Develop Reference

How do I Store the Value of Table Data which is Being Passed Dynamically from PHP to JavaScript after a Button Click Event?

I've been Trying to List Users in a 1 to 1 Chat Application in HTML Tables & uniquely Define Each Table cell data by the Name ID dynamically in PHP. The problem is I am Unable to retrieve the Same Table Cell Value after a Button Click for that Particular Record even after Passing the Name value in PHP.
<?php
include("functions.php");
$token = $user_details[5];
// Get all Users except the Logged user
$users_list = get_users_list($user_details[2]);
?>
<table class="table">
<thead class="thead-style">
<tr>
<td class="text-center">Users List</td>
<td class="text-center">Login Status</td>
<td class="text-center"></td>
</tr>
</thead>
<tbody>
<?php
while($fetch = mysqli_fetch_assoc($users_list))
{
?>
<tr class="table-row-users">
<td class="text-center" id="<?php echo $fetch['user_name']; ?>" value="<?php echo $fetch['user_name']; ?>">
<?php echo $fetch['user_name']; ?></td>
<td class="text-center"><?php echo $fetch['user_login_status']; ?></td>
<td class="text-center"><button class="btn btn-outline-primary receiver_email='<?php echo base64_encode($fetch["user_email"]);?>'" id="single_chat" onclick='setReceiver("<?php echo $fetch['user_name']; ?>")'>Chat</button></td>
</tr>
<?php
}
?>
</tbody>
</table>
JavaScript Code
function setReceiver(receiver_name)
{
var to_user_name = document.getElementById(receiver_name).value;//Unable to Retrieve the Value here
console.log(to_user_name);
//$('.receiver').append(to_user_name);
}
I am Facing the Error on the JS Side. Also this is my 1st Question on Stack Overflow.

After the click does not appear in bold

I created an internal email system within the project. When I receive a new message the column with the subject name in my table is bolded to inform that the message has not yet been read.
code:
<?php
while($row = mysqli_fetch_array($result))
{
?>
<section id="s1">
<div class="div1" id="minhaDiv" style="float: left;">
<table class="table table-bordered">
<tr>
<th width="20%">De</th>
<th width="60%">Assunto</th>
<th width="10%">Prioridade</th>
<th width="10%">Recebido</th>
</tr>
<tr>
<th width="10%" colspan=4>Recebido: <?php echo $row["Data"]; ?></th>
</tr>
<tr>
<td><?php echo $row["De"]; ?></td>
<td class="td-info view_data" id="<?php echo $row["Id"]; ?>" data-toggle="modal" href="#dataModal" width="20%" style="font-weight:bold" onclick="this.style['font-weight'] ='normal'"><?php echo $row["Assunto"]; ?></td>
<td><?php echo $row["Prioridade"]; ?></td>
<td><?php echo $row["Hora"]; ?></td>
</tr>
<tr>
<?php
}
?>
</table>
</div>
</section>
In the image, which is surrounded by green already clicked to read, the red has not yet vliquei to read, so it is bold:
I use this code to put bold inside the td:
width="20%" style="font-weight:bold" onclick="this.style['font-weight'] ='normal'"
The problem is that if you refresh the page, even after reading the messages, they come back in bold and should not. After clicking once, they can not be left in bold

Solution to achieve the condition.
I created a Status field in the database table, where 1 is unread message and 0 message is read, now is to create the condition in td with if. In the javascript with which I open the modal I made the following change:
$('.td-info').click(function(){
var item_id = $(this).attr("id");
var status = $(this).attr("Status");
$.ajax({
url:"./fetchRAD",
method: "POST",
data:{item_id:item_id, status:status},
success:function(data){
}
});
});
In td I indicated the id of the record in the id of td:
id="<?php echo $row["Id"]; ?>"
file with php:
if(isset($_POST["item_id"]))
{
$query = "Update centrodb.Alertas SET Status = '0' WHERE Id = '".$_POST["item_id"]."'";
$result = mysqli_query($conn, $query);
}
Pata check in the td we put like this:
width="20%" <?php echo $row["Status"] == '1'?' style="font-weight:bold" ':' style="font-weight:normal" '?>
td complete:
<td class="td-info view_data" id="<?php echo $row["Id"]; ?>" data-toggle="modal" href="#dataModal" width="20%" <?php echo $row["Status"] == '1'?' style="font-weight:bold" ':' style="font-weight:normal" '?>><?php echo $row["Assunto"]; ?></td>

Delete from database using javascript

I have a page containing a database table with all the rows and columns.
What I am trying to do is to select all the rows I want and then delete them when I click on the button.
This is what I've done so far in the table.php page:
<?php
include "config.php"; //connection to database
incude "home.js";
$funcao="Select * from palavras";
$result=mysqli_query($link, $funcao);
?>
<button id="button_apaga" type="button" onclick="delete()" > DELETE </button>
<?php if($result->num_rows > 0) { ?>
<table class="table">
<tr>
<th>IdPalavra</th>
<th>Palavra</th>
<th>Grau de Dificuldade</th>
<th>Data</th>
<th>Hora</th>
<th>Selecionar</th>
</tr>
<?php while($row = mysqli_fetch_assoc($result)) { ?>
<tr role="row">
<td><?php echo $row['idpalavras']; ?></td>
<td><?php echo $row['palavra']; ?></td>
<td><?php echo $row['graudificuldade']; ?></td>
<td><?php echo $row['data']; ?></td>
<td><?php echo $row['hora']; ?></td>
<td><input type="checkbox" name="check" id="checkbox" /></td>
</tr>
<?php } ?>
</table>
<?php }
else{
echo "0 resultados";
} ?>
JavaScript Page (home.js):
function delete(id){
var check = document.getElementById('checkbox');
if(check.checked) {
// sql query
}
My question is how can I do que sql query considering it's in a different page. Can I just open php and put the query inside?
Also how can I receive all the IDs from the selected rows to the function?
Thank you in advance.

One approach would be to use AJAX. For the purpose of condensing the code, I'm going to also incorporate jQuery into this solution. I am also going to change your checkbox to an individual button link for the sake of making this a bit less code. A solution to delete multiple at the same time could work similarly to this, but since you're using AJAX most likely this is going to be easier for your users.
Modify table.php
<?php
include "config.php"; //connection to database
incude "home.js";
$funcao="Select * from palavras";
$result=mysqli_query($link, $funcao);
?>
<?php if($result->num_rows > 0) { ?>
<table class="table">
<tr>
<th>IdPalavra</th>
<th>Palavra</th>
<th>Grau de Dificuldade</th>
<th>Data</th>
<th>Hora</th>
<th>Selecionar</th>
</tr>
<?php while($row = mysqli_fetch_assoc($result)) { ?>
<tr role="row" class="palavras_row">
<td><?php echo $row['idpalavras']; ?></td>
<td><?php echo $row['palavra']; ?></td>
<td><?php echo $row['graudificuldade']; ?></td>
<td><?php echo $row['data']; ?></td>
<td><?php echo $row['hora']; ?></td>
<td>Delete</td>
</tr>
<?php } ?>
</table>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js?ver=3.3.1"></script>
<script type="text/javascript">
(function($) {
$(document).on('click', '.palavras_row a.palavras_delete', function() {
var _id = $(this).attr('data-id');
var _row = $(this).parent().parent();
$.ajax({
url: 'delete.php',
data: {
idpalavras: _id
},
type: 'POST',
dataType: 'json',
success: function(__resp) {
if (__resp.success) {
_row.remove(); // Deletes the row from the table
}
}
});
});
})(jQuery);
</script>
Create a new file in the same folder as your table.php and name it delete.php
<?php
$idpalavras = filter_input(INPUT_POST, 'idpalavras', FILTER_SANITIZE_NUMBER_INT);
$success = false;
if ($idpalavras) {
include "config.php"; //connection to database
$funcao="delete from palavras where idpalavras = " . $idpalavras;
$result=mysqli_query($link, $funcao);
$success = true;
}
header('Content-Type: application/json');
echo json_encode(array('success' => $success));
The solution above sends a simple command to your PHP backend where the delete query can be run by PHP. You cannot run a mysql command directly from javascript since that is frontend code.
This code is a functional solution, but it is abbreviated; a more complete solution would have more detailed handling of potential errors (either via AJAX or processing your delete query). It should also have some security on your delete.php to make sure unauthorized users aren't able to delete records without the proper permission to do so.

How to use jQuery POST instead of html form to delete table entry

I am trying to delete the table entry without opening the .php file using jQuery post.
The whole thing works without problems when I just use the usual html post form.
The alert(data) does not trigger, it only adds ".../?player_id_del=1" or whatever ID click into the URL.
What am I doing wrong?
Here is some of my index.php, i get the whole data from a database:
<table class = "table table-hover">
<thead>
<tr>
<th>Player_ID</th>
<th>Username</th>
<th>First_Name</th>
<th>Last_Name</th>
<th>Rating</th>
<th>Country</th>
<th>Colour</th>
<th></th>
</tr>
</thead>
<tbody>
<? foreach($playerArray as $player):?>
<tr>
<td><? echo $player["PLAYER_ID"]; ?></td>
<td><? echo $player["USERNAME"]; ?></td>
<td><? echo $player["FIRST_NAME"]; ?></td>
<td><? echo $player["LAST_NAME"]; ?></td>
<td><? echo $player["RATING"]; ?></td>
<td><? echo $player["COUNTRY"]; ?></td>
<td><? echo $player["COLOUR"]; ?></td>
<td>
<form id="del-form">
<div>
<input type="number" id="player_id_del" name="player_id_del" value="<?php echo htmlspecialchars($player["PLAYER_ID"]); ?>" />
</div>
<div>
<button type="submit" id="submit-btn" class="btn btn-danger">Delete</button>
</div>
</form>
<script>
$("#submit-btn").click(function(){
$.post("deletePlayer.php", $("#del-form").serialize() , function(data) {
alert(data);
});
});
</script>
</td>
</tr>
<? endforeach ?>
</tbody>
</table>
Here is my deletePlayer.php:
<?php
//include DatabaseHelper.php file
require_once('DatabaseHelper.php');
//instantiate DatabaseHelper class
$database = new DatabaseHelper();
//Grab variable id from POST request
$player_id = '';
if(isset($_POST['player_id_del'])){
$player_id = $_POST['player_id_del'];
}
// Delete method
$error_code = $database->deletePlayer($player_id);
// Check result
if ($error_code == 1){
echo "Player with ID: '{$player_id}' successfully deleted!'";
}
else{
echo "Error can't delete Player with ID: '{$player_id}'. Errorcode: {$error_code}";
}
?>
Thank You in advance for any help!

By default jQuery's click event reload the document so, you should try using,
$("#submit-btn").click(function(e){
e.preventDefault();
e.stopPropagation();
});
Also instead of $.post, try using $.ajax

There are many issues in your code
E.g IDs for form and delete input button are repeating (id of element should not be same it should be unique),
The following code is the tested and working.
<?php
//include DatabaseHelper.php file
require_once('DatabaseHelper.php');
//instantiate DatabaseHelper class
$database = new DatabaseHelper();
$response = array();
//Grab variable id from POST request
$player_id = '';
if(isset($_POST['player_id_del'])){
$player_id = $_POST['player_id_del'];
}
// Delete method
$error_code = $database->deletePlayer($player_id);
// Check result
if ($error_code == 1){
$response["success"] = 1;
$response["id"] = $player_id;
$response["message"] = "Player with ID: '{$player_id}' successfully deleted!'";
}
else{
$response["success"] = 0;
$response["message"]= "Error can't delete Player with ID: '{$player_id}'. Errorcode: {$error_code}";
}
echo json_encode($response);
?>
<table class = "table table-hover" id="mPlayersTabel">
<thead>
<tr>
<th>Player_ID</th>
<th>Username</th>
<th>First_Name</th>
<th>Last_Name</th>
<th>Rating</th>
<th>Country</th>
<th>Colour</th>
<th></th>
</tr>
</thead>
<tbody>
<? foreach($playerArray as $player):?>
<tr id= "<? echo $player["PLAYER_ID"]; ?>">
<td><? echo $player["PLAYER_ID"]; ?></td>
<td><? echo $player["USERNAME"]; ?></td>
<td><? echo $player["FIRST_NAME"]; ?></td>
<td><? echo $player["LAST_NAME"]; ?></td>
<td><? echo $player["RATING"]; ?></td>
<td><? echo $player["COUNTRY"]; ?></td>
<td><? echo $player["COLOUR"]; ?></td>
<td>
<div>
<button type="submit" player-id="<? echo $player["PLAYER_ID"]; ?>" class="btn btn-danger" >Delete</button>
</div>
</td>
</tr>
<? endforeach ?>
</tbody>
</table>
<script>
$(document).ready(function(){
$(".btn-danger").on("click touchend" , function(){
var id = $(this).attr("player-id");
$.ajax({
url: 'deletePlayer.php',
type: 'POST',
data: {
player_id_del: id
},
dataType: 'json',
success: function (response) {
//Add this line and try
response = JSON.parse(JSON.stringify(response));
alert(response['message']);
switch (response['success']) {
case 1:
$("#mPlayer" + response['id']).remove();
break;
}
}
});
});
});
</script>

php with mqsql view data I was try do view in php. But first data does't show in output. Remaining data displayed. how can i get all data in table

I was try do view in php. But first data now showing in output. Remaining data displayed. how can i get all data in table.
<html>
<body>
<?php
include('connect.php');
$select=mysql_query("SELECT id,username FROM user order by id");
$i=1;
while($userrow=mysql_fetch_array($select))
{
$id=$userrow['id'];
$name=$userrow['username'];
?>
<table width="600" border="1" cellpadding="1" cellspaceing="1" >
<tr >
<th class="active">ID</th>
<th class="active">Name</th>
<tr>
<?php
while ($employee=mysql_fetch_assoc($select))
{
echo "<tr>";
echo "<td>".$employee['id']."</td>";
echo "<td>".$employee['username']."</td>";
}
}
?>
</table>
</body>
</html>

There are multiple issues:
Table rows had not been closed (</tr>)
Usage of mysql_* functions is deprecated in PHP 5 and removed in PHP 7; if you're writing new code, you should not be using mysql_* functions. Instead, use mysqli_* functions or the PDO library.
There were multiple for-loops to get records, but it would create new tables each iteration.
The table attribute "cellspacing" was misspelled.
The results object where they are stored can either be a resource or false.
Given these, I've made the following changes that will fix the above problems:
<?php
// I've commented out the connect.php file inclusion to highlight the change to how
// you'd connect to the MySQL database using mysqli_* instead of mysql_*. I'm guessing
// as to the contents of connect.php, but this should still highlight what needs to be
// done
// include('connect.php');
$db_connection = mysqli_connect('host', 'user', 'pass', 'database_name');
$employee_results = mysqli_query($db_connection, "SELECT id,username FROM user ORDER BY id");
?>
<html>
<body>
<table width="600" border="1" cellpadding="1" cellspacing="1">
<tr>
<th class="active">ID</th>
<th class="active">Name</th>
</tr>
<?php if ($employee_results === false): ?>
<tr>
<td colspan="2">No users</td>
</tr>
<?php else: ?>
<?php while ($employee = mysqli_fetch_assoc($employee_results)): ?>
<tr>
<td><?= $employee['id'] ?></td>
<td><?= $employee['username'] ?></td>
</tr>
<?php endwhile ?>
<?php endif ?>
</table>
</body>
</html>

<html>
<body>
<?php
include('connect.php');
$select=mysql_query("SELECT id,username FROM user order by id");
$i=1; ?>
<table width="600" border="1" cellpadding="1" cellspaceing="1" >
<tr>
<th class="active">ID</th>
<th class="active">Name</th></tr>
<?php while($userrow=mysql_fetch_array($select))
{
$id=$userrow['id'];
$name=$userrow['username'];
?>
<?php
echo "<tr>";
echo "<td>".$id."</td>";
echo "<td>".$name."</td></tr>";
}
?>
</table>
</body>
</html>`