I have to determine whether two concave/convex shapes are at distance d from each other . I know Separating Axis theorem might come handy in determining the distance , but that runs in O(n2) time , and I am looking for O(n) or O(nlogn) algorithm for any shape . I want to implement that for any two SVGs in javascript
This is a broad and arduous problem.
To handle the most difficult cases (like ellipse/Bezier distance), you will need to somehow flatten the outlines so I recommend to flatten in all cases, and solve the problem for two polygons only.
Amazingly, you find little resources on the Web for the distance between two polygons.
Assuming that you are dealing with the inside of the shapes (and not just the outline), you will first have to check the polygons for void intersection (otherwise the distance is 0). I guess that this can be done in time O(N.Log(N)).
Then, if I am right, the closest distance between two polygons is the shortest of the closest distances of all vertices to the other polygon. If you construct the Voronoi diagram of both polygons (which is doable in time O(N.Log(N))), you get two planar subdivision, in which you can solve the point-location problem in time Log(N) per point.
All put together should lead to an O(N.Log(N)) solution. You will need a specialized Computational Geometry library to achieve this.
Related
I'm looking for algorithm that will cut my convex polygon based on another convex polygon. It is gonna be for destructible terrain (diff) and for creating terrain (union) in 2D map in game.
Algorithm has to be Garbage Collector friendly and the only boolean operations that are neccessary are Union & Difference.
I've done some research and there are some github projects, but all of them produce some garbage more or less.
https://github.com/tmpvar/2d-polygon-boolean
https://github.com/w8r/GreinerHormann
I guess the best solution would be to learn one of these and re-make it my way. But maybe you've heard about some that suits my needs?
Thanks.
This problem involves two subproblems
find the intersection points between the two outlines
join the vertices that mus be joined.
For 1. you can exploit convexity: see both polygons as two monotone chains. When you travel the chains of the twopolygons simultaneously, say by increasing x, the intersections are detected when the ordinates cross each other between two abscissas.
For 2. notice that the union or difference are made of portions of the outlines alternating between one polygon and the other, at every interesection point.
Note that in the case of the difference, there can be several disconnected pieces.
I guess that you can implement this without any allocation/deallocation at all (but for the output polygon).
Basically what I am looking for is very similar to the following (although I am writing this in javascript):
Finding Minimum Distance between Contours
I have an image where I have already calculated outlines for multiple shapes and I want to connect the shapes if some point from object 1 and another point from object 2 share a minimum distance less than d.
The problem is that the accepted answer in that question seems to suggest looping through all points in object 2 for each point in object 1 which appears super inefficient to me. In my case scenario I will have multiple objects with large paths so that approach would not be feasible,
Is there some smarter method to approach this problem calculating the shortest point between two boundaries?
I am rendering a map out of SVG paths (using jVectormap).
There are cases where one region has to be merged with the neighboring region.
Unfortunately both regions don't touch each other and I have to interpolate to fill the space in between.
jVectormap uses very simple SVG paths with M to set the the absolute startpoint and l to connect relative points.
Does any of the SVG libraries cover such an operation?
I haven't tried this, but you may get around it by running the converter at jVectormap with the following parameters:
--buffer_distance=0
--where="ISO='region_1' OR ISO='region_2'"
Where region_1 and region_2 are the two regions that you need to merge.
Solving the problem this way also means that the generated SVG paths are true to the original coordinates, whereas a following fix may lead to some (probably minor) inconsistencies.
This might not be the kind of answer you're looking for, but using Raphael.js you could loop over the entire length of the path of one region getPointAtLength(), comparing it with all points of the second region. If the coordinates are closer than n pixels from any coordinates on the second region and the previous coordinates weren't, than that could be regarded a "glue" point. You would then jump to the second regio and start looping over it, if the next point is still closer than n points, than go in the opposite direction, if still closer change direction and go farther along the path till finding a point that's farther away from the original region than n pixels. Continue looping in that direction till once again finding a new "glue" point, where once again you will switch to the original region in the manner described and all points which weren't covered in this final loop could be discarded (or you could simply create a new shape based on the points you came across whilst looping over the length of the original region.
True enough, it's not the easiest script to make, but it should be quite do-able I believe, especially when you can use a function like getPointAtLength to find the points between the defined svg points (though you need to only 'record' the defined points, and that's sort of the hard path as Raphael.js doesn't excitedly have any functions which would help with this, still even that shouldn't be too hard to match up by hand (in code of course)).
I don't think there's a good answer to this, but I'd like to find out if there's a better way to do this.
I need to plot a mathematical function, which is nearly flat at one end of the display, and nearly vertical at the other end. The bottom left quadrant of a circle would be a good model. I can auto-generate as many points as required.
The problem is, I can't do this without all sorts of artefacts.
I haven't tried Bezier fitting; I don't think this would be even close. My understanding is that Bezier is for one-off manually-constructed pretty graphics, and not for real curve-fitting.
That leaves polylines. There are only 2 things I can do with polylines - I can select the line length (in other words, the number of points I auto-generate), and I can disable anti-aliasing (setAttributeNS(null, "shape-rendering", "crisp-edges").
If I generate lots of points, then I get jaggies everywhere, and the result is unusable. It can also look very much like it's oscillating, which makes it appear that I've incorrectly calculated the function. The anti-aliasing doesn't make any difference, since it doesn't operate across point boundaries.
The only solution I've got is to draw fewer points, so that it's obvious that I'm drawing segments. It's no longer smooth, but at least there are no jaggies or oscillation. I draw this with the default anti-aliasing.
Any ideas?
Edit:
It seems like the only answer to this is actually Bezier curve fitting. You have to preprocess to find the parameters of the required segments, and then plot the results. Google comes up with a number of hits on curve fitting with Beziers.
You have the mathematical function, and can therefore generate as many points as you need.
I assume the problem is that because you do not know the output resolution (SVG is device independent) you do not know how many points to generate. Otherwise you could just create a polyline where each line is approximately 1 pixel long.
Fitting your mathematical function to a bezier curve is (probably) not going to get a perfect match - just like a circle cannot be matched perfectly by a cubic bezier curve. And I think the task of fitting your function to a bezier curve would not be trivial (I've never done this).
Could you rather output your mathematical function to a canvas element? Then you could write some javascript code to plot your mathematical function dependant on the output resolution. Similar to how a graphics system renders a Bezier curve.
Do you know how graphics systems render Bezier curves? They approximate the bezier curve with a polyline, and then measure the error difference between the polyline and the bezier curve. If the difference is greater than a certain tolerance - where the tolerance is determined by the output resolution - the bezier is subdivided and the process repeated for each bezier curve. When the difference between beziers and polylines is below the tolerance, the polylines are drawn. http://en.wikipedia.org/wiki/B%C3%A9zier_curve#Computer_graphics
I suppose you want to draw y=f(x) over a certain interval [a,b]
A classical solution is to take N points uniformly distributed over [a,b], to compute f over these points and draw lines (or polynoms).
It of course doesn't work in your case, since y is nearly vertical in certain area. But why don't you take more points in these areas (and less points where the function is nearly horizontal) ?
You can compute the derivative of your function (or approximate this derivative with (f(x+h)-f(x))/h and h small) and determine the step between two successive points with this derivative
I am still working on my "javascript 3d engine" (link inside stackoverflow).
at First, all my polygons were faces of cubes, so sorting them by average Z was working fine.
but now I've "evolved" and I want to draw my polygons (which may contain more than 4 vertices)
in the right order, namely, those who are close to the camera will be drawn last.
basically,
I know how to rotate them and "perspective"-ize them into 2D,
but don't know how to draw them in the right order.
just to clarify:
//my 3d shape = array of polygons
//polygon = array of vertices
//vertex = point with x,y,z
//rotation is around (0,0,0) and my view point is (0,0,something) I guess.
can anyone help?
p.s: some "catch phrases" I came up with, looking for the solution: z-buffering, ray casting (?!), plane equations, view vector, and so on - guess I need a simple to understand answer so that's why I asked this one. thanks.
p.s2: i don't mind too much about overlapping or intersecting polygons... so maybe the painter's algorthm indeed might be good. but: what is it exactly? how do I decide the distance of a polygon?? a polygon has many points.
The approach of sorting polygons and then drawing them bottom-to-top is called the "Painter's algorithm". Unfortunately the sorting step is in general an unsolvable problem, because it's possible for 3 polygons to overlap each other:
Thus there is not necessarily any polygon that is "on top". Alternate approaches such as using a Z buffer or BSP tree (which involves splitting polygons) don't suffer from this problem.
how do I decide the distance of a polygon?? a polygon has many points.
Painter's algorithm is the simplest to implement, but it works only in very simple cases because it assumes that there is only a single "distance" or z-value for each polygon (which you could approximate to be the average of z-values of all points in the polygon). Of course, this will produce wrong results if two polygons intersect each other.
In reality, there isn't a single distance value for a polygon -- each point on the surface of a polygon can be at a different distance from the viewer, so each point has its own "distance" or depth.
You already mentioned Z-buffering, and that is one way of doing this. I don't think you can implement this efficiently on a HTML canvas, but here's the general idea:
You need to maintain an additional canvas, the "z-buffer", where each pixel's colour represents the z-depth of the corresponding pixel on the main canvas.
To draw a polygon, you go through each point on its surface and draw only those points which are closer to the viewer than any previous objects, as indicated by the z-buffer.
I think you will have some ideas by investigating BSP tree ( binary spaces partition tree ), even if the algo will require to split some of your polygon in two.
Some example could be find here http://www.devmaster.net/articles/bsp-trees/ or by google for BSP tree. Posting some code as a reply is, in my opinion, not serious since is a complex topic.