How do I change the value of a SELECT tag in MATERIALIZE CSS. I'm trying show the selected item that was stored from the database. I tried adding .material_select() at the end of the select but it only retrieves the LAST one in the row. How do I show every try ? Here's what I've tried so far.
$(function() {
<?php
$q = $db->query("SELECT buildingID, buildingName,building_projectID, floorNumber FROM tblBuilding");
while($r = $q->fetch(PDO::FETCH_ASSOC)){
$buildingID = $r['buildingID'];
$buildingName = $r['buildingName'];
$building_projectID = $r['building_projectID'];
$floorNumber = $r['floorNumber'];
$t = $db->query("select projectName from tblProject where projectID = $building_projectID ");
while($u = $t->fetch(PDO::FETCH_ASSOC)){
$projectName = $u['projectName'];
?>
$("#editModal<?php echo $buildingID ?>").click(function(){
alert('<?php echo $projectName ?>');
$("#editBuildingName").val("<?php echo $r['buildingName'] ?>");
$("#editBuildingProject").val("<?php echo $projectName");
$("#editBuildingFloors").val("<?php echo $floorNumber ?>");
});
<?php }}?>
});
instead of:
$("#editBuildingProject").val("<?php echo $projectName");
use this:
$("#editBuildingProject").val("<?php echo $building_projectID ?>").material_select('update');
Related
I have a form with one Select option and 3 input text box. I fetch the value of select option from database. I want to change data of the 3 input field based on what i select. I try many ways but faild.
<Select onchange="update(this)">
<?php
$query = "SELECT * FROM wheel1 ORDER BY chair_no ASC";
$run = mysqli_query($connect, $query);
$i = 0;
while ($chair = mysqli_fetch_assoc($start)) {
$i++;
?>
<option value="<?php echo $chair['chair_no'];?>"><?php echo $i ?></option>
<?php
$name = $chair['name'];
$phone = $chair['phone'];
$detail = $chair['detail'];
}
?>
It fetch data perfectly for Select menu, But only store the last value for name phone and detail variable. Here is javascript code.
function update( elem ) {
var name = "<?php echo $name; ?>";
var phone= "<?php echo $phone; ?>";
var detail = "<?php echo $detail; ?>";
document.getElementById("name").innerHTML = name;
document.getElementById("phone").innerHTML = phone;
document.getElementById("detail").innerHTML = detail;
}
Any help is appricated. Thanks in advance.
Set diffirent attribute in options for name, phone and detail
Demo: https://jsfiddle.net/sjhhv4pw/
<select onchange="update(this)">
<?php
$query = "SELECT * FROM wheel1 ORDER BY chair_no ASC";
$run = mysqli_query($connect, $query);
$i = 0;
while ($chair = mysqli_fetch_assoc($start)) {
$i++;
?>
<option data-name="<?php echo $chair['name']; ?>" data-phone="<?php echo $chair['phone']; ?>" data-detail="<?php echo $chair['detail']; ?>" value="<?php echo $chair['chair_no'];?>"><?php echo $i ?></option>
<?php
}
?>
</select>
jQuery:
function update( elem ) {
var name = $(elem).find("option:selected").attr("data-name");
var phone= $(elem).find("option:selected").attr("data-phone");
var detail = $(elem).find("option:selected").attr("data-detail");
}
Try below code
<Select onchange="update(this)">
" data-phone="" data-chair-detail="" value="">
javascript code, considering you are using jQuery
function update( elem ) {
var name = ele.data('chair-name');
var phone= ele.data('phone');
var detail = ele.data('chair-detail');
}
How to show a specific row?
In HTML + PHP I would do something like this:
See the ID #5
And the show.php
<?php
$query = mysql_query("SELECT name FROM table WHERE id=$_GET[id]");
$row = mysql_fethc_assoc($query);
echo $row['name'];
?>
But how can I do this with only HTML + Sqlite?
I would have to solve the problem in this way.
<?php
$query = mysql_query("SELECT name FROM table WHERE id=$_GET[id]");
$row = mysql_fethc_assoc($query);
if($row['name']=="the name you want to find")
{
echo $row['name'];
}
?>
I am currently having trouble with this. I would like to make one of my variables in Javascript have a PHP value. Here is what I mean:
<script>
JSvariable = <?php echo $PHPvariable; ?>;
</script>
For some reason that is not working. Here is my full (snippet) of code:
<script>
currentreplyid = <?php echo $allpostcomments[$key]['replyid']; ?>;
$('#parentcommentholder').val(currentreplyid);
</script>
I am sure it is some stupid mistake, but I can not seem to find it! What is the problem? Thank you!
PS #parentcommentholder is an input field, and it just had the value 0 after the field is supposed to of been changed.
Here is some source:
<?php
$postcommentsquery = "SELECT * FROM comments WHERE parent = :parent AND postid = :postid ORDER BY datecreated DESC";
$postcommentsparams = array(':parent' => $allreplies[$key]["postid"],
':postid' => $postid);
try{
$postcommentsstmt = $connection->prepare($postcommentsquery);
$postcommentsresult = $postcommentsstmt->execute($postcommentsparams);
}
catch(PDOException $ex){
echo ("Failed to run query: " . $ex->getMessage());
}
$allpostcomments = $postcommentsstmt->fetchAll();
foreach ($allpostcomments as $key => $value) {
?>
<script>
var currentreplyid = <?php echo $allpostcomments[$key]['replyid']; ?>;
$('#parentcommentholder').val(currentreplyid);
</script>
<input id="parentcommentholder"></div>
Don't forgot for give quotes ' or ". Use following:
<script>
var JSvariable = '<?php echo $PHPvariable; ?>';
//or
var JSvariable = "<?php echo $PHPvariable; ?>";
</script>
Reason: If php variable contains string and if while assigning it to javascript variable we shall not give quote like:
<?php $PHPvariable = 'String';?>
var JSvariable = <?php echo $PHPvariable; ?>;
Will transform into :
var JSvariable = String;//which will give error in javascript
But this will work fine if PHP variable contains a numeric value like:
<?php $PHPvariable = 2;?>
var JSvariable = <?php echo $PHPvariable; ?>;
Will transform into :
var JSvariable = 2;//which will work perfect
Complete code should be:
<script>
var currentreplyid = "<?php echo $allpostcomments[$key]['replyid']; ?>";
//or if you are sure your variable contains int value
var currentreplyid = parseInt("<?php echo $allpostcomments[$key]['replyid']; ?>");
$('#parentcommentholder').val(currentreplyid);
</script>
Try the below instead of using javascript (as I don't think you need it):
<?php
$postcommentsquery = "SELECT * FROM comments WHERE parent = :parent AND postid = :postid ORDER BY datecreated DESC";
$postcommentsparams = array(':parent' => $allreplies[$key]["postid"],
':postid' => $postid);
try{
$postcommentsstmt = $connection->prepare($postcommentsquery);
$postcommentsresult = $postcommentsstmt->execute($postcommentsparams);
}
catch(PDOException $ex){
echo ("Failed to run query: " . $ex->getMessage());
}
$allpostcomments = $postcommentsstmt->fetchAll();
foreach ($allpostcomments as $key => $value) {
?>
<input id="parentcommentholder" value="<?php echo ((int)$allpostcomments[$key]['replyid']>0) ? $allpostcomments[$key]['replyid'] : 0; ?>" />
<?php
}
?>
If your defiantly sure $allpostcomments[$key]['replyid'] is bringing back a value, this should work without any issues.
I am attempting to create a variable from a database array when an HTML link is clicked. The goal is to redirect the user to a form populated using one piece of array data. In other words, the database will be queried and form populated according to which link is clicked (whatever the values of $row[1], $row[2], and $row[3] are).
<?php
ini_set('display_errors',1); error_reporting(E_ALL);
$DATE = date('Y-m-d');
require_once 'IRCconfig.php';
$connection = new mysqli($db_hostname, $db_username, $db_password, $db_database);
if ($connection->connect_error) die($connection->connect_error);
$query = "SELECT * FROM CLIENT_CHECKIN1 WHERE DATE>='$DATE'";
$result = $connection->query($query);
if (!$result) die ("Database access failed: " . $connection->error);
$rows = $result->num_rows;
for ($j = 0 ; $j < $rows ; ++$j)
{
$result->data_seek($j);
$row = $result->fetch_array(MYSQLI_NUM);
echo <<<_END
<pre>
$row[1] $row[2] $row[3]
</pre>
_END;
}
?>
If anyone can provide me with some incite as to how I could accomplish this I'd appreciate it greatly.
Please read more about sessions here
Then, to answer your question:
First you need to start the session, as simple as session_start(); on the top of your script.
Second you need to instantiate session variables with the DB values like this: $_SESSION['var'] = $value;.
Third, in the html file or whatever, where the form relies, just check for it:
if(isset($_SESSION['var'])) {
echo '<input type="text" value="'.$_SESSION['var'].'" />';
} else {
echo '<input type="text" value="" />';
}
and use the value if it is set.
L.E:
So... first thing's first... session_start(); without it, there is no point of having session.
Second, you create it like $_SESSION['some_name'] = $row[1] so that var will keep the value from $row[1]. I am presuming that it's the value you need. Do NOT do do it like $_SESSION['$row1'] because first of all this is incorrect, you will NOT have the value of row1 there. You need an unique name so that you can call it where you have the form.
The above code will become something like this:
<?php
session_start();
ini_set('display_errors',1); error_reporting(E_ALL);
$DATE = date('Y-m-d');
require_once 'IRCconfig.php';
$connection = new mysqli($db_hostname, $db_username, $db_password, $db_database);
if ($connection->connect_error) die($connection->connect_error);
$query = "SELECT * FROM CLIENT_CHECKIN1 WHERE DATE>='$DATE'";
$result = $connection->query($query);
if (!$result) die ("Database access failed: " . $connection->error);
$rows = $result->num_rows;
for ($j = 0 ; $j < $rows ; ++$j)
{
$result->data_seek($j);
$row = $result->fetch_array(MYSQLI_NUM);
$_SESSION['first_row'] = $row[1];
$_SESSION['second_row'] = $row[2];
$_SESSION['third_row'] = $row[3];
echo <<<_END
<pre>
$row[1] $row[2] $row[3]
</pre>
_END;
}
?>
and, where you have the form and the <input type = "text" value = "" /> so where you need the value, just do it like this:
<input type = "text" value = "<?php echo (isset($_SESSION['first_row']) ? $_SESSION['first_row'] : ''); ?>" />
<input type = "text" value = "<?php echo (isset($_SESSION['second_row']) ? $_SESSION['second_row'] : ''); ?>" />
<input type = "text" value = "<?php echo (isset($_SESSION['third_row']) ? $_SESSION['third_row'] : ''); ?>" />
Hope this helps! :D
How can I collect the data on the row from the table that I select and use it in the result?
Here is the javascript I am using to show the data entry screen, once the function has been called by selecting the row. Now I just need to design a form in PHP that will include (1) some of the data from the row selected and (2) some new data that will be collected.
Here is the Javascript to select the row and call the data entry form
$(document).ready(function () {
$("tr").live('click',function(){
$.post('data_entry_form.php', function(data) {
$('#section2').html(data);
});
});
});
Here is the PHP Script
<?php
require_once "config.php";
$dbh = new PDO($dsn, $dbuser, $dbpass);
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$dbh->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$result = $dbh->query("SELECT aif_id, fee_source_id, company_name_per_sedar, document_filing_date FROM a_aif ORDER BY aif_id DESC");
$result->setFetchMode(PDO::FETCH_ASSOC);
echo "<table id=\"all_aifs\">";
echo "<tr>";
echo "<th><b>Document ID</b></th>";
echo "<th><b>Pubco Name</b></th>";
echo "<th><b>Filing Date</b></th>";
echo "<th><b>PDF</b></th>";
echo "</tr>";
foreach($result as $index => $row) {
echo "<tr>";
echo "<td>$row[fee_source_id]</td>";
echo "<td>$row[company_name_per_sedar]</td>";
echo "<td>$row[document_filing_date]</td>";
echo "<td>Placeholder</td>";
echo "</tr>";
}
echo "</table>";
echo "<br>";
$dbh = NULL;
?>
The "Correct" answer to this problem is NOT to read from the DOM. Never a good idea. I suggest you pass the record id to the ajax call and have the ajax call return an already-populated form.
//PHP
//place the data attribute in the tr
echo "<tr data-recordId='".$row['id']."'>";
//JS
$(document).ready(function () {
$("tr").live('click',function(){
//Get the ID from the row clicked
var id = $(this).data('recordId');
//short-hand
$('#section2').load('data_entry_form.php?id='+id);
});
});
Then your ajax page would just read $_REQUEST['id'] to get the id of the form being edited.
//Ajax side PHP
$id = (int)$_REQUEST['id'];
//Fetch data and use it to pre-populate form item
You would pre-populate your inputs like this
<input type="text" value="<?php echo $row['value']; ?>" />
or
echo '<input type="text" value="'.$row['value'].'" />';
NOTE: If your values contain quotes, you will want to replace them with the code "
echo '<input type="text" value="'.str_replace('"', '"', $row['value']).'" />';
Within the event handler, this and $(this) refer to your selected row:
$("tr").live('click',function(){
// this.cells[1] is the cell that contains Pubco Name
// You can also use $(this).children("td")[1]
...
});