToMatch.length; i++)
{
stringToMatchAsArrayOfChars.push(stringToMatch.substr(i, 1));
}
var stringToMatchEscaped = "";
for (var i = 0; i < stringToMatchAsArrayOfChars.length; i++)
{
if (stringToMatchAsArrayOfChars[i] !== " ")
{
stringToMatchEscaped = stringToMatchEscaped + "\\" + stringToMatchAsArrayOfChars[i];
}
else
{
stringToMatchEscaped = stringToMatchEscaped + " ";
}
}
var pattern = "^" + stringToMatch;
var regex = new RegExp(pattern, "i");
return regex.test("testing De$mond.");
I understand that the above method is much more verbose but what it basically does is :
var stringToMatchEscaped = "\D\e\$\m\o\n\d\. \\\(\b\l\a\h\)";
But it's not working. Why is that?
And, also, is there some other way of escaping stringToMatch other than the one suggested in the link I provided? i.e. without specifying which characters to escape like it's being dones with /[\-\[\]\/\{\}\(\)\*\+\?\.\\\^\$\|]/g ?
here is a simple regexp to make safe regexp patterns from string input.
var pattern= "De$mond.";
var regex = new RegExp(pattern.replace( /([.*+?^${}()|[\]\/\\])/g , '\\$1'), "i");
regex.test("testing De$mond. string here."); // === true
note that this means you cannot use the "wildcards" or any RegExp syntax, but you'll end up with a real regexp that will perform a literal match from the source text to the pattern.
I have a string as :
var str = "str is str, 12str345 and ABCstrDEF";
I want capture all str except ABCstrDEF (str surrounded by alphabetical characters)
Is it possible restrict alphabets with regex?
Go with
RegExp.quote = function(str) {
return (str + '').replace(/([.?*+^$[\]\\(){}|-])/g, "\\$1");
};
var re = new RegExp("/\b[^a-zA-Z]*?" + RegExp.quote(str) + "[^a-zA-Z]*?\b/g");
alert(input.match(re));