How to get the repeated letter in a string? - javascript

var a = "aaaaaaaaaabbffddcccuuekkjjmlotcfshhh";
Here I want to get the maximum and minimum entered values.For example, I have entered letter "a" as 10 times. That was the maximum. So I want to pint that value. How can I get the maximum entered values in a String using jquery or javascript.

A proposal with Array#forEach() and an object count:
var a = "aaaaaaaaaabbffddcccuuekkjjmlotcfshhh",
count = {}, min, max;
a.split('').forEach(function (a) {
count[a] = (count[a] || 0) + 1;
});
Object.keys(count).forEach(function (a, i) {
if (!i) {
min = [a];
max = [a];
return;
}
if (count[a] < count[min[0]]) {
min = [a];
return;
}
if (count[a] > count[max[0]]) {
max = [a];
return;
}
if (count[min[0]] === count[a]) {
min.push(a);
}
if (count[max[0]] === count[a]) {
max.push(a);
}
});
document.write('min: ' + min.join(', ') + ' with occurrence of ' + count[min[0]] + '<br>');
document.write('max: ' + max.join(', ') + ' with occurrence of ' + count[max[0]] + '<br>');
document.write('<pre>' + JSON.stringify(count, 0, 4) + '</pre>');

How can I get the maximum entered values in a String using jquery or
javascript.
try this
var a = "aaaaaaaaaabbffddcccuuekkjjmlotcfshhh";
var allchars = a.split("").sort();
var output = {};
allchars.forEach(function(val){ output[val] = output[val] || 0; output[val]++; });
Now find the key with highest value
var highestProp = "";
var highestValue = 0;
var lowestProp = "";
var lowestValue = Number.MAX_SAFE_INTEGER;
Object.keys(output).forEach(function(key){
if (output[key] > highestValue )
{
highestValue = output[key];
highestProp = key;
}
if (output[key] < lowestValue )
{
lowestValue = output[key];
lowestProp = key;
}
});
Now highestValue and highestProp has the highest values and highest-value property name. Similarly lowestValue and lowestProp has the lowest values and lowest-value property name.
DEMO
var a = "aaaaaaaaaabbffddcccuuekkjjmlotcfshhh";
var allchars = a.split("").sort();
var output = {};
allchars.forEach(function(val){ output[val] = output[val] || 0; output[val]++; });
var highestProp = "";
var highestValue = 0;
var lowestProp = "";
var lowestValue = Number.MAX_SAFE_INTEGER;
Object.keys(output).forEach(function(key){
if (output[key] > highestValue )
{
highestValue = output[key];
highestProp = key;
}
if (output[key] < lowestValue )
{
lowestValue = output[key];
lowestProp = key;
}
});
alert(highestProp + " has the highest frequency of " + highestValue);
alert(lowestProp + " has the lowest frequency of " + lowestValue);

Related

Javascript , sum of key pair value's

anyone have a solution to add up these key pair values for the one key? I've tried to add them to the key pair value using dict[id] += parseFloat(value) but it results in incorrect operation. I've tried using eval(valuestring), I'm pretty sure the value's inside the key are still a string. Need to get the sum of each ID for a leaderboard.
Any help is much appreciated.
Output of keys of dict_tips
'["U5WUV3A3G"]': '1000.0,200.0,300.0,100.0,500.0,420.0,42.0,98.0,500.0,150.0,300.0,300.0,25.0,200.0,',
'["U5FHMCWP7"]': '50.0,500.0,1000.0,45.0,1000.0,100.0,15.0,3.0,675.0,100.0,225.0,25.0,900.0,100.0,1000.0,10.0,30.0,0.001,0.005,1.755,1.724,1.5,',
'["U5SJQMME3"]': '100000.,100.0,100.0,100.0,50.0,100.0,100.0,40000.0,10.0,200.0,500.0,',
'["U6KAYAJ5Q"]': '100.0,200.0,900.0,100.0,100.0,100.0,1000.0,10.0,10.0,1000.0,100.0,100.0,1.0,10.0,800.0,200.0,100.0,190.0,190.0,10.0,10.0,',
'["U6F1AHQ8H"]': '10.0,100.0,',
'["U3H65TS9K"]': '500.0,100.0,200.0,500.0,35.414,12.345,',
'["U5HUZG3MF"]': '1.0,0.5,42.0,44.0,1.0,1.0,7.995,100.0,100.0,100.0,50.0,100.0,4.0,5.0,5.0,5.0,5.0,5.0,',
'["U5ZPTLXV5"]': '5.0,',
'["U6EMQC2LF"]': '737.998,2000.0,1000.0,300.0,666.0,6000.0,5000.0,5000.0,1000.0,5000.0,999.0,1.0,5000.0,3000.0,5000.0,9999.0,',
'["U62EVB2P7"]': '50.0,20.0,100.0,1.0,100.0,50.0,100.0,50.0,100.0,100.0,1.0,',
'["U3GJ9SREZ"]': '150.0,100.0,100.0,100.0,',
'["U6F0KBT2P"]': '1000.0,100.0,1000.0,100.0,800.0,100.0,100.0,',
'["U5WD17D5E"]': '150.0,75.0,',
'["U697Y6BL3"]': '5.0,1.0,51.0,2.0,1.0,1.0,5.0,',
'["U6GU038HX"]': '4000.0,',
'["U4B0NK2NR"]': '100.0,500.0,200.0,100.0,100.0,100.0,100.0,',
'["U6C23F8MT"]': '49.0,100.0,',
'["U5KQY01ST"]': '105.0,',
'["U6FSC0CC8"]': '100.0,100.0,',
'["U659939GF"]': '20.0,100.0,100.0,100.0,',
'["U5URNPRSA"]': '5.0,20.0,5.0,5.0,50.0,',
'["U5VAMV76F"]': '0.5,20.0,200.0,200.0,200.0,200.0,100.0,200.0,5.0,500.0,200.0,50.0,',
'["U5UL7KWKU"]': '150.0,200.0,',
'["U61NYHM25"]': '64.0,2.0,',
'["U6CMX965S"]': '10.0,10.0,20.0,50.0,30.0,',
'["U5G40R5PF"]': '499.0,',
'["U4XHS3DHA"]': '51.0,',
'["U69MY9WDS"]': '10.0,6.414,10.0,10.0,',
'["U666S65RC"]': '100.0,100.0,',
'["U5X3MEZ39"]': '1.0,1.0,10.01,10.1,0.002,0.01,1.1,' ]
Core
var dict_tips = [];
var dict_counts = [];
var sum = []
for (var i = 0; i < 200 ; i++) {
var str = res.messages.matches[i].text;
var stdout = capcon.captureStdout(function scope() {
for (var x = 46 ; x < 55 ; x++) {
process.stdout.write(str[x]);
}
});
var id = JSON.stringify(stdout.match(/.{1,9}/g))
var stdout = capcon.captureStdout(function scope() {
for (var x = 76 ; x < 85 ; x++) {
process.stdout.write(str[x]);
} });
var extract = JSON.stringify(stdout.match(/.{1,9}/g));
var parse = extract.indexOf(/.RDD|RD|R|D|:| /g)
var x = checkAndAdd(id,extract)
function checkAndAdd(id,extract) {
var found = dict_tips.some(function (el) {
return el.key === id; })
if (!found) { if (parse = -1)
{
var format = ( ""+extract.slice(2,9)).replace(/.RDD|RD|R|D|:| /g,'');
var x = format.substr(0, 9) + " " + format.substr(9);
var total = x.split(" ")
dict_tips.push({key: id})
dict_tips[id] += total
}
else
{
var format = extract.slice(2,9)
var x = format.substr(0, 9) + " " + format.substr(9)
var total = x.split(" ")
dict_tips.push({key: id})
dict_tips[id] = "";
dict_tips[id] += total
}
}
else
{
var extract = stdout.match(/.{1,9}/g);
var parse = extract.indexOf(/.RDD|RD|R|D|:| /g)
if (parse = -1)
{
var format = ( "" + extract).replace(/.RDD|RD|R|D|:| /g,'');
var x = format.substr(0, 9) + " " + format.substr(9);
var total = x.split(" ")
dict_tips[id] += total
}
else
{
var format = extract.slice(1,9)
var x = format.substr(0, 9) + " " + format.substr(9);
var total = x.split(" ")
dict_tips[id] += total
};
}
}
}
var sum = dict_tips.reduce(function(a, b) { return a + b; }, 0);
console.log(JSON.stringify(sum))
console.log(dict_tips)
Split the string, then parseFloat and sum up the values:
const data = {
'["U5WUV3A3G"]': '1000.0,200.0,300.0,100.0,500.0,420.0,42.0,98.0,500.0,150.0,300.0,300.0,25.0,200.0,',
'["U5FHMCWP7"]': '50.0,500.0,1000.0,45.0,1000.0,100.0,15.0,3.0,675.0,100.0,225.0,25.0,900.0,100.0,1000.0,10.0,30.0,0.001,0.005,1.755,1.724,1.5,',
'["U5SJQMME3"]': '100000.,100.0,100.0,100.0,50.0,100.0,100.0,40000.0,10.0,200.0,500.0,',
'["U6KAYAJ5Q"]': '100.0,200.0,900.0,100.0,100.0,100.0,1000.0,10.0,10.0,1000.0,100.0,100.0,1.0,10.0,800.0,200.0,100.0,190.0,190.0,10.0,10.0,',
'["U6F1AHQ8H"]': '10.0,100.0,',
'["U3H65TS9K"]': '500.0,100.0,200.0,500.0,35.414,12.345,',
'["U5HUZG3MF"]': '1.0,0.5,42.0,44.0,1.0,1.0,7.995,100.0,100.0,100.0,50.0,100.0,4.0,5.0,5.0,5.0,5.0,5.0,',
'["U5ZPTLXV5"]': '5.0,',
'["U6EMQC2LF"]': '737.998,2000.0,1000.0,300.0,666.0,6000.0,5000.0,5000.0,1000.0,5000.0,999.0,1.0,5000.0,3000.0,5000.0,9999.0,',
'["U62EVB2P7"]': '50.0,20.0,100.0,1.0,100.0,50.0,100.0,50.0,100.0,100.0,1.0,',
'["U3GJ9SREZ"]': '150.0,100.0,100.0,100.0,',
'["U6F0KBT2P"]': '1000.0,100.0,1000.0,100.0,800.0,100.0,100.0,',
'["U5WD17D5E"]': '150.0,75.0,',
'["U697Y6BL3"]': '5.0,1.0,51.0,2.0,1.0,1.0,5.0,',
'["U6GU038HX"]': '4000.0,',
'["U4B0NK2NR"]': '100.0,500.0,200.0,100.0,100.0,100.0,100.0,',
'["U6C23F8MT"]': '49.0,100.0,',
'["U5KQY01ST"]': '105.0,',
'["U6FSC0CC8"]': '100.0,100.0,',
'["U659939GF"]': '20.0,100.0,100.0,100.0,',
'["U5URNPRSA"]': '5.0,20.0,5.0,5.0,50.0,',
'["U5VAMV76F"]': '0.5,20.0,200.0,200.0,200.0,200.0,100.0,200.0,5.0,500.0,200.0,50.0,',
'["U5UL7KWKU"]': '150.0,200.0,',
'["U61NYHM25"]': '64.0,2.0,',
'["U6CMX965S"]': '10.0,10.0,20.0,50.0,30.0,',
'["U5G40R5PF"]': '499.0,',
'["U4XHS3DHA"]': '51.0,',
'["U69MY9WDS"]': '10.0,6.414,10.0,10.0,',
'["U666S65RC"]': '100.0,100.0,',
'["U5X3MEZ39"]': '1.0,1.0,10.01,10.1,0.002,0.01,1.1,'
}
const sums = Object.keys(data).reduce((results, key) => {
results[key] = data[key].split(',')
.map(item => parseFloat(item))
.filter(item => !isNaN(item))
.reduce((res, item) => res + item, 0)
return results
}, {})
console.log(sums)
In PHP, you would do an explode on the commas, think for javascript its split. After you would run a loop through each index of the array that the split function just created and adding to a total sum. You would need to do a parsefloat on each value of the index as well.
You can simply iterate through the keys of the data using for in.
Then you need to split the string into an array, and sum up the values using reduce.
const data = {
'["U5WUV3A3G"]': '1000.0,200.0,300.0,100.0,500.0,420.0,42.0,98.0,500.0,150.0,300.0,300.0,25.0,200.0,',
'["U5FHMCWP7"]': '50.0,500.0,1000.0,45.0,1000.0,100.0,15.0,3.0,675.0,100.0,225.0,25.0,900.0,100.0,1000.0,10.0,30.0,0.001,0.005,1.755,1.724,1.5,',
'["U5SJQMME3"]': '100000.,100.0,100.0,100.0,50.0,100.0,100.0,40000.0,10.0,200.0,500.0,',
'["U6KAYAJ5Q"]': '100.0,200.0,900.0,100.0,100.0,100.0,1000.0,10.0,10.0,1000.0,100.0,100.0,1.0,10.0,800.0,200.0,100.0,190.0,190.0,10.0,10.0,',
'["U6F1AHQ8H"]': '10.0,100.0,',
'["U3H65TS9K"]': '500.0,100.0,200.0,500.0,35.414,12.345,',
'["U5HUZG3MF"]': '1.0,0.5,42.0,44.0,1.0,1.0,7.995,100.0,100.0,100.0,50.0,100.0,4.0,5.0,5.0,5.0,5.0,5.0,',
'["U5ZPTLXV5"]': '5.0,',
'["U6EMQC2LF"]': '737.998,2000.0,1000.0,300.0,666.0,6000.0,5000.0,5000.0,1000.0,5000.0,999.0,1.0,5000.0,3000.0,5000.0,9999.0,',
'["U62EVB2P7"]': '50.0,20.0,100.0,1.0,100.0,50.0,100.0,50.0,100.0,100.0,1.0,',
'["U3GJ9SREZ"]': '150.0,100.0,100.0,100.0,',
'["U6F0KBT2P"]': '1000.0,100.0,1000.0,100.0,800.0,100.0,100.0,',
'["U5WD17D5E"]': '150.0,75.0,',
'["U697Y6BL3"]': '5.0,1.0,51.0,2.0,1.0,1.0,5.0,',
'["U6GU038HX"]': '4000.0,',
'["U4B0NK2NR"]': '100.0,500.0,200.0,100.0,100.0,100.0,100.0,',
'["U6C23F8MT"]': '49.0,100.0,',
'["U5KQY01ST"]': '105.0,',
'["U6FSC0CC8"]': '100.0,100.0,',
'["U659939GF"]': '20.0,100.0,100.0,100.0,',
'["U5URNPRSA"]': '5.0,20.0,5.0,5.0,50.0,',
'["U5VAMV76F"]': '0.5,20.0,200.0,200.0,200.0,200.0,100.0,200.0,5.0,500.0,200.0,50.0,',
'["U5UL7KWKU"]': '150.0,200.0,',
'["U61NYHM25"]': '64.0,2.0,',
'["U6CMX965S"]': '10.0,10.0,20.0,50.0,30.0,',
'["U5G40R5PF"]': '499.0,',
'["U4XHS3DHA"]': '51.0,',
'["U69MY9WDS"]': '10.0,6.414,10.0,10.0,',
'["U666S65RC"]': '100.0,100.0,',
'["U5X3MEZ39"]': '1.0,1.0,10.01,10.1,0.002,0.01,1.1,'
}
let sum = {};
for (var key in data) {
let arr = data[key].split(',');
let total = arr.reduce((acc, curr) => {
if (parseInt(curr)) {
return acc + parseInt(curr);
}
return acc;
}, 0);
sum[key] = total;
}
console.log(sum)

Create Array of Objects and count number of occurrence

I have an array of objects and want to create another array of objects based on.
I want to check if an object is repeated just want to show the count, otherwise show the object itself with count = 1.
<!-- I have an array-->
var arr =[{name:"coke",price:20},{name:"coke",price:20},{name:"coke",price:20},{name:"kabab",price:250}];
// I want to create another array based on "arr" like the one below
var test =[{name:"coke",price:20,count:3},{name:"kabab",price:20,count:1}];
//Any hint please
This may help you. This answer considers name or some identifier will be unique for each object.
counter = {}
var arr = [{
name: "coke",
price: 20
}, {
name: "coke",
price: 20
}, {
name: "coke",
price: 20
}, {
name: "kabab",
price: 250
}];
var obj = {};
var counter = {}
for (var i = 0, len = arr.length; i < len; i++) {
obj[arr[i]['name']] = arr[i];
counter[arr[i]['name']] = (counter[arr[i]['name']] || 0) + 1
}
newArr = new Array();
for (var key in obj){
newArr.push(extend( obj[key], {count:counter[key]}));
}
function extend(a, b){
for(var key in b)
if(b.hasOwnProperty(key))
a[key] = b[key];
return a;
}
console.log(newArr)
var arr =[{name:"coke",price:20},{name:"coke",price:20},{name:"coke",price:20},{name:"kabab",price:250}];
var countNameMapping = {}, finalArr = [];
var arrLength = arr.length;
for(i=0; i<arrLength; i++){
var tempObj = {name:arr[i], price:arr[i].price, occurance:1};
var productName = arr[i].name;
if(countNameMapping[productName] === undefined){
countNameMapping[productName] = tempObj;
}else{
countNameMapping[productName].occurance += 1;
}
}
for(var k in countNameMapping){
finalArr.push(countNameMapping[k])
}
console.log(finalArr );
You can try this one:
var arr =[{name:"coke",price:20},{name:"coke",price:20},{name:"coke",price:20},{name:"kabab",price:250}];
var result = [];
arr.map(function(arrObject) {
if (result.length > 0) {
result.map(function(resultObject) {
if (resultObject.name != arrObject.name) {
arrObject.count = 1;
result.push(arrObject);
} else {
resultObject.count++;
}
})
} else {
arrObject.count = 1;
result.push(arrObject);
}
})
console.log(result);
This will provide the result you are looking for:
var arr =[{name:"coke",price:20},{name:"coke",price:20},{name:"coke",price:20},{name:"kabab",price:250}];
var map = arr.reduce((accum, item) => {
var obj = accum.get(item.name) || Object.assign({}, item, {count:0});
obj.count++;
return accum.set(item.name, obj);
}, new Map());
var res = [...map.values()];
More or less...
var arr = [{
name: "coke",
price: 20
}, {
name: "coke",
price: 20
}, {
name: "coke",
price: 20
}, {
name: "kabab",
price: 250
}];
// I want to create another array based on "arr" like the one below
// var test =[{name:"coke",price:20,count:3},{name:"kabab",price:20,count:1}];
var count = {};
var test = [];
for (var i = 0, len = arr.length; i < len; i++) {
var id = JSON.stringify(arr[i]);
if (count.hasOwnProperty(id)) {
count[id].count++;
} else {
test.push(arr[i]); // Data contamination. Too lazy to copy object
count[id] = test[test.length - 1]; // Could be better.
count[id].count = 1;
}
}
console.log(test);
This is probably what are you looking for:
How does it work?
First, your array arr will use a forEach loop to find each object and if if new you will add it to the results array. The method isNew() will return true if the object is new.
For each new object founded you will count the number of occurrences using findOccurrences() To reduce the number of "loops" you will slice the array according to the index. So you don't need to search again over the already processed data.
So now you can build an new object, using the name, price and count.
Finally, you can push() the new object to the results array.
var arr =[{name:"coke",price:20},{price:20,name:"coke"},{name:"coke",price:20},{name:"kabab",price:250}];
var results = [];
var index = 0;
var originalDiv = document.getElementById('original');
var resultsDiv = document.getElementById('results');
arr.forEach(function(obj) {
if (isNew(obj)) {
var counter = findOccurrences(obj, arr.slice(index, arr.length));
var newObj = {
name: obj.name,
price: obj.price,
count: counter
}
results.push(newObj);
}
index++;
});
printArray(arr, originalDiv);
printArray(results, resultsDiv);
function isNew(newObj) {
var wasFound = true;
if (typeof results != "undefined" && results != null && results.length > 0) {
results.forEach(function(obj) {
if (newObj.name === obj.name && newObj.price === obj.price) {
return false;
} else {
wasFound = false;
}
});
return !wasFound;
} else {
return true;
}
}
function findOccurrences(newObj, objects) {
var count = 0;
if (typeof objects != "undefined" && objects != null && objects.length > 0) {
objects.forEach(function(obj) {
if (newObj.name === obj.name && newObj.price === obj.price) {
count++;
}
});
}
return count;
}
function printArray(objects, div) {
var count = 0;
if (typeof objects != "undefined" && objects != null && objects.length > 0) {
objects.forEach(function(obj) {
var newElement = document.createElement('p');
newElement.innerHTML = 'item ' + count + ': ';
Object.keys(obj).forEach(function(key) {
newElement.innerHTML += key + ': ' + obj[key] + ', ';
});
newElement.innerHTML = newElement.innerHTML.slice(0, -2);
div.appendChild(newElement);
count++;
});
}
}
<div id="original"><p>Original Array</p></div>
<div id="results"><p>Results Array</p></div>
Update:
More optimization.
var arr =[{name:"coke",price:20},{name:"coke",price:20},{name:"coke",price:20},{name:"kabab",price:250},{name:"coke",price:20},{name:"coke",price:20},{name:"kabab",price:250}];
var accumulator = {};
var results = [];
var index = 0;
var originalDiv = document.getElementById('original');
var resultsDiv = document.getElementById('results');
String.prototype.hashCode = function() {
var hash = 0;
if (this.length == 0) return hash;
for (i = 0; i < this.length; i++) {
var char = this.charCodeAt(i);
hash = ((hash << 5) - hash) + char;
hash |= 0; // Convert to 32bit integer
}
var c = (hash & 0x0FFFFFFF)
.toString(16)
.toUpperCase();
return '0000000'.substring(0, 7 - c.length) + c;
};
arr.forEach(function(obj) {
var id = JSON.stringify(obj).hashCode();
console.log(id);
if (accumulator.hasOwnProperty(id)) {
accumulator[id].count++;
} else {
results.push(obj);
accumulator[id] = results[results.length - 1];
accumulator[id].count = 1;
}
});
printArray(arr, originalDiv);
printArray(results, resultsDiv);
function printArray(objects, div) {
var count = 0;
if (typeof objects != "undefined" && objects != null && objects.length > 0) {
objects.forEach(function(obj) {
var newElement = document.createElement('p');
newElement.innerHTML = 'item ' + count + ': ';
Object.keys(obj).forEach(function(key) {
newElement.innerHTML += key + ': ' + obj[key] + ', ';
});
newElement.innerHTML = newElement.innerHTML.slice(0, -2);
div.appendChild(newElement);
count++;
});
}
}
<div id="original">
<p>Original Array</p>
</div>
<div id="results">
<p>Results Array</p>
</div>

Expansion of algebraic term

I am trying to expand an algebraic term.
(x+1)(x+1)/x => x + 2 + x^-1
(x+1)^3 => x^3 + 3x^2 + 3x + 1
(x^2*x)(x^2) => x^5
This is my attempt at it. I have tried a lot of ways trying to fix the problems below.
Problems:
Like terms should be added together
(x+1)(x+1)(x+1) should be valid.
(x+1)^2 should be equal to (x+1)(x+1)
x(x+1) should be valid
1x^n should just be x^n
There should be no 0x^n terms.
nx^0 terms should just be n
Code Snippet:
function split(input) {
return ((((input.split(")(")).toString()).replace(/\)/g, "")).replace(/\(/g, "")).split(','); }
function strVali(str) {
str = str.replace(/\s+/g, "");
var parts = str.match(/[+\-]?[^+\-]+/g);
// accumulate the results
return parts.reduce(function(res, part) {
var coef = parseFloat(part) || +(part[0] + "1") || 1;
var x = part.indexOf('x');
var power = x === -1 ?
0:
part[x + 1] === "^" ?
+part.slice(x + 2) :
1;
res[power] = (res[power] || 0) + coef;
return res;
}, {});
}
function getCoeff(coeff) {
var powers = Object.keys(strVali(coeff));
var max = Math.max.apply(null, powers);
var result = [];
for(var i = max; i >= 0; i--)
result.push(strVali(coeff)[i] || 0);
return result; }
function evaluate(expression) {
var term1 = getCoeff(expression[0]);
var term2 = getCoeff(expression[1]);
var expand = "";
for ( var j = 0; j < term1.length; j++ ) {
for ( var i = 0; i < term2.length; i++ ) {
expand += Number(term1[j] * term2[i]) + 'x^ ' + (Number(term1.length) - 1 - j + Number(term2.length) - 1 - i) + ' + ';
}}
var final = "";
for ( var Z = 0; Z < getCoeff(expand).length; Z++) {
final += ' ' + getCoeff(expand)[Z] + 'x^ {' + (getCoeff(expand).length - Z - 1) + '} +';
}
final = "$$" + ((((((final.replace(/\+[^\d]0x\^ \{[\d]+\}/g,'')).replace(/x\^ \{0}/g,'')).replace(/x\^ \{1}/g,'x')).replace(/[^\d]1x\^ /g,'+ x^')).replace(/\+ -/g,' - ')).slice(0, -1)).substring(1,(final.length)) + "$$";
document.getElementById('result').innerHTML = final;
MathJax.Hub.Queue(["Typeset", MathJax.Hub, document.getElementById('result')]);
}
function caller() {
var input = document.getElementById('input').value;
evaluate(split(input)); }
div.wrapper {
width: 100%;
height:100%;
border:0px solid black;
}
input[type="text"] {
display: block;
margin : 0 auto;
padding: 10px;
font-size:20px;
}
button{
margin:auto;
display:block;
background-color: white;
color: black;
border: 2px solid #555555;
padding-left: 20px;
padding-right: 20px;
font-size: 20px;
margin-top:10px;
}
button:hover {
box-shadow: 0 12px 16px 0 rgba(0,0,0,0.24),0 17px 50px 0 rgba(0,0,0,0.19);
}
<script type="text/javascript" async
src="https://cdnjs.cloudflare.com/ajax/libs/mathjax/2.7.0/MathJax.js?config=TeX-MML-AM_CHTML">
</script>
<div class='wrapper'><input id="input" title="Enter Expression" type="text" value="(x^2+x+1)(x^2+x+1)"></div>
<div> <button onclick="caller()">Click</button></div>
<div id="result">$$x^4 + 2x^3 + 3x^2 + 2x + 1$$</div>
Reference:
How to calculate coefficients of polynomial expansion in javascript
Getting coefficients of algebraic term
How to get a term before a character?
Edit: I have re-written my original answer from when the question did not include the - and / operators). My new answer supports - and /.
Since you have not defined a precise grammar, I have made some assumptions. I support the +, -, /, ^ operators and the implicit multiply. These can operate on numbers, x and (...) expressions, except that right hand side of the ^ operator must be a number. I allow spaces between tokens.
Limitations: The -is a binary not unary - operator, So x-2 if OK, -2 on its own is a syntax error. The / is limited. You may divide by a value with a single coefficient such as 2, 'x', 2x^2, but not by cannot have 1/(x^2+1), which would evaluate to an infinite series.
It first takes the string and wraps it in a 'tokenizer' which lets you look it one token at a time, where a token is a number, x, ( ) or operator.
It then calls evaluateSum() which evaluates things separated by + or -, where each thing is a product evaluated by evaluateProduct(). This in turn uses evaluatePower() to evalue the ^. Finally evaluateTerm() looks for x, numbers and bracketed sub-expressions which are evaluates recursively with evaluateSum(). This hierarchy creates the correct operator precedence and evaluation order.
Each layer of the evaluation returns a 'coefficients' object which s array-like, but may contain megative indexes. For example [1,0,1] means 1+x^2.
It can cope with any number of nested brackets and a lot of other case such as xx(x) is x^3, 2^3 is 8. I have added a few throws for syntax errors, for example 2^x is illegal.
function makeTokenizer(source) {
var c, i, tokenizer;
i = 0; // The index of the current character.
c = source.charAt(i); // The current character.
function consumeChar() { // Move to next c, return previous c.
var prevC = c;
i += 1;
c = source.charAt(i);
return prevC;
}
tokenizer = {
next : function () {
var str;
while (c === ' ') { // Skip spaces
consumeChar();
}
if (!c) {
tokenizer.token = undefined; // End of source
} else if (c >= '0' && c <= '9') { // number
str = consumeChar(); // First digit
while (c >= '0' && c <= '9') { // Look for more digits.
str += consumeChar();
}
tokenizer.token = Number(str);
} else if (c === "x") {
tokenizer.token = consumeChar();
} else { // single-character operator
tokenizer.token = consumeChar();
}
}
};
tokenizer.next(); // Load first token.
return tokenizer;
}
function makeCoefficients() { // Make like an array but can have -ve indexes
var min = 0, max = 0, c = {};
return {
get: function (i) {
return c[i] || 0;
},
set: function (i, value) {
c[i] = value;
min = Math.min(i, min);
max = Math.max(i + 1, max);
return this; // for chaining
},
forEach: function (callback) {
var i;
for (i = min; i < max; i += 1) {
if (this.get(i)) {
callback(this.get(i), i);
}
}
},
toString: function () {
var result = "", first = true;
this.forEach(function (val, power) {
result += (val < 0 || first) ? "" : "+";
first = false;
result += (val === 1 && power !== 0) ? "" : val;
if (power) {
result += "x";
if (power !== 1) {
result += "^" + power;
}
}
});
return result;
},
toPowerOf: function (power) {
if (power === 0) {
return makeCoefficients().set(0, 1); // Anything ^0 = 1
}
if (power === 1) {
return this;
}
if (power < 0) {
throw "cannot raise to negative powers";
}
return this.multiply(this.toPowerOf(power - 1));
},
multiply: function (coefficients) {
var result = makeCoefficients();
this.forEach(function (a, i) {
coefficients.forEach(function (b, j) {
result.set(i + j, result.get(i + j) + a * b);
});
});
return result;
},
divide: function (coefficients) {
// Division is hard, for example we cannot do infinite series like:
// 1/(1 + x^2) = sum_(n=0 to infinity) 1/2 x^n ((-i)^n + i^n)
// So we do a few easy cases only.
var that = this, result = makeCoefficients(), done;
coefficients.forEach(function (value, pow) {
that.forEach(function (value2, pow2) {
result.set(pow2 - pow, value2 / value);
});
if (done) {
throw "cannot divide by " + coefficients.toString();
}
done = true;
});
return result;
},
add: function (coefficients, op) {
var result = makeCoefficients();
this.forEach(function (value, i) {
result.set(value, i);
});
op = (op === "-" ? -1 : 1);
coefficients.forEach(function (value, i) {
result.set(i, result.get(i) + value * op);
});
return result;
}
};
}
var evaluateSum; // Called recursively
function evaluateTerm(tokenizer) {
var result;
if (tokenizer.token === "(") {
tokenizer.next();
result = evaluateSum(tokenizer);
if (tokenizer.token !== ")") {
throw ") missing";
}
tokenizer.next();
} else if (typeof tokenizer.token === "number") {
result = makeCoefficients().set(0, tokenizer.token);
tokenizer.next();
} else if (tokenizer.token === "x") {
tokenizer.next();
result = makeCoefficients().set(1, 1); // x^1
} else {
return false; // Not a 'term'
}
return result;
}
function evaluatePower(tokenizer) {
var result;
result = evaluateTerm(tokenizer);
if (tokenizer.token === "^") {
tokenizer.next();
if (typeof tokenizer.token !== "number") {
throw "number expected after ^";
}
result = result.toPowerOf(tokenizer.token);
tokenizer.next();
}
return result;
}
function evaluateProduct(tokenizer) {
var result, term, divOp;
result = evaluatePower(tokenizer);
if (!result) {
throw "Term not found";
}
while (true) {
divOp = (tokenizer.token === "/");
if (divOp) {
tokenizer.next();
term = evaluatePower(tokenizer);
result = result.divide(term);
} else {
term = evaluatePower(tokenizer);
if (!term) {
break;
}
result = result.multiply(term);
}
}
return result;
}
function evaluateSum(tokenizer) {
var result, op;
result = evaluateProduct(tokenizer);
while (tokenizer.token === "+" || tokenizer.token === "-") {
op = tokenizer.token;
tokenizer.next();
result = result.add(evaluateProduct(tokenizer), op);
}
return result;
}
function evaluate(source) {
var tokenizer = makeTokenizer(source),
coefficients = evaluateSum(tokenizer);
if (tokenizer.token) {
throw "Unexpected token " + tokenizer.token;
}
console.log(source + " => " + coefficients.toString());
}
// Examples:
evaluate("(x+1)(x+1)"); // => 1+2x+x^2
evaluate("(x+1)^2"); // => 1+2x+x^2
evaluate("(x+1)(x+1)(x+1)"); // => 1+3x+3x^2+x^3
evaluate("(x+1)^3"); // => 1+3x+3x^2+x^3
evaluate("(x)(x+1)"); // => x+x^2
evaluate("(x+1)(x)"); // => x+x^2
evaluate("3x^0"); // => 3
evaluate("2^3"); // => 8
evaluate("(x+2x(x+2(x+1)x))"); // => x+6x^2+4x^3
evaluate("(x+1)(x-1)"); // => -1+x^2
evaluate("(x+1)(x+1)/x"); // x^-1+2+x
//evaluate("(x+1)/(x^2 + 1)"); //throws cannot divide by 1+2x
It can handle +, -, / and implicit multiplication. It expands the parenthesis accordingly and adds them to the original expression while removing the parenthesised version. It collects like terms accordingly. Limitations: It cannot divide by a polynomial and it does not support the * operator.
function strVali(str) {
str = str.replace(/\s+/g, "");
var parts = str.match(/[+\-]?[^+\-]+/g);
return parts.reduce(function(res, part) {
var coef = parseFloat(part) || +(part[0] + "1") || 1;
var x = part.indexOf('x');
var power = x === -1 ?
0:
part[x + 1] === "^" ?
+part.slice(x + 2) :
1;
res[power] = (res[power] || 0) + coef;
return res;
}, {});
}
function getCoeff(coeff) {
var powers = Object.keys(strVali(coeff));
var max = Math.max.apply(null, powers);
var result = [];
for(var i = max; i >= 0; i--)
result.push(strVali(coeff)[i] || 0);
return result; }
function format(str) {
str = ' ' + str;
str = str.replace(/-/g,'+-').replace(/x(?!\^)/g,'x^1').replace(/([+\/*)(])(\d+)([+\/*)(])/g,'$1$2x^0$3').replace(/([^\d])(x\^-?\d+)/g,'$11$2').replace(/(-?\d+x\^\d+)(?=\()/g,'($1)').replace(/(\))(-?\d+x\^\d+)/g,'$1($2)').replace(/([^\)\/])(\()([^\*\/\(\)]+?)(\))(?![(^\/])/g,'$1$3');
str = str.replace(/(\([^\(\)]+?\))\/(\d+x\^-?\d+)/g,'$1/($2)').replace(/(\d+x\^-?\d+)\/(\d+x\^-?\d+)/g,'($1)/($2)').replace(/(\d+x\^-?\d+)\/(\(\d+x\^-?\d+\))/g,'($1)/$2');
return str;
}
function expBrackets(str) {
var repeats = str.match(/\([^\(\)]+?\)\^\d+/g);
if ( repeats === null ) { return str; } else { var totalRepeat = '';
for ( var t = 0; t < repeats.length; t++ ) { var repeat = repeats[t].match(/\d+$/); for ( var u = 0; u < Number(repeat); u++ ) { totalRepeat += repeats[t].replace(/\^\d+$/,''); }
str = str.replace(/\([^\(\)]+?\)\^\d+/, totalRepeat); totalRepeat = ''; }
return str; }
}
function multiply(str) {
var pairs = str.match(/\([^\(\)]+?\)\([^\(\)]+?\)/g);
if ( pairs !== null ) { while ( pairs !== null ) { var output = '';
for (var i = 0; i < pairs.length; i++) { var pair = pairs[i].slice(1).slice(0, -1).split(')('); var firstCoeff = getCoeff(pair[0]); var secondCoeff = getCoeff(pair[1]);
for (var j = 0; j < firstCoeff.length; j++) {
for (var k = 0; k < secondCoeff.length; k++) { output += firstCoeff[j] * secondCoeff[k] + 'x^' + Number(firstCoeff.length - 1 - j + secondCoeff.length - 1 - k) + '+'; } }
var regexp = new RegExp(pairs[i].replace(/\(/g,'\\(').replace(/\+/g,'\\+').replace(/\)/g,'\\)').replace(/\^/g,'\\^').replace(/\-/g,'\\-'));
str = str.replace(regexp, '(' + (output.slice(0, -1).replace(/[^\d]0x\^\d+/g,'')) + ')');
output = ''; }
pairs = str.match(/\([^\(\)]+?\)\([^\(\)]+?\)/g); } }
else { }
str = str.replace(/\+/g,' + ');
return str;
}
function divide(str) {
if ( str.match(/\/(\(-?\d+x\^-?\d+.+?\))/g) === null && str.match(/\//g) !== null ) {
while ( pairs !== null ) {
var pairs = str.match(/\([^\(\)]+?\)\/\([^\(\)]+?\)/g);
var output = '';
for (var i = 0; i < pairs.length; i++) {
var pair = pairs[i].slice(1).slice(0, -1).split(')/(');
var firstCoeff = getCoeff(pair[0]);
var secondCoeff = getCoeff(pair[1]);
for (var j = 0; j < firstCoeff.length; j++) {
for (var k = 0; k < secondCoeff.length; k++) {
output += firstCoeff[j] / secondCoeff[k] + 'x^' + Number(firstCoeff.length - 1 - j - secondCoeff.length + 1 + k) + '+';
output = output.replace(/([+-])Infinityx\^\-?\d+/g,'').replace(/([+-])NaNx\^\-?\d+/g,'');
} }
var regexp = new RegExp(pairs[i].replace(/\(/g,'\\(').replace(/\+/g,'\\+').replace(/\)/g,'\\)').replace(/\^/g,'\\^').replace(/\-/g,'\\-'));
str = str.replace(regexp, '(' + (output.slice(0, -1).replace(/[^\d]0x\^-?\d+/g,'')) + ')');
output = ''; }
pairs = str.match(/\([^\(\)]+?\)\/\([^\(\)]+?\)/g); } }
else { }
return str;
}
function evaluate(str) {
var result = format(divide(format(multiply(expBrackets(format((str)))))));
var resultCollect = '';
result = result.replace(/\s+/g, "").replace(/[^\d]0x\^-?\d+/g,'').replace(/\+/g,' + ');
if ( result === '') {
document.getElementById('result').innerHTML = '$$' + str + '$$' + '$$ = 0 $$';
MathJax.Hub.Queue(["Typeset", MathJax.Hub, document.getElementById('result')]);
} else if ( result.match(/-?\d+x\^-\d+/g) === null && str.match(/\/(\(-?\d+x\^-?\d+.+?\))/g) === null) {
for ( var i = 0; i < getCoeff(result).length; i++ ) {
resultCollect += getCoeff(result)[i] + 'x^' + Number(getCoeff(result).length - 1 - i) + '+' ; }
if ( resultCollect !== '')
resultCollect = '$$ = ' + resultCollect.slice(0,-1).replace(/[^\d]0x\^-?\d+/g,'').replace(/\+/g,' + ').replace(/x\^0/g,'').replace(/x\^1(?!\d+)/g,'x').replace(/\^(-?\d+)/g,'\^\{$1\}').replace(/\+ -/g,' - ') + '$$';
else
resultCollect = 'Error: Trying to divide by a polynomial ';
document.getElementById('result').innerHTML = '$$' + str.replace(/\^(-?\d+)/g,'\^\{$1\}') + '$$' + resultCollect;
MathJax.Hub.Queue(["Typeset", MathJax.Hub, document.getElementById('result')]);
} else {
resultCollect = '$$ = ' + result.replace(/\^(-?\d+)/g,'\^\{$1\}') + '$$';
document.getElementById('result').innerHTML = '$$' + str.replace(/\^(-?\d+)/g,'\^\{$1\}').replace(/\+ -/g,' - ') + '$$' + resultCollect;
MathJax.Hub.Queue(["Typeset", MathJax.Hub, document.getElementById('result')]);
}
}
function caller() {
var input = document.getElementById('input').value;
evaluate(input);
}
div.wrapper {
width: 100%;
height:100%;
border:0 solid black;
}
input[type="text"] {
display: block;
margin : 0 auto;
padding: 10px;
font-size:20px;
}
button{
margin:auto;
display:block;
background-color: white;
color: black;
border: 2px solid #555555;
padding-left: 20px;
padding-right: 20px;
font-size: 20px;
margin-top:10px;
}
button:hover {
box-shadow: 0 12px 16px 0 rgba(0,0,0,0.24),0 17px 50px 0 rgba(0,0,0,0.19);
}
<script type="text/javascript" async
src="https://cdnjs.cloudflare.com/ajax/libs/mathjax/2.7.0/MathJax.js?config=TeX-MML-AM_CHTML">
</script>
<input id="input" type="text" title="Enter Expression: ">
<button onclick="caller()">Click</button>
<div id="result"></div>
<div id="errors"></div>
My approach utilizes two helper classes:
-Term: This stores a coefficient and an object, the keys of which are variables and the values of which are the exponents. It has methods for determining whether terms are the "same" (i.e. whether they have the same variables with the same exponents, thus allowing them to be added), adding terms, and multiplying terms.
-Polynomial: This stores an array of terms. It has methods for adding two polynomials, multiplying two polynomials, and simplifying polynomials (eliminating terms with 0 coefficients and combining like terms).
It has two substantial helper functions:
-findOuterParens - Given a string, this function returns the indices of the first outermost pair of left and right parentheses.
-parseExpressionStr - This function uses a regular expression to split a string into three types of substrings: 1) a number, 2) a symbol (i.e. a variable, like 'x' or 'y'), or 3) an operator (*, -, +, ^, /). It creates Polynomial objects for the first two types and leaves the operators as strings.
The expand function runs the show. It takes in a string and returns a Polynomial object representing the expanded form of the polynomial in the string. It does this as follows:
1) It deals with parentheses by recursion. It uses findOuterParens to find all outermost parenthsized substrings. So for "3x*(x+4)+(2(y+1))*t", for instance, it would find "x+4" and "2(y+1)" as parenthsized substrings. It then passes these to itself for further parsing. For "2(y+1)", it would identify "y+1" as a parenthesized substring, and pass this to itself, for three levels of recursion for this example.
2) It deals with other parts of the string using parseExpressionStr. After steps 1 and 2, it has an array containing Polynomial objects and operators (stored as strings). It then proceeds to simplifying and expanding.
3) It converts subtraction subproblems to addition subproblems by replacing all -'s with +'s and multiplying all polynomials following -'s by -1.
4) It converts division subproblems to multiplication subproblems by replacing /'s with *'s and inverting the Polynomial following the /. If the polynomial following the / has more than one term, it throws an error.
5) It converts power subproblems to multiplication subproblems by replacing ^'s with a series of multiplications.
6) It adds in implicit *'s. I.e. if two Polynomial elements are right next to each other in the array, then it's inferred that they are being multiplied, so, e.g. '2*x' == '2x'.
7) Now the array has polynomial objects alternating with either '+' or '*'. It first performs all polynomial multiplications and then performs all additions.
8) It performs a final simplification step and returns the resulting expanded polynomial.
<html>
<head></head>
<body></body>
<script>
function findOuterParens(str) {
var leftIndex = str.indexOf('('), leftNum = 1, rightNum = 0;
if (leftIndex === -1)
return
for (var i=leftIndex+1; i<str.length; i++) {
if (str[i] === '(')
leftNum++;
else if (str[i] === ')')
rightNum++, rightIndex=i;
if (leftNum === rightNum)
return {start: leftIndex, end: rightIndex}
}
throw Error('Parenthesis at position ' + leftIndex + ' of "' + str + '" is unpaired.');
}
function parseExpressionStr(inputString) {
var result = [], str = inputString;
while (str) {
var nextPart = str.match(/([\d]+)|([\+\-\^\*\/])|([a-zA-z])/);
if (!nextPart)
return result;
if (nextPart.length === 0)
throw Error('Unable to parse expression string "' + inputString + '". Remainder "' + str + '" could not be parsed.');
else if (nextPart[1]) // First group (digits) matched
result.push(new Polynomial(parseFloat(nextPart[0])));
else if (nextPart[3]) // Third group (symbol) matched
result.push(new Polynomial(nextPart[0]));
else // Second group (operator) matched
result.push(nextPart[0]);
str = str.substring(nextPart.index+nextPart[0].length);
}
return result
}
function isOperator(char) {
return char === '*' || char === '/' || char === '^' || char === '+' || char === '-';
}
function Polynomial(value) {
this.terms = (value!==undefined) ? [new Term(value)] : [];
}
Polynomial.prototype.simplify = function() {
for (var i=0; i<this.terms.length-1; i++) {
if (this.terms[i].coeff === 0) {
this.terms.splice(i--, 1);
continue;
}
for (var j=i+1; j<this.terms.length; j++) {
if (Term.same(this.terms[i], this.terms[j])) {
this.terms[i] = Term.add(this.terms[i], this.terms[j]);
this.terms.splice(j--, 1);
}
}
}
}
Polynomial.add = function(a, b) {
var result = new Polynomial();
result.terms = a.terms.concat(b.terms);
result.simplify();
return result
}
Polynomial.multiply = function(a, b) {
var result = new Polynomial();
a.terms.forEach(function(aTerm) {
b.terms.forEach(function (bTerm) {
result.terms.push(Term.multiply(aTerm, bTerm));
});
});
result.simplify();
return result
}
Polynomial.prototype.toHtml = function() {
var html = ''
for (var i=0; i<this.terms.length; i++) {
var term = this.terms[i];
if (i !== 0)
html += (term.coeff < 0) ? ' - ' : ' + ';
else
html += (term.coeff < 0) ? '-' : '';
var coeff = Math.abs(term.coeff);
html += (coeff === 1 && Object.keys(term.symbols).length > 0) ? '' : coeff;
for (var symbol in term.symbols) {
var exp = term.symbols[symbol];
exp = (exp !== 1) ? exp : '';
html += symbol + '<sup>' + exp + '</sup>';
}
}
return html;
}
function Term(value) {
this.symbols = {};
if (typeof value==='string') { // Symbol
this.symbols[value] = 1;
this.coeff = 1;
} else if (typeof value==='number') { // Number
this.coeff = value;
} else {
this.coeff = 1;
}
}
Term.same = function(a, b) {
if (Object.keys(a.symbols).length != Object.keys(b.symbols).length)
return false
else
for (var aSymbol in a.symbols)
if (a.symbols[aSymbol] != b.symbols[aSymbol]) return false
return true
}
Term.add = function(a, b) {
var result = new Term();
Object.assign(result.symbols, a.symbols);
result.coeff = a.coeff + b.coeff;
return result
}
Term.multiply = function(a, b) {
var result = new Term();
Object.assign(result.symbols, a.symbols);
for (var symbol in b.symbols) {
if (!(symbol in result.symbols))
result.symbols[symbol] = 0;
result.symbols[symbol] += b.symbols[symbol];
if (result.symbols[symbol] === 0)
delete result.symbols[symbol];
}
result.coeff = a.coeff * b.coeff;
return result
}
function expand(str) {
var result = [];
var parens = findOuterParens(str);
while (parens) {
result = result.concat(parseExpressionStr(str.slice(0,parens.start)));
result.push(expand(str.slice(parens.start+1, parens.end)))
str = str.slice(parens.end+1);
parens = findOuterParens(str);
}
result = result.concat(parseExpressionStr(str));
// Move -s to coefficients
var minus = result.indexOf('-'), minusPoly = new Polynomial(-1);
while (minus !== -1) {
result[minus] = '+';
result[minus+1] = Polynomial.multiply(minusPoly, result[minus+1]);
minus = result.indexOf('-');
}
// Get rid of +s that follow another operator
var plus = result.indexOf('+');
while (plus !== -1) {
if (plus===0 || isOperator(result[plus-1])) {
result.splice(plus--, 1);
}
plus = result.indexOf('+', plus+1);
}
// Convert /s to *s
var divide = result.indexOf('/');
while (divide !== -1) {
result[divide] = '*';
var termsToInvert = result[divide+1].terms;
if (termsToInvert.length > 1)
throw Error('Attempt to divide by a polynomial with more than one term.');
var termToInvert = termsToInvert[0];
for (var symbol in termToInvert.symbols) {
termToInvert.symbols[symbol] = -termToInvert.symbols[symbol];
}
termToInvert.coeff = 1/termToInvert.coeff;
divide = result.indexOf('/');
}
// Convert ^s to *s
var power = result.indexOf('^');
while (power !== -1) {
var exp = result[power+1];
if (exp.terms.length > 1 || Object.keys(exp.terms[0].symbols).length != 0)
throw Error('Attempt to use non-number as an exponent');
exp = exp.terms[0].coeff;
var base = result[power-1];
var expanded = [power-1, 3, base];
for (var i=0; i<exp-1; i++) {
expanded.push('*');
expanded.push(base);
}
result.splice.apply(result, expanded);
power = result.indexOf('^');
}
// Add implicit *s
for (var i=0; i<result.length-1; i++)
if (!isOperator(result[i]) && !(isOperator(result[i+1])))
result.splice(i+1, 0, '*');
// Multiply
var mult = result.indexOf('*');
while (mult !== -1) {
var product = Polynomial.multiply(result[mult-1], result[mult+1]);
result.splice(mult-1, 3, product);
mult = result.indexOf('*');
}
// Add
var add = result.indexOf('+');
while (add !== -1) {
var sum = Polynomial.add(result[add-1], result[add+1]);
result.splice(add-1, 3, sum);
add = result.indexOf('+');
}
result[0].simplify();
return result[0];
}
var problems = ['(x+1)(x+1)/x', '(x+1)^3', '(x^2*x)(x^2)', '(x+1)(x+1)(x+1)',
'(x+1)^2', 'x(x+1)', '1x^4', '(x + (x+2))(x+5)', '3x^0', '2^3',
'(x+2x(x+2(x+1)x))', '(x+1)(x-1)', '(x+1)(y+1)', '(x+y+t)(q+x+7)'];
var solutionHTML = '';
for (var i = 0; i<problems.length; i++) {
solutionHTML += problems[i] + ' => ' + expand(problems[i]).toHtml() + '<br>';
}
document.body.innerHTML = solutionHTML;
</script>
</html>
It outputs:

Sum ranged values

I am trying to sum the ranged values but for some reason it's not summing. Any idea why?
I am not a very good in JavaScript but I have some knowledge...
function bag(input) {
var sheet = SpreadsheetApp.getActiveSpreadsheet()
var AllValues = sheet.getRange(input).getValues();
var FValue = "";
var TotalGold = 0;
var TotalSilver = 0;
var TotalBronze = 0;
for(i = 0; i < AllValues.length; i++) {
var total = AllValues[i][0].split(" ");
for(i = 0; i < total.length; i++){
if (total[i].indexOf("g") >= 0) {
var value = total[i].replace("g","");
var gold = value * 1;
TotalGold = TotalGold + gold;
}
else if (total[i].indexOf("s") >= 0) {
var value = total[i].replace("s","");
var silver = value * 1;
TotalSilver = TotalSilver + silver;
}
else if (total[i].indexOf("b") >= 0) {
var value = total[i].replace("b","");
var bronze = value * 1;
TotalBronze = TotalBronze + bronze;
}
else {
return null;
}
}
}
return TotalGold + "g " + TotalSilver + "s " + TotalBronze + "b";
}
It appears you are overwriting your value of i in the nested iteration. Pick another identifier. E.g: for (var j = 0; j < total.length; j++) { ... }

Javascript .Replace Alternative

I am coding a template for eBay. However, eBay does not allow .replace. The code below is for a rollover tab section.When the user hovers over tab(a), the correspodning div div(a) is made to become visible.
Is there a workaround to get the code to work without using .replace?
var divs = new Array();
divs.push("contentPayment");
divs.push("contentShipping");
divs.push("contentWarranty");
divs.push("contentContact");
var navs = new Array();
navs.push("nav1");
navs.push("nav2");
navs.push("nav3");
navs.push("nav4");
///////////////////////////////////////
function hasClass(element, cls) {
return (' ' + element.className + ' ').indexOf(' ' + cls + ' ') > -1;
}
///////////////////////////////////////////////////////////////////////
function toggleDisplay(id) {
for (var i = 0; i < divs.length; i++) {
var item = document.getElementById(divs[i]);
item.style.display = 'none';
}
var target = document.getElementById(id);
target.style.display = 'block';
///////////////////////////////////////////////////////////////////////////////////////////////////////
////////////////////////////PAYMENT IS HOVERED////////////////////////////////////////////////////////
if (id == "contentPayment") {
var CurrentTab = document.getElementById("nav1");
var AlreadyActive = hasClass(CurrentTab, "tabActive");
if (AlreadyActive === false) {
for (var i = 0; i < navs.length; i++) {
var otherTabs = document.getElementById(navs[i]);
otherTabs.className = otherTabs.className.replace(' tabActive', '');
}
CurrentTab.className += " " + "tabActive";
}
}
/////////////////////////////////////////////////////////////////////////////////////////////
////////////////////////////Shipping IS HOVERED////////////////////////////////////////////////////////
if (id == "contentShipping") {
var CurrentTab = document.getElementById("nav2");
var AlreadyActive = hasClass(CurrentTab, "tabActive");
if (AlreadyActive === false) {
for (var i = 0; i < navs.length; i++) {
var otherTabs = document.getElementById(navs[i]);
otherTabs.className = otherTabs.className.replace(' tabActive', '');
}
CurrentTab.className += " " + "tabActive";
}
}
///////////////////////////////////////////////////////////////////////////////////////////////////////
////////////////////////////Warranty IS HOVERED////////////////////////////////////////////////////////
if (id == "contentWarranty") {
var CurrentTab = document.getElementById("nav3");
var AlreadyActive = hasClass(CurrentTab, "tabActive");
if (AlreadyActive === false) {
for (var i = 0; i < navs.length; i++) {
var otherTabs = document.getElementById(navs[i]);
otherTabs.className = otherTabs.className.replace(' tabActive', '');
}
CurrentTab.className += " " + "tabActive";
}
}
///////////////////////////////////////////////////////////////////////////////////////////////////////
////////////////////////////Contact IS HOVERED////////////////////////////////////////////////////////
if (id == "contentContact") {
var CurrentTab = document.getElementById("nav4");
var AlreadyActive = hasClass(CurrentTab, "tabActive");
if (AlreadyActive === false) {
for (var i = 0; i < navs.length; i++) {
var otherTabs = document.getElementById(navs[i]);
otherTabs.className = otherTabs.className.replace(' tabActive', '');
}
CurrentTab.className += " " + "tabActive";
}
}
}
You may try this as an alternative of replace function
String.prototype.fakeReplace = function(str, newstr) {
return this.split(str).join(newstr);
};
var str = "Welcome javascript";
str = str.fakeReplace('javascript', '');
alert(str); // Welcome
DEMO.
For a more efficient, but slightly longer method, use this:
String.prototype.myReplace = function(pattern, nw) {
var curidx = 0, len = this.length, patlen = pattern.length, res = "";
while(curidx < len) {
var nwidx = this.indexOf(pattern, curidx);
console.log(nwidx);
if(nwidx == -1) {
break;
}
res = res + this.substr(curidx, nwidx - curidx);
res = res + nw;
curidx = nwidx + patlen;
}
return res;
};
alert("Glee is awesome".myReplace("awesome", "very very very awesome"));
See it in action: little link.
Hope that helped!

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