I am trying to get data from MySQL using ajax and jQuery. Right now, the only thing being returned is "0". Here is my PHP function:
function dallas_db_facebook_make_post () {
global $wpdb;
$query = "SELECT * FROM wp_dallas_facebook WHERE time > NOW() ORDER BY time LIMIT 1";
$results = $wpdb->get_results($query, ARRAY_A);
foreach($results as $result) {
$fbpost = $result['text'];
}
}
Here is my jQuery function:
function send_fb_post() {
jQuery.ajax({
type: "GET",
url: my_ajax.ajaxurl,
data: {
'action': 'dallas_db_facebook_make_post'
},
beforeSend: function() {
},
success: function(data){
console.log(data);
},
error: function(){
},
});
};
You are not getting anything, because you are not printing/echoing anything.
What happens if you try
foreach($results as $result) {
echo $fbpost = $result['text'];
}
You code is not working because you are not print anything on server side. so you can small change in your code like below.
jsonencode is use to return an array of data.
function dallas_db_facebook_make_post () {
global $wpdb;
$query = "SELECT * FROM wp_dallas_facebook WHERE time > NOW() ORDER BY time LIMIT 1";
$results = $wpdb->get_results($query, ARRAY_A);
$fbpost = array();
foreach($results as $result) {
$fbpost = $result['text'];
}
echo json_encode($fbpost);
exit;
}
in response you json_encodeed data. You can decode and use this data using below function in response callback.
function send_fb_post() {
jQuery.ajax({
type: "GET",
url: my_ajax.ajaxurl,
data: {
'action': 'dallas_db_facebook_make_post'
},
beforeSend: function() {
},
success: function(data){
console.log(jQuery.parseJSON( data ));
},
error: function(){
},
});
};
Related
I want to populate a select2 dropdown with an AJAX response function with data that will be called whenever the dropdown required for it changes value. I console logged to be sure that the function gets reached, but nonetheless, the instructions are not being ran by the machine:
create.tpl - Holds front-end code
$('.select2lead').select2({
minimumInputLength: 3,
ajax: {
type: 'GET',
url: '/modules/support/ajaxLeadSearch.php',
dataType: 'json',
delay: 250,
data: function (params) {
return {
term: params.term
};
},
processResults: function (data) {
return {
results: data,
more: false
};
}
}
});
$('.select2lead').on("change", function() {
var value = $(this).val();
// console.log(value);
searchProjectsByLeadID(value);
});
function searchProjectsByLeadID(id){
$('.select2project').select2({
minimumInputLength: 3,
ajax: {
type: 'GET',
url: '/modules/support/ajaxProjectSearch.php',
dataType: 'json',
delay: 250,
data: {
"id": id
},
processResults: function (data) {
return {
results: data,
more: false
};
}
}
});
console.log(id);
}
ajaxProjectSearch.php
<?php
require_once('../../config.php');
$login = new Login();
if (!$login->checkLogin()) {
echo lang($_SESSION['language'], "INSUFFICIENT_RIGHTS");
exit();
}
$db = new Database();
// Select the projects
$query = "
SELECT
ProjectID AS project_id,
ProjectSummaryShort AS project_summary,
FROM
`rapports_projectTBL`
INNER JOIN LeadTBL ON rapports_projectTBL.LeadID=LeadTBL.LeadID
WHERE
ProjectID > 0
AND
rapports_projectTBL.LeadID LIKE :leadId
ORDER BY
ProjectID
ASC
";
$binds = array(':leadId' => $_GET['id']);
$result = $db->select($query, $binds);
$json = [];
foreach ($result as $row){
$json[] = ['id'=>$row['project_id'], 'text'=>$row['project_summary']];
}
echo json_encode($json);
Network output in console
https://i.imgur.com/6ZmGGxa.png
*As we can see, the searchProjectsByLeadID(id) function gets called but we get nothing back. No errors nor any values. The only thing getting transported is the first select box, which fetches lead data upon whats typed in the searchbox. *
RESOLVED
Issue was called by having the SQL query looking for a LIKE rather than a DIRECT MATCH:
WRONG
WHERE
ProjectID > 0
AND
rapports_projectTBL.LeadID LIKE :leadId
CORRECT
WHERE
rapports_ProjectTBL.LeadID=:leadId
I have a few caption boxes that I want to be able to edit inline and to save these to my database to update a certain record in my table.
For some reason, nothing happens when I click the save button.. not even in the console.
It's just using jQuery at the moment, will I have to use AJAX for this?
If so any tips would be great to point me in right direction as I'm not familiar that much with AJAX.
Here is my code:
index.php
<div class="caption" id="caption1" contenteditable="true" style="min-height: 450px;">
<?php
$query3 = "SELECT * From (select * from ckeditor ORDER BY id DESC LIMIT 2) AS name ORDER BY id LIMIT 1";
$show = mysql_query($query3, $con);
while ($row = mysql_fetch_array($show))
{
echo $row['file'];
}
?>
</div>
<button type="button" id="save"><span>Save</span></button>
<script>
$(document).ready(function (e) {
$("#save").click(function (e) {
var data = CKEDITOR.instances.caption1.getData();
var options = {
url: "save.php",
type: "post",
data: { "editor" : encodeUriComponent(data) },
success: function (e) {
echo "Succesfully updated!";
}
};
}
});
</script>
</div>
save.php
<?php
$connection = mysql_connect("localhost", "", "");
$db = mysql_select_db("castle", $connection);
//Fetching Values from URL
$data = nl2br($_POST['caption1']);
//Insert query
$query ="INSERT INTO `ckeditor`(`file`) VALUES ('$data')";
echo "Form Submitted Succesfully";
mysql_close($connection);
?>
You need to send the data to the server like this;
$.ajax({
url: "save.php",
data: {
"editor" : encodeUriComponent(data)
},
error: function() {
//Error
},
success: function(data) {
//Success
},
type: 'POST'
});
Currently you are just creating an object called 'options'
Your code should look like this;
$("#save").click(function (e) {
var data = CKEDITOR.instances.caption1.getData();
$.ajax({
url: "save.php",
data: {
"editor" : encodeUriComponent(data)
},
error: function() {
//Error
},
success: function(data) {
alert('Success');
},
type: 'POST'
});
}
Just a side note, 'echo' doesn't work in js. You need to use 'alert()' or 'console.log()'
i have an array , which has to be passed from backend to frontend using ajax, i am new to ajax i know the syntax but got stuck , below is my code
backend(PHP)
$s_q = "SELECT `ans` FROM `bec_log_response` WHERE session_id=1 AND paper_id=2";
$s_res = mysql_query($s_q, $db2);
while($row= mysql_fetch_array($s_res))
{
echo $row['ans'];
}
$result = array('ans' => $row['ans'] );
Javascript code
function get_solution()
{
$.ajax({
url: 'waiting.php',
dataType: 'json',
type: 'GET',
timeout: 30 * 1000,
data: {sol:row},
success: function(json){
$('#saved').html(json.ans);
},
error: function(){}
});
}
i am getting an error in this code data: {sol:row}.
The response data from php is not in json format..
$result = array('ans' => $row['ans'] );
echo json_encode($result);
add this in your php code
Create a JSON on the PHP Side and catch it with $.getJSON jquery
Server Side:
$row_1 = array();
$s_q = "SELECT `ans` FROM `bec_log_response` WHERE session_id=1 AND paper_id=2";
$result = mysql_query($s_q) or die (mysql_error());
while($r = mysql_fetch_assoc($result)) {
$row_1[] = $r;
}
$post_data = json_encode(array('ans' => $row_1));
echo $post_data;
Client Side:
$.getJSON("result.php", function(json) {
console.log(json)
$.each( json, function( key, data ) {
//loop through the json if necessary
});
});
I am doing some Add, Edit, and Delete for my project in school. The codes in the add module went well, in fact I've added few records. Then, here comes the Edit module, at first it was quite good, similar codes was used from the add module. But as I try and try, the post in the edit module was empty.
here's my edit codes:
$(".careersEdit").click(function () {
var careersTableSelect = encodeURIComponent($("input:radio[name=careersTableSelect]:checked").val());
if (careersTableSelect > 0) {
$(".careersEditForm_load").show();
$(".careersEditForm_error").hide();
$(".careersEditForm").hide();
var dataStringCareersEdit = 'careersTableSelect=' + careersTableSelect;
$.ajax({
type: "POST",
url: "admin/careers/process/careersEditGet.php",
data: dataStringCareersEdit,
beforeSend: function(){
alert(dataStringCareersEdit);
},
success: function () {
setTimeout("", 5000);
fetchResult();
},
error: function () {
alert("Post Error");
}
});
function fetchResult() {
$.ajax({
url: "admin/careers/process/careersEditGet.php",
type: "POST",
dataType: "json",
success: function (result) {
if (result) {
$("input#careersEditPosition").val(result['position']);
$("input#careersEditCompany").val(result['company']);
$("input#careersEditLocation").val(result['location']);
$(".careersEditForm_load").hide();
$(".careersEditForm").show();
}
},
error: function () {
alert("Fetch Error");
}
});
}
} else {
$(".careersEditForm").hide();
$(".careersEditForm_load").hide();
$(".careersEditForm_error").show();
}
});
Here's the careersEditGet.php:
<?php
include('connect.php');
error_reporting(0);
$careersTableSelect = $_POST['careersTableSelect'];
//$careersTableSelect = $careersTableSelect + 1;
//echo $careersTableSelect;
$query = "SELECT * FROM atsdatabase.admincareers WHERE refNum ='" . $careersTableSelect . "' LIMIT 0 , 30";
$runQuery = mysql_query($query);
if (!$runQuery) {
die('Could not enter data: ' . mysql_error());
}
$result = mysql_fetch_row($runQuery);
$array = array(
'position' => "" . $result[1] . "",
'company' => "" . $result[2] . "",
'location' => "" . $result[3] . "",
);
echo json_encode($array);
mysql_close($connection);
?>
Yes, the code is ugly/wrong/crap, I'm quite new to jquery stuffs, about 3-4 days. To those that will help, please do correct me. I wanna learn this jquery ajax stuff. Gracias
Maybe try passing data in more common way:
change
data: dataStringCareersEdit,
to
data: { "careersTableSelect" : careersTableSelect },
Call your ajax function once like,
$.ajax({
url: "admin/careers/process/careersEditGet.php",
type: "POST",
dataType: "json",
data: {careersTableSelect: careersTableSelect},
success: function (result) {
if (result) {
$("input#careersEditPosition").val(result.position);// json not array
$("input#careersEditCompany").val(result.company);// json not array
$("input#careersEditLocation").val(result.location);// json not array
$(".careersEditForm_load").hide();
$(".careersEditForm").show();
}
},
error: function () {
alert("Fetch Error");
}
});
Thanks guys for all the effort to answer this question, I've consulted to a friend who's a web developer, taught me how to properly use ajax in jquery. ;)
You are doing something fundamentally wrong when u are posting Data from jQuery.Ajax..
The data should be an object and the key should be the name of the server side POST variable which will be used later in the PHP ...
Example :
data : {"server_side_vriable" : "Your_data_to_Post" }
......
var dataStringCareersEdit = 'careersTableSelect=' + careersTableSelect + "&careersTableSelect=" + careersTableSelect;
$.ajax({
type: "POST",
url: "admin/careers/process/careersEditGet.php",
data: {"careersTableSelect" : dataStringCareersEdit},
beforeSend: alert(dataStringCareersEdit),
success: function () {
alert("Fetching Result");
setTimeout("", 3000);
$.ajax({
url: "admin/careers/process/careersEditGet.php",
type: "GET",
dataType: "json",
success: function (result) {
if (result) {
$("input#careersEditPosition").val(result['position']);
$("input#careersEditCompany").val(result['company']);
$("input#careersEditLocation").val(result['location']);
$(".careersEditForm_load").hide();
$(".careersEditForm").show();
}
},
error: function () {
alert("Fetch Error");
}
});
},
error: function () {
alert("Post Error");
}
});
I don't know why this double json response are not successful:
[{"first_content":"content",...}][{"second_content":"content",...}]
So i am getting the message Oops! Try Again.
if(isset($_GET['start'])) {
echo get_posts($db, $_GET['start'], $_GET['desiredPosts']);
echo get_posts1($db, $_GET['start'], $_GET['desiredPosts']);
$_SESSION['posts_start']+= $_GET['desiredPosts'];
die();
}
var start = <?php echo $_SESSION['posts_start']; ?>;
var desiredPosts = <?php echo $number_of_posts; ?>;
var loadMore = $('#load-more');
loadMore.click(function () {
loadMore.addClass('activate').text('Loading...');
$.ajax({
url: 'profile.php',
data: {
'start': start,
'desiredPosts': desiredPosts
},
type: 'get',
dataType: 'json',
cache: false,
success: function (responseJSON, responseJSON1) {
alert(responseJSON);
loadMore.text('Load More');
start += desiredPosts;
postHandler(responseJSON, responseJSON1);
},
error: function () {
loadMore.text('Oops! Try Again.');
},
complete: function () {
loadMore.removeClass('activate');
}
});
});
What is the solution to get a double json response ? With one there is no problem
"Double JSON response" as you call them is basically invalid JSON. You should have something like so:
{"first_content":"content", "second_content":"content",...}
Or as a couple of people mentioned:
[{"first_content":"content",...}, {"second_content":"content",...}]
You probably need to modify some server side code, your get_posts function could return a PHP array instead of a JSON array. Example:
function get_posts(){
$array = array('content' => 'foo', 'title' => 'bar');
return $array;
}
Then in your profile.php:
if(isset($_GET['start'])) {
$posts = get_posts($db, $_GET['start'], $_GET['desiredPosts']);
$posts1 = get_posts1($db, $_GET['start'], $_GET['desiredPosts']);
echo array($posts, $posts1);
$_SESSION['posts_start']+= $_GET['desiredPosts'];
die();
}