I have a php page which encodes an array into a JSON-object or JSONP-callback and simply echoes the result. Because this will become a standalone page that will be accessed directly, I would like to gather insights and include google analytics.
The JSON encode php page:
<?php
$arr = array('country' => 'United States', 'city' => 'New York');
if(isset ($_GET['jsonp'])) {
echo $_GET['jsonp'] . '(' . json_encode($arr) . ')';
}
else {
echo json_encode($arr);
}
?>
The jQuery decode part:
<script>
$.getJSON('https://geoip-db.com/json/geoip.php?jsonp=callback')
.done (function(location)
{
$('#country').html(location.country);
$('#city').html(location.city);
});
</script>
Google guidelines suggest to create a separate php file which contains the javascript tracking code, and include it in all the php pages you want to track. Something like:
<?php include_once("analyticstracking.php") ?>
This way, the tracker works, but when trying to decode the generated JSON object, the JQuery part breaks on a syntax error, caused by the injected tracker script. The php encode page echoes the tracker script too, which produces a useless JSON result.
Any suggestions?
I'm not sure if I understand your problem correctly, but you could always do a call to Google Analytics with serverside code via the measurement protocol:
$url = "v=1&t=pageview&tid=UA-39221247-1&cid=5555&dp=%2Fmy%2Fpage";
fopen($url);
Where "v" is the version, "tid" the account number, "cid" the client id and "dp" a document path for your page.
That way there will be no tracking code in the parsed output that would break the jQuery code.
If you want to aggregate individual views into a session you need to maintain the cid between call yourself.
Note that this does not mix very well with the Javascript based tracking (even if you use a client id from an existing ga cookie it would start a new session within GA).
Could you not load it like this in the footer?
$( document ).ready(function() {
$("analytics-tracking").load('analyticstracking.php');
});
The answer of Eike pointed me in the right direction, therefore +1 for his answer, but I had to use cURL instead of fopen().
My complete working solution:
<?php
$curl_handle=curl_init();
curl_setopt($curl_handle, CURLOPT_URL,'http://www.google-analytics.com/collect/v=1&tid=UA-xxxxxxx-1&cid=555&t=pageview&dp=%2Fgeoip.php');
curl_setopt($curl_handle, CURLOPT_CONNECTTIMEOUT, 2);
curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($curl_handle, CURLOPT_USERAGENT, 'Geoip tracker');
$query = curl_exec($curl_handle);
curl_close($curl_handle);
$arr = array('country' => 'United States', 'city' => 'New York');
if(isset ($_GET['jsonp'])) {
echo $_GET['jsonp'] . '(' . json_encode($arr) . ')';
}
else {
echo json_encode($arr);
}
?>
I guess that is all fine with your google analytics part, jquery breaks because you return at getJson a not json value, in the if() part you return something like:
callback('country' => 'United States', 'city' => 'New York');
Not a valid json, the else part is fine, you should echo the same in the 2 parts.
Related
I’m trying to receive a JSON POST on a payment interface website, but I can’t decode it.
When I print :
echo $_POST;
I get:
Array
I get nothing when I try this:
if ( $_POST ) {
foreach ( $_POST as $key => $value ) {
echo "llave: ".$key."- Valor:".$value."<br />";
}
}
I get nothing when I try this:
$string = $_POST['operation'];
$var = json_decode($string);
echo $var;
I get NULL when I try this:
$data = json_decode( file_get_contents('php://input') );
var_dump( $data->operation );
When I do:
$data = json_decode(file_get_contents('php://input'), true);
var_dump($data);
I get:
NULL
The JSON format is (according to payment site documentation):
{
"operacion": {
"tok": "[generated token]",
"shop_id": "12313",
"respuesta": "S",
"respuesta_details": "respuesta S",
"extended_respuesta_description": "respuesta extendida",
"moneda": "PYG",
"monto": "10100.00",
"authorization_number": "123456",
"ticket_number": "123456789123456",
"response_code": "00",
"response_description": "Transacción aprobada.",
"security_information": {
"customer_ip": "123.123.123.123",
"card_source": "I",
"card_country": "Croacia",
"version": "0.3",
"risk_index": "0"
}
}
}
The payment site log says everything is OK. What’s the problem?
Try;
$data = json_decode(file_get_contents('php://input'), true);
print_r($data);
echo $data["operacion"];
From your json and your code, it looks like you have spelled the word operation correctly on your end, but it isn't in the json.
EDIT
Maybe also worth trying to echo the json string from php://input.
echo file_get_contents('php://input');
If you already have your parameters set like $_POST['eg'] for example and you don't wish to change it, simply do it like this:
$_POST = json_decode(file_get_contents('php://input'), true);
This will save you the hassle of changing all $_POST to something else and allow you to still make normal post requests if you wish to take this line out.
It is worth pointing out that if you use json_decode(file_get_contents("php://input")) (as others have mentioned), this will fail if the string is not valid JSON.
This can be simply resolved by first checking if the JSON is valid. i.e.
function isValidJSON($str) {
json_decode($str);
return json_last_error() == JSON_ERROR_NONE;
}
$json_params = file_get_contents("php://input");
if (strlen($json_params) > 0 && isValidJSON($json_params))
$decoded_params = json_decode($json_params);
Edit: Note that removing strlen($json_params) above may result in subtle errors, as json_last_error() does not change when null or a blank string is passed, as shown here:
http://ideone.com/va3u8U
Use $HTTP_RAW_POST_DATA instead of $_POST.
It will give you POST data as is.
You will be able to decode it using json_decode() later.
Read the doc:
In general, php://input should be used instead of $HTTP_RAW_POST_DATA.
as in the php Manual
$data = file_get_contents('php://input');
echo $data;
This worked for me.
You can use bellow like..
Post JSON like bellow
Get data from php project user bellow like
// takes raw data from the request
$json = file_get_contents('php://input');
// Converts it into a PHP object
$data = json_decode($json, true);
echo $data['requestCode'];
echo $data['mobileNo'];
echo $data['password'];
Quite late.
It seems, (OP) had already tried all the answers given to him.
Still if you (OP) were not receiving what had been passed to the ".PHP" file, error could be, incorrect URL.
Check whether you are calling the correct ".PHP" file.
(spelling mistake or capital letter in URL)
and most important
Check whether your URL has "s" (secure) after "http".
Example:
"http://yourdomain.com/read_result.php"
should be
"https://yourdomain.com/read_result.php"
or either way.
add or remove the "s" to match your URL.
If all of the above answers still leads you to NULL input for POST, note that POST/JSON in a localhost setting, it could be because you are not using SSL. (provided you are HTTP with tcp/tls and not udp/quic)
PHP://input will be null on non-https and if you have a redirect in the flow, trying configuring https on your local as standard practice to avoid various issues with security/xss etc
The decoding might be failing (and returning null) because of php magic quotes.
If magic quotes is turned on anything read from _POST/_REQUEST/etc. will have special characters such as "\ that are also part of JSON escaped. Trying to json_decode( this escaped string will fail. It is a deprecated feature still turned on with some hosters.
Workaround that checks if magic quotes are turned on and if so removes them:
function strip_magic_slashes($str) {
return get_magic_quotes_gpc() ? stripslashes($str) : $str;
}
$operation = json_decode(strip_magic_slashes($_POST['operation']));
I got "null" when I tried to retrieve a posted data in PHP
{
"product_id": "48",
"customer_id": "2",
"location": "shelf", // shelf, store <-- comments create php problems
"damage_types":{"Pests":1, "Poke":0, "Tear":0}
// "picture":"jhgkuignk" <-- comments create php problems
}
You should avoid commenting JSON code even if it shows no errors
I'd like to post an answer that also uses curl to get the contents, and mpdf to save the results to a pdf, so you get all the steps of a tipical use case. It's only raw code (so to be adapted to your needs), but it works.
// import mpdf somewhere
require_once dirname(__FILE__) . '/mpdf/vendor/autoload.php';
// get mpdf instance
$mpdf = new \Mpdf\Mpdf();
// src php file
$mysrcfile = 'http://www.somesite.com/somedir/mysrcfile.php';
// where we want to save the pdf
$mydestination = 'http://www.somesite.com/somedir/mypdffile.pdf';
// encode $_POST data to json
$json = json_encode($_POST);
// init curl > pass the url of the php file we want to pass
// data to and then print out to pdf
$ch = curl_init($mysrcfile);
// tell not to echo the results
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1 );
// set the proper headers
curl_setopt($ch, CURLOPT_HTTPHEADER, [ 'Content-Type: application/json', 'Content-Length: ' . strlen($json) ]);
// pass the json data to $mysrcfile
curl_setopt($ch, CURLOPT_POSTFIELDS, $json);
// exec curl and save results
$html = curl_exec($ch);
curl_close($ch);
// parse html and then save to a pdf file
$mpdf->WriteHTML($html);
$this->mpdf->Output($mydestination, \Mpdf\Output\Destination::FILE);
In $mysrcfile I'll read json data like this (as stated on previous answers):
$data = json_decode(file_get_contents('php://input'));
// (then process it and build the page source)
I’m trying to receive a JSON POST on a payment interface website, but I can’t decode it.
When I print :
echo $_POST;
I get:
Array
I get nothing when I try this:
if ( $_POST ) {
foreach ( $_POST as $key => $value ) {
echo "llave: ".$key."- Valor:".$value."<br />";
}
}
I get nothing when I try this:
$string = $_POST['operation'];
$var = json_decode($string);
echo $var;
I get NULL when I try this:
$data = json_decode( file_get_contents('php://input') );
var_dump( $data->operation );
When I do:
$data = json_decode(file_get_contents('php://input'), true);
var_dump($data);
I get:
NULL
The JSON format is (according to payment site documentation):
{
"operacion": {
"tok": "[generated token]",
"shop_id": "12313",
"respuesta": "S",
"respuesta_details": "respuesta S",
"extended_respuesta_description": "respuesta extendida",
"moneda": "PYG",
"monto": "10100.00",
"authorization_number": "123456",
"ticket_number": "123456789123456",
"response_code": "00",
"response_description": "Transacción aprobada.",
"security_information": {
"customer_ip": "123.123.123.123",
"card_source": "I",
"card_country": "Croacia",
"version": "0.3",
"risk_index": "0"
}
}
}
The payment site log says everything is OK. What’s the problem?
Try;
$data = json_decode(file_get_contents('php://input'), true);
print_r($data);
echo $data["operacion"];
From your json and your code, it looks like you have spelled the word operation correctly on your end, but it isn't in the json.
EDIT
Maybe also worth trying to echo the json string from php://input.
echo file_get_contents('php://input');
If you already have your parameters set like $_POST['eg'] for example and you don't wish to change it, simply do it like this:
$_POST = json_decode(file_get_contents('php://input'), true);
This will save you the hassle of changing all $_POST to something else and allow you to still make normal post requests if you wish to take this line out.
It is worth pointing out that if you use json_decode(file_get_contents("php://input")) (as others have mentioned), this will fail if the string is not valid JSON.
This can be simply resolved by first checking if the JSON is valid. i.e.
function isValidJSON($str) {
json_decode($str);
return json_last_error() == JSON_ERROR_NONE;
}
$json_params = file_get_contents("php://input");
if (strlen($json_params) > 0 && isValidJSON($json_params))
$decoded_params = json_decode($json_params);
Edit: Note that removing strlen($json_params) above may result in subtle errors, as json_last_error() does not change when null or a blank string is passed, as shown here:
http://ideone.com/va3u8U
Use $HTTP_RAW_POST_DATA instead of $_POST.
It will give you POST data as is.
You will be able to decode it using json_decode() later.
Read the doc:
In general, php://input should be used instead of $HTTP_RAW_POST_DATA.
as in the php Manual
$data = file_get_contents('php://input');
echo $data;
This worked for me.
You can use bellow like..
Post JSON like bellow
Get data from php project user bellow like
// takes raw data from the request
$json = file_get_contents('php://input');
// Converts it into a PHP object
$data = json_decode($json, true);
echo $data['requestCode'];
echo $data['mobileNo'];
echo $data['password'];
Quite late.
It seems, (OP) had already tried all the answers given to him.
Still if you (OP) were not receiving what had been passed to the ".PHP" file, error could be, incorrect URL.
Check whether you are calling the correct ".PHP" file.
(spelling mistake or capital letter in URL)
and most important
Check whether your URL has "s" (secure) after "http".
Example:
"http://yourdomain.com/read_result.php"
should be
"https://yourdomain.com/read_result.php"
or either way.
add or remove the "s" to match your URL.
If all of the above answers still leads you to NULL input for POST, note that POST/JSON in a localhost setting, it could be because you are not using SSL. (provided you are HTTP with tcp/tls and not udp/quic)
PHP://input will be null on non-https and if you have a redirect in the flow, trying configuring https on your local as standard practice to avoid various issues with security/xss etc
The decoding might be failing (and returning null) because of php magic quotes.
If magic quotes is turned on anything read from _POST/_REQUEST/etc. will have special characters such as "\ that are also part of JSON escaped. Trying to json_decode( this escaped string will fail. It is a deprecated feature still turned on with some hosters.
Workaround that checks if magic quotes are turned on and if so removes them:
function strip_magic_slashes($str) {
return get_magic_quotes_gpc() ? stripslashes($str) : $str;
}
$operation = json_decode(strip_magic_slashes($_POST['operation']));
I got "null" when I tried to retrieve a posted data in PHP
{
"product_id": "48",
"customer_id": "2",
"location": "shelf", // shelf, store <-- comments create php problems
"damage_types":{"Pests":1, "Poke":0, "Tear":0}
// "picture":"jhgkuignk" <-- comments create php problems
}
You should avoid commenting JSON code even if it shows no errors
I'd like to post an answer that also uses curl to get the contents, and mpdf to save the results to a pdf, so you get all the steps of a tipical use case. It's only raw code (so to be adapted to your needs), but it works.
// import mpdf somewhere
require_once dirname(__FILE__) . '/mpdf/vendor/autoload.php';
// get mpdf instance
$mpdf = new \Mpdf\Mpdf();
// src php file
$mysrcfile = 'http://www.somesite.com/somedir/mysrcfile.php';
// where we want to save the pdf
$mydestination = 'http://www.somesite.com/somedir/mypdffile.pdf';
// encode $_POST data to json
$json = json_encode($_POST);
// init curl > pass the url of the php file we want to pass
// data to and then print out to pdf
$ch = curl_init($mysrcfile);
// tell not to echo the results
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1 );
// set the proper headers
curl_setopt($ch, CURLOPT_HTTPHEADER, [ 'Content-Type: application/json', 'Content-Length: ' . strlen($json) ]);
// pass the json data to $mysrcfile
curl_setopt($ch, CURLOPT_POSTFIELDS, $json);
// exec curl and save results
$html = curl_exec($ch);
curl_close($ch);
// parse html and then save to a pdf file
$mpdf->WriteHTML($html);
$this->mpdf->Output($mydestination, \Mpdf\Output\Destination::FILE);
In $mysrcfile I'll read json data like this (as stated on previous answers):
$data = json_decode(file_get_contents('php://input'));
// (then process it and build the page source)
I’m trying to receive a JSON POST on a payment interface website, but I can’t decode it.
When I print :
echo $_POST;
I get:
Array
I get nothing when I try this:
if ( $_POST ) {
foreach ( $_POST as $key => $value ) {
echo "llave: ".$key."- Valor:".$value."<br />";
}
}
I get nothing when I try this:
$string = $_POST['operation'];
$var = json_decode($string);
echo $var;
I get NULL when I try this:
$data = json_decode( file_get_contents('php://input') );
var_dump( $data->operation );
When I do:
$data = json_decode(file_get_contents('php://input'), true);
var_dump($data);
I get:
NULL
The JSON format is (according to payment site documentation):
{
"operacion": {
"tok": "[generated token]",
"shop_id": "12313",
"respuesta": "S",
"respuesta_details": "respuesta S",
"extended_respuesta_description": "respuesta extendida",
"moneda": "PYG",
"monto": "10100.00",
"authorization_number": "123456",
"ticket_number": "123456789123456",
"response_code": "00",
"response_description": "Transacción aprobada.",
"security_information": {
"customer_ip": "123.123.123.123",
"card_source": "I",
"card_country": "Croacia",
"version": "0.3",
"risk_index": "0"
}
}
}
The payment site log says everything is OK. What’s the problem?
Try;
$data = json_decode(file_get_contents('php://input'), true);
print_r($data);
echo $data["operacion"];
From your json and your code, it looks like you have spelled the word operation correctly on your end, but it isn't in the json.
EDIT
Maybe also worth trying to echo the json string from php://input.
echo file_get_contents('php://input');
If you already have your parameters set like $_POST['eg'] for example and you don't wish to change it, simply do it like this:
$_POST = json_decode(file_get_contents('php://input'), true);
This will save you the hassle of changing all $_POST to something else and allow you to still make normal post requests if you wish to take this line out.
It is worth pointing out that if you use json_decode(file_get_contents("php://input")) (as others have mentioned), this will fail if the string is not valid JSON.
This can be simply resolved by first checking if the JSON is valid. i.e.
function isValidJSON($str) {
json_decode($str);
return json_last_error() == JSON_ERROR_NONE;
}
$json_params = file_get_contents("php://input");
if (strlen($json_params) > 0 && isValidJSON($json_params))
$decoded_params = json_decode($json_params);
Edit: Note that removing strlen($json_params) above may result in subtle errors, as json_last_error() does not change when null or a blank string is passed, as shown here:
http://ideone.com/va3u8U
Use $HTTP_RAW_POST_DATA instead of $_POST.
It will give you POST data as is.
You will be able to decode it using json_decode() later.
Read the doc:
In general, php://input should be used instead of $HTTP_RAW_POST_DATA.
as in the php Manual
$data = file_get_contents('php://input');
echo $data;
This worked for me.
You can use bellow like..
Post JSON like bellow
Get data from php project user bellow like
// takes raw data from the request
$json = file_get_contents('php://input');
// Converts it into a PHP object
$data = json_decode($json, true);
echo $data['requestCode'];
echo $data['mobileNo'];
echo $data['password'];
Quite late.
It seems, (OP) had already tried all the answers given to him.
Still if you (OP) were not receiving what had been passed to the ".PHP" file, error could be, incorrect URL.
Check whether you are calling the correct ".PHP" file.
(spelling mistake or capital letter in URL)
and most important
Check whether your URL has "s" (secure) after "http".
Example:
"http://yourdomain.com/read_result.php"
should be
"https://yourdomain.com/read_result.php"
or either way.
add or remove the "s" to match your URL.
If all of the above answers still leads you to NULL input for POST, note that POST/JSON in a localhost setting, it could be because you are not using SSL. (provided you are HTTP with tcp/tls and not udp/quic)
PHP://input will be null on non-https and if you have a redirect in the flow, trying configuring https on your local as standard practice to avoid various issues with security/xss etc
The decoding might be failing (and returning null) because of php magic quotes.
If magic quotes is turned on anything read from _POST/_REQUEST/etc. will have special characters such as "\ that are also part of JSON escaped. Trying to json_decode( this escaped string will fail. It is a deprecated feature still turned on with some hosters.
Workaround that checks if magic quotes are turned on and if so removes them:
function strip_magic_slashes($str) {
return get_magic_quotes_gpc() ? stripslashes($str) : $str;
}
$operation = json_decode(strip_magic_slashes($_POST['operation']));
I got "null" when I tried to retrieve a posted data in PHP
{
"product_id": "48",
"customer_id": "2",
"location": "shelf", // shelf, store <-- comments create php problems
"damage_types":{"Pests":1, "Poke":0, "Tear":0}
// "picture":"jhgkuignk" <-- comments create php problems
}
You should avoid commenting JSON code even if it shows no errors
I'd like to post an answer that also uses curl to get the contents, and mpdf to save the results to a pdf, so you get all the steps of a tipical use case. It's only raw code (so to be adapted to your needs), but it works.
// import mpdf somewhere
require_once dirname(__FILE__) . '/mpdf/vendor/autoload.php';
// get mpdf instance
$mpdf = new \Mpdf\Mpdf();
// src php file
$mysrcfile = 'http://www.somesite.com/somedir/mysrcfile.php';
// where we want to save the pdf
$mydestination = 'http://www.somesite.com/somedir/mypdffile.pdf';
// encode $_POST data to json
$json = json_encode($_POST);
// init curl > pass the url of the php file we want to pass
// data to and then print out to pdf
$ch = curl_init($mysrcfile);
// tell not to echo the results
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1 );
// set the proper headers
curl_setopt($ch, CURLOPT_HTTPHEADER, [ 'Content-Type: application/json', 'Content-Length: ' . strlen($json) ]);
// pass the json data to $mysrcfile
curl_setopt($ch, CURLOPT_POSTFIELDS, $json);
// exec curl and save results
$html = curl_exec($ch);
curl_close($ch);
// parse html and then save to a pdf file
$mpdf->WriteHTML($html);
$this->mpdf->Output($mydestination, \Mpdf\Output\Destination::FILE);
In $mysrcfile I'll read json data like this (as stated on previous answers):
$data = json_decode(file_get_contents('php://input'));
// (then process it and build the page source)
I have got data from mysql in php, and i want to send it to typescript using JSON. but when load the php page. nothing showed in the screen. It always shows a blank page.
$select ="SELECT * from `filiere`";
$run = mysqli_query($connect, $select);
$temp = array();
while($row=mysqli_fetch_row($run)) {
$temp[] = $row;
}
echo json_encode($temp);
from the code, it should show the data in json format.
what it is the problem?
I think i've understood where is my error.
You are all right. i have some data with frensh letters like ('é', 'ù'..). I think that was the problem.
Thank you all
In PHP, an unexpeted blank page usually means some kind of error + error reporting turned off.
Try to turn error reporting on
ini_set('display_startup_errors',1);
ini_set('display_errors',1);
error_reporting(E_ALL);
EDIT #1:
Based on the comments, it seems that json_encode() fails, so returns false (echoing false will result in a blank page).
The json_last_error() and/or json_last_error_msg() functions should be used to find the error.
EDIT #2:
The first argument of json_encode() must hold only UTF-8 encoded strings.
did you set endpoint content-type on php ?
header('Content-Type: application/json');
For some reason, when I try to send JSON data to a PHP page (where it gets downloaded as a spreadsheet), it runs without error, but doesn't bring up the prompt to download the spreadsheet. The JSON has generated without problem (I have made the PHP page create the file on the server, before trying to make it download without creating it).
Here is the JavaScript code that sends the JSON data to the server:
function writeToSpreadsheet()
{
// get the json for #theTable
var tableJSON = tableToJSON("tr:not(#titleRow)");
//alert(tableJSON);
alert("Sending table data to be written to the spreadsheet...");
$.post('/ResearchProject/tableContent/exportTable.php', {'table': tableJSON}).done(
function(response) { alert(((response == '') ? response : (tableJSON.title + ' written to file!')));})
.fail(function (xhr, ajaxOptions, thrownError) { alert("ERROR:" + xhr.responseText+" - "+thrownError); });
}
and here is exportTable.php
<?php
function cleanData(&$str)
{
$str = preg_replace("/\t/", "\\t", $str); // escaping all of the tabs
$str = preg_replace("/\r?\n/", "\\n", $str); // escaping any and all cases of carriage return
// if there is a single double-quote in the string, we wrap the string in quotes, replace every single double-quote with double double-quotes, and
// end with a double-quote
if(strstr($str, '"')) $str = '"' . str_replace('"', '""', $str) . '"';
}
// the data is coming from a JSON object that is being sent here
if (isset($_POST['table']))
{
$tableJSON = $_POST['table']; # somehow, this is already a PHP array (exactly the one we need)!!
// get the name of the table from the $tableJSON
$tableName = $tableJSON['title'];
// get the title row from $tableJSON
$titleRow = $tableJSON['titleRow'];
// fix the titleRow
foreach ($titleRow as $heading)
{
$heading = trim(preg_replace('/\s+/', ' ', $heading));
}
// get the rows from $tableJSON
$rows = $tableJSON['rows'];
// form the filename from the tableName
$fileName = $tableName . '.xls';
// here, we download the file without even creating it
header("Content-Disposition: attachment; filename=\"$fileName\"");
header("Content-Type: application/vnd.ms-excel");
// we echo the titleRow first
array_walk($titleRow, 'cleanData');
echo implode(chr(9), $titleRow) . "\r\n";
?>
<script>console.log('Title row written to file.');</script>
<?php
// now we echo the data
foreach($rows as $row)
{
array_walk($row, 'cleanData');
echo implode(chr(9), $row) . "\r\n";
?>
<script>console.log('Data row written to file.');</script>
<?php
}
}
else
{
echo 'You sent me no data :(\n';
}
?>
OK, MikeWarren, how do I test this??
You can test it by selecting a table from the dropdown menu and clicking the "Export table to spreadsheet" button here: http://dinotator.biokdd.org/ResearchProject/tableViewer.php
I am trying to have it where the table that is on the HTML page gets converted into an JSON object, and then downloaded. Thus, I would need to POST the data to the PHP page, right? (Query strings don't work.)
Query strings won't work because you are using jQuery's $.post call which means that your data is sent in the body of the request, as opposed to a query string which is what a GET uses. For JSON you do indeed want to use a POST.
As for what's going wrong, you need to decode your JSON into a PHP array using json_decode. Unfortunately it can't simply handle JSON how it is.
So most likely you'll want to do:
// now a poorly named variable
$tableJSON = json_decode($_POST['table']);
Also, looking at your Ajax, $.post does accept a .fail() listener, but it doesn't pass any error data as part of the callback. So if you want to be able to handle incoming response errors you'll need to use $.ajax:
$.ajax({
type: "POST",
url: "/your/url.php",
dataType: "json",
error: errorCallback
});
Finally, looking at how your code is structured, if you're actually trying to save to file, you're going to need some more logic. Right now, you're just rendering that table, and then returning it as a response which will show up in your done function. You're going to add some more logic in order to make it actually download. This question entails your exact problem.
Good luck!
I have found so much bad advice on the internet about how to solve this problem. One of the answers here also didn't work. :(
I have decided to get advice from a friend of mine, and me and him have decided on this approach:
Have my exportData.php simply write the data to $_SESSION, echo a JSON-encoded "success", and then exit
On exit, on the client-side of things, if "success" has been received, have the JavaScript open up a new tab to a file that I have created called downloadFile.php which actually does the downloading.
Why didn't sending the data between files work?
Downloading data entails setting the right headers and printing the data. When you send data to the file to do this (via AJAX), the buffer that the data is printed to is the one for response. You can see this by saying something like
success: function(response)
{
alert(response);
} and see the data that you "downloaded" not get downloaded, but get printed on-screen.
However, if you go to the file instead of simply passing data to it, your data will download, provided that it has access to the data that you are trying to download. You can see examples of this here: www.the-art-of-web.com/php/dataexport/ . In those examples, the data was "static" (that is, only existing in the scope of that PHP file, until download happened).
We then see that we should let another file handle the downloading. Here is what its contents should look like:
<?php
if (!isset($_SESSION))
session_start();
function cleanData(&$str)
{
$str = preg_replace("/\t/", "\\t", $str); // escaping all of the tabs
$str = preg_replace("/\r?\n/", "\\n", $str); // escaping any and all cases of carriage return
// if there is a single double-quote in the string, we wrap the string in quotes, replace every single double-quote with double double-quotes, and
// end with a double-quote
if(strstr($str, '"')) $str = '"' . str_replace('"', '""', $str) . '"';
}
// get the data from $_SESSION
if (isset($_SESSION))
{
$fileName = $_SESSION['fileName'];
$titleRow = $_SESSION['titleRow'];
$rows = $_SESSION['rows'];
// set the excel headers
header("Content-Type: application/vnd.ms-excel");
//header("Content-type: application/octet-stream");
header("Content-Disposition: attachment; filename=\"$fileName\"");
header("Pragma: no-cache");
header("Expires: 0");
// attempt download
array_walk($titleRow, 'cleanData');
echo implode(chr(9), $titleRow) . "\r\n";
// now we echo the data
foreach($rows as $row)
{
array_walk($row, 'cleanData');
echo implode(chr(9), $row) . "\r\n";
}
}
else
{
die('Problem with session variable. Data could not be sent for download.');
}
exit;
?>
Of course, before doing this, make sure that you have 'fileName', 'titleRow', and 'rows' already written to $_SESSION.
This should help anyone having problem downloading HTML table to Excel spreadsheet via PHP, and the best part is that you don't have to bloat your server by downloading an entire library, for potentially the functionality of one button!!