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How to use ID from a table and send it to php file for query [closed]

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So I've this admin-dashboard where I want to click on the options link which will take me to another page or show a modal of that particular person's details.
So basically, I want to get the ID of one particular person and send it to backend for query and display the details.
My doctor-details.php file
<?php
require('config.php');
$sql = "SELECT * FROM doctor";
$result = mysqli_query($conn, $sql);
$count = mysqli_num_rows($result);
if($count > 0){
while($rows = mysqli_fetch_array($result)){
?>
<tr>
<td><?php echo $rows['id'];?> </td>
<td><?php echo $rows['f_name'];?></td>
<td><?php echo $rows['l_name'];?></td>
<td><?php echo $rows['email'];?></td>
<td><?php echo $rows['contact_number'];?></td>
<td><?php echo $rows['gender'];?></td>
<td> Options</td>
</tr>
<?php
}
}
?>
my ajax code for doctor's details
//For Doctor
$(document).ready(function(){
$("#load-doctor-data").click(function(){
$.ajax({
url: 'views/admin/doctor-details.php',
type: 'POST',
success: function(result){
$("#response-doctor").html(result);
}
});
});
});
//Hide table on login
$("#show-doctor-details").hide();
$(document).ready(function(){
$("#load-doctor-data").click(function(){
$("#show-doctor-details").show();
$("#show-patient-details").hide();
});
});

window.addEventListener('load', function() {
var trs = document.getElementById('response-doctor').querySelectorAll('tr');
for (var i = 0; i < trs.length; i++) {
var tds = trs[i].querySelectorAll('td');
tds[tds.length-1].querySelector('a').setAttribute('href', '/user/'+tds[0].innerHTML);
}
});
My bad, this sloution more easier (inside doctor-details.php):
<td> Options</td>

You can make entire table row as link
For example:
<tr a="profile.php?id=<?php echo $rows['id'?];">
...
<tr>
This is how you can add link on every row which leads you to profile.php file where you can show personal information. When you are in profile.php you can access person's id with $_GET['id'] and fetch data from database using this id. If you are looking for more detailed answer don't hesitate to ask.

Is it possible to combine javascript/jquery and mysql/php

I have a odd question i cannot find the answer to, which probably means it is impossible. The reason i ask is i am creating a food delivery website. In the admin panel of my website administers are able to input restaurant details and menus. Part of the details is how much a customer must spend before they can checkout for delivery. so i want to be able to deactivate the checkout button, but when they met the minimum order fee the button activates.
This is my first time attempting anything like this, i have looked all over and i can only find posts or tutorials on how to deactivate then activate a button when a certain event takes place using javascript or jQuery and i know i would have to get the minimum order fee from the DB.
The only logical answer is to combine them.
I am trying to achieve something similar to this...
Shopping
I followed a tutorial to do this, it is a mini fixed shopping cart, which is on the same page as the shopping cart. It redirects to shopping_cart.php from product_page.php. Most aspects on product_page.php is dynamically made.
mysqli_stmt_execute($runn_query);
while ($get_row = mysqli_fetch_array($runn_query)) {
echo "<div id='prods_ere'>";
$item_sub = $get_row['Product_Price'] * $value;
echo $value . ' x ' .$get_row['Product_Name']. ' # £' . $get_row['Product_Price'] . '<a id="minus" class="buttons" href="Shopping_cart.php?remove=' . $Product_Id . '">-</a> <a id="plus" class="buttons" href="Shopping_cart.php?add_item=' . $Product_Id . '"> + </a> <a id="del" class="buttons" href="Shopping_cart.php?delete=' . $Product_Id . '">✖</a> </br><p id="sub">£' . $item_sub . '</p>';
echo "<br>";
echo "<br>";
echo "<hr id='shopp_dashed'>";
echo "</div>";
}
}
//creating subtotal
$sub_total += $item_sub;
$num_items += $value;
$total += $sub_total;
}
}
//subtotal and empty cart message
if ($sub_total == 0) {
echo "Ouch.. its empty in here";
} else {
echo "<div id='grey'>";
echo"Subtotal (excl delivery)";
echo "<br/>";
echo "<div id='sub_t'>";
echo '£' . number_format($sub_total, 2);
echo "</div>";
echo "<br/>";
echo"Items";
echo "<br/>";
echo "$num_items";
echo "<br/>";
echo "</div>";
echo "<div id='total'>";
echo"Total: ";
echo "$total";
echo "</div>";
}
Products page
<div id="prods_here">
<!-- PLACE PRODUCTS HERE-->
<?php cart(); ?>
</div>

Well, I'm not sure how you're keeping track of the customer's order but let's say you're keep track of it in a counter, say, totalOrderAmt. As they are making changes to the order, keep this updated and add a condition to the page, that when the totalOrderAmt >= checkOutAmt, enable the checkOut button.
I can add more details if you post some code, may be.

If you're using PHP you could load a JavaScript object on each restaurant page that basically makes a minimum_order_price variable available on the DOM for the JavaScript to handle the rest:
<html>
<head>
...
</head>
<body>
<h1>Restaurant X</h1>
<p>Minimum order: <span id="_restaurantMinimumOrder"></span></p>
<input id="submit" type="submit" class="disabled" value="Checkout" disabled>
<script type="text/javascript">
<?php
echo "window.RestaurantDetails = {}";
echo "window.RestaurantDetails.minimum = $RestaurantMinimumOrder";
?>
</script>
</body>
</html>
In this instance, $RestaurantMinimumOrder is something you configure and setup on PHP (I am not sure what you're setup is so I went with a variable name). From there, when the page is parsed from the server, the PHP will echo out that JavaScript. Once the page loads, window.RestaurantDetails will be available for the rest of your JavaScript to use. I've also included an example implementation:
<script type="text/javascript">
// set price on the DOM
var priceEl = document.getElementById('_restaurantMinimumOrder');
priceEl.textContent = window.RestaurantDetails.minimum;
// ensure submit button is disabled initially
var submitEl = document.getElementById('submit');
submitEl.disabled = true;
</script>
From here, if you're using jQuery you can easily adjust the state of the submit button based on whatever logic flow you have setup. Let me know if you have more questions. Best of luck! Cheers ~

Get var from a PHP page [closed]

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I'm having a problem with my PHP. I would like to send data from my page to another page. But it's all in PHP. I need to take an input value and a combobox value. And I don't know how to do it.
Here's my PHP :
<?php
session_start();
$q = intval($_GET['q']);
$db = mysql_connect('localhost', 'root', 'root');
mysql_select_db('Projet',$db);
$sql2 = "select IDControle, NomControle from Controle WHERE IDUser='".$_SESSION['id']."'";
$req2 = mysql_query($sql2) or die('Erreur SQL !<br>'.$sql2.'<br>'.mysql_error());
echo'<select id="controleChoix" name="controleChoix">';
while ($data2 = mysql_fetch_array($req2)){
echo '<option value="'.$data2['IDControle'].'">'.$data2['NomControle'].'</option>';
}
echo '</select>';
echo '<input type="hidden" name="selected_text" id="selected_text" value="" />';
$sql = "select ID, Nom, Prenom from User where Groupe ='".$q."'";
$req = mysql_query($sql) or die('Erreur SQL 2!<br>'.$sql.'<br>'.mysql_error());
echo '<ul class="list-group">';
while ($data = mysql_fetch_array($req)){
echo '<li class="list-group-item"><strong>Nom</strong> : '.$data['Nom'].' <br> <strong>Prénom</strong> : '.$data['Prenom'].'<br>';
echo '<input type="text" name="note" id="note"/> ';
echo '<a class="label label-success" href="ajouterNote.php?var1='.$data2['IDControle'].'&var2='.$data['ID'].'&var3='.$test.'"><i class="fa fa-fw fa-check"></i></a></li>';
}
echo '</ul>';
echo '<a class="btn btn-primary" href="#">Ajouter toutes les notes</i></a></li>';
?>
I need to send the input note.value, the select controleChoix.value and the intval q that I've received from another page.

As you already seem to use SESSIONS, you could easily transfer your data from one page to another using these $_SESSION variables.
https://secure.php.net/manual/en/book.session.php
edit: Please keep in mind that this isn't secure at all. The values can easily be changed by the user. Using this you might want to validate the values first, before using.

Delete specific uploaded file from folder on server and display remaining files

going a bit crazy trying to get this to work... I have a photo upload page that lets you upload multiple photos and displays all the uploaded photos of a specific user below the upload form. I also place a delete button next to each photo however once you delete a photo it keeps displaying that image (although with a broken link as the photo is deleted from the server). I start by looping through a table that holds the file dir and name and then displays those photos. I have a submit button that calls the unlink() function.
$photoQuery= "SELECT * FROM photo_index WHERE User_ID='$UserID'";
$result = mysqli_query($dbcon, $photoQuery);
while ($photo_data = mysqli_fetch_array($result)){
echo "<form id=photo_Form action=listing_photos.php method=post> ";
echo "<input type=hidden name=photoDir value='$photo_data[Photo_Dir]' />";
echo "<input type=submit name=photoDel id=submit_but value=Delete />";
echo "</form>";
echo "<img src='$photo_data[Photo_Dir]' height=100px width=100px>";
}
Then here is the php that deletes the photo file and the row in the table that stored the photo info.
if (isset($_POST['photoDel'])){
$fh = fopen($_POST['photoDir'], 'a');
fclose($fh);
unlink($_POST['photoDir']);
$photoDel= "DELETE FROM photo_index WHERE Photo_Dir='$_POST[photoDir]'";
$result = mysqli_query($dbcon, $photoDel) or die(mysql_error());
echo "Photo Removed";
}
I had to open and close the file before using unlink because if I didnt I would always get a warning after the photo was deleted saying that unlink(images/somephoto.jpg) did not exist (because it had been removed from the server already)
Once the delete button is clicked it should refresh the page shouldn't it?? and when the page refreshes it should reload the query and only display the photos that are listed in the photo tabel?? For what ever reason it takes two refreshes to get that result. Any help would be very much appreciated, or any way to just do this better! Cheers.

First off, your code is vulnerable to SQL injection. You should look into that. Next, maybe you should use JS to find and remove the image from the document. So, have a <button> that runs a function which removes the image with that specific source from the document.
Here's a PHP snippet:
$photoQuery= "SELECT * FROM photo_index WHERE User_ID='$UserID'";
$result = mysqli_query($dbcon, $photoQuery);
while ($photo_data = mysqli_fetch_array($result)){
echo "<form id=photo_Form action=listing_photos.php method=post> ";
echo "<input type=hidden name=photoDir value=". $photo_data[Photo_Dir] . "/>";
echo "<input type=submit name=photoDel id=submit_but value=Delete />";
echo "</form>";
echo "<img src=" .$photo_data[Photo_Dir]. " id = 'picture' height=100px width=100px>";
echo "<script>
var d = getElementById('submit_but');
var b = getElementById('pic');
d.onclick = function(){
pic.parentNode.removeChild(b);
return true;
}
</script>";
}
See here for the JavaScript:
http://jsfiddle.net/BUXBq/

value "ID" for the selected row is not parsing on AJAX JQUERY [closed]

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I have an HTML table where the data was retrieved from a database using PHP hence I used a loop to echo the rows. Which created my initial problem of trying to retrieve the correct ID using AJAX. I was recommended using class to create my JQUERY Code I don't knoe what I am doing wrong.
My objective:
I am trying to parse the selected row's ID into my jquery code which then parses into a second php script.
This is my code of the HTML table:
<form id="mainform" >
<table id="table1">
<?php
$result = mysql_query("SELECT * FROM test");
while ($row = mysql_fetch_array($result))
{
$ID = $row['ID'];
echo "<tr data-rows='$ID'><td>$ID</td>";
echo "<td><input type='hidden' class='hf' value='$ID' /></td>";
echo "<td><input type='button' class='abc' value='select' /></td></tr>";
}
?>
</table>
</form>
This is my JAVASCRIPT code:
<script>
$( document ).ready(function() {
$(".abc").each(function(){
var btn = $(this);
btn.on("click",function(){
$("#newdiv").empty();
var rowId = $(this).closest('tr').attr('data-row');
$('.hf').each(function(){
$.get("boom.php", { ID: rowId } ,function(data) {
$("#newdiv").append(data);
});
});
});
});
});
</script>
I don't know where I went wrong?
I edted the CODE to my latest version

Convert this line
echo "<tr><td>".$ID."</td></tr>";
To this:
echo "<tr data-row='$ID'><td>$ID</td>";
Then, in your javascript, use the power of jQuery to find that attribute in your onClick handler.
btn.on("click",function() {
var rowId = $(this).closest('<tr>').attr('data-row');
}
The variable rowId should now match which row you are on. From there you can pass that in your AJAX calls.
EDIT: You also have mismatched selectors on your jQuery each() function. You have
$("#abc").each(function(){
}
But in the HTML, the button has no ID selector, only a class. Change that line to this:
$('.abc').each(function () {
}