How to update this script to respect JQuery AJAX syntax?

How to update this script to respect JQuery AJAX syntax? - javascript

I have a functioning script that takes an option value, stores it in a variable q and sends an xmlhttp get call to a php script that queries a database a returns an html table with results. What I'm trying to do is update this to jQuery.ajax() with get method format ... any help is appreciated.
example_ajax_html_js.php:
<html>
<head>
<script src="//code.jquery.com/jquery-2.2.1.min.js"></script>
<script>
function showUser(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("txtHint").innerHTML = xmlhttp.responseText;
}
};
xmlhttp.open("GET","/getuser.php?q="+str,true);
xmlhttp.send();
}
}
</script>
</head>
<body>
<form>
<select name="users" onchange="showUser(this.value)">
<option value="">Select a person:</option>
<option value="Sophia">Sophia</option>
<option value="Daniel">Daniel</option>
</select>
</form>
<br>
<div id="txtHint"><b>Person info will be listed here...</b></div>
</body>
</html>
which calls getuser.php:
<!DOCTYPE html>
<html>
<head>
<style>
table {
width: 100%;
border-collapse: collapse;
}
table, td, th {
border: 1px solid black;
padding: 5px;
}
th {text-align: left;}
</style>
</head>
<body>
<?php
$q = $_GET['q'];
// connect to db
$sql="SELECT * FROM table WHERE first = '".$q."'";
$result = mysqli_query($web_dbi, $sql) or die("Error " . mysqli_error($web_dbi));
echo "<table>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>extrainfo1</th>
<th>extrainfo2</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['first'] . "</td>";
echo "<td>" . $row['last'] . "</td>";
echo "<td>" . $row['extrainfo1'] . "</td>";
echo "<td>" . $row['extrainfo2'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($web_dbi);
?>
</body>
</html>

Even easier than using jQuery's ajax method, I'd use the load method. Makes your job a piece of cake:
function showUser(str) {
if (str == "") {
$("#txtHint").html("");
return;
}
$("#txtHint").load("/getuser.php?q="+str);
}
That's it!
http://api.jquery.com/load/

Related

How to filter the talbe using select option in php and mysql

I want to use the select option to update the table. these are the code and when I try it, no data have been display to table..im using js but still nothing happens..it only display the fields but no data in it. help me pls.
<html>
<head>
<script>
function showUser(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("txtHint").innerHTML = this.responseText;
}
};
xmlhttp.open("GET","getuser.php?q="+str,true);
xmlhttp.send();
}
}
</script>
</head>
<body>
<form>
<select name="users" onchange="showUser(this.value)">
<option value="">Select a person:</option>
<option value="1">150-2012-00007</option>
<option value="2">120-2013-001</option>
<option value="3">130-2012-0022</option>
<option value="4">130-2012-0554</option>
</select>
</form>
<br>
<div id="txtHint"><b>Person info will be listed here...</b></div>
</body>
</html>
this is the code for the getuser.php
<html>
<head>
<style>
table {
width: 100%;
border-collapse: collapse;
}
table, td, th {
border: 1px solid black;
padding: 5px;
}
th {text-align: left;}
</style>
</head>
<body>
<?php
$q = intval($_GET['q']);
$db_host = 'localhost'; // Server Name
$db_user = 'root'; // Username
$db_pass = ''; // Password
$db_name = 'ofes'; // Database Name
$conn = mysqli_connect($db_host, $db_user, $db_pass, $db_name);
if (!$conn)
{
die ('Failed to connect to MySQL: ' . mysqli_connect_error());
}else{
echo "";
}
$sql="SELECT * FROM tbl_student WHERE Id_number = '".$q."'";
$result = mysqli_query($conn,$sql);
echo "<table>
<tr>
<th>Name</th>
<th>Id number</th>
<th>Passwordr</th>
<th>Course</th>
<th>School Year</th>
<th>Semester</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['Id_number'] . "</td>";
echo "<td>" . $row['password'] . "</td>";
echo "<td>" . $row['course'] . "</td>";
echo "<td>" . $row['school_year'] . "</td>";
echo "<td>" . $row['semester'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($conn);
?>
</body>
</html>
basically when I choose from the select option the table will be updated automatically.

want to fetch conditional data using ajax

My Working scenario is, i have 4 types of Pen
1-Diamond
2-Gold
3- Bronze
4- Silver
i want when someone select Diamond Pen on the bottom input he will type quantity so if he select 1-Diamond Pen so the amount should be vary with each other, on the same way all 4 types pen rates should be vary.
My Code is
ajax.php
<!DOCTYPE html>
<html>
<head>
<script>
function showUser(str) {
if (str=="") {
document.getElementById("txtHint").innerHTML="";
return;
}
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
} else { // code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function() {
if (this.readyState==4 && this.status==200) {
document.getElementById("txtHint").innerHTML=this.responseText;
}
}
xmlhttp.open("GET","getuser.php?q="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>
<form>
<!-- <input type="text" name="users" onchange="showUser(this.value)"> -->
<select name="users" onchange="showUser(this.value)">
<option value="">Select a person:</option>
<option value="1">Diamond</option>
<option value="2">Gold</option>
<option value="3">Bronze</option>
<option value="4">Silver</option>
</select>
<!-- <input type="submit" name="users"> -->
</form>
<br>
<div id="txtHint"><b>Person info will be listed here.</b></div>
</body>
</html>
getuser.php
<!DOCTYPE html>
<html>
<head>
<style>
table {
width: 100%;
border-collapse: collapse;
}
table, td, th {
border: 1px solid black;
padding: 5px;
}
th {text-align: left;}
</style>
</head>
<body>
<?php
$q = intval($_GET['q']);
$con = mysqli_connect('localhost','root','','fm_all');
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
mysqli_select_db($con,"ajax_demo");
$sql="SELECT * FROM all_company WHERE id = '".$q."'";
$result = mysqli_query($con,$sql);
echo "<table>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Age</th>
<th>Hometown</th>
<th>Job</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['city'] . "</td>";
echo "<td>" . $row['province'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
</body>
</html>
The problem is only Drop Box value is working, i do not know how to attach input quantity box with it. please help.
Note: this code is working according to id when i select drop box value so it show according to id but i did not attach it with quantity.

You can achieve this by following way in case you don't want for perform any operation on form submit
call showUser() on onkeyup for input and provide it some id may be quantity
call showUser() on onchange for select box and also provide it some id can be pen
function showUser(){
quantity = $("#quantity").val();
selected_pen = $("#pen").val();
if (quantity != null && selected_pen != null && typeof(quantity) !='undefined'){
your ajax calling code
}
}
you can call above function onchange for select box and on onkeyup in input textbox. But with above mentioned way it will call ajax every time there is change in your text field or select box.

How can I get multiple values from a radio button and then assign them into single variables and display them on a page?

// A major problem is once a user selects a radiobutton and hits submit the value, it sends an array. I would like to place those individual queries(route_no, to_city, from_city, price) on the nextpage.php page in a table next to their table headers or next to the tags. I cant do this because, confirm value sends all queries as a single string/array. How can I fix this please help me.enter image description here
here is my html page
<html>
<head>
<script>
function showUser(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("txtHint").innerHTML = xmlhttp.responseText;
}
};
xmlhttp.open("GET","display3.php?q="+str,true);
xmlhttp.send();
}
}
</script>
</head>
<body>
<form>
<select name="to_city" onchange="showUser(this.value)">
<option value="">Select a person:</option>
<option value="Sydney">Sydney</option>
<option value="Brisbane">Brisbane</option>
<option value="3">Joseph Swanson</option>
<option value="4">Glenn Quagmire</option>
</select>
</form>
<br>
<div id="txtHint"><b>Person info will be listed here...</b></div>
</body>
</html>
here is my display3.php page
<!DOCTYPE html>
<style>
td{
padding-top: 10px;
padding-right: 10px;
padding-bottom: 10px;
padding-left: 10px;
}
</style>
<body>
<?php
$q = strval($_GET['q']);
$con = mysqli_connect('localhost','root','','mydb');
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
mysqli_select_db($con,"flights");
$sql="SELECT * FROM flights WHERE to_city = '".$q."'";
$result = mysqli_query($con,$sql);
?>
<form action="nextpage.php" method="get">
<?php
echo "<table>
<tr>
<th>Route_no</th>
<th>to_city</th>
<th>from_city</th>
<th>price</th>
<th>Confirm</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
$all_values = $row['route_no'] .",".$row['to_city'].",".$row['from_city'].",".$row['price'];
echo "<tr>";
echo "<td>" . $row['route_no'] . "</td>";
echo "<td>" . $row['to_city'] . "</td>";
echo "<td>" . $row['from_city'] . "</td>";
echo "<td>" . $row['price'] . "</td>";
echo "<td><input type='radio' name='Confirm' value='".$all_values."'></td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
<input type="submit" value="Submit">
</form>
</body>
</html>
here is my nextpage.php
<!DOCTYPE html>
<head>
<style>
td{
padding-top: 10px;
padding-right: 10px;
padding-bottom: 10px;
padding-left: 10px;
}
</style>
<body>
<h1>Booking Details</h1>
<h2>Flight No.</h2>
<h2>to_city</h2>
<h2>from_city</h2>
<h2>Price</h2>
<?php
echo $_GET['Confirm'];
?>
<table >
</body>
</head>
</html>

use explode function to form a array separated by , .
<?php
$str = "4,sydney,canberra,120.00";
print_r (explode(",",$str));
?>
out put
Array
(
[0] => 4
[1] => sydney
[2] => canberra
[3] => 120.00
)

Yes explode can work like so, in nextpage.php
<!DOCTYPE html>
<head>
<style>
td{
padding-top: 10px;
padding-right: 10px;
padding-bottom: 10px;
padding-left: 10px;
}
</style>
<?php
$details = explode(",", $_GET['Confirm']);
?>
</head>
<body>
<h1>Booking Details</h1>
<table>
<tr>
<th>Flight No.</th>
<td><?=$details[0]?></td>
</tr>
<tr>
<th>to_city</th>
<td><?=$details[1]?></td>
</tr>
<tr>
<th>from_city</th>
<td><?=$details[2]?></td>
</tr>
<tr>
<tr>
<th>Price</th>
<td><?=$details[3]?></td>
</tr>
</table>
</body>
</html>

Calculate two input values of fetched data using jquery

The code below displays a table of data in input box based on drop down selection. Then I want to multiply row1 and row2 values and should display in row3. But the calculation between row1 and row2 is not working using jQuery. Need help!
display.php
<!DOCTYPE html>
<html lang="en">
<head>
<link href="//code.jquery.com/ui/1.11.2/themes/smoothness/jquery-ui.min.css" rel="stylesheet" type="text/css" />
<script src="//code.jquery.com/jquery-1.11.0.min.js"></script>
<script src="//code.jquery.com/ui/1.11.2/jquery-ui.min.js"></script>
<script type="text/javascript">
function showUser(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("txtHint").innerHTML = xmlhttp.responseText;
}
}
xmlhttp.open("GET","ajax.php?q="+str,true);
xmlhttp.send();
}
}
$(document).ready(function() {
$('#form').on('keyup', '.test1', calcTotal) ;
$('#form').on('keyup', '.test2', calcTotal) ;
function calcTotal() {
var $row2 = $(this).closest('tr'),
test_row = $row2.find('.test1').val(),
test_row2 = $row2.find('.test2').val(),
total = test_row * test_row2;
$row2.find('.test3').val(total);
}
});
</script>
</head>
<body>
<form name="form_name" method="post" id="form_name" action="" >
<select name="select_name" id="select_name" onchange="showUser(this.value)">
<option value="22">22</option><option value="33">33</option></select>
<div id="txtHint"></div>
</form>
</body>
</html>
ajax.php
<?php
$q = $_GET['q'];
include('connection.php');
$sql="SELECT * from clients where value='".$q."' ";
$result = mysql_query($sql);
echo "<table id='form'>
<tr>
<th>row1</th>
<th>row2</th>
<th>row3</th>
</tr>";
while($row = mysql_fetch_array($result)) {
$row1=$row['row1'];
$row2=$row['row2'];
$row3=$row['row3'];
echo "<tr>";
echo "<td><input type='text' name='test1[]' class='test1' value='$row1' /></td>";
echo "<td><input type='text' name='test2[]' class='test2' value='$row2' /></td>";
echo "<td><input type='text' name='test3[]' class='test3' value='$row3'/></td>";
echo "</tr>";
}
echo "</table>";
?>

Replace these two line
$('#form').on('keyup', '.test1', calcTotal) ;
$('#form').on('keyup', '.test2', calcTotal) ;
With this
$(document).on('keyup', '.test1, .test2', calcTotal) ;
Because #form was added in the DOM after it's construction.

I think
$('#form').on('keyup','.test1',calcTotal) ;
should be replaced with
$('#form').on('keyup', '#test1', calcTotal) ;
as test1 is id of input and not class.

this js script , accept only integer

im having a problem with this code , the select statement returns value only when the parameter is integer ... look at the code ..my problem is when the value of the dropdown ( select ) is an integer , the select statement works fine , otherwise it returns nothing .
<script>
function showUser(str)
{
if (str=="")
{
document.getElementById("txtHint").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","getuser.php?q="+str,true);
xmlhttp.send();
}
</script>
<body>
<form>
<select name="users" onchange="showUser(users.value)">
<option value="">choose a subject</option>
<option value="223">English</option>
<option value="2">ar</option>
<option value="161">علوم عامة</option>
<option value="ar">عربي</option>
</select>
<br>
<div id="txtHint"><b>Course info will be listed here.</b></div>
</p>
<p> </p>
<div class="clear"></div></div></div>
<div class="clear"></div>
</div>
</div>
</form>
</body>
//---------------and the getuser.php is
<?php
require_once("_gradeviewr.php");
$q = intval($_GET['q']);
$con = mysqli_connect('localhost','root','','evang_www');
if (!$con)
{
die('Could not connect: ' . mysqli_error($con));
}
mysqli_select_db($con,"evang_www");
$sql="SELECT * FROM uploaded WHERE subject = '".$q."'";
$result = mysqli_query($con,$sql);
echo "<table border='1'>
<tr>
<th>subject</th>
<th>Date from</th>
<th>Date To</th>
<th>filename</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['subject'] . "</td>";
echo "<td>" . $row['datefrom'] . "</td>";
echo "<td>" . $row['dateto'] . "</td>";
echo "<td>" . $row['filename'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>

Try this
HTML
<select name="users" id="urselectboxId">
Script
$('#urselectboxId').on('change',function(){
var str=$(this).val();
if (str=="")
{
$("txtHint").text("");
return;
}
else
{
$.ajax({
url:"getuser.php",
type:"get",
dataType:'json',
data: {q:str},
success:function(data){
// codes....
}
});
}
});

Develop Reference

JavaScript is the programming language of the Web.

How to update this script to respect JQuery AJAX syntax? - javascript

Even easier than using jQuery's ajax method, I'd use the load method. Makes your job a piece of cake: function showUser(str) { if (str == "") { $("#txtHint").html(""); return; } $("#txtHint").load("/getuser.php?q="+str); } That's it! http://api.jquery.com/load/

Related

How to filter the talbe using select option in php and mysql

want to fetch conditional data using ajax

How can I get multiple values from a radio button and then assign them into single variables and display them on a page?

Calculate two input values of fetched data using jquery

this js script , accept only integer

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