I want to validate a password via JavaScript with help of an Ajax function.
If it is successful, I want to pass back the variable (boolean, true or false) and do something in my PHP file depending on the callback.
But this doesn't work. Here is my code:
PHP file: update.php
<input href="javascript:void(0);" role="button" ype="submit" value="Submit" onclick="ValidatePassword()>'
JAVASCRIPT: ValidatePassword()
In my Javascript function I check the password with this ajax call and if it is successfull, it should callback the result to the php function.
$.ajax({
type: "POST",
url: "checkpw.php",
data: dataString,
cache: false,
success: function(response)
{
if (result != -1 )
{
$("#passwd").val('');
// RETURN TO PHP FILE update.php -> PW IS VALID
} else {
// RETURN TO PHP FILE update.php -> PW IS INVALID
}
}
});
PHP file: update.php
Now I want to use the callback in the php function like:
<?php
if (passwordCallback == true)
...
else
...
?>
What should I do in the ajax success function to return the value to my php file?
As I suggested in the comments, if this is not coded correctly it can lead to security issues. If it is coded correctly then it will end up doing the password check twice when it only needs to be done once.
Instead what you could do is:
$.ajax({
type: "POST",
url: "checkandupdate.php", //Combination of both
data: dataString,
cache: false,
success: function(response)
{
if (result != -1 ) {
$("#passwd").val('');
}
}
});
File checkandupdate.php
<?php
require "checkpw.php"; // Or whatever you need to do to validate the password
// At this point "checkpw.php" determined if the password is valid and(ideally) you can check the outcome
//Assume we store the outcome of the check in $passwordIsValid as a boolean indicating success
if ($passwordIsValid) {
//Do whatever you need to do when the password is valid
echo "1"
}
else {
// Do whatever you need to do when the password is invalid
echo "-1";
}
?>
You need to write a JavaScript function like:
function sendReturnToPHP(url, result) {
$.ajax({
type: "POST",
url: url,
data: JSON.parse(result),
cache: false,
success: function(response) {}
});
}
Now you can easily call it in your request success.
Related
I want to update the value of an input field when I receive some information from an api. I tried using:
$('#txtFirstName').val($_SESSION['jUser']['first_name']);
But an error occurs due to the PHP not being able to run in a js file. How can I make this update otherwise? Is there a way in js to update the entire form and input fields without submitting?
I can't reload the entire window, because it will eliminate other information that the user of the website has put in.
1) put value into #txtFirstName from php script
// script.php code
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
echo $_SESSION['jUser']['first_name'];
}
// javascript code
function func(){
$.ajax({
type: "POST",
url: "script.php",
success: function (response) {
$('#txtFirstName').val(response);
},
error: function (e) {
console.log("ERROR : ", e);
}
});
}
2) put value into $_SESSION['jUser']['first_name'] from javascript
// javascript code
function func(){
var your_value = "some_value";
$.ajax({
type: "POST",
url: "script.php",
data: { va: your_value },
success: function (response) {
console.log("value setted to session successfully");
},
error: function (e) {
console.log("ERROR : ", e);
}
});
}
// script.php code
if ($_SERVER['REQUEST_METHOD'] === 'POST' && $_POST['va'] !='') {
$_SESSION['jUser']['first_name'] = $_POST['va'];
echo "ok";
}
Why don't you just echo the value from php script and make an AJAX request from javascript to get the value ? This should be the recommended approach.
However, it can also be accomplished with the approach you've taken:
let first_name = <?php echo $_SESSION['jUser']['first_name']; ?>:
$('#txtFirstName').val(first_name);
For further reading, you can visit How do I embed PHP code in JavaScript?
.
I am sending data to a PHP file using AJAX and depending on what data is sent, an alert() is either shown or not shown.
Inside the success function in AJAX, how do I detect if an alert box was shown?
var called = $("#called").val();
$.ajax({
type: "POST",
url: "send.php",
data: "name=" + called,,
success: function(data) {
if(alert box was shown) {
// something happens
}else{
// alert box wasn't shown, something else happens.
}
}
});
send.php:
<?php
if($_POST['name'] == 'john') {
echo'
<script>
alert("Correct name");
</script>
';
}
It would be better to send back a result form the ajax request and show/don't show the alert in the success callback:
$.ajax({
type: "POST",
url: "send.php",
data: "name=" + called,,
success: function(data) {
if ( data == "show" ) {
// something happens
alert("Correct name");
} else {
// alert box wasn't shown, something else happens.
}
}
});
And on your server:
if ( $_POST['name'] == 'john' ) {
echo "show";
}
You could use json_encode() php function to return data from php.
This will be a better approach :
PHP :
if (!isset($_POST['name'] || empty($_POST['name']) {
die(json_encode(array('return' => false, 'error' => "Name was not set or is empty")));
} elseif ($_POST['name'] == "John") {
die(json_encode(array('return' => true)));
} else {
die(json_encode(array('return' => false, 'error' => "Name is different than John.")));
}
At this point, you will be allowed to check the returned values from JS and decide if you need to display the success alert or send an error message to the console (or do what ever you want...).
JS :
var called = $("#called").val();
$.ajax({
type: "POST",
url: "send.php",
dataType: "JSON", // set the type of returned data to json
data: {name: called}, // use more readable syntaxe
success: function(data) {
if (data.return) { // access the json data object
alert("Congrats ! Your name is John !");
} else {
console.log("Sorry, something went wrong : " + data.error);
}
}
});
So, json_encode() allows to return easy accessible object from JS and will also allows you to set and display error messages easily in case the return is false.
Hope it helps !
PHP does not know if an alert has been shown, because in javascript the alert() function has no return value and no events which you could use to send an ajax request a click confirmation to the server.
One solution is to use a confirm() command inside the success event of your $.ajax(), which sends anothe ajax request if the user clicked "ok" or "cancel".
Something like this
var called = $("#called").val();
$.ajax({
type: "POST",
url: "send.php",
data: "name=" + called,
success: function(data) {
if (data == "show") {
var clicked = confirm("Correct name");
if (clicked == true || clicked == false) {
$.ajax({
url: "send.php?clicked=1",
});
}
}
else {
// Whatever to do than...
}
}
});
i have a little problem with my script.
I want to give data to a php file with AJAX (POST).
I dont get any errors, but the php file doesn't show a change after AJAX "runs" it.
Here is my jquery / js code:
(#changeRank is a select box, I want to pass the value of the selected )
$(function(){
$("#changeRank").change(function() {
var rankId = this.value;
//alert(rankId);
//$.ajax({url: "/profile/parts/changeRank.php", type: "post", data: {"mapza": mapza}});
//$("body").load("/lib/tools/popups/content/ban.php");
$.ajax({
type: "POST",
async: true,
url: '/profile/parts/changeRank.php',
data: { 'direction': 'up' },
success: function (msg)
{ alert('success') },
error: function (err)
{ alert(err.responseText)}
});
});
});
PHP:
require_once('head.php');
require_once('../../lib/permissions.php');
session_start();
$user = "test";
if($_SESSION["user"] != $user && checkPermission("staff.fakeLogin", $_SESSION["user"], $mhost, $muser, $mpass, $mdb))
$_SESSION["user"] = $user;
header('Location:/user/'.$user);
die();
When i run the script, javascript comes up with an alert "success" which means to me, that there aren't any problems.
I know, the post request for my data is missing, but this is only a test, so im planning to add this later...
I hope, you can help me,
Greets :)
$(function(){
$("#changeRank").change(function() {
var rankId = this.value;
//alert(rankId);
//$.ajax({url: "/profile/parts/changeRank.php", type: "post", data: {"mapza": mapza}});
//$("body").load("/lib/tools/popups/content/ban.php");
$.ajax({
type: "POST",
async: true,
url: '/profile/parts/changeRank.php',
data: { 'direction': 'up' },
success: function (msg)
{ alert('success: ' + JSON.stringify(msg)) },
error: function (err)
{ alert(err.responseText)}
});
});
});
require_once('head.php');
require_once('../../lib/permissions.php');
session_start();
$user = "test";
if($_SESSION["user"] != $user && checkPermission("staff.fakeLogin", $_SESSION["user"], $mhost, $muser, $mpass, $mdb))
$_SESSION["user"] = $user;
echo json_encode($user);
This sample code will let echo the username back to the page. The alert should show this.
well your js is fine, but because you're not actually echoing out anything to your php script, you wont see any changes except your success alert. maybe var_dump your post variable to check if your data was passed from your js file correctly...
Just return 0 or 1 from your php like this
Your PHP :
if($_SESSION["user"] != $user && checkPermission("staff.fakeLogin", $_SESSION["user"], $mhost, $muser, $mpass, $mdb))
{
$_SESSION["user"] = $user;
echo '1'; // success case
}
else
{
echo '0'; // failure case
}
Then in your script
success: function (msg)
if(msg==1)
{
window.location = "home.php"; // or your success action
}
else
{
alert('error);
}
So that you can get what you expect
If you want to see a result, in the current page, using data from your PHP then you need to do two things:
Actually send some from the PHP. Your current PHP redirects to another URL which might send data. You could use that or remove the Location header and echo some content out instead.
Write some JavaScript that does something with that data. The data will be put into the first argument of the success function (which you have named msg). If you want that data to appear in the page, then you have to put it somewhere in the page (e.g. with $('body').text(msg).
I have this ajax send two variables to php, it sends the 2nd one trough fine but the first variable is always reported by php as NULL, i console log the javascript variable before sendign it and it does return an array of strings so I have no idea what is going on.
console.log(givenSpots);
jQuery.ajax({
type: "POST",
url: "includes/map/update.php",
data: {'spots': givenSpots, 'thisEvent': givenEvent},
dataType: "json",
cache: false,
async: false,
success: function(result){
response = result;
}
});
The receiving PHP is:
session_start();
if(isset($_SESSION["adminid"])){
$currentUser = $_SESSION["adminid"];
} else if(isset($_SESSION["vartotojasid"])){
$currentUser = $_SESSION["vartotojasid"];
} else $currentUser = false;
if ($currentUser) {
file_put_contents("update.txt", "0 ");
include_once "../../../../../../connection.php";
$event = $_POST["thisEvent"];
if (isset($_POST["spots"])) {
$data = $_POST["spots"];...
you need to encode your array to json before sending it to php, you can use
JSON.stringify(postDataArray)
or using jquery $.post :
$.post(yourURL, {
data : $.toJSON(postDataArray)
}, function(response){
//do something with your response
}
);
than just decode it with php and use it on your server
i am adding the value to database by using ajax after adding i want to display the value in front end but now after success i am using window.location to show the data because of this the page getting refresh,i don't want to refresh the page to show the data ,anyone guide me how to do this.
below is my ajax
$(function() {
$(".supplierpriceexport_button").click(function() {
var pricefrom = $("#pricefrom").val();
var priceto = $("#priceto").val();
var tpm = $("#tpm").val();
var currency = $("#currency").val();
var dataString = 'pricefrom='+ pricefrom +'&priceto='+priceto+'&tpm='+tpm+'¤cy='+currency;
if(pricefrom=='')
{
alert("Please Enter Some Text");
}
else
{
$("#flash").show();
$("#flash").fadeIn(400).html;
$.ajax({
type: "POST",
url: "supplierpriceexport/insert.php",
data: dataString,
cache: false,
success: function(html){
$("#display").after(html);
window.location = "?action=suppliertargetpiceexport";
$("#flash").hide();
}
});
} return false;
});
});
The code that you are using to post the data needs to return some meaningful data, JSON is useful for this, but it can be HTML or other formats.
To return your response as JSON from PHP, you can use the json_encode() function:
$return_html = '<h1>Success!</h1>';
$success = "true";
json_encode("success" => $success, "html_to_show" => $return_html);
In this piece of code, you can set your dataType or JSON and return multiple values including the HTML that you want to inject into the page (DOM):
$.ajax({
type: "POST",
url: "supplierpriceexport/insert.php",
data: dataString,
cache: false,
//Set the type of data we are expecing back
dataType: json
success: function(return_json){
// Check that the update was a success
if(return_json.success == "true")
{
// Show HTML on the page (no reload required)
$("#display").after(return_json.html_to_show);
}
else
{
// Failed to update
alert("Not a success, no update made");
}
});
You can strip out the window.location altogether, else you won't see the DOM update.
Just try to return the values that you need from the ajax function.Something like this might do.
In your insert.php
echo or return the data at the end of the function that needs to be populated into the page
$.ajax({
type: "POST",
url: "supplierpriceexport/insert.php",
data: dataString,
cache: false,
success: function(data){
//Now you have obtained the data that was was returned from the function
//if u wish to insert the value into an input field try
$('#input_field').val(data); //now the data is pupolated in the input field
}
});
Don't use window.location = "?action=suppliertargetpiceexport";
This will redirect to the page suppliertargetpiceexport
$.ajax({
type: "POST",
url: "supplierpriceexport/insert.php",
data: dataString,
cache: false,
success: function(html){
$('#your_success_element_id').html(html); // your_success_element_id is your element id where the html to be populated
$("#flash").hide();
}
});
your_success_element_id is your element id where the html to be populated