Can you help me solve a little problem?
I have some set of figures. After click, selected figure copied to another div (basket).
In the basket should appear new button. But in my solution this buttom appeared again after each click.
How I can fix this?
Thanks and sorry for my English
This code
<div class="products__list__items">
<div class="products__list__item row">
<figure class="product first" data-class="first">
<img src="https://www.tineye.com/images/robot-search-header.png" alt="product1" class="product__img">
<figcaption class="product__title">One</figcaption>
</figure>
</div>
<div class="products__list__item row">
<figure class="product first" data-class="first">
<img src="https://www.tineye.com/images/robot-search-header.png" alt="product1" class="product__img">
<figcaption class="product__title">Two</figcaption>
</figure>
</div>
<div class="products__list__item row">
<figure class="product first" data-class="first">
<img src="https://www.tineye.com/images/robot-search-header.png" alt="product1" class="product__img">
<figcaption class="product__title">Three</figcaption>
</figure>
</div>
</div>
<div class="basket">
</div>
Jquery code
$(document).ready(function() {
var addToBasket = function() {
var that = $(this);
if(!that.hasClass('added')) {
that.clone().appendTo($('.basket'));
that.addClass('added');
};
$('.basket .product').append('<button>x</button>');
};
$(document).on("click",".products__list__item .product",addToBasket);
});
Here fiddle
https://jsfiddle.net/fhxx9hm3/
You should add the button only once per product.
var addToBasket = function() {
var that = $(this);
if(!that.hasClass('added')) {
//Append the button here
that.clone().add('<button>x</button>').appendTo($('.basket'));
//Or
//that.clone().append('<button>x</button>').appendTo($('.basket'));
that.addClass('added');
};
//Following statement is not required
//$('.basket .product').append('<button>x</button>');
};
DEMO
Related
I have a problem where I'm making a card photo 1 that contains an invisible child container that has buttons and when mouse over it appears above the parent element photo 2, I have mouse out event that hides the child div and the problem is that the event occurs also when the mouse over the child div which cause the blinking of the child div (add CSS class that makes it visible and removes it at the same time, check attached gif)
addHandlerHoverCardView(handler) {
var card;
// parent element is movie-list
this._parentElement.addEventListener("mouseover", function (e) {
card = e.target.closest(".card");
if (card != null) {
handler(card, 'show');
}
})
this._parentElement.addEventListener('mouseout', function (e) {
const data = e.target.closest('.hover-div');
if (data != null) {
handler(card, 'hide');
}
})
}
<div class="movie-list">
<div class="movie-details">
<div class="card"
onmouseout="hideBottomCard()" onmouseover="showBottomCard()">
<img src="image\176630.jpg" alt="">
<div class="hover-div">
<div class="item">
<img src="image\active-my-list.png" alt="">
<img src="image\active-favourite.png" alt="">
<img src="image\active-watch-later.png" alt="">
</div>
</div>
</div>
<h5>2015 / Fiction, Drama</h5>
<h4>The Wolf Of Wall Street</h4>
</div>
</div>
You can try adding the onmouseout and onmouseover attr to the image, not the div.
<div class="movie-list">
<div class="card"
>
<img src="image\176630.jpg" alt="" onmouseout="hideBottomCard()" onmouseover="showBottomCard()">
<div class="hover-div">
<div class="item">
<img src="image\active-my-list.png" alt="">
<img src="image\active-favourite.png" alt="">
<img src="image\active-watch-later.png" alt="">
</div>
</div>
</div>
<h5>2015 / Fiction, Drama</h5>
<h4>The Wolf Of Wall Street</h4>
I spent lots of time trying to figure out getting a values from an element using jquery. Here's the code
<div class="school">
<div class="school-prev">
<img src="images/photos.png" class="img-responsive" alt="" />
</div>
<h5 class="school-title">Admin</h5>
<small class="text-muted">School Board</small>
</div>
<div class="school">
<div class="school-prev">
<img src="images/photos2.png" class="img-responsive" alt="" />
</div>
<h5 class="school-title">Finance</h5>
<small class="text-muted">School Board</small>
</div>
Jquery Coe
$(document).ready(function(){
$(".school").click('.school-title', function(e){
var showValue=$(this).text();
alert(showValue);
});
});
Example of return values: Admin School Board;
Expected value is should be "Admin or Finance"
NB: Any solution should consider outside div(school) clickable and not school-title div alone.
Warm regards.
Try the following jQuery code:
$(document).ready(function(){
// console.log('th');
$(document).on('click','.school .school-title', function(e){
e.preventDefault()
var th = $(this); //change over here
console.log(th.text());
});
});
You can change $(".school").click('.school-title', function(e){ to $(".school").on('click', '.school-title', function(e) { and it will solve the problem for you.
After updating your NB, you can use:
$(document).ready(function() {
$(".school").click(function(e) {
var showValue = $('.school-title',this).text()
alert(showValue);
});
});
Demo
$(document).ready(function() {
$(".school").click(function(e) {
var showValue = $('.school-title',this).text()
alert(showValue);
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="school">
<div class="school-prev">
<img src="images/photos.png" class="img-responsive" alt="" />
</div>
<h5 class="school-title">Admin</h5>
<small class="text-muted">School Board</small>
</div>
<div class="school">
<div class="school-prev">
<img src="images/photos2.png" class="img-responsive" alt="" />
</div>
<h5 class="school-title">Finance</h5>
<small class="text-muted">School Board</small>
</div>
You want a click anywhere in the school div to get the title - not just on the title itself. To do that, you just need to check for the school-title child element in the click function on school.
This will get all children with the class school-title (of which there will only be one - it works the same as find except on direct children only) and get the text from it:
$(document).ready(function(){
$(".school").click('.school-title', function(e){
var showValue=$(this).children('.school-title').text();
alert(showValue);
});
});
/* Just for illustration to make it easier to see what is happening */
.school { border: 1px solid #ccc;}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="school">
<div class="school-prev">
<img src="images/photos.png" class="img-responsive" alt="" />
</div>
<h5 class="school-title">Admin</h5>
<small class="text-muted">School Board</small>
</div>
<div class="school">
<div class="school-prev">
<img src="images/photos2.png" class="img-responsive" alt="" />
</div>
<h5 class="school-title">Finance</h5>
<small class="text-muted">School Board</small>
</div>
You only have one child with school-title in this case, but it will work with multiple titles if needed (e.g. if you did want to get "Admin School Board" for example, you could simply add the school-title class to the text-muted element).
Reference: jQuery children documentation
You are using 'school' class name for the click event and want to get the value child element of div. That is not possible in this way.
Simply Change the code "$(this).text();" to "$(classname,this).text();".
Happy coding.
I'm trying to get the value of an element when a user click on it. This is my code:
<div id="heroes-selection" class="row dflex justify-content-left">
<figure id="luna" class="heroes-pic border text-danger m-3" value="heroes.luna">
<img class="animated-gif">
</figure>
<figure id="qop" class="heroes-pic border text-danger m-3" value="heroes.qop">
<img class="animated-gif">
</figure>
</div>
I've tried to use Jquery $(this) and the result came out as undefined.
$(".heroes-pic").on("click", () => {
player = $(this).attr("value");
console.log(player);
});
My goal is to get the value heroes.luna when the user click on the figure with id="luna". The same for id="qop", I need to get the value heroes.qop. Thank you!
You have to use the classic function instead of arrow function. this on arrow function refers to the HTMLDocument and on the object clicked. And that is the reason why you are not getting the correct result. You are getting attr value from HTMLDocument.
$(".heroes-pic").on("click", function() {
player = $(this).attr("value");
console.log(player);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="heroes-selection" class="row dflex justify-content-left">
<figure id="luna" class="heroes-pic border text-danger m-3" value="heroes.luna"> heroes.luna
<img class="animated-gif">
</figure>
<figure id="qop" class="heroes-pic border text-danger m-3" value="heroes.qop"> heroes.qop
<img class="animated-gif">
</figure>
</div>
Other option: you can use event.currentTarget instead of this on arrow function
Like:
$(".heroes-pic").on("click", (event) => {
player = $(event.currentTarget).attr("value");
console.log(player);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="heroes-selection" class="row dflex justify-content-left">
<figure id="luna" class="heroes-pic border text-danger m-3" value="heroes.luna">
<img class="animated-gif">heroes.luna
</figure>
<figure id="qop" class="heroes-pic border text-danger m-3" value="heroes.qop">
<img class="animated-gif">heroes.qop
</figure>
</div>
This is because you are using an arrow function that binds the this parameter to the enclosing scope's this.
See https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Functions/Arrow_functions#No_separate_this
replace it with a function:
$(".heroes-pic").on("click", function () {
player = $(this).attr("value");
console.log(player);
}
I have the main image and a zoom icon for it and I have an image next to the first image. I wanna write a JavaScript code where when I click on the second image it changes the first image scr and the zoom icon's href link I found a code for it, but I can't make it work. This is the code I have so far:
<script type="text/javascript">
function change(menuId, image, newImage, newUrl)
{
var img = document.getElementById(image);
img.src = newImage;
document.getElementById('d3').href = newUrl;
}
</script>
and i tried to do make it work like that
<script type="text/javascript">
function change(menuId, image, newImage, newUrl)
{
var img = document.getElementById(image);
img.src = newImage;
document.getElementById('d3').href = newUrl;
}
</script>
<div class="thumbnail">
<div id="main_img">
<img id="img" src="assets/example/latest/S8621A.png" alt=""/>
<div class="caption">
<span class="ico-block">
<a class="ico-zoom" href="assets/example/latest/S8621A.png" id="d3"><span></span></a>
</span>
</div>
</div>
</div>
<div style="text-align:center">
<div id="thumb_img">
<img src='assets/img/fekete.png' onclick='changeImage("assets/example/latest/S8621A.png")' >
<img src='assets/img/barna.png' onclick='changeImage("assets/example/latest/S8621B.png")' onclick='document.getElementById'("d3").href = '(assets/example/latest/S8621B.png)'>
</div></div>
I just don't know how it should work. I really don't understand that whole JavaScript. Can someone help me or show me how will it work? THX for the help.
As others have already said, change() should be changeImage() or vice versa.
There was no obvious target for the MenuId parameter so it's removed.
Made the zoomImage() function just for the hell of it.
Click any of the bottom images and the top one changes and the GO link's href changes as well.
The zoom icon will enlarge the top image by 50% without leaving the page.
Added 2 more functions…not sure what OP wants.
imageZoom() will use transform: scale() to zoom the image.
resetImage() will reset the image back to 128px
Snippet
img {
cursor: pointer;
}
<script src="http://gh-canon.github.io/stack-snippet-console/console.min.js"></script>
<script type="text/javascript">
function changeImage(newImage, newUrl) {
var img = document.getElementById('img');
img.src = newImage;
document.getElementById('goto').href = newUrl;
return false;
}
function zoomImage() {
var img = document.getElementById('img');
if (img.style.width == "192px") {
img.style.width = "128px"
} else {
img.style.width = "192px";
}
return false;
}
function imageZoom() {
var img = document.getElementById('img');
if (img.style.width == "512px") {
img.style.transform = "scale(.25)";
} else {
img.style.transform = "scale(4)";
}
return false;;
}
function resetImage() {
var img = document.getElementById('img');
img.style.width = "0px";
img.style.transform = "scale(1)"
img.style.width = "128px";
return false;
}
</script>
<div class="thumbnail">
<div id="main_img">
<img id="img" src="https://upload.wikimedia.org/wikipedia/en/2/24/Lenna.png" alt="" width="128" />
<div class="caption">
<div class="ico-block">
<a id="goto" href="https://upload.wikimedia.org/wikipedia/en/2/24/Lenna.png">GO</a>
<a class="ico-big" href="#" id="d3" width="32" onclick="zoomImage();">
<img src="http://icons.iconarchive.com/icons/rafiqul-hassan/blogger/32/Zoom-In-icon.png" />
</a>
<a class="ico-zoom" href="#" id="3d" width="32" onclick="imageZoom();">
<img src="https://image.freepik.com/free-icon/zoom-in-pc_318-11477.jpg" width="32" />
</a>
</div>
</div>
</div>
</div>
<div style="text-align:center">
<div id="thumb_img">
<img src='http://i44.tinypic.com/2uxz43b.jpg' onclick='changeImage("http://cnx.org/resources/b785d2ec9b6302264f1ed942f4ec1b822d6f7b4c/lena.jpg", "http://cnx.org/resources/b785d2ec9b6302264f1ed942f4ec1b822d6f7b4c/lena.jpg")' width="128">
<img src='http://www.log85.com/tmp/doc/img/perfectas/lenna/lenna1.jpg' onclick='changeImage("http://lh3.ggpht.com/_ERXQs5oLNgE/S01Ee_26lsI/AAAAAAAAAlY/1T0Dl4QJiYk/s800/lenaV.jpg", "http://lh3.ggpht.com/_ERXQs5oLNgE/S01Ee_26lsI/AAAAAAAAAlY/1T0Dl4QJiYk/s800/lenaV.jpg")'
width="128">
<button onclick="resetImage();">RESET</button>
</div>
</div>
First you need to make sure the js function works.
Second, <img src='assets/img/barna.png' onclick='changeImage("assets/example/latest/S8621B.png")' onclick='document.getElementById'("d3").href = '(assets/example/latest/S8621B.png)'> is not right, it should be
<img src='assets/img/barna.png' onclick='changeImage("assets/example/latest/S8621B.png")' onclick='document.getElementById("d3").href = "assets/example/latest/S8621B.png"'> if my understanding is right.
Small description would be: you just need to assign clicked image to zoom icon to give it toggle effect.[that we doing by getElementById("d3") part
<script type="text/javascript">
function changeImage(element,newUrl) {
element.src = newUrl;
document.getElementById("d3").href= newUrl;
}
</script>
<div class="thumbnail">
<div id="main_img">
<img id="img" src="assets/example/latest/S8621A.png" alt=""/>
<div class="caption">
<span class="ico-block">
<a class="ico-zoom" href="assets/example/latest/S8621A.png" id="d3"><span></span></a>
</span>
</div>
</div>
</div>
<div style="text-align:center">
<div id="thumb_img">
<img src='assets/img/fekete.png' onclick='changeImage(this, "assets/example/latest/S8621A.png")'>
<img src='assets/img/barna.png' onclick='changeImage(this, "assets/example/latest/S8621B.png")'>
</div>
</div></div>
This should do it:
function changeImage(element,newUrl) {
element.src = newUrl;
document.getElementById('d3').href = newUrl;
}
<div class="thumbnail">
<div id="main_img">
<img id="img" src="assets/example/latest/S8621A.png" alt="" />
<div class="caption">
<span class="ico-block">
<a class="ico-zoom" href="assets/example/latest/S8621A.png" id="d3"><span></span>
</a>
</span>
</div>
</div>
</div>
<div style="text-align:center">
<div id="thumb_img">
<img src='assets/img/fekete.png' onclick='changeImage(this, "assets/example/latest/S8621A.png")'>
<img src='assets/img/barna.png' onclick='changeImage(this, "assets/example/latest/S8621B.png")' onclick='document.getElementById' ( "d3").href='(assets/example/latest/S8621B.png)'>
</div>
</div>
Hey Robert Updated now
<!-- start: Portfolio -->
<section id="portfolio-grid" class="portfolio">
<article class="javascript html">
<script type="text/javascript">
function changeImage(element,newUrl) {
element.src = newUrl;
document.getElementById('d3').href = newUrl;
}
</script>
<div class="thumbnail">
<div id="main_img">
<img id="img" src="assets/example/latest/S8621A.png" alt="" />
<div class="caption">
<span class="ico-block">
<a class="ico-zoom" href="assets/example/latest/S8621A.png" id="d3"><span></span>
</a>
</span>
</div>
</div>
</div>
<div style="text-align:center">
<div id="thumb_img">
<img src='assets/img/fekete.png' onclick='changeImage(this, "assets/example/latest/S8621A.png")'>
<img src='assets/img/barna.png' onclick='changeImage(this, "assets/example/latest/S8621B.png")'>
</div>
</div>
I am a newbie to JavaScript and I need to use it with bootstrap for my own web page. My question is now how can I make a loop so that pictures names (stored as an array) can emerge in the right places of the HTML code so I do not have to copy the blocks of code for each picture.
For example :
<div class="row">
<div class="col-md-3 col-xs-6 portfolio-item">
<img class="img-responsive" src="01.jpg">
</div>
</div>
<div class="row">
<div class="col-md-3 col-xs-6 portfolio-item">
<img class="img-responsive" src="01.jpg">
</div>
</div>
<div class="row">
<div class="col-md-3 col-xs-6 portfolio-item">
<img class="img-responsive" src="02.jpg">
</div>
</div>
<div class="row">
<div class="col-md-3 col-xs-6 portfolio-item">
<img class="img-responsive" src="03.jpg">
</div>
</div>
As we can see here the only different text is the src.How can I store the names (paths) in an array and make a loop that changes the src property?
Thank you!
Try this demo: http://jsbin.com/pinoxeqapi/1/edit?html,output
I think that's what you're looking for.
CODE
$(function () {
var images = ["01.jpg", "01.jpg", "02.jpg", "03.jpg"];
$.each(images, function (index, element) {
var imgContainer = "<div class='row'><div class='col-md-3 col-xs-6 portfolio-item><img class='img-responsive' src='" + element + "'></div></div>";
$("body").append(imgContainer);
});
});
First Include JQuery (If not)
<script>
var srcArray = ['01.jpg', '02.jpg', '03.jpg', '04.jpg'];
$(document).ready(function () {
for (var i = 0; i < srcArray.length; i++) {
$('div.row img.img-responsive').eq(i).attr("src", srcArray[i]);
}
});
</script>
I would recommend using one of the templating frameworks described in some of the other answers. If you're interested to see how to implement this in pure JS:
var temp = document.querySelector('#portfolio-item-template');
['01.jpg', '02.jpg', '03.jpg', '04.jpg'].forEach(function(src) {
temp.content.querySelector(".img-responsive").src = src;
var newImg = document.importNode(temp.content, true);
document.querySelector('#insertion-point').appendChild(newImg);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<template id="portfolio-item-template">
<div class="row">
<div class="col-md-3 col-xs-6 portfolio-item">
<img class="img-responsive">
</div>
</div>
</template>
<div id="insertion-point">
</div>
You can use a template stored in the HTML and then generate the actual elements using an array of the image sources. Something like John Resig's micro-templates can achieve this.
<script type="text/template" id="img-tmpl">
<div class="row">
<div class="col-md-3 col-xs-6 portfolio-item>
<img class="img-responsive" src="<%= src %>">
</div>
</div>
</script>