Develop Reference

prevent result, show through AJAX, after reload browser

I have a insert query through ajax. It is working correctly. But when I reload browser then result disappears from div section and if I insert form through ajax again then result is showing.
I have a file first.php (in which, form is present), a AJAX code and a firstcall.php where query will be execute.
My first.php (html form) is:
<form class="reservation-form mb-0" action="" method="post" autocomplete="off">
<input name="name1" id="name1" class="form-control" type="text" placeholder="Enter Name" required aria-required="true">
<input name="age" id="age" class="form-control" required type="number" placeholder="Enter Age" aria-required="true">
<input type="checkbox" id="checkbox" class="checkbox1" name="namec[]" value="<?php echo $value['id']; ?>" >
<input type="button" class="pull-right btn btn-warning" value="Submit" id="submit">
</form>
Here data should be display:
<div class="col-md-5">
<div class="panel panel-primary" id="showdata">
<!-- Here is the results, but when reload browser then result disapper-->
</div>
</div>
AJAX is:
<script type="text/javascript">
$(document).ready(function(){
$("#submit").click(function(){
var name1 = $("#name1").val();
var age = $("#age").val();
var chkArray=[];
$('.checkbox1:checked').each( function() {
chkArray.push($(this).val());
} );
var selected;
selected = chkArray.join(',') ;
if(selected.length > 1){
$.ajax( {
url:'firstcall.php',
type:'POST',
data:{name1: name1,age: age,namec: chkArray},
}).done(function(data){
$("#showdata").html(data);
});
}
else{
alert("Please at least one of the checkbox");
}
});
});
</script>
firstcall.php is:
<div class="panel panel-primary" id="showdata">
<?php
foreach($_POST['namec'] as $selected){
echo $selected;
$_SESSION['name1']=$_POST["name1"];
$_SESSION['age']=$_POST["age"];
echo $name1=$_SESSION['name1'];
echo $age=$_SESSION['age'];
$query=mysql_query("insert into patient_details (p_name,p_age,g_number) values ('$name1','$age','$selected')") or die(mysql_error());
}
?>

First of all fix your query to use MySQLi, instead of MySQL, check this or the PHP manual
Also don't ever add direct $_POST or $_GET variables into your mysql query, filter them first using mysqli_real_escape.
$name1 = mysqli_real_escape($link, $_POST["name1"]);
$age = mysqli_real_escape($link, $_POST["age"]);
After that, to show the data when the page reloads, you need to load the data with the page, easiest way to do that is just add in your HTML PHP tags with an echo command inside, adding your variables.

If I understand your question correctly, you want the Ajax result to also show on page load?
Right now you only execute the JS after a click (so on page load/relaod you will just see the html), you might want to execute it after page load aswell (so execute the script without the .click)
You could create a function once, and call it when the page is ready and on click.

Run a JavaScript function from a php if statement

I would like to create a php IF statement so If it receives the key "test" by POST, <h2> hello </ h2> should be output, otherwise <span> error </ span>
How can I make that?
<div id="rre">
<h2 class="desktop">Hamburg,a major port city in northern Germany.</h2>
<h2 class="mobil">Berlin,is the capital and the largest city of Germany.</h2>
</div>
<form action="viereck.html" method="POST">
<input type="text" name="check"?>
<input type="button" value="Klick" onclick="klick();" />
</form>
<script type="text/javascript">
function klick() {
jQuery('#rre').html('<h1>Hallo</h1>');
}
</script>

The response that you return needs to be inside script tags like:
echo '<script type="text/javascript">alert();</script>';

Why you don't do that with jquery: Try smth like this
<script type="text/javascript">
function klick() {
if($("#text").val() == 'test'){
jQuery('#rre').html("<h1>Hello there!</h1>");
}else{
jQuery('#rre').html("Error");
}
}
</script>
Html
<div id="rre">
<h2 class="desktop">Hamburg,a major port city in northern Germany.</h2>
<h2 class="mobil">Berlin,is the capital and the largest city of Germany.</h2>
</div>
<form action="viereck.html" method="POST">
<input type="text" name="check"? id="text">
<input type="button" value="Klick" onclick="klick();" />
</form>
JSFIDDLE

If the page you're posting to is viereck.html, you're going to be unable to use PHP on it.
If you can change the file to viereck.php, you can POST to it like you're doing, with action="viereck.php" method="POST" Then, at the top of your page, check for POST values in PHP like:
<?php
if(isset($_POST['check'])){
$check = '<span>error</span>';
if($_POST['check'] == 'test'){
$check = '<h1>Hallo</h1>';
}
}
?>
And if your jQuery is on the same page, you can insert the PHP like:
<script type="text/javascript">
function klick() {
jQuery('#rre').html(<?= $check; ?>);
}
</script>
Doing it this way though can lead to some serious headaches as your project grows, I wouldn't recommend it. Why not look into using AJAX? You can submit a form and return a message indicating success or failure, as well as why. You can then create your HTML in jQuery instead of a PHP string like:
// On form submit
$.ajax({
url: "viereck.php",
type: 'POST',
success: function(result){
var msg = $('<h1>').text('Hallo');
$('#rre').html(msg);
},
error: function(result){
var msg = $('<span>').text('Error');
$('#rre').html(msg);
}
});

Submit form using one button, one to emailmeform using html script and another to my internal database

Im sorry for my bad english.
Im begineer with PHP and all coding method.
I've been searching this for a days and still cannot find what I need lack to my understanding especially with php, java or ajax.
I have an emailmeform form and I have my own form on 1 php file which I want when client submit the send button, it will save the data entered previously by client to my internal database and send it to emailmeform in the same time but I cannot make this happen.
The solution I think will work is maybe ajax or javascript, but since lack of my knowledge with those codes I cannot solve this issue by my self.
Here's my code (all in 1 php script page):
<?php
session_start();
include "connection/database.php";
$sql = mysql_query("SELECT * from tb_config");
$config = mysql_fetch_array($sql);
if (isset($_POST['send'])) {
$username = $_POST['element_1'];
$password = $_POST['element_2'];
$referral = $_POST['referral'];
$a = mysql_num_rows(mysql_query("SELECT * from tb_member where username='$username'"));
if (empty($username) || empty($password)) {
echo "<script> alert('Please fill all the required form!!'); </script>";
} else if (strlen($_POST['element_2']) < 6) {
echo "<script> alert('Password at least 6 digit!!!'); </script>";
} else {
$save = mysql_query("insert into tb_member(username,password) values ('$username','$password')");
exit;
}
}
?>
<!-- this is emailmeform scipt -->
<form id="emf-form" target="_parent" class="leftLabel" enctype="multipart/form-data" method="post" action="http://www.emailmeform.com/builder/emf/to/ref">
<div id="emf-form-description"><h2>Form Register</h2></div>
</div>
<ul>
<li id="emf-li-0" class="emf-li-field emf-field-text data_container ">
<label class="emf-label-desc" for="element_0">Your Name</label>
<div class="emf-div-field"><input id="element_0" name="element_0" value="" size="30" type="text"
class="validate[optional]"/><div class="emf-div-instruction">Please fill your name</div></div>
<div class="emf-clear"></div>
</li><li id="emf-li-1" class="emf-li-field emf-field-text data_container ">
<label class="emf-label-desc" for="element_1">Username <span>*</span></label>
<div class="emf-div-field"><input id="username" name="element_1" value="<?php if (isset($_POST['element_1'])) { echo $_POST['element_1']; } ?>" size="30" type="text"
class="validate[required,length[6,15]]"/><div class="emf-div-instruction">At least 6 characters</div></div>
<div class="emf-clear"></div>
</li><li id="emf-li-2" class="emf-li-field emf-field-text data_container ">
<label class="emf-label-desc" for="element_2">Password <span>*</span></label>
<div class="emf-div-field"><input id="element_2" name="element_2" value="" size="30" type="text"
emf_mask_input="true"
class="validate[required,length[6,]]"/><div class="emf-div-instruction">At least 6 characters</div></div>
<li id="emf-li-post-button" class="middle">
<input value="Send" type="submit" name="send" onmouseover="return true;"/>
</li>
</ul>
<input name="element_counts" value="14" type="hidden" />
<input name="embed" value="forms" type="hidden" />
</form>
This script works and send to emailmeform, but wont submit any data to my internal database, BUT IF I change the action button to
<form method="post" action="">, this will submit to my internal database but not send to emailmeform. I want this work together, submit to my database and send it also to emailmeform.
I have struggling with this and still not found the answer.
Kindly please help.
Any help will be appreciated
Thanks

Refer this, it will demostrate how to insert data in database

Send multiple headers or multiple submitting for the form?

When the user inserts two numbers (from-to), I want to send (((full path))) for each number.
how would I accomplish this? Is there a way in PHP, javascript or any other language. Would I send many headers or multiple submissions for the form?
P.S:
The (go.php) page that receive and process each number individually.. I can't put hands on it to make changes, I only must send individual numbers to it because that's how the other page is coded.
This what i've tried:
<form action="test.php" method="post">
<input type="text" name="first">
<input type="text" name="second">
<input type="submit" name="submit">
</form>
<?php
$f=$_POST['first'];
$s=$_POST['second'];
for($i=$f; $i<=$s; $i++){
header('location:go.php?f='.$i);
}
?>

you can not send header twice you can do this like below
<?php
$f=$_POST['first'];
$s=$_POST['second'];
header('location:go.php?first='.$i.'&second='.$s);
?>
go.php
you can catch these two variables using get method
<?php
$first=$_GET['first'];
$second=$_GET['second'];
//rest of the code
?>

Why not use javascript to submit so many times:
// supposing you have jQuery
for (var i = Number($(':input[name=first]').val()),
end = Number($(':input[name=second]').val());
i <= end; i++) {
$.get('go.php', { f: i }, function (response){
// do something with response
});
}

You can't do it via simple single script. You can do it via multithreading or curl. I am giving you example of curl:
one.php
<form action="test.php" method="post">
<input type="text" name="first">
<input type="text" name="second">
<input type="submit" name="submit">
</form>
<?php
$f=$_POST['first'];
$s=$_POST['second'];
for($i=$f; $i<=$s; $i++){
//write curl code to execute two.php with url : http:// yoursite.com/two.php?f=$i
}
?>
two.php
<?php
header('location:go.php?f='.$_REQEST['f']);
?>
Hope this explanation help you. Best of Luck.

php variables get values from jquery variables without post to the database

<script>
$(document).ready(function(){
$("#date").click(function(){
start = $("#date_start").val();
end = $("#date_end").val();
});
});
</script>
<input name='date_A' type='text' id='date_start' />
<input name='date_B' type='text' id='date_end' />
<input type="button" id="date" class="button" value="check" />
The question is how to get value of "start" and "end" from the jquery to put that in PHP variable without post it first to database?
<?php
$start_date = "";
$end_date = "";
?>
The both variables above need the value of the variable "start" and "end" from jquery above

$(document).ready(function(){
$("#date").click(function(){
start = $("#date_start").val();
end = $("#date_end").val();
$.ajax({
type: 'post',
url: '/your_page_link/',
data: {start : start, end : end},
success: function (res) {
}
});
});
});
In PHP:
<?php
if(!empty($_POST)){ // If you are using same page, then it'll help you to detect ajax request.
$start_date = $_POST['start'];
$end_date = $_POST['end'];
}
?>

I fear you want to read values from jQuery and inject them in PHP in the same page, which is impossible.
You have to understand what PHP is first. It generates the page, that is then sent to the browser, that then executes jQuery code. PHP code completely disappeared from the generated page. jQuery has no idea of PHP's presence, they just can't interact this way. You must use a GET or POST query in order to send values to a PHP page, back to the server.
You want to read things like this : Difference between Javascript and PHP

This is what you have to do.
<form id="form" name="form" action="" method="post">
<div id="block">
<input type="text" name="startDate" id="startDate" placeholder="Start date" required/>
<input type="text" name="endDate" id="endDate" placeholder="End date" required />
<input type="submit" id="Download" name="Download" value="Download"/>
</div>
</form>
and put this code in the same page
<?php
$startDate = $_POST['startDate'];
$endDate = $_POST['endDate'];
?>