Develop Reference

Change image based on images position on the screen

I've been trying to find a way that an image will fade and switch to a different image when the images container is visible and scrolled up a certain amount on screen and changes back when you scroll the element back down.
I found the exact functionality being used on this page: http://www.asicstiger.com/gb/en-gb/knit (the 4th section down under the video). I know you could use a jQuery scrollTop method in some cases and all the examples I've found on stackoverflow so far mention this but it doesn't work on my responsive page as elements move around on the page so the images I wan't to switch aren't always at the same hight from page top.
.top {height:100vh;width:100%; background:red}
.scrollImageSwap {width:100%;}
.scrollImageSwap img {width:100%;}
.scrollImageSwap .image1 {display:block;}
.scrollImageSwap .image2 {display:none;}
.bottom {height:100vh;width:100%; background:red}
<div class="top"></div>
<div class="scrollImageSwap">
<img class="image1" src="https://openclipart.org/image/800px/svg_to_png/19972/ivak-TV-Test-Screen.png" alt="image 1" />
<img class="image2" src="http://www.hertenkamp-enkhuizen.nl/test/wp-content/uploads/sites/7/2015/06/testbeeld.jpg" alt="image 2" />
</div>
<div class="bottom"></div>
Can anyone help?

OP noticed the solution worked, but did not use a fade. I have updated the answer.
You can use jQuery's fadeIn(); and fadeOut(); to achieve this:
$(document).scroll(function(){
if($(this).scrollTop() >= $('.scrollImageSwap').offset().top - 5) {
$(".image1").stop().fadeOut(1000, function(){
$(".image2").stop().fadeIn(1000);
});
}
else {
$(".image2").stop().fadeOut(1000, function(){
$(".image1").stop().fadeIn(1000);
});
}
});
This should work properly, as shown in this fiddle.

How to hide the rest of unused image

more you ask, more knowledge you get. Right ? I don't know this question is basic or not but a little make me think hard.
Look pic 1 what do i have.
pic 1: http://imgur.com/YFpfo69
When i upload an image, it will show up to the container called <img id="image"/> and the image is horizontally draggable. My problem is, how do i hide the rest of unused image ? When i dragging the image, the rest will not showing up

To fix this you can place overflow: hidden in the CSS of the parent element of the #image element.

Add the style overflow: hidden; to the parent element, like this:
<div style="overflow: hidden;">
<img src="img.png" id="image" />
</div>

HTML: set max width for image within div

I have a page with several divs like the following using Bootstrap classes.
The divs and buttons adjust their width properly when the screen size changes.
However, the image does not which then causes the image to overlap the underlying div when being watched on a small screen.
Is there any way I can set a max width for the image or do something so that it never exceeds the underlying div ? I tried adding height="auto" and width="80%" to the image but that didn't work.
<div class="txtcntr well well-large span4">
<img src="images/icons/bl_Queue.png" alt="" />
<br /><br />
Check Queue
</div>
Many thanks for any help with this, Tim.

You can try to add css property max-width: 100% for the image

Fluent change of images

I make an image gallery. I have 9 fields, in each field there is an image (or better, there is a part of image). In total, I have 9 big images and in each of that fields there is a 1/9 of each big image.
When I "hover" one of these nine fields, I need to change the other fields to the rest of this image and see the whole image over all fields.
Okay, this I am able to make with CSS and a little bit of JS, but I am looking for any javascript/jQuery effect, let´s say to change image by image from right top corner to left bottom corner, any fluently change between images.
Example, with 3 images:
HTML:
<img onmouseover="show_image('r');" rel="1" src="" class="r">
<img onmouseover="show_image('r');" rel="1" src="" class="r">
<img onmouseover="show_image('b');" rel="2" src="" class="b">
<img onmouseover="show_image('g');" rel="3" src="" class="g">
<img onmouseover="show_image('b');" rel="2" src="" class="b">
<img onmouseover="show_image('g');" rel="3" src="" class="g">
<img onmouseover="show_image('r');" rel="1" src="" class="r">
<img onmouseover="show_image('b');" rel="2" src="" class="b">
<img onmouseover="show_image('g');" rel="3" src="" class="g">
CSS:
img {float: left; width: 30%; height: 100px; margin: 0 9px 9px 0;}
img:nth-child(3n+3) {margin-right: 0;}
.g {background: #070;}
.b {background: #00f;}
.r {background: #f00;}
JavaScript:
function show_image(id) {
$('img').removeClass().addClass(id).removeAttr('onmouseover');
}
(fiddle)
Do you have any idea how to make the fluent change of images when hover one of them?
In HTML there should be all 27 small images, it´s no problem, I´m looking for the switching effect. You can send links for examples, maybe I only don´t know how to call what I need :-)
Thanks.

Ok, I understand your question now!
You mean, when you hover over on an image, the rest of images get replaced by its remaining parts and whole of the 9 images match up to complete the image?
You need to set these functions!
Try to remove the onmouseover function from the element, and try to use jQuery for that!
Lets start the example!
The example image tag:
<img src="some/source/to_file.png" alt="photo" class="image5" id="red" />
First you need to get the image on which the mouse over event occured, like this:
$('img').mouseover(function () {
var id = $(this).attr('id');
var class = $(this).attr('class');
if(id == 'red') {
if(class == 'image5') {
/* replace all the other images with red one
* here you will check the image's class too, which is the number
* location where it is present at!
*/
}
}
}
After this, you will need to shift the image's back too! For that, use this:
$('img').mouseleave(function () {
// shift the src tag back as
$('.image5').attr('src', 'its/src/to_file5.png');
$('.image7').attr('src', 'its/src/to_file7.png');
$('.image6').attr('src', 'its/src/to_file6.png');
}
And so on.
And yes, you will be needed to keep the images in the browser as downloaded files on the page load and just keep shifting them once the user hover's over!
In your fiddle, all you're doing is adding a classname but you are not removing or reverting it back on mouseleave event; there is no mouseleave event.

You can use the jQuery UI switchClass() method which allows you to animate whole class.
Here is a working code sample using your as basis:
function show_image(id) {
$('img').each(function() {
var className = this.className;
if (className == id)
className = '';
$(this).removeClass().switchClass(className, id, 1000, 'linear').removeAttr('onmouseover');
});
}
Since it's removing one class and add other, if the one you remove and add is the same it won't work hence the need to check and reset.
As for "linear" it's just my personal choice of easing method, choose your own from the full list.
Updated fiddle.

jquery mouseover with fade and text

Firstly I have to say I have no coding experience whatsoever, but will try to explain what I am trying to acheive.
I have the following code with 2 images... blue.png is a color image
bluebw.png is the same image in black and white. Code simply changes images on mouse over.
<script type='text/javascript'>
$(document).ready(function(){
$(".blue").hover(function() {
$(this).attr("src","files/blue.png");
}, function() {
$(this).attr("src","files/bluebw.png");
});
});
</script>
<a href="page-1.html">
<img src="files/bluebw.png" alt="dresses" class="blue" height="300" width="170" />
What I would like to do is the following:
add the option for fade in/out on mouseover of the 2 images (fast/slow/or none)
add display text on mouse over with fade in/out on mouseover (fast/slow/or none) after the image fade, format text (font/alignment/top bottom center/background/opacity)
I'm really flying in the dark here :) Any help would be immensely appreciated.
Cheers

Try this:
Suppose you have an HTML structure like this:
<div id="element" style="position:relative;">
<img src="image1.gif" id="img1" />
<img src="image2.gif" id="img2" style="display:none" />
</div>
and css :
img {
position:absolute;
top:0;
left:0;
}
jQuery code:
$("#element").hover(function() {
//fadeout first image using jQuery fadeOut
$("#img1").fadeOut(200);
//fadein second image using jQuery fadeIn
$("#img2").fadeIn(200);
}, function () {
//fadeout second image using jQuery fadeOut
$("#img1").fadeIn(200);
//fadein first image using jQuery fadeIn
$("#img2").fadeOut(200);
});
Here is a fiddle for demo
Or you can use css3 transition:
Here is a fiddle using css3 and jQuery.hover as fallback for ie