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regex target specific character around variable

Hi,
I have this code:
var room = 'room2';
var exitroom = 'room1,room2,room3';
exitroom = exitroom.replace(/,${room},/,'');
console.log(exitroom);
you can try it here: https://jsfiddle.net/uq9w0Ls4/
my expected output is simply room1,room3 by taking room2 out but since it may change its position within the string I want to target the , no matter if it comes before or after the string but I cant figure out the regex logic here. I know I could just do simply:
var room = 'room2';
var exitroom = 'room1,room2,room3';
exitroom = exitroom.replace(room+',','').replace(','+room,'');
console.log(exitroom);
which works but I think regex would be a more direct approach.
Thank you.

First, by writing .replace(/,${room},/,'') you are not using the variable room.
To use a variable in a regex you should call new RegExp()
Second, if you want a regex that will match when the comma is before or after the word, you can use a group () with an Or | operator.
so it should look like this:
var reg = new RegExp(`(?:${room},|,${room})`, "g");
exitroom.replace(reg,'');
The ?: at the beginning of the group, is just so it should be a non-capturing group, it should work just fine also without it

Match a string between two other strings with regex in javascript

How can I use regex in javascript to match the phone number and only the phone number in the sample string below? The way I have it written below matches "PHONE=9878906756", I need it to only match "9878906756". I think this should be relatively simple, but I've tried putting negating like characters around "PHONE=" with no luck. I can get the phone number in its own group, but that doesn't help when assigning to the javascript var, which only cares what matches.
REGEX:
/PHONE=([^,]*)/g
DATA:
3={STATE=, SSN=, STREET2=, STREET1=, PHONE=9878906756,
MIDDLENAME=, FIRSTNAME=Dexter, POSTALCODE=, DATEOFBIRTH=19650802,
GENDER=0, CITY=, LASTNAME=Morgan

The way you're doing it is right, you just have to get the value of the capture group rather than the value of the whole match:
var result = str.match(/PHONE=([^,]*)/); // Or result = /PHONE=([^,]*)/.exec(str);
if (result) {
console.log(result[1]); // "9878906756"
}
In the array you get back from match, the first entry is the whole match, and then there are additional entries for each capture group.
You also don't need the g flag.

Just use dataAfterRegex.substring(6) to take out the first 6 characters (i.e.: the PHONE= part).

Try
var str = "3={STATE=, SSN=, STREET2=, STREET1=, PHONE=9878906756, MIDDLENAME=, FIRSTNAME=Dexter, POSTALCODE=, DATEOFBIRTH=19650802, GENDER=0, CITY=, LASTNAME=Morgan";
var ph = str.match(/PHONE\=\d+/)[0].slice(-10);
console.log(ph);

JavaScript escape stars on regular expression

I am trying to get a serial number from a zigbee packet (i.e get from 702442500 *13*32*702442500#9).
So far, I've tried this:
test = "*#*0##*13*32*702442500#9##";
test.match("\*#\*0##\*13\*32\*(.*)#9##");
And this:
test.match("*#*0##*13*32*(.*)#9##");
With no luck. How do I get a valid regular expression that does what I want?

The below regex matches the number which has atleast three digits,
/([0-9][0-9][0-9]+)/
DEMO

If you want to extract the big number, you can use:
/\*#\*0##\*13\*32\*([^#]+)#9##/
Note that I use delimiters / that are needed to write a pattern in Javascript (without the regexp object syntax). When you use this syntax, (double)? quotes are not needed. I use [^#]+ instead of .* because it is more clear and more efficent for the regex engine.

The easiest way to grab that portion of the string would be to use
var regex = /(\*\d{3,}#)/g,
test = "*13*32*702442500#9";
var match = test.match(regex).slice(1,-1);
This captures a * followed by 3 or more \d (numbers) until it reaches an octothorpe. Using the global (/g) modifier will cause it to return an array of matches.
For example, if
var test = "*13*32*702442500#9
*#*0##*13*32*702442500#9##";
then, test.match(regex) will return ["*702442500#", "*702442500#"]. You can then slice the elements of this array:
var results = [],
test = "... above ... ",
regex = /(\*\d{3,}#)/g,
matches = test.match(regex);
matches.forEach(function (d) {
results.push(d.slice(1,-1));
})
// results : `["702442500", "702442500"]`

Changing character between two strings

How can i change the character after "#overlay/" and before "/" after that first one?
var x = "www.foo.com/#overlay/2/";
x.replace(/#overlay\/([^]*)\//, "1"); // i'm expecting: www.foo.com/#overlay/1/
I'm using this code, but no success. I don't understand that much from regex.
I've searched some questions but without success.

I would not use a regular expression here. You can just use .split().
var url, newUrl, peices;
url = 'www.foo.com/#overlay/2/';
// Split the string apart by /
peices = url.split('/');
// Changing the 3 element in the array to 1, it was originally 2.
peices[2] = 1;
// Let's put it back together...
newUrl = peices.join('/');

You're making 3 mistakes :
you're replacing too much
you don't use the returned value. replace doesn't change the passed string (strings are immutable) but returns a new one
you forgot to precise in your capturing group when to stop (in fact it doesn't even have to be a capturing group)
You can do this :
x = x.replace(/(#overlay\/)[^\/]*\//, "$11/");
$1 here refers to the first captured group, so that you don't have to type it in the replacement string.
For example it changes
"www.foo.com/#overlay/2/rw/we/2345"
into
"www.foo.com/#overlay/1/rw/we/2345"

javascript regex to extract the first character after the last specified character

I am trying to extract the first character after the last underscore in a string with an unknown number of '_' in the string but in my case there will always be one, because I added it in another step of the process.
What I tried is this. I also tried the regex by itself to extract from the name, but my result was empty.
var s = "XXXX-XXXX_XX_DigitalF.pdf"
var string = match(/[^_]*$/)[1]
string.charAt(0)
So the final desired result is 'D'. If the RegEx can only get me what is behind the last '_' that is fine because I know I can use the charAt like currently shown. However, if the regex can do the whole thing, even better.

If you know there will always be at least one underscore you can do this:
var s = "XXXX-XXXX_XX_DigitalF.pdf"
var firstCharAfterUnderscore = s.charAt(s.lastIndexOf("_") + 1);
// OR, with regex
var firstCharAfterUnderscore = s.match(/_([^_])[^_]*$/)[1]
With the regex, you can extract just the one letter by using parentheses to capture that part of the match. But I think the .lastIndexOf() version is easier to read.
Either way if there's a possibility of no underscores in the input you'd need to add some additional logic.