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I have two arrays, keys and commonkeys.
I want to create a key-value pair using these two arrays and the output should be like langKeys.
How to do that?
This is array one:
var keys=['en_US','es_ES', 'pt_PT','fr_FR','de_DE','ja_JP','it_IT']
This is array two:
var commonKeys=['en-*','es-*', 'pt-*','fr-*','de-*','ja-*','it-*', '*']
This is the output I need:
var langKeys = {
'en-*': 'en_US',
'es-*': 'es_ES',
'pt-*': 'pt_PT',
'fr-*': 'fr_FR',
'de-*': 'de_DE',
'ja-*': 'ja_JP',
'it-*': 'it_IT',
'*': 'en_US'
};
You can use map() function on one array and create your objects
var keys=['en_US','es_ES', 'pt_PT','fr_FR','de_DE','ja_JP','it_IT'];
var commonKeys=['en-*','es-*', 'pt-*','fr-*','de-*','ja-*','it-*', '*'];
var output = keys.map(function(obj,index){
var myobj = {};
myobj[commonKeys[index]] = obj;
return myobj;
});
console.log(output);
JavaScript is a very versatile language, so it is possible to do what you want in a number of ways. You could use a basic loop to iterate through the arrays, like this:
var keys=['en_US','es_ES', 'pt_PT','fr_FR','de_DE','ja_JP','it_IT']
var commonKeys=['en-*','es-*', 'pt-*','fr-*','de-*','ja-*','it-*', '*']
var i;
var currentKey;
var currentVal;
var result = {}
for (i = 0; i < keys.length; i++) {
currentKey = commonKeys[i];
currentVal = keys[i];
result[currentKey] = currentVal;
}
This example will work in all browsers.
ES6 update:
let commonKeys = ['en-*', 'es-*', 'pt-*', 'fr-*', 'de-*', 'ja-*', 'it-*', '*'];
let keys = ['en_US', 'es_ES', 'pt_PT', 'fr_FR', 'de_DE', 'ja_JP', 'it_IT', 'en_US'];
let zipArrays = (keysArray, valuesArray) => Object.fromEntries(keysArray.map((value, index) => [value, valuesArray[index]]));
let langKeys = zipArrays(commonKeys, keys);
console.log(langKeys);
// let langKeys = Object.fromEntries(commonKeys.map((val, ind) => [val, keys[ind]]));
What you want to achieve is to create an object from two arrays. The first array contains the values and the second array contains the properties names of the object.
As in javascript you can create new properties with variales, e.g.
objectName[expression] = value; // x = "age"; person[x] = 18,
you can simply do this:
var keys=['en_US','es_ES', 'pt_PT','fr_FR','de_DE','ja_JP','it_IT'];
var commonKeys=['en-*','es-*', 'pt-*','fr-*','de-*','ja-*','it-*', '*'];
var langKeys = {};
var i;
for (i=0; i < keys.length; i++) {
langKeys[commonKeys[i]] = keys[i];
}
EDIT
This will work only if both arrays have the same size (actually if keys is smaller or same size than commonKeys).
For the last element of langKeys in your example, you will have to add it manually after the loop.
What you wanted to achieve was maybe something more complicated, but then there is missing information in your question.
Try this may be it helps.
var langKeys = {};
var keys=['en_US','es_ES', 'pt_PT','fr_FR','de_DE','ja_JP','it_IT']
var commonKeys=['en-*','es-*', 'pt-*','fr-*','de-*','ja-*','it-*', '*']
function createArray(element, index, array) {
langKeys[element]= keys[index];
if(!keys[index]){
langKeys[element]= keys[index-(commonKeys.length-1)];
}
}
commonKeys.forEach(createArray);
console.info(langKeys);
Use a for loop to iterate through both of the arrays, and assign one to the other using array[i] where i is a variable representing the index position of the value.
var keys = ['en_US', 'es_ES', 'pt_PT', 'fr_FR', 'de_DE', 'ja_JP', 'it_IT'];
var commonKeys = ['en-*', 'es-*', 'pt-*', 'fr-*', 'de-*', 'ja-*', 'it-*', '*'];
var langKeys = {};
for (var i = 0; i < keys.length; i++) {
var commonkey = commonKeys[i];
langKeys[commonkey] = keys[i];
}
console.log(JSON.stringify(langKeys));
let keys = ['en_US', 'es_ES', 'pt_PT', 'fr_FR', 'de_DE', 'ja_JP', 'it_IT'];
let commonKeys = ['en-*', 'es-*', 'pt-*', 'fr-*', 'de-*', 'ja-*', 'it-*', '*'];
// declaration of empty object where we'll store the key:value
let result = {};
// iteration over first array to pick up the index number
for (let i in keys) {
// for educational purposes, showing the number stored in i (index)
console.log(`index number: ${i}`);
// filling the object with every element indicated by the index
// objects works in the basis of key:value so first position of the index(i)
// will be filled with the first position of the first array (keys) and the second array (commonKeys) and so on.
result[keys[i]] = commonKeys[i];
// keep in mind that for in will iterate through the whole array length
}
console.log(result);
I have two multidimensional array and i want to create a third multidimensional array:
var reports = [
[48.98,153.48],
[12.3,-61.64]
];
var vulc = [
["ciccio",48.98,153.48],
["cicci",12.3,-61.64],
["intruso",59.9,99.9]
];
And i want to create a new multidimensional array
var nuovarray= [];
for (i=0; i<= reports.length; i++) {
var attivi= reports[i];
var attlat= attivi[0];
var attlng= attivi[1];
for (s=0; s<=vulc.length; s++){
var vulca= vulc[s];
var vulcanam= vulca[0];
var vulcalat= vulca[1];
var vulcalng= vulca[2];
if ((vulcalat==attlat) && (vulcalng==attlng){
var stato= "A";
nuovarray.push([vulcanam,vulcalat,vulcalng,stato]);
}
else{
var stato= "N";
nuovaarray.push([vulcanam,vulcalat,vulcalng,stato]);
}
}
}
i would like to have
var nuovarray= [
["ciccio",48.98,153.48,"N"],
["cicci",12.3,-61.64,"N"],
["intruso",59.9,99.9,"A"]
];
But i don't know if this code is good :/
As I said in the comment, in the for loop, use < not <= (array of length N has indexes 0 ... N-1) ... and swap the outer loop with the inner loop, and only push with value 'N' before the end of the outer loop if the inner loop hasn't pushed with value 'A'
var reports = [
[48.98,153.48],
[12.3,-61.64]
];
var vulc = [
["ciccio",48.98,153.48],
["cicci",12.3,-61.64],
["intruso",59.9,99.9]
];
var nuovarray= [];
for(var s = 0; s < vulc.length; s++) {
var vulca = vulc[s];
var stato= "A"; // default, no match
var vulcanam= vulca[0];
var vulcalat= vulca[1];
var vulcalng= vulca[2];
for(var i = 0; i < reports.length; i++) {
var attivi = reports[i];
var attlat= attivi[0];
var attlng= attivi[1];
if ((vulcalat==attlat) && (vulcalng==attlng)) {
stato = "N";
break; // we've found a match, so set stato = N and stop looping
}
}
nuovarray.push([vulcanam,vulcalat,vulcalng,stato]);
}
document.getElementById('result').innerHTML = (nuovarray).toSource();
<div id='result'></div>
I believe the code will not work the way it is written. At least, it will not give you the expected output. You are iterating through the vulc array inside the loop which iterates through reports. And you are pushing to the nuovarray inside the inner loop. So I would expect 6 elements in nuovarray, not the 3 elements you are expecting.
Did you try running it? That's the easiest way to prove incorrectness.
var reports = [
[48.98,153.48],
[12.3,-61.64]
];
var vulc = [
["ciccio",48.98,153.48],
["cicci",12.3,-61.64],
["intruso",59.9,99.9]
];
var nuovarray = [];
vulc.forEach(function(item, indx){
var bN = 'undefined' !== typeof reports[indx];
bN = bN && item[1] == reports[indx][0] && item[2] == reports[indx][1];
item.push(bN ? 'N' : 'A');
nuovarray.push(item);
});
console.log(nuovarray);
The code maps the given vulc to nuovarray and add the wanted flag to it. The flag is selected by a search over reports and if found, an 'N' is applied, otherwise an 'A' is applied.
var reports = [
[48.98, 153.48],
[12.3, -61.64]
],
vulc = [
["ciccio", 48.98, 153.48],
["cicci", 12.3, -61.64],
["intruso", 59.9, 99.9]
],
nuovarray = vulc.map(function (a) {
a.push(reports.some(function (b) {
return a[1] === b[0] && a[2] === b[1];
}) ? 'N' : 'A')
return a;
});
document.getElementById('out').innerHTML = JSON.stringify(nuovarray, null, 4);
<pre id="out"></pre>
The map() method creates a new array with the results of calling a provided function on every element in this array.
Array.prototype.map()
The push() method adds one or more elements to the end of an array and returns the new length of the array.
Array.prototype.push()
The some() method tests whether some element in the array passes the test implemented by the provided function.
Array.prototype.some()
var reports = [
[48.98,153.48],
[12.3,-61.64]
];
var vulc = [
["ciccio",48.98,153.48],
["cicci",12.3,-61.64],
["intruso",59.9,99.9]
];
console.log(vulc.map(function (item, index) {
item.push(reports.some(function (report) {
return report[0] == item[1] && report[1] == item[2];
})?"N":"A");
return item;
}));
If performance matters, you should use something better than O(n^2):
var existingPoints = {};
reports.forEach(function (row) {
existingPoints[row.join()] = true;
});
var nuovarray = vulc.map(function (row) {
var point = row.slice(1, 3).join();
var flag = existingPoints[point] ? 'A' : 'N';
return row.concat([flag]);
});
var actual = [
{"country":"UK","month":"JAN","SR":"John P","AC":"24","PR":"2","TR":1240},
{"country":"AUSTRIA","month":"JAN","SR":"Brad P","AC":"64","PR":"12","TR":1700},
{"country":"ITALY","month":"JAN","SR":"Gim P","AC":"21","PR":"5","TR":900},
{"country":"UK","month":"FEB","SR":"John P","AC":"14","PR":"4","TR":540},
{"country":"AUSTRIA","month":"FEB","SR":"Brad P","AC":"24","PR":"12","TR":1700},
{"country":"ITALY","month":"FEB","SR":"Gim P","AC":"22","PR":"3","TR":600},
{"country":"UK","month":"MAR","SR":"John P","AC":"56","PR":"2","TR":1440},
{"country":"AUSTRIA","month":"MAR","SR":"Brad P","AC":"24","PR":"12","TR":700},
{"country":"ITALY","month":"MAR","SR":"Gim P","AC":"51","PR":"5","TR":200}
];
var expect = [
{month:"JAN",val: {"UK":"24","AUSTRIA":"64","ITALY":"21"}},
{month:"FEB",val: {"UK":"14","AUSTRIA":"24","ITALY":"22"}},
{month:"MAR",val: {"UK":"56","AUSTRIA":"24","ITALY":"51"}}
];
I have array of objects which i need to reshape for one other work. need some manipulation which will convert by one function. I have created plunker https://jsbin.com/himawakaju/edit?html,js,console,output
Main factors are Month, Country and its "AC" value.
Loop through, make an object and than loop through to make your array
var actual = [
{"country":"UK","month":"JAN","SR":"John P","AC":"24","PR":"2","TR":1240},
{"country":"AUSTRIA","month":"JAN","SR":"Brad P","AC":"64","PR":"12","TR":1700},
{"country":"ITALY","month":"JAN","SR":"Gim P","AC":"21","PR":"5","TR":900},
{"country":"UK","month":"FEB","SR":"John P","AC":"14","PR":"4","TR":540},
{"country":"AUSTRIA","month":"FEB","SR":"Brad P","AC":"24","PR":"12","TR":1700},
{"country":"ITALY","month":"FEB","SR":"Gim P","AC":"22","PR":"3","TR":600},
{"country":"UK","month":"MAR","SR":"John P","AC":"56","PR":"2","TR":1440},
{"country":"AUSTRIA","month":"MAR","SR":"Brad P","AC":"24","PR":"12","TR":700},
{"country":"ITALY","month":"MAR","SR":"Gim P","AC":"51","PR":"5","TR":200}
];
var outTemp = {};
actual.forEach(function(obj){ //loop through array
//see if we saw the month already, if not create it
if(!outTemp[obj.month]) outTemp[obj.month] = { month : obj.month, val: {} };
outTemp[obj.month].val[obj.country] = obj.AC; //add the country with value
});
var expected = []; //convert the object to the array format that was expected
for (var p in outTemp) {
expected.push(outTemp[p]);
}
console.log(expected);
Iterate through array and create new list
var actual = [
{"country":"UK","month":"JAN","SR":"John P","AC":"24","PR":"2","TR":1240},
{"country":"AUSTRIA","month":"JAN","SR":"Brad P","AC":"64","PR":"12","TR":1700},
{"country":"ITALY","month":"JAN","SR":"Gim P","AC":"21","PR":"5","TR":900},
{"country":"UK","month":"FEB","SR":"John P","AC":"14","PR":"4","TR":540},
{"country":"AUSTRIA","month":"FEB","SR":"Brad P","AC":"24","PR":"12","TR":1700},
{"country":"ITALY","month":"FEB","SR":"Gim P","AC":"22","PR":"3","TR":600},
{"country":"UK","month":"MAR","SR":"John P","AC":"56","PR":"2","TR":1440},
{"country":"AUSTRIA","month":"MAR","SR":"Brad P","AC":"24","PR":"12","TR":700},
{"country":"ITALY","month":"MAR","SR":"Gim P","AC":"51","PR":"5","TR":200}
];
var newList =[], val;
for(var i=0; i < actual.length; i+=3){
val = {};
val[actual[i].country] = actual[i]["AC"];
val[actual[i+1].country] = actual[i+1]["AC"];
val[actual[i+2].country] = actual[i+2]["AC"];
newList.push({month: actual[i].month, val:val})
}
document.body.innerHTML = JSON.stringify(newList);
This is the correct code... as above solution will help you if there are 3 rows and these will be in same sequnece.
Here is perfect solution :
var actual = [
{"country":"UK","month":"JAN","SR":"John P","AC":"24","PR":"2","TR":1240},
{"country":"AUSTRIA","month":"JAN","SR":"Brad P","AC":"64","PR":"12","TR":1700},
{"country":"ITALY","month":"JAN","SR":"Gim P","AC":"21","PR":"5","TR":900},
{"country":"UK","month":"FEB","SR":"John P","AC":"14","PR":"4","TR":540},
{"country":"AUSTRIA","month":"FEB","SR":"Brad P","AC":"24","PR":"12","TR":1700},
{"country":"ITALY","month":"FEB","SR":"Gim P","AC":"22","PR":"3","TR":600},
{"country":"UK","month":"MAR","SR":"John P","AC":"56","PR":"2","TR":1440},
{"country":"AUSTRIA","month":"MAR","SR":"Brad P","AC":"24","PR":"12","TR":700},
{"country":"ITALY","month":"MAR","SR":"Gim P","AC":"51","PR":"5","TR":200}
];
var tmpArray = [];
var obj =[];
for(var k=0; k<actual.length; k++){
var position = tmpArray.indexOf(actual[k].month);
if(position == -1){
tmpArray.push(actual[k].month);
val = {};
for(var i=0; i<actual.length; i++){
if(actual[i].month == actual[k].month){
val[actual[i].country] = actual[i]["AC"];
}
}
obj.push({month: actual[k].month, val:val});
}
}
I need to know if one or more duplicates exist in a list. Is there a way to do this without travelling through the list more than once?
Thanks guys for the suggestions. I ended up using this because it was the simplest to implement:
var names = [];
var namesLen = names.length;
for (i=0; i<namesLen; i++) {
for (x=0; x<namesLen; x++) {
if (names[i] === names[x] && (i !== x)) {alert('dupe')}
}
}
Well the usual way to do that would be to put each item in a hashmap dictionary and you could check if it was already inserted. If your list is of objects they you would have to create your own hash function on the object as you would know what makes each one unique. Check out the answer to this question.
JavaScript Hashmap Equivalent
This method uses an object as a lookup table to keep track of how many and which dups were found. It then returns an object with each dup and the dup count.
function findDups(list) {
var uniques = {}, val;
var dups = {};
for (var i = 0, len = list.length; i < len; i++) {
val = list[i];
if (val in uniques) {
uniques[val]++;
dups[val] = uniques[val];
} else {
uniques[val] = 1;
}
}
return(dups);
}
var data = [1,2,3,4,5,2,3,2,6,8,9,9];
findDups(data); // returns {2: 3, 3: 2, 9: 2}
var data2 = [1,2,3,4,5,6,7,8,9];
findDups(data2); // returns {}
var data3 = [1,1,1,1,1,2,3,4];
findDups(data3); // returns {1: 5}
Since we now have ES6 available with the built-in Map object, here's a version of findDups() that uses the Map object:
function findDups(list) {
const uniques = new Set(); // set of items found
const dups = new Map(); // count of items that have dups
for (let val of list) {
if (uniques.has(val)) {
let cnt = dups.get(val) || 1;
dups.set(val, ++cnt);
} else {
uniques.add(val);
}
}
return dups;
}
var data = [1,2,3,4,5,2,3,2,6,8,9,9];
log(findDups(data)); // returns {2 => 3, 3 => 2, 9 => 2}
var data2 = [1,2,3,4,5,6,7,8,9];
log(findDups(data2)); // returns empty map
var data3 = [1,1,1,1,1,2,3,4];
log(findDups(data3)); // returns {1 => 5}
// display resulting Map object (only used for debugging display in snippet)
function log(map) {
let output = [];
for (let [key, value] of map) {
output.push(key + " => " + value);
}
let div = document.createElement("div");
div.innerHTML = "{" + output.join(", ") + "}";
document.body.appendChild(div);
}
If your strings are in an array (A) you can use A.some-
it will return true and quit as soon as it finds a duplicate,
or return false if it has checked them all without any duplicates.
has_duplicates= A.some(function(itm){
return A.indexOf(itm)===A.lastIndexOf(itm);
});
If your list was just words or phrases, you could put them into an associative array.
var list=new Array("foo", "bar", "foobar", "foo", "bar");
var newlist= new Array();
for(i in list){
if(newlist[list[i]])
newlist[list[i]]++;
else
newlist[list[i]]=1;
}
Your final array should look like this:
"foo"=>2, "bar"=>2, "foobar"=>1
I have two JavaScript arrays below that both have the same number of entries, but that number can vary.
[{"branchids":"5006"},{"branchids":"5007"},{"branchids":"5009"}]
[{"branchnames":"GrooveToyota"},{"branchnames":"GrooveSubaru"},{"branchnames":"GrooveFord"}]
I want to combine these two arrays so that I get
[{"5006":"GrooveToyota"},{"5007":"GrooveSubaru"},{"5008":"GrooveFord"}]
I'm not sure how to put it into words but hopefully someone understands. I would like to do this with two arrays of arbitrary length (both the same length though).
Any tips appreciated.
It's kind of a zip:
function zip(a, b) {
var len = Math.min(a.length, b.length),
zipped = [],
i, obj;
for (i = 0; i < len; i++) {
obj= {};
obj[a[i].branchids] = b[i].branchnames;
zipped.push(obj);
}
return zipped;
}
Example (uses console.log ie users)
var ids = [{"branchids":"5006"},{"branchids":"5007"},{"branchids":"5009"}];
var names = [{"branchnames":"GrooveToyota"},{"branchnames":"GrooveSubaru"},{"branchnames":"GrooveFord"}];
var combined = [];
for (var i = 0; i < ids.length; i++) {
var combinedObject = {};
combinedObject[ids[i].branchids] = names[i].branchnames;
combined.push(combinedObject);
}
combined; // [{"5006":"GrooveToyota"},{"5006":"GrooveSubaru"},{"5006":"GrooveFord"}]
Personally, I would do it IAbstractDownvoteFactor's way (+1), but for another option, I present the following for your coding pleasure:
var a = [{"branchids":"5006"},{"branchids":"5007"},{"branchids":"5009"}];
var b = [{"branchnames":"GrooveToyota"},{"branchnames":"GrooveSubaru"},{"branchnames":"GrooveFord"}];
var zipped = a.map(function(o,i){ var n={};n[o.branchids]=b[i].branchnames;return n;});
similar to #robert solution but using Array.prototype.map
var ids = [{"branchids":"5006"},{"branchids":"5007"},{"branchids":"5009"}],
names = [{"branchnames":"GrooveToyota"},{"branchnames":"GrooveSubaru"},{"branchnames":"GrooveFord"}],
merged = ids.map(function (o, i) { var obj = {}; obj[o.branchids]=names[i].branchnames; return obj; });
merged; //[{5006: "GrooveToyota"}, {5006: "GrooveSubaru"}, {5006:"GrooveFord"}]
Cheers!