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I get the content of a textarea with:
var stringArray = document.getElementById('textarea').value;
I must remove all blank lines (even blank lines with spaces). What is an efficient way to do that?
EDIT: I want to remove the blank lines, not the whitespace.
e.g.
A
B
C
D
to
A
B
C
D
Finally I managed to make it work. This is the code just in case someone else would need it:
function delBlankLines() {
var stringArray = document.getElementById('textarea').value.split('\n');
var temp = [""];
var x = 0;
for (var i = 0; i < stringArray.length; i++) {
if (stringArray[i].trim() != "") {
temp[x] = stringArray[i];
x++;
}
}
temp = temp.join('\n');
document.myform.textarea.value = temp;
}
So, the textarea content is split into a string array, that array is looped and checked if the trimmed current line is blank; if it's not, the line is copied to a temporary string array (basically the blank lines are ignored). At the end, I update the textarea with the temporary string array.
you can use the native JavaScript trim method (available on the string prototype): textareaValue.trim().
Trivia: there's automatic setting of window.textarea to be document.getElementById('textarea'). So you can access that by just doing textarea. Therefore to access the textual content of the textarea you can use: textarea.innerHTML or const textAreaValue = textarea.value.
Next, run textAreaValue.trim(); this will get rid of any outer white space. " \n\n textArea \n\n\t\n " will turn into just "textArea".
Ok now we can split on new lines: const stringArray = textAreaValue.split('\n'). Since \n is the carriage return aka new line symbol.
Next, we'll want to skip any lines which have nothing but whitespace which we can probably find in a few ways but to be safest \S should work. To test out different regexes I recommend: regex101.com.
For a more modern version:
textarea.value = `
the
quick
brown
fox
jumped
over the lazy
dog.
`;
/*
function oldSolution() {
var cleanedString = '';
console.log(textarea.value);
var stringArray = textarea.value.trim().split('\n');
for(var i = 0; i < stringArray.length; i++){
var line = stringArray[i];
if(line.match('/\S/') !== -1){
cleanedString += line.trim();
}
}
console.log(cleanedString);
output.innerText = cleanedString;
return cleanedString;
}
*/
const cleanText = () => {
const stringArray = textarea.value
.trim()
.split('\n')
.filter(line => /\S/.test(line));
console.log({stringArray})
const cleanedString = stringArray.map(line => line.trim()).join(' ');
console.log(cleanedString);
output.innerText = cleanedString;
return cleanedString;
}
<textarea rows='5' cols='50' id='textarea'></textarea>
<input type='button' value='Extract Text' onclick='cleanText()'/>
<div id="output"></div>
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I can't run my code in the Google Apps Script editor. Clicking Run gives the error document is undefined.
I am trying to create a function that separates a String into substrings using a separator character and returns those substrings in an array.
function splitSrt(str, delim) {
var word = "";
var num = 0;
str = str + delim;
var x = str.length;
var substr_list = [];
for( var i = 0; i < x; i++){
if(str[i] != delim)
word = word + str[i];
else{
if(word.length != 0)
substr_list.push(word);
word = "";
}
}
return substr_list;
}
var str = "hello my world";
var delim = ' ';
var res = splitSrt(str, delim);
res.forEach(a => {
document.write( a + "<br>");
});
The code you quote will not work in Apps Script because it is attempting to write to a web page through the DOM method document.write(), which is not available in server-side code such as Node.js or Apps Script.
The problem is "function that separates a String into substrings using a passable character and returns them in an array"
You probably do not need to write a function for that. Simply use String.split(), like this:
function test() {
const str = "hello my world";
const delim = ' ';
const res = str.split(delim);
res.forEach(word => {
console.log(word);
});
}
For more complex splitting, use a regular expression as the separator.
If you really need to create your own string splitter function, start with something like this:
function splitSrt(str, delim) {
return String(str).split(delim);
}
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Edited because i wasn't clear enough
I have some text from a .txt file, that i want to display on a HTML page. I want to have a linebreak before- and after an uppercase line, but not for standalone words. Like if more than 2 words are uppercase, they should be on a seperate line, but not if its only one word.
const text1 = "I want THIS ON A SEPERATE LINE but not THIS text here";
function convertText(text) {
...check for uppercase line....
document.write(modifiedText)
}
convertText(text1);
/*
Wanted result:
I want
THIS ON A SEPERATE LINE
but not THIS text here
*/
How can I do this?
You'll need to split each word up, put them into groups of capitalised and non-capitalised and then iterate through those groups, checking each word to find if there are multiple capitalised words in each group. Something like the following should do the job:
function convertText(text) {
const words = text.split(' '); // split the string into an array of word strings
let currentLine = '';
// groups of words of the same case
const wordGroups = [];
let lastWordWasAllCaps = false;
// group words by case
for (const word of words) {
if (word === word.toUpperCase()) {
if(!lastWordWasAllCaps) {
// word is in block capitals, but the last one wasn't
wordGroups.push(currentLine);
currentLine = word;
} else {
currentLine = currentLine.concat(' ', word);
}
lastWordWasAllCaps = true;
} else {
if (lastWordWasAllCaps) {
// word is not in block capitals, but the last one was
wordGroups.push(currentLine);
currentLine = word;
} else {
currentLine = currentLine.concat(' ', word);
}
lastWordWasAllCaps = false;
}
}
// push the last line
wordGroups.push(currentLine);
let finalString = '';
let breakNextLine = true;
// now look through the groups of words and join any single full capital words to their siblings
for (const wordGroup of wordGroups) {
// if a group is all caps and has no spaces, join it without a line break
if (wordGroup === wordGroup.toUpperCase() && !wordGroup.includes(' ')) {
finalString = finalString.concat(' ', wordGroup);
// tell the next set to join without a line break
breakNextLine = false;
} else {
if (breakNextLine) {
finalString = finalString.concat('\n', wordGroup);
} else {
finalString = finalString.concat(' ', wordGroup);
}
breakNextLine = true;
}
}
return finalString.slice(2); // remove the added spaces at the start
}
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If i have 'var' how can i get "e,o,o" out of it ?
With substring you can only get the position
var str = "Hello world!";
var res = str.substring(1, 4);
It's not entirely clear if you only want the vowels or if you want all except the vowels. Either way, a simple regular expression can get the characters you need.
let str = "Hello World";
let res = str.match(/[aeiou]/ig).join("");
console.log(res);
let res2 = str.match(/[^aeiou]/ig).join("");
console.log(res2);
Remove the .join("") part if you want an array, otherwise this gives you a string
How about:
var str = "Hello world!";
var theGoods = str.split('').filter(c => ['e', 'o'].includes(c)).join('');
Or if you wanted the 'inverse' behavior
var str = "Hello world!";
var theGoods = str.split('').filter(c => !['e', 'o'].includes(c)).join('');
You can loop the string and store those vowels in an array.
var arr = [];
for(var i = 0; i < str.length; i++){
if(str[i] == 'e' || str[i] == 'o'){
arr.push(str[i]);
}
}
console.log(arr);}
It's pretty easy to extract them, as long as you know RegEx (regular expression)
var str = "Hello world!" // The original string
var res = str.match(/[aeiou]/gi).join("") // Extracting the vowels
// If you want to get the consonants, here you go.
var res2 = str.match(/[^aeiou]/gi).join("")
// Logging them both
console.log(res)
console.log(res2)
function deletevowels(str) {
let result = str.replace(/[aeiou]/g, '')
return result
}
var text = "Hi test of Replace Javascript";
const a = deletevowels(text);
console.log(a);
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I am trying to clean up a string (anything that contains unwanted characters, diacritics, etc.) entered by a user and replace with just one string with no spaces.
I came across this error:
Execution failed: SyntaxError: Unterminated parenthetical.
It stopped at this line: idoff = accented.search(a2.charAt(i));
I was able to update our old legacy code when we encountered several accented letters (diacritics). I saw a code that I could use to resolve it but somehow I cannot figure out to how fix this one.
function clean(a2) {
/* if string contains accented letters, index below and use regular text */
var accented = 'ÁÀÂÃÄÄÅÆáàâãäåąÇçćčÐÉÉÊËèéêëðęÍÍÎÏíîïłÑñńÖÓŐÓÔÕØöóőôõøÜŰÙÚÛÜüűúûŠšŸÿýŽžŻżŁ';
var regularText = 'AAAAAAAAaaaaaaaaCcccDEEEEeeeeeeIIIIiiilNnnOOOOOOOooooooUUUUUUuuuuSSYyyZzZzL';
var idoff = -1,new_text = '';
var lentext = a2.toString().length -1
for (i = 0; i <= lentext; i++) {
idoff = accented.search(a2.charAt(i));
if (idoff == -1) {
new_text = new_text + a2.charAt(i);
} else {
new_text = new_text + regularText.charAt(idoff);
}
}
// return new_text;
/* Locate where in the string that contains ":", remove it including spaces and change string to lowercase */
var space = new_text.indexOf(":");
if (space > -1) {
var answer = new_text.substring(space);
answer = answer.replace(/[\.,-\/#!$%\^&\*;:{}=\-_`~()"'+#<>?]/g,"")
answer = answer.replace(/ /g,"");
answer = answer.toLowerCase();
} else {
var answer = new_text;
answer = answer.replace(/[\.,-\/#!$%\^&\*;:{}=\-_`~()"'+#<>?]/g,"")
answer = answer.replace(/ /g,"");
answer = answer.toLowerCase();
}
return answer;
}
If string is like this ABC-XYZ-LMN (AB12): XxxX Set Çompanÿ I want to clean it up to this xxxxsetcompany.
String.prototype.search expects a regular expression, but you're passing in a character (string). As you iterate over a2 you eventually come across an open parenthesis (the one surrounding "AB12"). An open parenthesis is not a valid regex.
To fix this you could use String.prototype.includes instead.
However, I think a more elegant solution to your issue may look something like this:
function clean(a2) {
/* if string contains accented letters, index below and use regular text */
const accented = 'ÁÀÂÃÄÄÅÆáàâãäåąÇçćčÐÉÉÊËèéêëðęÍÍÎÏíîïłÑñńÖÓŐÓÔÕØöóőôõøÜŰÙÚÛÜüűúûŠšŸÿýŽžŻżŁ';
const regularText = 'AAAAAAAAaaaaaaaCcccDEEEEeeeeeeIIIIiiilNnnOOOOOOOooooooUUUUUUuuuuSSYyyZzZzL'.split('');
let answer = '';
a2.split('').forEach((char) => {
let accentIndex = accented.indexOf(char);
if (accentIndex > -1) {
answer += regularText[accentIndex];
} else {
answer += char;
}
});
answer = answer.replace(/\W/gi, '');
return answer.toLowerCase();
}
console.log(clean('ABC-XYZ-LMN (AB12): XxxX Set Çompanÿ'));
Add the code after function clean(a2) {
var name = name;
name = name.replace(/[\])}[{(]/g, '');
name = name.toLowerCase();
...
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My objective is to split string (less than 80 characters) evenly to create a square or rectangle of strings.
var squareStr = function(str) {
}
console.log(squareStr('whatwonderfulday'));
console.log(squareStr('if life was easy god then god would not have given us brain to think'));
should output:
what
wond
erfu
lday
iflifewa
seasythe
ngodwoul
dnothave
givenusb
raintoth
ink
is this possible? I've been told I can use Math.sqrt but I'm not too sure how.
Thanks.
You can use a for loop to slice the string into the pieces and add a new line (\n) at the end of each chunk.
If you want to automatically use the square root of the string length you can do it like this:
function squareCode(string){
let squareString = "";
string = string.replace(/\s/g, '');
const splitNum = Math.floor(Math.sqrt(string.length));
for(i=0; i<= string.length; i+=splitNum){
squareString = `${squareString}${string.slice(i, i+splitNum)}\n`;
}
return squareString;
}
console.log(squareCode('whatwonderfulday'));
console.log(squareCode('if life was easy god then god would not have given us brain to think'));
console.log(squareCode('asdfasdf asdfasdfasd fasdfwe wer df gf dgdfgertqewdfsf fgdgewfwdsgewerfsd fdgdfgqefasdf'));
In the following function you'll pass in the string you want to slice as well as the number you want to slice at:
function squareCode(string, splitNum){
let squareString = "";
string = string.replace(/\s/g, '');
for(i=0; i<= string.length; i+=splitNum){
squareString = `${squareString}${string.slice(i, i+splitNum)}\n`;
}
return squareString;
}
console.log(squareCode('whatwonderfulday', 4));
console.log(squareCode('if life was easy god then god would not have given us brain to think', 8));
You could use this function. It replace all the empty spaces, then convert the string into an array and chunk it. Finally if merge every chunk and apply \n to each one.
var squareStr = function(str, chunk) {
str = str.replace(/ /g, '')
str = str.split('');
temp = []
for (i=0; i<str.length; i+=chunk)
temp.push(str.slice(i,i+chunk));
return temp.map(function(a){return a.join('')+"\n"}).join('')
}
console.log(squareStr('whatwonderfulday', 4));
console.log(squareStr('if life was easy god then god would not have given us brain to think', 8));
So many ways of doing that...
All other answers here are correct too, here's my approach, a more "readable" answer, using very basic recurses...
You have should at least tried...
I also have included a check to see if the string lenght is under 80.
var squareStr = function(str, charsPerLine) {
if (str.length > 80){
return;
}
str = str.replace(/ /g,'')
var stringSplited = str.split('');
var newString = '';
stringSplited.forEach(function(letter,index){
if (index % charsPerLine == 0 && newString.length > 0){
newString += '\n'; //IF YOU WANT TO USE IT IN THE HTML, USE '<br>' HERE
}
newString += letter;
});
console.log(newString);
return newString;
}
squareStr('whatwonderfulday', 4);
squareStr('if life was easy god then god would not have given us brain to think', 8);
Unless you're dealing with really long strings, I don't see a reason not to use replace to insert a newline every n characters:
function squareText(input) {
const inputNoSpaces = input.replace(/\s/g, '');
const partLen = Math.ceil(Math.sqrt(inputNoSpaces.length));
const replaceExpr = new RegExp(`.{1,${partLen}}`, 'g');
return inputNoSpaces.replace(replaceExpr, '$&\n');
}
const input = 'if life was easy then god would not have given us brain to think';
console.log(squareText(input));
This just calculates the line length and then creates a new RegExp that matches that many characters and uses it to replace each match with itself plus a newline.