I have 2 orders in JSON.
[
{
"Type": "Example",
"booking_date": "2016-03-31T00:00:00.000Z",
"arriving_time": "2016-03-31T00:00:00.000Z",
"vendor": "b3d1d9c076a937929376e21b",
"buffer_time": "2016-03-31T00:00:00.000Z",
"order": [],
"items": []
}
]
[
{
"booking_date": "2016-03-31T00:00:00.000Z",
"order1": [
{
"max_item": "4",
"cost_per_package": "500",
"cost_per_item": "100",
"arrive_before_time": "2016-03-31T00:00:00.000Z"
}
]
}
]
I have to add order #1 details into order #2. How do I add it? it should add details as per booking date.
Order1
{
"order1": [
{
"Type": "Example",
"booking_date": "2016-03-31T00:00:00.000Z",
"arriving_time": "2016-03-31T00:00:00.000Z",
"vendor": "b3d1d9c076a937929376e21b",
"buffer_time": "2016-03-31T00:00:00.000Z",
"order": [],
"items": []
}
]
}
Order2
{
"order2": [
{
"booking_date": "2016-03-31T00:00:00.000Z",
"order1": [
{
"max_item": "4",
"cost_per_package": "500",
"cost_per_item": "100",
"arrive_before_time": "2016-03-31T00:00:00.000Z"
}
]
}
]
}
To copy contents of array order1 to order do something like this -
order1[0].order = angular.copy(order2[0].order1);
Related
I have a data array, there are multiple objects in this array, and the data object is an array. There may be more than one object in this array. How can I copy these objects under a single array?
const test = []
const data = [
{
"_id": "124141",
"name": "test",
"data": [
{
"price":10,
"title": "sda"
},
]
},
{
"_id": "2525",
"name": "test2",
"data": [
{
"price":20,
"title": "asdas"
},
]
}
]
[{
"price":10,
"title": "sda"
},
{
"price":20,
"title": "asdas"
},
]
If this is the output I expect, it should be like this. how can I do that
const data = [
{
"_id": "124141",
"name": "test",
"data": [
{
"price":10,
"title": "sda"
},
{
"price":99,
"title":"aaaaa"
}
]
},
{
"_id": "2525",
"name": "test2",
"data": [
{
"price":20,
"title": "asdas"
},
]
}
];
console.log(data.map(e => e.data).flat());
// OR
console.log(data.flatMap(e => e.data));
I have an array like this
{
"activities": [
{
"activityId": "60f672b20f38640008a6c29b",
"_id": "610cb887b149cb00095e1eb6",
"trackingProgress": [
{
"_id": "610cb8ee541fea0009189c36",
"dateRecorded": "2021-07-16T00:00:00.000Z",
"items": [
{
"_id": "610cb8ee541fea0009189c37",
"feelingType": "Satisfied",
"times": 2
}
]
},
{
"_id": "611358300fea490008d56ea7",
"dateRecorded": "2021-08-10T00:00:00.000Z",
"items": [
{
"_id": "6113583b0fea490008d56eae",
"feelingType": "Neutral",
"times": 1
}
]
},
{
"_id": "611b6068fed9100009a4f689",
"dateRecorded": "2021-08-17T00:00:00.000Z",
"items": [
{
"_id": "611b6068fed9100009a4f68a",
"feelingType": "Satisfied",
"times": 4
}
]
}
],
"title": "Losing & Managing Weight",
"description": "Losing weight",
"order": null,
"daysOfWeek": [
"tuesday"
],
"reminderTimeAt": "09:00 am",
"type": "Custom",
"progressOverview": {
"notSatisfied": 0,
"neutral": 1,
"satisfied": 6
}
}
]
}
I use JSONPATH to get _id in items
$.activities.[*].trackingProgress.[*].items[*].[_id]
it return an array like this
[
"610cb8ee541fea0009189c37",
"6113583b0fea490008d56eae",
"611b6068fed9100009a4f68a"
]
But, i want to keep the "_id", something like :
[
"_id":"610cb8ee541fea0009189c37",
"_id":"6113583b0fea490008d56eae",
"_id":"611b6068fed9100009a4f68a"
]
How can i do that?? Thank you a lots, i search internet but i found nothing
If you use map, you can get an array of items that each have an _id and value.
let result = [
"610cb8ee541fea0009189c37",
"6113583b0fea490008d56eae",
"611b6068fed9100009a4f68a"
].map(i => ({"_id": i}))
Results in:
[{ _id: "610cb8ee541fea0009189c37" },
{ _id: "6113583b0fea490008d56eae" },
{ _id: "611b6068fed9100009a4f68a" }]
I want to group By sub-work in array
Here is my array I want to group By sub-work
result = [
{
"date": "10-07-2019",
"data": [
{
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [
{
"id": 7,
"title": 'subdata-1',
}
]
}
]
},
{
"date": "12-07-2019",
"data": [
{
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [
{
"id": 7,
"title": 'subdata-1',
}
]
}
]
},
]
Here is what I try
result = _(result)
.map(function(items, data) {
_.groupBy(items.data, function({ sub_work }) {
return sub_work;
});
})
.value();
first I map result into data then I try to groupby but It's return null
Update
I want my output look like this
[
{
"date": "10-07-2019",
sub-work: [{
sub-work : "sub_work1",
sub-data[
{
"id": 7,
"title": 'subdata-1',
}
]
}]
}
]
...........................
It would be better if you could provide your expected result.
Here's what I could infer:
_(result)
.map(function(obj) { // Convert into a 2D array.
return obj.data.map(e => Object.assign(e, {date: obj.date}));
})
.flatten() // We have an array of objects now.
.groupBy('sub-work') // We can call groupBy().
.value();
Here's what you get:
{
"sub_work1": [{
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [{
"id": 7,
"title": "subdata-1"
}],
"date": "10-07-2019"
}, {
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [{
"id": 7,
"title": "subdata-1"
}],
"date": "12-07-2019"
}]
}
I want get the id from table records that have the array match with other record from the same table's array example:
it is record of user '1'
✔ r.db('fotogena').table('users').filter({user:'1'}).pluck('pleasures')
{
"pleasures": [
{
"category": "432f1ae0-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1ae1-a7b1-11e7-86dc-d709d79803e4"
]
},
{
"category": "432f1aef-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1af5-a7b1-11e7-86dc-d709d79803e4"
]
},
{
"category": "432f1afa-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1afb-a7b1-11e7-86dc-d709d79803e4",
"432f1afc-a7b1-11e7-86dc-d709d79803e4",
"432f1afd-a7b1-11e7-86dc-d709d79803e4"
]
},
{
"category": "432f1b02-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1b03-a7b1-11e7-86dc-d709d79803e4",
"432f1b04-a7b1-11e7-86dc-d709d79803e4",
"432f1b07-a7b1-11e7-86dc-d709d79803e4"
]
}
]
}
and i want compare each one that items(without the user '1') inside that pleasure.subCategory with others records inside the same table with the same estructure.
Table with 3 records
[
{
"date": "2017-10-03T03:58:02.651Z",
"id": "d82279a7-fbc6-40a2-99ca-39796ea57efa",
"pleasures": [
{
"category": "432f1ae0-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1ae1-a7b1-11e7-86dc-d709d79803e4"
]
},
{
"category": "432f1aef-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1af5-a7b1-11e7-86dc-d709d79803e4"
]
},
{
"category": "432f1afa-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1afb-a7b1-11e7-86dc-d709d79803e4",
]
},
{
"category": "432f1b02-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1b03-a7b1-11e7-86dc-d709d79803e4",
]
}
],
"user": "1"
},
{
"date": "2017-10-07T02:59:45.942Z",
"id": "174c0e35-da79-4ca8-b237-8ec569cc27b1",
"pleasures": [
{
"category": "432f1ae0-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1ae1-a7b1-11e7-86dc-d709d79803e4",
]
},
{
"category": "432f1aef-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1af3-a7b1-11e7-86dc-d709d79803e4",
"432f1af4-a7b1-11e7-86dc-d709d79803e4"
]
},
{
"category": "432f1afa-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1aff-a7b1-11e7-86dc-d709d79803e4",
]
},
{
"category": "432f1b02-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1b04-a7b1-11e7-86dc-d709d79803e4",
]
}
],
"user": "10"
},
{
"date": "2017-10-07T02:07:13.715Z",
"id": "dd11edac-e0f5-43ac-811a-eaa78a6509c7",
"pleasures": [
{
"category": "432f1ae0-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1ae1-a7b1-11e7-86dc-d709d79803e5"
]
},
{
"category": "432f1aef-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1af3-a7b1-11e7-86dc-d709d79803e5"
]
},
{
"category": "432f1afa-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1af3-a7b1-11e7-86dc-d709d79803e6"
]
},
{
"category": "432f1b02-a7b1-11e7-86dc-d709d79803e4",
"subCategory": [
"432f1af3-a7b1-11e7-86dc-d709d79803e7"
]
}
],
"user": "25"
}
]
i think that maybe can be it:
r.db('fotogena').table('users').filter({user:'1'}).pluck('pleasures').map(pleasures=>{
return //do something
})
i could solve it, later of search and search, i could created a script that show that i want get
I had that do in unique query(no joins) compare arrays with arrays using .contains() and worked very good
r.db('fotogena').table('users').filter(users=>{
return users('pleasures').contains(category=>{
return category('subCategory').contains(subCategory=>{
return r.db('fotogena').table('users').filter({user: '1'}).pluck('pleasures').contains(pleasures2=>{
return pleasures2('pleasures').contains(subCate2=>{
return subCate2('subCategory')
.contains(subCategory2=>{
return subCategory2.eq(subCategory)
})
})
})
})
}).and(users('user').ne('1'))
})
I have been trying to implement the sap.m.tree for multilevel hierarchy data, and the attribute names are different.
I have been through the FIORI guidelines https://experience.sap.com/fiori-design-web/tree/ for the same and I understand that is the exact control I need. from the SAPUI5 explored https://sapui5.hana.ondemand.com/explored.html#/entity/sap.m.Tree/samples
I couldn't get much of help as they have the example over the same data and there are no aggregations.
Can anyone help me with a lead, an example would be highly appreciated.
Json
{
"d": {
"__count": "4",
"results": [
{
"ID": "1234",
"FID": "00145E9279201EE799E3027FBE864F24",
"FName" : "Header"
"Sequence": 0,
"Values": {
"results": [
{
"ID": "321",
"Value": "FChild",
},
{
"ID": "321",
"Value": "FChild",
}
]}
}]
}
}
The answer is late but maybe it helps someone else.
The structure of the json for the tree should be like this:
[
{
"text": "Node1",
"ref": "sap-icon://attachment-audio",
"nodes":
[
{
"text": "Node1-1",
"ref": "sap-icon://attachment-e-pub",
"nodes":[
{
"text": "Node1-1-1",
"ref": "sap-icon://attachment-html"
},
{
"text": "Node1-1-2",
"ref": "sap-icon://attachment-photo",
"nodes":[
{
"text": "Node1-1-2-1",
"ref": "sap-icon://attachment-text-file",
"nodes":[
{
"text": "Node1-1-2-1-1",
"ref": "sap-icon://attachment-video"
},
{
"text": "Node1-1-2-1-2",
"ref": "sap-icon://attachment-zip-file"
},
{
"text": "Node1-1-2-1-3",
"ref": "sap-icon://course-program"
}
]
}
]
}
]
},
{
"text": "Node1-2",
"ref": "sap-icon://create"
}
]
},
{
"text": "Node2",
"ref": "sap-icon://customer-financial-fact-sheet"
}
]
Then you use it in the "items" aggregation of the Tree. Just format the JSON that way and it will work. The important part is the:
[
{
"anyTextFieldYouWant": "Node1",
"nodes":
[
{
"anyTextFieldYouWant": "Node1-1"
},
{
"anyTextFieldYouWant": "Node1-2"
}
]
}
]