I'm trying to test words string which don't begin with a specific word,
var content = 'special-src="http://www.link.com" ';
var src = new RegExp(/\b(?!special-)\w*src=*\b/g);
console.log(src.test(content));
This should console a false, but it's not.
But, if I remove the - from the regex and content, the result is fine so I guess this is kind of escaping issue ?
What you're looking for is a negative lookbehind (?<!special-), not negative lookahead (?!special-). I've got it working in Regex Workbench, but Javascript doesn't support this natively.
This approach looks like it might work: http://davidchin.me/blog/simulate-regex-lookbehind-in-javascript/
Try with:
var content = 'special-src="http://www.link.com" ';
var src = /^(?!special\-)\w*src=.*$/g;
console.log(src.test(content));
UPDATE
There was a mistake in the expression, should be !? instead ?!. The correct code is
var content = 'special-src="http://www.link.com" ';
var src = /^(!?special\-)\w*src=.*$/g;
console.log(src.test(content));
Related
I'm trying to match #(\w+) in a div content and remove it.
Here's what i've tried : http://jsfiddle.net/mxgde6m7/1/ .
#(\w+) works , but it doesn't replace with space.
var content = document.getElementById('contentbox');
var find = '#(\w+)';
var reg = new RegExp(find, 'g');
var result = content.innerHTML.replace(reg, ' ');
alert(result);
<div id="contentbox">#d test
What i want: <div id="contentbox">test
</div>
Thanks in advance.
EDIT
Okay, one problem solved, another one came up.
My script http://jsfiddle.net/mxgde6m7/9/ works perfectly there, but when i try it on my website, only a half works. The last part where it should replace #(\w+) with space doesn't work at all. If i copy/paste the CONTENT of the function in console(chrome), it works , but if i paste the function and i call it, it doesn't work.
Please help ! I'm stuck.
Using a RegExp constructor, you need two backslashes \\ in place of each backslash \.
var find = '#(\\w+)';
hwnd is correct that you need to double escape \w in your regular expression.
var find = '#(\\w+)';
But, you could also make this code much cleaner by defining a regex literal like so -
var content = document.getElementById('contentbox');
var result = content.innerHTML.replace(/#(\w+)/g, ' ');
alert(result);
Doing it this way doesn't require double escaping, as it's not a string.
I want to match the First url followed by a space using regex expression while typing in the input box.
For example :
if I type www.google.com it should be matched only after a space followed by the url
ie www.google.com<SPACE>
Code
$(".site").keyup(function()
{
var site=$(this).val();
var exp = /^http(s?):\/\/(\w+:{0,1}\w*)?(\S+)(:[0-9]+)?(\/|\/([\w#!:.?+=&%#!\-\/]))?/;
var find = site.match(exp);
var url = find? find[0] : null;
if (url === null){
var exp = /[-\w]+(\.[a-z]{2,})+(\S+)?(\/|\/[\w#!:.?+=&%#!\-\/])?/g;
var find = site.match(exp);
url = find? 'http://'+find[0] : null;
}
});
Fiddle
Please help, Thanks in advance
you should be using a better regex to correctly match the query & fragment parts of your url. Have a look here (What is the best regular expression to check if a string is a valid URL?) for a correct IRI/URI structured Regex test.
But here's a rudimentary version:
var regex = /[-\w]+(\.[a-z]{2,})+(\/?)([^\s]+)/g;
var text = 'test google.com/?q=foo basdasd www.url.com/test?q=asdasd#cheese something else';
console.log(text.match(regex));
Expected Result:
["google.com/?q=foo", "www.url.com/test?q=asdasd#cheese"]
If you really want to check for URLs, make sure you include scheme, port, username & password checks just to be safe.
In the context of what you're trying to achieve, you should really put in some delay so that you don't impact browser performance. Regex tests can be expensive when you use complex rules especially so when running the same rule every time a new character is entered. Just think about what you're trying to achieve and whether or not there's a better solution to get there.
With a lookahead:
var exp = /[-\w]+(\.[a-z]{2,})+(\S+)?(\/|\/[\w#!:.?+=&%#!\-\/])?(?= )/g;
I only added this "(?= )" to your regex.
Fiddle
so I've been running around regexp for a while now, and been using RegEx101 to test my patterns, and it never failed (yet).
So I am trying to replace android Emojicons strings to their appropriate HTML image tage via regex, the code seems to match without an issue in the site above, and even works with PHP, but somehow, it doesn't match at all in javascript... so here is my code:
function loadEmojisInMessage(message) {
var regExp = /({emoji:(.*?)})/g; //var regExp = new RegExp("({emoji:(.*?)})","g");
message.replace(regExp, '<img src="emojis/emoji_$2.png" id="$2" class="emojicon" />').toString();
return message;
}
at first I thought I am doing something wrong, so I changed the code to this, just for testing
function loadEmojisInMessage(message) {
var regExp = /({emoji:(.*?)})/g; //var regExp = new RegExp("({emoji:(.*?)})","g");
message.replace(regExp, 'test?').toString();
return message;
}
but even this does not replace at all! (my thought is that it is having an issue matching the pattern in the string :/ )
example strings to match :
{emoji:em_1f50f}
What I am trying to do here is replace the entire string (above) with image HTML tag, while using the second match [it is the second bracket () ] for the URL string
Best Regards
UPDATE :
I forgot to add first matching bracket, sorry!
Also, you can test the pattern here
You're not assigning the result of the replace() method call back to the variable message. If you don't to this, message remains unchanged.
message = message.replace(regExp, '<img src="emojis/emoji_$2.png" id="$2" class="emojicon" />');
I have a string (from the pathname in the url) and I am trying to pull out part of it, but I'm having trouble.
This is what I have so far:
^(/svc_2/pub/(.*?).php)
The string is:
/svc_2/pub/stats/dashboard.php?ajax=1
How can I get a regex that returns /pub/stats/dashboard only?
If it's always that format (I'm assuming the /svc_2/ is always there) this should do it.
var s = "/svc_2/pub/stats/dashboard.php?ajax=1";
var match = s.match(/\/svc_2(.+)\./)[1];
But not if anything comes before that.
For this, using a regex is too much, but here is:
var string = "/svc_2/pub/stats/dashboard.php?ajax=1";
console.log(string.replace(/.*(\/pub.*)\.php.*$/,"$1"));
But you can do it, without a regex, like this
console.log(string.substr(6,string.indexOf(".php")-6));
In both cases, the console.log will give you /pub/stats/dashboard
This is not very flexible, but should work in this specific case.
var basedir = '/svc_2/', str = '/svc_2/pub/stats/dashboard.php?ajax=1';
str = str.substring(basedir.length, str.indexOf('.'));
alert(str);
I have some text content (read in from the HTML using jQuery) that looks like either of these examples:
<span>39.98</span><br />USD
or across multiple lines with an additional price, like:
<del>47.14</del>
<span>39.98</span><br />USD
The numbers could be formatted like
1,234.99
1239,99
1 239,99
etc (i.e. not just a normal decimal number). What I want to do is get just whatever value is inside the <span></span>.
This is what I've come up with so far, but I'm having problems with the multiline approach, and also the fact that there's potentially two numbers and I want to ignore the first one. I've tried variations of using ^ and $, and the "m" multiline modifier, but no luck.
var strRegex = new RegExp(".*<span>(.*?)</span>.*", "g");
var strPrice = strContent.replace(strRegex, '$1');
I could use jQuery here if there's a way to target the span tag inside a string (i.e. it's not the DOM we're dealing with at this point).
You could remove all line breaks from the string first and then run your regex:
strContent = strContent.replace(/(\r\n|\n|\r)/gm,"");
var strRegex = new RegExp(".*<span>(.*?)</span>.*", "g");
var strPrice = strContent.replace(strRegex, '$1');
This is pretty easy with jQuery. Simply wrap your HTML string inside a div and use jQuery as usual:
var myHTML = "<span>Span 1 HTML</span><span>Span 2 HTML</span><br />USD";
var $myHTML = $("<div>" + myHTML + "</div>");
$myHTML.find("span").each(function() {
alert($(this).html());
});
Here's a working fiddle.
try using
"[\s\S]*<span>(.*?)</span>[\s\S]*"
instead of
".*<span>(.*?)</span>.*"
EDIT: since you're using a string to define your regex don't forget to esacpe your backslashes, so
[\s\S]
would be
[\\s\\S]
You want this?
var str = "<span>39.98</span><br />USD\n<del>47.14</del>\n\n<span>40.00</span><br />USD";
var regex = /<span>([^<]*?)<\/span>/g;
var matches = str.match(regex);
for (var i = 0; i < matches.length; i++)
{
document.write(matches[i]);
document.write("<br>");
}
Test here: http://jsfiddle.net/9LQGK/
The matches array will contain the matches. But it isn't really clear what you want. What does there's potentially two numbers and I want to ignore the first one means?