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I need help to convert this code to codeigniter MVC i have 3 file php Openlink3.php for viewer class.php for class and databaseConnection.php for model
i have problem converting this php file to codeigniter. Please help me.
this my PHP code Openlink.php
<?php
include("DatabaseConnection.php");
include("class.php");
Global $AppCode;
//$AppCode='0001';
$user='0772';
$db = new dbconnection();
$conn = $db->dbOpen();
$misApp = new misApplication();
$sql="SELECT a.RAL_Code,a.RAL_App_Name,a.RAL_Remarks,b.RAL_APPIconLocation,b.RAL_ApplicationLink FROM R_Application_List as a ,R_Application_Links as b where a.RSC_Active=1 and a.RAL_Code=b.RAL_APPCODE";
$rs=odbc_exec($conn,$sql);
$appcount;
echo "<table align=center cellpadding=10>";
echo "<tr height=120>";
$appcount=0;
while (odbc_fetch_row($rs))
{
$appcode=odbc_result($rs,"RAL_Code");
$appname=odbc_result($rs,"RAL_App_Name");
$desc=odbc_result($rs,"RAL_Remarks");
$icon=odbc_result($rs,"RAL_APPIconLocation");
$applink=trim(odbc_result($rs,"RAL_ApplicationLink"));
if($appcount==3){
echo "<tr height=120>";
//echo "<td>";
$appcount=0;
}
//echo "<td>".$appcode."</td>";
//echo "<td>".$appname."</td>";
echo "<td valign=bottom><img src=".$icon."height=30 width=150 onclick='openApp(\"$appcode\",\"$user\",\"$applink\");' </img></td>";
//echo "<td><input type=\"button\" ></td>"
//echo "<td>".$desc."</td>";
echo '<script>openApp();</script>';
$appcount++;
//echo $icon."<br/>";
}
echo "</table>";
?>
<img src="dtr.png" height="30" width="150" onclick=openApp("0001","<?php echo $user; ?>","<?php echo $appLink = $misApp->getAppLink($conn,"0001",$user); ?>") ></img></br>
<input type="button" id="btn.DTR"; name="btn.Dtr"; value="DTR"; onclick='openApp("0001","<?php echo $user; ?>","<?php echo $appLink = $misApp->getAppLink($conn,"0001",$user); ?>")'/>
<input type="button" id="jose"; name="btn.OpenApp"; value="Approval System(test)"; background="dtr.png";onclick='openApp("0014","<?php echo $user; ?>","<?php echo $appLink = $misApp->getAppLink($conn,"0002",$user); ?>")'/>
<script language="javascript">
function openApp(Appcode, User, link){
var OpenLink;
OpenLink = link+"?A1="+User+"&A2="+Appcode; // Concatenating strings
//alert(OpenLink);
//document.write (OpenLink); // printing the Concatenated string
//window.open(OpenLink);
//window.open(OpenLink,'_blank', 'toolbar=no,status=no,menubar=no,scrollbars=no,resizable=no,left=10000, top=10000, width=10, height=10, visible=none', '');
window.location.href = OpenLink;
}
</script>
</html>
this my PHP code class.php
<?php
class misApplication{
public function getAppLink($actveConn,$appCode,$user){
$linktoOpen;
$sql="select * from R_Application_Links where RAL_APPCode='$appCode'";
$rs=odbc_exec($actveConn,$sql);
while (odbc_fetch_row($rs))
{
$a=odbc_result($rs,"RAL_APPCode");
$b=odbc_result($rs,"RAL_InstallationLink");
$link=odbc_result($rs,"RAL_ApplicationLink");
$d=odbc_result($rs,"RAL_APPIconLocation");
}
$linktoOpen = $link.$user.$appCode;
return trim($link);
odbc_close($actveConn);
}
}
?>
DatabaseConnection.php
<?php
class dbconnection{
public function dbOpen(){
$conn=odbc_connect("Global02","USER-00","USER00");
if (!$conn){
exit("Connection Failed: " . $conn);
}
else{
return $conn;
}
}
}
?>
when i convert it it always have an error.
Simple steps you have to follow, you can need to check user guide first, anyway try this
You have to follow these steps:
Step 1: For database connection
In database.php
set your database configuration inside $db['default']
Load your database using autoload.php
$autoload['libraries'] = array('database');
Step 2:
Create model Example Mdl_mis.php
Example:
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
class Mdl_mis extends CI_Model {
function getAllApplink(){
$this->db->select("SELECT a.RAL_Code,a.RAL_App_Name,a.RAL_Remarks,b.RAL_APPIconLocation,b.RAL_ApplicationLink");
$this->db->from("R_Application_List as a");
$this->db->join("R_Application_Links as b","a.RAL_Code=b.RAL_APPCODE",'INNER');
$this->db->where("a.RSC_Active",1);
$result = $this->db->get()->result_array();
return $result;
}
function getAppLink($appCode,$user){
$this->db->select("*");
$this->db->from("R_Application_Links");
$this->db->where("RAL_APPCode",$appCode);
$result = $this->db->get()->row_array();
$a = $result['RAL_APPCode'];
$b = $result['RAL_InstallationLink'];
$link = $result['RAL_ApplicationLink'];
$d = $result['RAL_APPIconLocation'];
$linktoOpen = $link.$user.$appCode;
return trim($link);
}
}
?>
Step 3:
Create Controller example MisApplication.php
Create one method also
Example:
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
class MisApplication extends CI_Controller {
public function index()
{
/* Load you model first */
$this->load->model('Mdl_mis');
$data['all_link'] = $this->Mdl_mis->getAllApplink();
/* Create one view called index.php and load it and pass your data*/
$this->load->view('index',$data);
}
}
?>
Step 4: Put code in index.php view
<!DOCTYPE html>
<html>
<body>
<table align=center cellpadding=10>";
<tr height=120>";
<?php
$appcount=0;
foreach($all_link as $rs))
{
$appcode = $rs["RAL_Code"];
$appname = $rs["RAL_App_Name"];
$desc = $rs["RAL_Remarks"];
$icon = $rs["RAL_APPIconLocation"];
$applink = trim($rs["RAL_ApplicationLink"]);
if($appcount==3){
echo "<tr height=120>";
//echo "<td>";
$appcount=0;
}
//echo "<td>".$appcode."</td>";
//echo "<td>".$appname."</td>";
echo "<td valign=bottom><img src=".$icon."height=30 width=150 onclick='openApp(\"$appcode\",\"$user\",\"$applink\");' </img></td>";
//echo "<td><input type=\"button\" ></td>"
//echo "<td>".$desc."</td>";
echo '<script>openApp();</script>';
$appcount++;
}
echo "</table>";
?>
<img src="dtr.png" height="30" width="150" onclick=openApp("0001","<?php echo $user; ?>","<?php echo $appLink = $this->Mdl_mis->getAppLink("0001",$user); ?>") ></img></br>
<input type="button" id="btn.DTR"; name="btn.Dtr"; value="DTR"; onclick='openApp("0001","<?php echo $user; ?>","<?php echo $appLink = $this->Mdl_mis->getAppLink("0001",$user); ?>")'/>
<input type="button" id="jose"; name="btn.OpenApp"; value="Approval System(test)"; background="dtr.png";onclick='openApp("0014","<?php echo $user; ?>","<?php echo $appLink = $this->Mdl_mis->getAppLink("0002",$user); ?>")'/>
<script language="javascript">
function openApp(Appcode, User, link){
var OpenLink;
OpenLink = link+"?A1="+User+"&A2="+Appcode; // Concatenating strings
//alert(OpenLink);
//document.write (OpenLink); // printing the Concatenated string
//window.open(OpenLink);
//window.open(OpenLink,'_blank', 'toolbar=no,status=no,menubar=no,scrollbars=no,resizable=no,left=10000, top=10000, width=10, height=10, visible=none', '');
window.location.href = OpenLink;
}
</script>
</html>
Related
Am trying to pass a variable from an external php script to scripts tag in the main page but the main_page.php is returning an undefined variable which is the array that i intend to pass from PHP to js. Its a university units registration system, any help will be greatly appreciated.
my javascript is
<script>
var m=<?php echo json_encode($ar) ?>;
alert(m[0]);
</script>
And my PHP file with the array variable ($ar) is this
<?php
$course=$semester="";
$course_err=$semester_err="";
$link = mysqli_connect("localhost","root","","courses");
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
if($_SERVER["REQUEST_METHOD"] == "POST"){
if(empty(trim($_POST["name"]))){
$course_err= "course is not set";
} else {
$course=($_POST["name"]);
}
if(empty(trim($_POST["email"]))){
$semester_err= "semester is not set";
} else {
$semester=($_POST["email"]);
}
}
if(empty($course_err || $semester_err)){
$sql="SELECT `$semester` FROM `$course`";
$retval=mysqli_query($link,$sql);
if(mysqli_num_rows($retval)>0){
while ($row= mysqli_fetch_assoc($retval)){
echo "<form method='post' name='units'>";
echo "<li class='list-group-item' style='background:#663300;color:#fff'>
<input type='checkbox' id='firstnit'><p style='color:#fff;font-
size:1.2em;'>{$row[$semester]}</p></li><br>";
echo "</form>";
$ar=array($row);
$_SESSION["tempArray"]=$ar;
echo json_encode($ar);
}
}else{
echo "<li class='list-group-item' style='color:#111;'>0 units
registered</li>";
}
echo "<script>alert('The units have been added to the iframe with success');
</script>";
echo "<br/>";
echo "<button onclick='Array()' class='btn'>Submit Units</button>";
}
?>
I have a column in my db, tip_sting:
1 row example(each one has the same format):
G1-11, G2-21, P2-50, P4-20, P100-2,
I'm using this when editing a item(I want to create(as many selects in the string) and put the values automaticaly in the select) :
https://jsfiddle.net/avrzwt6k/
So I was thinking of doing something like:
$pieces = explode(",", $tip_stingu);
$a=count($pieces); // piece1
echo $a;
echo '<br>';
echo $pieces[1]; // piece2
echo '<br>';
$tip_stinga=explode("-",$pieces);
I just dont know how could I continue?
Do you need something like this?
<?php
$items = "G1-11, G2-21, P2-50, P4-20, P100-2";
$pieces = explode(",", $items);
echo ("<select>");
foreach ($pieces as $piece) {
$tip_stinga = explode("-", $piece);
echo ('<option value="'.$tip_stinga[1].'">'.$tip_stinga[0].'</option>');
}
echo ("</select>");
?>
Using PHP & Javascript you can do:
<html>
<body>
<form id="example" name="example">
<select name="myName" id="myID" onchange="updateText()">
<?php
$tip_stingu = "G1-11, G2-21, P2-50, P4-20, P100-2,";
$pieces = explode(', ', $tip_sting);
$piece1 = explode('-', $pieces[0])[1];
foreach($pieces as $piece) {
$tip_stinga = explode("-", $piece);
echo ('<option value="'.$tip_stinga[1].'">'.$tip_stinga[0].'</option>');
}
echo '</select><input type="text" value="'.$piece1.'" id="quantity" /><br />'
?>
</form>
<script>
function updateText() {
document.getElementById("quantity").value = document.getElementById("myID").value;
}
</script>
</body>
</html>
You also have a trailing comma at the end of your example, if that's a problem you can use:
echo ('<option value="'.rtrim($tip_stinga[1], ',').'">'.$tip_stinga[0].'</option>');
instead of:
echo ('<option value="'.$tip_stinga[1].'">'.$tip_stinga[0].'</option>');
I need to pass a javascript array, via POST, to a PHP file.
I've tried to semplify my original business trying to explain my troubles ...
This is my first PHP file, in which I declare a javascript array and I set each element to 1 value (not a great business I know, but it doesn't matter, it's only to explain ....)
<?php
echo '<form action="testPhp-2.php" method="POST" target="testPhp-2">';
echo '<script type="text/javascript">';
echo 'var arr_selections = [];';
echo 'for(i=0; i < 10; i++)';
echo ' {';
echo ' arr_selections[i] = 1';
echo ' }';
echo 'arr_selections_json = JSON.stringify(arr_selections);';
echo 'alert (arr_selections[2]);';
echo 'document.write("<br/>");';
echo ' ';
// echo 'document.write("<input type="hidden" />");';
echo 'document.write("<input type=\"hidden\" name=\"arr_selections_json\" value=\"arr_selections_json\" />");';
echo ' ';
echo '</script>';
echo ' <input type="submit" value="Controlla">';
echo ' </form>';
?>
.... and here you are the code of testPhp-2 file ...
<?php
if(isset($_POST['arr_selections_json']))
{
echo "OK, array exist !! ";
echo '</br>';
echo '</br>';
$arr_selections = json_decode($_POST['arr_selections_json'], true);
echo $arr_selections[0];
}
else {
echo "NO; array does not exist !! ";
echo '</br>';
echo '</br>';
}
?>
Now, if you try to execute the code you'll see the OK, array exist !! message but no array value is printed about the echo $arr_selections[0]; line of code in testPhp-2.php file.
Any suggestion will be appreciated! Thank you in advance!
Cesare
Problem is that you're setting the value of the input to the litteral string "arr_selections_json" instead of to the contents of that variable.
Change
echo 'document.write("... value=\"arr_selections_json\" />");';
To
echo 'document.write("... value=\""+arr_selections_json+"\" />");';
I am trying to update records by php code. but having trouble in my code.
code is running without using functions (get40(),show()) but i want to use buttons to call these functions.
code is give below:
this is main code file:
<?php
$data;
$count=0;
$host='localhost';
$uname='root';
$pass="";
$dbname="testing";
$db=new mysqli($host,$uname,$pass,$dbname);
$result;
$query;
if (mysqli_connect_errno()) {
echo 'Error: Could not connect to database. Please try again later.';
exit;
}
function get40($off='0', $rcd='2')
{
global $db,$result,$query;
$query="SELECT sword, tword, reviewed from TempDictionary LIMIT $off,$rcd";
$result = $db->query($query)or trigger_error($db->error);
}
function show()
{
global $db,$result,$query;
echo "<form action='testSave.php' method='POST'>";
echo "<table border=1 >";
while($row = mysqli_fetch_array($result))
{
global $count;
$count+=1;
echo "<tr>";
echo "<td><input type='text' name='s[]' value=" . $row['sword'] . "></td>";
echo "<td><input type='text' name='t[]' value=" . $row['tword'] . "></td>";
echo "<td><input type='text' name='r[]' size='1' value=" .$row['reviewed'] . "></td>";
echo "</tr>";
}
echo "</table>";
echo "<input type='text' name='no' size='2' value=" .$count. ">";
echo "<input type='submit' value='Save'>";
echo "</form>";
}
//get40(1,2);
//show();
mysqli_close($db);
?>
<script type="text/javascript">
function get()
{
<?php
get40(0,3);
show();
?>
}
</script>
<form action="" method="POST">
<input type=button name=btnGet value=Get onclick="get()">
</form>
and savetest.php file is:
<?php
$no=$_POST['no'];
$i=0;
$s=$_POST['s'];
$t=$_POST['t'];
$r=$_POST['r'];
$host='localhost';
$uname='root';
$pass="";
$dbname="testing";
$db=new mysqli($host,$uname,$pass,$dbname);
if (mysqli_connect_errno()) {
echo 'Error: Could not connect to database. Please try again later.';
exit;
}
// display
foreach ($s as $key=>$value)
{
print "$key = $value $t[$key] $r[$key]";
echo '<br>';
}
// save to DB
foreach ($s as $key=>$value)
{
// $query="UPDATE TempDictionary set sword=".$value.",tword=".$t[$key].",reviewed=".$r[$key]."
// WHERE sword=".$value;
$query="UPDATE TempDictionary set sword='$value',tword='$t[$key]',reviewed='$r[$key]'
WHERE sword='$value'";
$result = $db->query($query)or trigger_error($db->error);
}
mysqli_close($db);
?>
the problem is while i click button it does not works.
AFAIK you are trying to run PHP code with Javascript code.
Use Jquery/Ajax to solve your problem. You can Google for that or look at stackoverflow.
Step 1: Learn how a click on a button can run PHP
Run php function inside jQuery click
Step 2: Learn how to use data from a database and populate a form with it:
ajax call to populate form fields from database query when select value changes
That's the first step in solving your problem. (sorry it's no copy/paste solution, just a pointer in the right direction)
please in need help in updating multiple rows based on dynamic data fetched from mysql database. I have implemented this using $_Post to udate.php file, but how can i do this using ajax.
//THIS SCRIPT FETCH FROM DATABASE
<body>
<?php
mysql_connect("localhost","root","");
mysql_select_db("student") or die("Unable to select database");
$sql = "SELECT * FROM students ORDER BY id";
$result = mysql_query($sql) or die($sql."<br/><br/>".mysql_error());
$i = 0;
echo '<table width="50%">';
echo '<tr>';
echo '<td>ID</td>';
echo '<td>Name</td>';
echo '<td>Address</td>';
echo '</tr>';
echo "<form name='form_update' method='post' action='update.php'>\n";
while ($students = mysql_fetch_array($result)) {
echo '<tr>';
echo "<td>{$students['id']}<input type='hidden' name='id[$i]'value='{$students['id']}' /></td>";
echo "<td>{$students['name']}</td>";
echo "<td><input type='text' size='40' name='address[$i]' value='{$students['address']}' /></td>";
echo '</tr>';
++$i;
}
echo '<tr>';
echo "<td><input type='submit' value='submit' /></td>";
echo '</tr>';
echo "</form>";
echo '</table>';
echo $i; ?>
</body>
// HERE IS THE UPDATE SCRIPT
// On clicking submit all rows are updated but i still cant achieve dis with ajax.
UPDATE.PHP
$size = count($_POST['address']);
$i = 0;
while ($i < $size) {
$address= $_POST['address'][$i];
$id = $_POST['id'][$i];
$query = "UPDATE students SET address = '$address' WHERE id = '$id' LIMIT 1";
mysql_query($query) or die ("Error in query: $query");
echo "$address<br /><br /><em>Updated!</em><br /><br />";
++$i;
}
?>
HERE IS WHAT I HAVE TRIED ON AJAX
function update(){
var j=0;
while(j< <?php echo $i ; ?>){
var id=$("#id" + j);
var address=$("#address" + j);
$.ajax(
{
url:"update.php",
type:"post",
data:{id:id.val(),address:address.val()},
success:function(response)
{
}
});
}
ANY HELP WILL BE APPRECIATED
You shouldn't need to loop and execute multiple POSTs. Simply serialize the form data and send it to the script, e.g.:
$.ajax({
url: 'update.php',
type: 'post',
data: $('#your-form-id').serialize(),
success:function(response){
// do something
}
});
Also, you should consider revising your PHP to prevent SQL injection: How can I prevent SQL injection in PHP?