I'm trying to modify my regex which requires user to type at least one letter and one digit which looks like this :
new RegExp('^(?=.*[a-z])(?=.*[0-9]).+$')
And I want to prevent user from using certain words like email address part before #.
So let's assume the email address is example#example.com
I want to force user to use a string that doesn't contain example in it (any part of the string)
This is what I have so far:
\b(?:(?!example)\w)+\b
But it doesn't really force the user to use at least one character and one digit.
When I'm trying to restric it I'm ending up with this:
\b(?:(?!example).*[a-z].*[0-9])+\b
But now the strings must follow the order of example then a [a-z] and then [0-9]
Any help greatly appreciated
Thanks!
In your sample the negative lookahead disallows example only at start of the string. Just add .*? as joker to disallow the word anywhere in the string and use word boundaries \b if needed.
/^(?!.*?example)(?=\D*\d)[^a-z]*[a-z].*$/i
(?!.*?example) first lookahead disallows example anywhere in the line
(?=\D*\d) second lookahead requires a digit after any amount of \D non-digits.
[^a-z]*[a-z] matches any amount of non-alphetic characters until an alphabetic.
See demo at regex101
Actually you just need two lookaheads for being independent of condition. One for the required digit and one for the word. The requirement of alphabetic can be done inside the pattern.
Lookarounds are zero-length assertions triggered at a certain position.
I have a field in my application where users can enter a hashtag.
I want to validate their entry and make sure they enter what would be a proper HashTag.
It can be in any language and it should NOT precede with the # sign.
I am writing in JavaScript.
So the following are GOOD examples:
Abcde45454_fgfgfg (good because: only letters, numbers and _)
2014_is-the-year (good because: only letters, numbers, _ and -)
בר_רפאלי (good because: only letters and _)
арбуз (good because: only letters)
And the following are BAD examples:
Dan Brown (Bad because has a space)
OMG!!!!! (Bad because has !)
בר רפ#לי (Bad because has # and a space)
We had a regex that matched only a-zA-Z0-9, we needed to add language support so we changed it to ignore white spaces and forgot to ignore special characters, so here I am.
Some other StackOverflow examples I saw but didn't work for me:
Other languges don't work
Again, English only
[edit]
Added explanation why bad is bad and good is good
I don't want a preceding # character, but if I would to add a # in the beginning, it should be a valid hashtag
Basically I don't want to allow any special characters like !##$%^&*()=+./,[{]};:'"?><
If your disallowed characters list is thorough (!##$%^&*()=+./,[{]};:'"?><), then the regex is:
^#?[^\s!##$%^&*()=+./,\[{\]};:'"?><]+$
Demo
This allows an optional leading # sign: #?. It disallows the special characters using a negative character class. I just added \s to the list (spaces), and also I escaped [ and ].
Unfortunately, you can't use constructs like \p{P} (Unicode punctuation) in JavaScript's regexes, so you basically have to blacklist characters or take a different approach if the regex solution isn't good enough for your needs.
I don't understand why this question does not get more votes. Hashtag detection for multiple languages is a problem. The only working option I could find is posted by Lucas above (all other ones do not work so well).
It needs a modification though:
#[^\s!##$%^&*()=+.\/,\[{\]};:'"?><]+
DEMO
this detects all the hashtags, not only in the beginning of the string, fixes an unescaped character, and removes the unnecessary $ in the end.
First if we exclude all symbol it will not a handy solution. Because symbol depends on keyboard layout and there are hundreds of math symbols and so on. So use this..
[\p{sc=Bengali}|\p{L}_\p{N}]+
1. If you think if language need extra care include like \p{sc=Bengali}|\p{sc=Spanish} etc. Suppose bangla has surrogate alphabet like া, ে ৌ etc so codepoint need to recognize Bangla separately first by \p{sc=Bengali}
2. Than use \p{L} that matches anything that is a Unicode letter a-z and letters like é,ü,ğ,i,ç too or normal any alphabet without complex...matches a single code point in the category "letter"
3. _ underscore allowed
4. \p{N} matches any kind of numeric character in any script. (\d matches only a digit (equal to [0-9]) but for allowed Unicode digit \p{N} only option, because its works with any digit codepoint)
I want to do some basic String testing in Node.js. Assume I have a form where users enter their name and I wanna check if it's just rubbish or a real name.
Happily (or sadly for my check) I get users from all around the world which means that their names contain non-english characters, like ä ö ü ß é. I was used to use /[A-Za-z -]{2,}/ but this doesn't match names like "Jan Buschtöns".
Do I have to manually add every possible non-english but latin character to my RegEx to work? I don't want a 100+ characters long RegEx like /[A-Za-z -äöüÄÖÜßéÉèÈêÊ...]{2,}/.
Check http://www.regular-expressions.info/unicode.html and http://xregexp.com/plugins/
You would need to use \p{L} to match any letter character if you want to include unicode.
Speaking unicode, alternative of \w is [\p{L}\p{N}_] then.
Update: As of ES2018, JavaScript supports Unicode property escapes such as \p{L}, which matches anything that Unicode considers to be a letter. All modern browsers support this feature, so that's probably the way to go as long as you don't care about ancient browsers.
Old answer for pre-ES2018 browsers:
The answer depends on exactly what you want to do.
As you have noticed, [A-Za-z] only matches Latin letters without diacritics.
If you only care about German diacritics and the ß ligature, then you can just replace that part with [A-Za-zÄÖÜäöüß], e.g.:
/[A-Za-zÄÖÜäöüß -]{2,}/
But that probably isn’t what you want to do. You probably want to match Latin letters with any diacritics, not just those used in German. Or perhaps you want to match any letters from any alphabet, not just Latin.
Other regular expression dialects have character classes to help you with problems like this, but unfortunately JavaScript’s regular expression dialect has very few character classes and none of them help you here.
(In case you don’t know, a “character class” is an expression that matches any character that is a member of a predefined group of characters. For example, \w is a character class that matches any ASCII letter, or digit, or an underscore, and . is a character class that matches any character.)
This means that you have to list out every range of UTF-16 code units that corresponds to a character that you want to match.
A quick and dirty solution might be to say [a-zA-Z\u0080-\uFFFF], or in full:
/[A-Za-z\\u0080-\\uFFFF -]{2,}/
This will match any letter in the ASCII range, but will also match any character at all that is outside the ASCII range. This includes all possible alphabetic characters with or without diacritics in any script. However, it also includes a lot of characters that are not letters. Non-letters in the ASCII range are excluded, but non-letters outside the ASCII range are included.
The above might be good enough for your purposes, but if it isn’t then you will have to figure out which character ranges you need and specify those explicitly.
If you want just Latin letters, including those with less common diacritics like åēį, but excluding e.g. Chinese, Devanagari, and Cyrillic characters, you can use \p{Script=Latin} with the u flag. This feature is called Unicode property escapes, and was introduced in ES2018.
For example, /\p{Script=Latin}+/u will match a word that only contains Latin characters.
This is a JavaScript/node.js question, but I barely see any actual JavaScript code which shows how to do it. Its a bit trickier, because it requires the Unicode "u" flag:
// Result: '_ {_} [_]'
'ulike {adj} [ubøyelig]'.replace(/\p{L}+/gu, '_')
I know this question is old but I'm working on some NPL software and I needed to match all words in most latin-like languages and I did this with the following piece of code.
let myString = "Whatever you want here, ex. Bân-lâm-gú or bokmål or Português or Română or Slovenčina or Slovenščina";
let wordchar = 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let re = new RegExp(`(?<=[^${wordchar}]*)[${wordchar}]+(?=[${wordchar}]*)`, "g");
console.log(myString.match(re)); // ["Whatever", "you", "want", "here", "ex", "Bân-lâm-gú", "or", "bokmål", "or", "Português", "or", "Română", "or", "Slovenčina", "or", "Slovenščina"]
For russian and latin alphabet I've used
[\\wа-яА-Я]
I'm trying to create a regex pattern that allows the user to create a username with the following specifications. (For the purposes of this initial pattern, I'm only using standard american English alphabet.
The first character must be an alphabetic letter (uppercase or lowercase). [a-zA-Z]
The last character must be a alphanumeric (uppercase or lowercase). [a-zA-Z0-9]
Any characters in between must be letters or numbers with one rule:
The user can use a period(.), dash(-), or underscore(_) but it must be followed by an alphanumeric character. So no repeats of one or more of these characters at a time.
I've tried the following regex pattern but am not getting the results I was hoping for. Thanks for taking the time to help me on this.
^[a-zA-Z]([a-zA-Z0-9]+[._-]?[a-zA-Z0-9]+)+$
EDIT
It might actually be working the way I expected. But I'm always getting two matches returned to me. The first one being the entire valid string, the second being a shortened version of the first string usually chopping off the first couple of characters.
Examples of valid inputs:
Spidy
Spidy.Man
Ama-za-zing_Spidy
Examples of invalid inputs:
Extreme___Spidy (repeated underscores)
The_-_Spidy (repeated special characters)
_ _ SPIDY _ _ (starts and ends with special characters)
Sounds like this pattern:
^[a-zA-Z]([._-]?[a-zA-Z0-9])*$
^[a-zA-Z]([._-]?[a-zA-Z0-9]+)*$
I want to validate any string that contains çÇöÖİşŞüÜğĞ chars and starting at least 5 chars.String to validate can contain spaces.RegEx must validate like "asd Çğ ğT i" for example.
Any reply will helpful.
Thanks.
You can use escape sequences of the form
\uXXXX
where each "X" can be any hex digit. Thus:
\u0020
is the same as a plain space character, and
\u0041
is upper-case "A". Thus you can encode the Unicode values for the characters you're interested in and then include them in a regex character class. To make sure the string is at least five characters long, you can use a quantifier in the regex.
You'll end up with something like:
var regex = /^[A-Za-z\u00nn\u00nn\u00nn]{5,}$/;
where those "00nn" things would be the appropriate values. As to exactly what those values are, you should be able to find them on a reference site like this one or maybe this one. For example I think that "Ö" is \u00D6. (Some of your characters are in the Unicode Latin-1 Supplement, while others are in Latin Extended A.)