Develop Reference

Input field appear after selecting a check box. HTML

I have a Twitter Bootstrap form that has 6 vertical check boxes. I need to have an input form field each time they select a checkbox. It could be in the form of a popup or maybe something that appears out to the right of the checkbox. I figure this is some kind of javascript function but I have no idea how to do so. Any suggestions would be greatly appreciated. Each textbox if selected should have a field that pops up asking them for how many years experience they have in this certain field. This will info will be collected via $_POST variables. So each checkbox popup should have its own unique name so i can post it.
<div class="form-group">
<label class="col-md-4 control-label" for="positionsought">Position Sought</label>
<div class="col-md-4">
<div class="checkbox">
<label for="positionsought-0">
<input type="checkbox" name="positionsought" id="positionsought-0" value="Cutting">
Cutting
</label>
</div>
<div class="checkbox">
<label for="positionsought-1">
<input type="checkbox" name="positionsought" id="positionsought-1" value="Sewing">
Sewing
</label>
</div>
<div class="checkbox">
<label for="positionsought-2">
<input type="checkbox" name="positionsought" id="positionsought-2" value="Upholstery">
Upholstery
</label>
</div>
<div class="checkbox">
<label for="positionsought-3">
<input type="checkbox" name="positionsought" id="positionsought-3" value="Frame Department">
Frame Department
</label>
</div>
<div class="checkbox">
<label for="positionsought-4">
<input type="checkbox" name="positionsought" id="positionsought-4" value="Mill Room">
Mill Room
</label>
</div>
<div class="checkbox">
<label for="positionsought-5">
<input type="checkbox" name="positionsought" id="positionsought-5" value="Cushion">
Cushion
</label>
</div>
<div class="checkbox">
<label for="positionsought-6">
<input type="checkbox" name="positionsought" id="positionsought-6" value="Any">
Any
</label>
</div>
</div>
</div>

Although you already have found an answer, I believe that this would work better for your situation since you say you will have 6 checkboxes. This dynamically creates input fields for each checkbox by their names and removes them when the checkbox is unchecked.
First add this function to each checkbox onclick="dynInput(this);"
<input type="checkbox" name="check1" onclick="dynInput(this);" />
and add this to wherever you would like the inputs to display.
<p id="insertinputs"></p>
Then simply add this javascript function to your head.
<script type="text/javascript">
function dynInput(cbox) {
if (cbox.checked) {
var input = document.createElement("input");
input.type = "text";
var div = document.createElement("div");
div.id = cbox.name;
div.innerHTML = "Text to display for " + cbox.name;
div.appendChild(input);
document.getElementById("insertinputs").appendChild(div);
} else {
document.getElementById(cbox.name).remove();
}
}
</script>
JsFiddle here: http://jsfiddle.net/brL6gy7r/

You can use JavaScript here to do the job. When the checkbox is clicked and checked (because you can also check out.) a dialog will pop-up with all input-fields you want. You can change the dialog part to your desires. but this part is your main function:
$(document).ready(function () {
$('#chkBox').click(function () {
if ($(this).is(':checked')) {
// create input field
} else {
// if checkbox is not checked.. dont show input field
}
});
});
For a full demo on how to do this with a dialog, click this link and observe
http://jsfiddle.net/Runman44/5vy1m233/
Notice that you will need jQuery (and jQuery UI if you want to use the dialog like me)

There is a zero-JavaScript version that is dead simple and works in all major browsers. It takes advantage of the :checked pseudo-class and the adjacency selector. It works with an arbitrary number of checkboxes.
HTML:
<input type="checkbox" />
<input type="text" />
CSS:
input[type=text] {
visibility:hidden;
}
input[type=checkbox]:checked + input[type=text] {
visibility:visible;
}
here is the live demo
If you prefer, you can use display:none and display:inline rather than the visibility property.
The example I've provided assumes that the text field immediately follows the checkbox in the markup, but some variant of sibling/child selectors can be used to select it no matter where it is, as long as it is either a sibling or child (direct or indirect) of the checkbox.

If parent element has only 2 child elements do something, else something else

So I have this html markup:
<div class="buttons-holder>
<label class="my-btn">
<input name="example" value="1" type="radio"> YES
</label>
<label class="my-btn">
<input name="example" value="0" checked="checked" type="radio"> NO
</label>
</div>
But sometimes I have more than one label inside the .buttons-holder element. How can I specify in jQuery to apply my jQuery code only if there exists 2 label elements?
I tried something like this but it still applies to all elements:
if ($('form label:has(input[type="radio"])').eq(2)) {
//do something
} else {
//do something else
}
Jsfiddle: http://jsfiddle.net/jw51hggc/

Based on your comments and fiddle
$('form .buttons-holder').filter(function(){
return $(this).children('label:has(input[type="radio"])').length == 2
}).wrapInner('<div class="wrap"></div>');
Demo: Fiddle

CSS is not changing through calling JS in HTML

my JS code is bellow:
// JavaScript Document
function bubbleColor() {
if($("#Checkbox1").is(":checked") && $("#Checkbox2").is(":checked"))
{
$(".bubble").css("background-color", "red");
}
}
var el = document.getElementById(".bubble");
el.onclick = bubbleColor;
And my targeted HTML:
<div id="circle" class="bubble">
<p class="circle_text">
#6
</p>
</div>
<br/><br/>
<input type="checkbox" value="1" id="Checkbox1" name="Checkbox1"/> Answer one <br/>
<input type="checkbox" value="1" id="Checkbox2" name="Checkbox2"/> Answer two <br/>
<input type="checkbox" value="1" id="Checkbox3" name="a3"/> Answer three <br/>
Desired output:
When somebody checks [selects] both the Checkbox1 and Checkbox2, the #6 background should be Red color.
Problem:
The code does not seem to work.
Any help please?

Im assuming you are using jquery (as you are changing css with jquery)
The behaviour you describe in your question implies that changing the checkbox should trigger a verification, so why do you attach the bubbleColor function to clicking on the .bubble div?
Try something like this:
// Alternatively you could use a class to select the checkboxes
$("input[type='checkbox']").change(bubbleColor);
Ofcourse ideally you should change your function to remove the red color if you uncheck the boxes:
function bubbleColor() {
if ($("#Checkbox1").is(":checked") && $("#Checkbox2").is(":checked")) {
$(".bubble").css("background-color", "red");
} else {
$(".bubble").css("background-color", "transparent");
}
}
Fiddle: http://jsfiddle.net/sQCcF/2/
Edit:
If what you want is to ensure user only selects 1 option then you should use radio buttons instead of checkboxes, as that is the default behavior:
<input type="radio" name="inputname" value="1"/>
<input type="radio" name="inputname" value="2"/>
<input type="radio" name="inputname" value="3"/>
The name has to be the same for the inputs, but each one will have a different value, selecting one will automatically unselect the other.

Problem is at
var el = document.getElementById(".bubble");
You are selecting element with ID of .bubble (bubble is a class)
Change it to and check :
var el = document.getElementById("circle");

First of all you attach an event handler for the click event on div with class "bubble".
Then, you use document.getElementById method to select an element but you use as argument the class of that element, not the ID.
For this to work you need to attach the click event handler to checkbox elements.
Something like this:
$('input[type="checkbox"]').click(function() {
bubbleColor();
});

Replace var el = document.getElementById(".bubble");
el.onclick = bubbleColor;
with
$(".bubble").click(bubbleColor) ;
should work.

Try this code
HTML
<div id="circle" class="bubble">
<p class="circle_text">
#6
</p>
</div>
<br/><br/>
<input type="checkbox" value="1" id="Checkbox1" name="Checkbox1" class="chBox"/> Answer one <br/>
<input type="checkbox" value="1" id="Checkbox2" name="Checkbox2" class="chBox" /> Answer two <br/>
<input type="checkbox" value="1" id="Checkbox3" name="a3" class="chBox" /> Answer three <br/>
JQUERY
$(document).ready(function(){
// you can use '.chBox class or input[type='checkbox']'
$('.chBox').bind('click', function(){
if($("#Checkbox1").is(":checked") && $("#Checkbox2").is(":checked"))
{
$(".bubble").css("background-color", "red");
}else{
$(".bubble").css("background-color", "#fff");
}
});
});

Showing, hiding checkboxes with jquery using fadeIn fadeOut

I am writing a form, it has checkboxes, and I wrote a script to show and hide them (specifically hide all other checkboxes when one of them is selected).
I reached this far when I need this to hide the input checkboxes, but what this code below is doing, is: it shows only 1 of checkboxes (the second one). Why, how can I hide both of the checkboxes at the same time ?
$('input:checkbox.individual' && 'input:checkbox.organization').stop(true,true).fadeIn("normal")
this is my html:
<div class="field check check-entity">
<label for="entity_type">For what kind of entity are you requesting sponsorship?<span class="form_required">*</span></label><br><br>
<input type="checkbox" name="entity_type" value="entity_project" class="project"/><label for="entity_project" class="lalbe_project">Project</label>
<input type="checkbox" name="entity_type" value="entity_individual" class="individual"/><label for="entity_individual"class="label_individual">Individual</label>
<input type="checkbox" name="entity_type" value="entity_organization" class="organization"/><label for="entity_organization" class="label_organization">Organisation</label>
</div>

Use a , in the selection string to select multiple groups of elements
$('input.individual:checkbox, input.organization:checkbox')
// ^ see here

Is this the effect you wanted to achieve?
http://jsfiddle.net/z37br/
HTML:
<div class="field check check-entity">
<label for="entity_type">For what kind of entity are you requesting sponsorship?
<span class="form_required">*</span>
</label>
<br><br>
<input type="checkbox" name="entity_type" value="entity_project" data-type="project"/>
<label for="entity_project" class="lalbe_project">Project</label>
<input type="checkbox" name="entity_type" value="entity_individual" data-type="individual"/>
<label for="entity_individual"class="label_individual">Individual</label>
<input type="checkbox" name="entity_type" value="entity_organization" data-type="organization"/>
<label for="entity_organization" class="label_organization">Organisation</label>
</div>
JS:
$('input').change(function() {
if ($(this).prop('checked')) {
var clickedCheckboxType = $(this).attr('data-type');
$('input').each(function() {
if (clickedCheckboxType != $(this).attr('data-type')) {
$(this).fadeOut('fast');
$(this).next().fadeOut('fast');
}
});
}
else {
$('input').fadeIn('fast');
$('input').next().fadeIn('fast');
}
});

Jquery/javascript Radio button hide/show logic for checked attribute for pageload

I was trying to code jquery/JS logic for hide/show description based on radio button being checked or not. If the radio button is checked on page load, i want the description associated with that radio button to load. But the default one of the either has to selected/checked
I did try to code with .change and click methods inside ready(). But was not successful
I have only two radio buttons, I'm not a Javascript/jquery person. Any input is appreciated. This is an example
<div id="ServiceSelection">
<input type="radio" name="Service" checked="Checked" value="B"> Option 1
<br>
<input type="radio" name="Service" value="P"> Option 2
<br>
<div id="DivB" style="display:none" class="desc">B Description goes here </div>
<div id="DivP" style="display:none" class="desc">P Description goes here </div>
</div>
Edited DIV:
<div id="ServiceSelection">
<input type="radio" name="Service" checked="Checked" value="B"> Option 1
<br>
<div id="DivB" style="display:none" class="desc">B Description goes here </div>
<input type="radio" name="Service" value="P"> Option 2
<br>
<div id="DivP" style="display:none" class="desc">P Description goes here </div>
</div>
Thanks in advance
J

if($('input[name=Service]').is(':checked')){ //is it checked?
var v = $('input[name=Service]:checked').val(); //get the value
$('div[id$='+v+']').show(); //target the end of selector, and match it to our value
}
$('input[name=Service]').on('click', function(){
$(this).parent().find('div').hide(); //hide the divs...
$('div[id$='+$(this).val()+']').show(); //show the div based on our value again..
});
fiddle

Try this:
function ShowData(evt) {
var val = $("input[name=Service]:checked").val();
if (val == 'B') {
$('#DivB').show();
$('#DivP').hide();
} else {
$('#DivP').show();
$('#DivB').hide();
}
}
$('input[name=Service]:radio').change(ShowData);
ShowData();
DEMO HERE

I'd suggest:
// hide the div elements with JavaScript, so they're visible to those
// users with JavaScript disabled:
$('#ServiceSelection div[id]').hide();
// select the radio input elements and bind to the change event
$('input:radio').change(function(){
// find the element whose id is equal to 'Div' + the value of the radio,
// show that div, hide the sibling div elements
$('#Div' + this.value).show().siblings('div').hide();
// filter the radio elements to find the one that's checked, and trigger the change event
}).filter(function(){return this.checked; }).change();
JS Fiddle demo.
References:
change().
filter().
hide
().
show().
siblings().