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Pretty self explanatory when you look at the following, but basically, a date string in a disabled field is pulled out. I split it by the forward slash, and I have tried everything I can think of to parse it into a number, but nothing works? I have been at this for hours. Any thoughts?
$('input[id$="ChestImagingDay5"]').val();
"8/6/2015"
$('input[id$="ChestImagingDay5"]').val().split('/')
[
0: "8",
1: "6",
2: "2015",
length: 3
]
$('input[id$="ChestImagingDay5"]').val().split('/')[0]
"8"
parseInt($('input[id$="ChestImagingDay5"]').val().split('/')[0])
NaN
parseInt($('input[id$="ChestImagingDay5"]').val().toString().split('/')[0])
NaN
parseInt($('input[id$="ChestImagingDay5"]').val().toString().split('/')[0].toString())
NaN
parseInt($('input[id$="ChestImagingDay5"]').val().toString().split('/')[0].toString(),10)
NaN
parseInt($('input[id$="ChestImagingDay5"]').val().toString().split('/')[0].toString(),'10')
NaN
Edit:
<input name="ctl00$ctl00$cphMain$plFormContent$txtChestImagingDay5" type="text" id="cphMain_plFormContent_txtChestImagingDay5" disabled="disabled" class="aspNetDisabled classTarget" style="width:94px;">
You correctly pointed out the likely problem in the comments; if you have a , it makes parseInt fail. You could strip out unprintable characters.
var parts = document.querySelector('input').value.split('/');
var int = parseInt(parts[0], 10);
console.log('Wrong Int value: ' + int); //NaN
// To make sure it works, strip out any non-printing characters.
// Got this regex from https://jsfiddle.net/shivassmca/8b0x66af/2/
// Mileage may vary, may be overkill
var re = /[\0-\x1F\x7F-\x9F\xAD\u0378\u0379\u037F-\u0383\u038B\u038D\u03A2\u0528-\u0530\u0557\u0558\u0560\u0588\u058B-\u058E\u0590\u05C8-\u05CF\u05EB-\u05EF\u05F5-\u0605\u061C\u061D\u06DD\u070E\u070F\u074B\u074C\u07B2-\u07BF\u07FB-\u07FF\u082E\u082F\u083F\u085C\u085D\u085F-\u089F\u08A1\u08AD-\u08E3\u08FF\u0978\u0980\u0984\u098D\u098E\u0991\u0992\u09A9\u09B1\u09B3-\u09B5\u09BA\u09BB\u09C5\u09C6\u09C9\u09CA\u09CF-\u09D6\u09D8-\u09DB\u09DE\u09E4\u09E5\u09FC-\u0A00\u0A04\u0A0B-\u0A0E\u0A11\u0A12\u0A29\u0A31\u0A34\u0A37\u0A3A\u0A3B\u0A3D\u0A43-\u0A46\u0A49\u0A4A\u0A4E-\u0A50\u0A52-\u0A58\u0A5D\u0A5F-\u0A65\u0A76-\u0A80\u0A84\u0A8E\u0A92\u0AA9\u0AB1\u0AB4\u0ABA\u0ABB\u0AC6\u0ACA\u0ACE\u0ACF\u0AD1-\u0ADF\u0AE4\u0AE5\u0AF2-\u0B00\u0B04\u0B0D\u0B0E\u0B11\u0B12\u0B29\u0B31\u0B34\u0B3A\u0B3B\u0B45\u0B46\u0B49\u0B4A\u0B4E-\u0B55\u0B58-\u0B5B\u0B5E\u0B64\u0B65\u0B78-\u0B81\u0B84\u0B8B-\u0B8D\u0B91\u0B96-\u0B98\u0B9B\u0B9D\u0BA0-\u0BA2\u0BA5-\u0BA7\u0BAB-\u0BAD\u0BBA-\u0BBD\u0BC3-\u0BC5\u0BC9\u0BCE\u0BCF\u0BD1-\u0BD6\u0BD8-\u0BE5\u0BFB-\u0C00\u0C04\u0C0D\u0C11\u0C29\u0C34\u0C3A-\u0C3C\u0C45\u0C49\u0C4E-\u0C54\u0C57\u0C5A-\u0C5F\u0C64\u0C65\u0C70-\u0C77\u0C80\u0C81\u0C84\u0C8D\u0C91\u0CA9\u0CB4\u0CBA\u0CBB\u0CC5\u0CC9\u0CCE-\u0CD4\u0CD7-\u0CDD\u0CDF\u0CE4\u0CE5\u0CF0\u0CF3-\u0D01\u0D04\u0D0D\u0D11\u0D3B\u0D3C\u0D45\u0D49\u0D4F-\u0D56\u0D58-\u0D5F\u0D64\u0D65\u0D76-\u0D78\u0D80\u0D81\u0D84\u0D97-\u0D99\u0DB2\u0DBC\u0DBE\u0DBF\u0DC7-\u0DC9\u0DCB-\u0DCE\u0DD5\u0DD7\u0DE0-\u0DF1\u0DF5-\u0E00\u0E3B-\u0E3E\u0E5C-\u0E80\u0E83\u0E85\u0E86\u0E89\u0E8B\u0E8C\u0E8E-\u0E93\u0E98\u0EA0\u0EA4\u0EA6\u0EA8\u0EA9\u0EAC\u0EBA\u0EBE\u0EBF\u0EC5\u0EC7\u0ECE\u0ECF\u0EDA\u0EDB\u0EE0-\u0EFF\u0F48\u0F6D-\u0F70\u0F98\u0FBD\u0FCD\u0FDB-\u0FFF\u10C6\u10C8-\u10CC\u10CE\u10CF\u1249\u124E\u124F\u1257\u1259\u125E\u125F\u1289\u128E\u128F\u12B1\u12B6\u12B7\u12BF\u12C1\u12C6\u12C7\u12D7\u1311\u1316\u1317\u135B\u135C\u137D-\u137F\u139A-\u139F\u13F5-\u13FF\u169D-\u169F\u16F1-\u16FF\u170D\u1715-\u171F\u1737-\u173F\u1754-\u175F\u176D\u1771\u1774-\u177F\u17DE\u17DF\u17EA-\u17EF\u17FA-\u17FF\u180F\u181A-\u181F\u1878-\u187F\u18AB-\u18AF\u18F6-\u18FF\u191D-\u191F\u192C-\u192F\u193C-\u193F\u1941-\u1943\u196E\u196F\u1975-\u197F\u19AC-\u19AF\u19CA-\u19CF\u19DB-\u19DD\u1A1C\u1A1D\u1A5F\u1A7D\u1A7E\u1A8A-\u1A8F\u1A9A-\u1A9F\u1AAE-\u1AFF\u1B4C-\u1B4F\u1B7D-\u1B7F\u1BF4-\u1BFB\u1C38-\u1C3A\u1C4A-\u1C4C\u1C80-\u1CBF\u1CC8-\u1CCF\u1CF7-\u1CFF\u1DE7-\u1DFB\u1F16\u1F17\u1F1E\u1F1F\u1F46\u1F47\u1F4E\u1F4F\u1F58\u1F5A\u1F5C\u1F5E\u1F7E\u1F7F\u1FB5\u1FC5\u1FD4\u1FD5\u1FDC\u1FF0\u1FF1\u1FF5\u1FFF\u200B-\u200F\u202A-\u202E\u2060-\u206F\u2072\u2073\u208F\u209D-\u209F\u20BB-\u20CF\u20F1-\u20FF\u218A-\u218F\u23F4-\u23FF\u2427-\u243F\u244B-\u245F\u2700\u2B4D-\u2B4F\u2B5A-\u2BFF\u2C2F\u2C5F\u2CF4-\u2CF8\u2D26\u2D28-\u2D2C\u2D2E\u2D2F\u2D68-\u2D6E\u2D71-\u2D7E\u2D97-\u2D9F\u2DA7\u2DAF\u2DB7\u2DBF\u2DC7\u2DCF\u2DD7\u2DDF\u2E3C-\u2E7F\u2E9A\u2EF4-\u2EFF\u2FD6-\u2FEF\u2FFC-\u2FFF\u3040\u3097\u3098\u3100-\u3104\u312E-\u3130\u318F\u31BB-\u31BF\u31E4-\u31EF\u321F\u32FF\u4DB6-\u4DBF\u9FCD-\u9FFF\uA48D-\uA48F\uA4C7-\uA4CF\uA62C-\uA63F\uA698-\uA69E\uA6F8-\uA6FF\uA78F\uA794-\uA79F\uA7AB-\uA7F7\uA82C-\uA82F\uA83A-\uA83F\uA878-\uA87F\uA8C5-\uA8CD\uA8DA-\uA8DF\uA8FC-\uA8FF\uA954-\uA95E\uA97D-\uA97F\uA9CE\uA9DA-\uA9DD\uA9E0-\uA9FF\uAA37-\uAA3F\uAA4E\uAA4F\uAA5A\uAA5B\uAA7C-\uAA7F\uAAC3-\uAADA\uAAF7-\uAB00\uAB07\uAB08\uAB0F\uAB10\uAB17-\uAB1F\uAB27\uAB2F-\uABBF\uABEE\uABEF\uABFA-\uABFF\uD7A4-\uD7AF\uD7C7-\uD7CA\uD7FC-\uF8FF\uFA6E\uFA6F\uFADA-\uFAFF\uFB07-\uFB12\uFB18-\uFB1C\uFB37\uFB3D\uFB3F\uFB42\uFB45\uFBC2-\uFBD2\uFD40-\uFD4F\uFD90\uFD91\uFDC8-\uFDEF\uFDFE\uFDFF\uFE1A-\uFE1F\uFE27-\uFE2F\uFE53\uFE67\uFE6C-\uFE6F\uFE75\uFEFD-\uFF00\uFFBF-\uFFC1\uFFC8\uFFC9\uFFD0\uFFD1\uFFD8\uFFD9\uFFDD-\uFFDF\uFFE7\uFFEF-\uFFFB\uFFFE\uFFFF]/g;
var betterInt = parseInt( parts[0].replace(re, ''), 10 );
console.log('Correct Int value: ' + betterInt); //8
<input value="8/12/07">
Related
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Closed 12 months ago.
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const str = 'Do. Or do not. There is no try.';
console.log(str.endsWith('try', 30)); //true
console.log(str.endsWith('try.', 30)); //false
Can anyone explain why in example 2 it is false. I think it is similar with above and must return true?
Because in endsWith() the second parameter is length.
The string
Do. Or do not. There is no try.
is 31 characters long, by setting the length parameter to 30, you're only testing
Do. Or do not. There is no try
which does not end with try.
As Ian said, you can omit the length parameter to test the entire string:
const str = 'Do. Or do not. There is no try.';
console.log(str.endsWith('try')); // false
console.log(str.endsWith('try.')); // true
It's because y is the 30th character, and in the length parameter of the function call you've specified it should test the ending of the first 30 characters of the string. Therefore it doesn't take the . (which is the 31st character) into account.
You're actually only testing the following text:
Do. Or do not. There is no try
More info: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/endsWith
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I have this expression:
/width*$/.test(oldStyle)
And oldStyle has this inside of it:
width:90%;height:inherit;padding-left:20px;
The expression should return true as i have tested it in a online JavaScript regex expression tool.
Why is this returning false?
Can i use this expression the way i have coded?
You need to use . to match any character followed by the * to match 1 or more.
const oldStyle = 'width:90%;height:inherit;padding-left:20px;';
const result = /width.*$/.test(oldStyle);
document.getElementById('result').innerHTML = "Result: " + result;
<div id="result"></div>
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Clarification - I want to check if str1 and str2 share common substring.
str1 = "and we know that the lion"
str2 = "the lion is big"
by using those two string because the lion happens to show on both string then true will be invoked.
Thanks.
You can use String.includes that will return a boolean value:
console.log("and we know that the lion".includes("the lion is big")); // returns false
console.log("and we know that the lion".includes("the lion")); // returns true
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I have a phone number like (123) 456-7891. I need number like 1234567891.
How can I do that in Javascript ?
To be on the safe side, I would recommend removing everything except + (for country codes) and digits:
result = subject.replace(/[^+\d]+/g, "");
You can use String.replace() to do this. Pass it a RegExp that matches everything but digits and replace them with ''.
var number = '(123) 456-7891';
number = number.replace(/[^\d]/g, '');
alert("(123) 456-7891".replace(/[\(\)\-\s]+/g, ''));
please check this link.it might help you
http://www.w3resource.com/javascript/form/phone-no-validation.php
there are many examples here.it might be useful for you.
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Can someone tell me how to replace the number "2" with another number in this string"? For example, if it's a 2, it should be a 3, if it's a 3 it should be a 4, etc.
Please note that the number can be any number from 1 through 5.
/img/tmp/2_th.jpg
Just use String#replace:
s.replace(/\d+(?=_)/, "replaced");
To replace any number from 1-5 use:
s.replace(/[1-5](?=_)/, "replaced");
Here (?=_) is used a positive lookahead which makes sure match a number which is followed by underscore _.
UPDATE: Based on your edit you can use this code to increment matched number by 1:
s.replace(/([1-5])(?=_)/, function(n) {return parseInt(n)+1;});
Read More About Lookarounds in Regex
I understand from your question that you want to replace any number by the following one (" if it's a 2, it should be a 3, if it's a 3 it should be a 4").
Then you can do this :
var input = "/img/tmp/2_th.jpg";
var output = input.replace(/\d+/g,function(s){ return +s+1 })
Result :
"/img/tmp/3_th.jpg"