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var data = {};
data.info.id = "alpha";
This logs to the console: "TypeError: data.info is undefined".
Well that's great and all but I need to store a value in data.info.id. Isn't that what objects are supposed to do?
This should produce an object that looks like this:
data: {
info: {
id: "alpha"
}
}
Is data.info = {} really a necessary step?
In response to Patrick Evans - that's an unrelated question.
Well there is another way. That's putting the info-object directly in the data-object like this:
var data = {
info: {}
}
data.info.id = "alpha";
console.log(data);
Related
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Closed 26 days ago.
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I need to get the result of this object, I've tried json.count(id_reported) and json['count(id_reported)'] but none worked.
const json = {
'count(id_reported)': 21
};
//console.log(json.count(id_reported));
console.log(json['count(id_reported)']);
In Javascript, Typescript and so in Express in the end, its easy to handle such things.
var myObject = {
'count': 21
}
myObject = JSON.parse(myObject);
console.log(myObject.count);
The JSON.parse is only needed, if you object is a string. Is it a Javascript object you do not need to parse.
The count(id_reported) part I don't understand. If your object looks like this in the end:
{
count(1): 1,
count(2): 2,
}
and you don't know the structure at all you can use a for loop:
for (let data in myObject) {
console.log(data); // data will be the key; so count(1) as example
}
See the in keyword in the for loop. This will give you the key. The on keyword otherwise gives the object in an array as example.
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Consider this simple attempt to find a value in an object:
var config = {
product1: {
ids: ['master']
},
product2: {
ids: ['ps1', 'ps2']
}
};
var id = 'ps2';
var slotID = 'master';
var categorySlotIds = config[slotID].ids;
categorySlotIds.find(id);
I get: TypeError: Cannot find function find in object product1, product2
If I do typeof(categorySlotIDs) the result is object.
The manual for find says: The find() method returns the first element in the provided array
What gives?
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Closed 8 years ago.
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Can someone please explain why this code isn't working?
(it has been simplified for this example)
$(document).ready(function () {
var test = 'broken';
test = test.replace('broken','working');
console.log(test); // working
var field = $('[for="tournament_name"]').html();
console.log(field); // Tournament Name:
console.log(typeof field); // string
field = field.relpace(':',''); // Uncaught TypeError: undefined is not a function
});
I don't understand why it is saying replace() is undefined?
I did read through the docs, what am I missing here?
Maybe it's a typo:
relpace --> replace
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For some reason I need to push an Array inside other array.
For example,
var a = ["Test1", 1];
var b = ["Test2", 2];
var c = [];
c.push(a);
c.push(b);
alert(c);
For this code I need the following output,
["Test1", 1],["Test2", 2]
But what I am getting is
Test1,1,Test2,2
Any help will be highly appreciable.
You've already done it correctly: c.push(a) and c.push(b) work, but you don't want to use alert() for debugging.
Though it might be more convenient since you don't have to open up a console, it's going to give you output that is inconsistent with the actual structure of the data because using alert(x) converts whatever x is to a string.
Always use console.log(). Had you done that in this case, you would have seen something like this in the console:
Demo
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I am tying to add a property to a JS object inside a function. I can do it outside but not inside. Please explain. Sorry. I am missing something very basic here.
var newobj = {'prop1' : 12, 'prop2' : 25};
myfunc(newobj);
function myfunc(someobj) {
someobj.prop3 = 45;
}
This gives a syntax error.
Chances are something else is interfering because it works for me.
If you dump newobj before the function call you get:
{"prop1":12,"prop2":25}
And after the function call:
{"prop1":12,"prop2":25,"prop3":45}
As you can see, the new property has been added.
I would suggest either looking at what you have more closesly (make sure you're not copying the value and then passing it) or add some console.log call in your code as it goes through. You can also, in most of the browsers, use the debugger to step through the code to see where it may be fouled.