Develop Reference

Queue on click function

I am pretty new to jQuery and I am having a bit of difficulty adapting to it being a Java nerd.
I am trying to make these 3 boxes so that when you click one of them, it comes forward and the two in the back dim and stay there, in the back. The problem is that, I want to make it so when you click more than 1 box consecutively, the second box clicked doesn't come forward until the animation ends, much like a queue of box clicks. Right now it's all mixed up and the dimming is fine but the boxes come forward as soon as I click them and not when they should.
I tried callbacks and deferred to no avail.
Here is the code:
Javascript:
var zindex = 1;
$('.box_listener').click(function() {
$(this).css('z-index', zindex += 1);
$(this).siblings('.box_listener').fadeTo(3000, 0.5);
$(this).fadeTo(1, 1);
});
Here is the JSFiddle:
https://jsfiddle.net/asger/5yvvgoda/14/
var zindex = 1;
$('.box_listener').click(function() {
$(this).css('z-index', zindex += 1);
$(this).siblings('.box_listener').fadeTo(3000, 0.5);
$(this).fadeTo(1, 1);
});
#backgroundbox {
position: absolute;
width: 400px;
height: 200px;
background-color: #E5E8E8;
z-index: -5;
border-style: solid;
border-width: 1px;
}
.box_listener {
position: absolute;
width: 120px;
height: 120px;
background-color: white;
border-style: solid;
border-width: 1px;
}
#redbox {
left: 270px;
top: 20px;
border-color: red;
z-index: 0;
}
#bluebox {
left: 230px;
top: 60px;
border-color: blue;
z-index: 0;
}
#greenbox {
left: 210px;
top: 77px;
border-color: lightgreen;
z-index: 0;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="backgroundbox">
<div class="box_listener" id="redbox">
</div>
<div class="box_listener" id="bluebox">
</div>
<div class="box_listener" id="greenbox">
</div>
</div>
Cheers and thanks!

A more bulletproof approach is to not use jQuery animations at all and instead use CSS transitions. The reason for this is twofold; CSS transitions can be automatically reversed and they can be GPU accelerated. It also means you don't have to artificially wait for the transition to complete before allowing user input.
To accomplish this, just set up two CSS classes; One that tells the elements you're going to animate how they should transition. The other class changes the values on the element, which causes the transition to happen. Then all jQuery needs to do is addClass() and removeClass() in order to cause the transitions to occur.
Below is an example of it in action. I've highlighted the most important aspects with comments.
$('.btn').on('click', function() {
// remove the active class from all buttons,
// this will reverse the transition
$('.btn').removeClass('active');
// apply it to only the current button clicked,
//this will start the transition
$(this).addClass('active');
});
.btn {
display: block;
width: 200px;
padding: 10px 20px;
margin-bottom: 5px;
background: cornflowerblue;
border: 0;
cursor: pointer;
/* set up a transition on any css transformations like
translating, scaling, rotating, etc. */
transition: transform 300ms ease-in-out;
}
/* when this class is added to the button it will scale it, but the
transition already on the button will make sure it happens slowly */
.active {
transform: scale(1.2);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<h2>Click the buttons</h2>
<button class="btn">First</button>
<button class="btn">Second</button>
<button class="btn">Third</button>

Position div relatively to icon position

THE FIDDLE
When a user hovers over a chevron icon next to a name on my website a div appears with options.
The Problem: The names can have different lengths and I would like to display the div below the chevron no matter how long the name is.
Here is my code:
HTML
<div class='settings'><i class='icon ion-chevron-down'></i></div>
<div class='settings-wrapper'>
<ul class='settings-bubble'>
<li>Bearbeiten</li>
<li>Löschen</li>
</ul>
</div>
SCSS
// The chevron icon
.settings {
display: inline;
position: relative;
padding: .1em 0 0 .5em;
opacity: 0; // I display the chevron on hover using jquery
}
// The options bubble
.settings-wrapper {
position: relative;
}
.settings-bubble {
position: absolute;
top: 0;
left: 0;
width: auto;
height: auto;
margin: 0;
padding: 0 .6em;
opacity: 0;
z-index: 9999;
li {
position: relative;
display: block;
a { float: left; }
}
}
I would be very thankful for any kind of help!!
If I change left: 0 to right: 0it looks like this:

When the icon is hovered, there is an event handler that displays the div. In that handler, you can inspect the x and y coordinates of the icon. When you display the div, you can modify its style to be positioned relative to the icon. For example:
var chevron = document.getElementById('chevron');
var popup = document.getElementById('popup');
chevron.addEventListener('mouseover', function(e) {
popup.classList.remove('hidden');
popup.style.left = e.target.offsetLeft + 'px';
});
chevron.addEventListener('mouseout', function(e) {
popup.classList.add('hidden');
});
.hidden {
display: none;
}
#popup {
position: absolute;
border: 1px solid #000;
}
<h1 contenteditable="true">Some long title <span id="chevron">></span></h1>
<div id="popup" class="hidden">popup</div>
I left the title editable so you can make it longer and see the popup change position.

In .settings-bubble change left: 0; into right: 0; and it will stick to the inner right side of the parent instead of the inner left.
EDIT: the trick is to add the div containing the bubble into the div containing the string of arbitrary length, and attach that bubble inside that div to the inner right-hand side, as illustrated by this fiddle.

Controlling JQuery Animate Function

I've been playing with "marginLeft: "100%"" but that only moves the div off the screen entirely. I want the div, onClick, to float:right against the edge of the right side of the screen.
JSFiddle:
https://jsfiddle.net/487r8qza/
HTML
<div id="footer">
<one id="one">
</one>
<two id="two">
</two>
<three id="three">
</three>
</div>
JavaScript
$("#footer").click(function(){
$("#one").animate({
marginLeft: "+=900px",
}, 2000 );
$("#two").animate({
marginLeft: "+=900px",
}, 800 );
$("#three").animate({
marginLeft: "+=900px",
}, 333 );
});
$("#three").click(function() {
$("#three").animate({
marginLeft: "100%"} , 1000
);
});
CSS
#footer {
margin: 0;
padding: 0;
float: left;
width: 100%;
max-width: 100%;
height: 115px;
background-color: #4a4a4a;
}
one {
margin: 0;
padding: 0;
float: left;
width: 300px;
background-color: #070707;
height: 115px;
margin-left: -900px;
}
one,two,three {
text-align: center;
color: white;
font-family: "Raleway", Arial, Helvetica, Trebuchet MS, Tahoma, sans-serif;
font-weight: bold;
font-size: 16px;
line-height: 115px;
}
one:hover {
background: black;
margin: 0;
padding: 0;
width: 300px;
height: 115px;
float: left;
transition: all 0.3s ease-out;
cursor: pointer;
}
two:hover {
background: black;
margin: 0;
padding: 0;
width: 300px;
height: 115px;
float: left;
transition: all 0.3s ease-out;
cursor: pointer;
}
three:hover {
background: black;
margin: 0;
padding: 0;
width: 300px;
height: 115px;
float: left;
transition: all 0.3s ease-out;
cursor: pointer;
}
two {
margin: 0;
padding: 0;
float: left;
width: 300px;
background-color: #1a1a1a;
height: 115px;
margin-left: -900px;
}
three {
margin: 0;
padding: 0;
float: left;
width: 300px;
background-color: #2c2c2c;
height: 115px;
margin-left: -900px;
}

Sorry if it took this long, something came up. Right, so I got it working. Hope this helps
JSFIDDLE
As for CSS, I kept it as simple as possible. The trick here is to make your DIVs display inline-block, so that at the very start, they are neatly stacked next to each other. You will also want to have them all be float right.
CSS:
.box-container{
width: 100%;
height: 115px;
position: relative;
overflow: hidden;
}
.box-item{
width: 300px;
height: 115px;
position: relative;
display: inline-block;
float: right;
cursor: pointer;
}
.b0{
background: #7888D9;
}
.b1{
background: #76D54E;
}
.b2{
background: #DF7B41;
}
Next, in your HTML, you need to give each DIVs the same classname, which will simplify the Jquery click event. Finally, we will also give our first DIV a classname of "current". This will control which DIV must move and which DIV must wait and stay idle as long as the one beside him hasn't moved. You'll understand soon enough.
HTML:
<div class="box-container">
<div class="box-item b0 current">
Box 1
</div>
<div class="box-item b1">
Box 2
</div>
<div class="box-item b2">
Box 3
</div>
</div>
Finally, as for the Jquery, this is where it gets a bit complicated, I'll try to explain the best I can. Bare in mind that math is not quite my forte. Since our DIVS all float right in the CSS, well, they will all be stacked to the right (of course). To counter that and position them to the left, we need to give each DIV a right position. This position will be some kind of offset. To get this number, we need to multiply the width of a DIV by the total number of DIVs. After that, we must subtract this number to the total width of our DIVs' container (basically the browser width).
As for the click event, we must first check if the DIV we clicked has our "current" classname. If it does, we move it, if not, we don't. The easy part is moving them. By resetting a DIV's right value to 0, each one will slide accordingly to the right with our animate event. Once this is done, we switch the "current" classname to the next DIV. We then increment a counter. This will help to see if all DIVs has been moved.
Once all DIVs have been moved to the right, there is an IF statement that will check our counter and see if it is greater than our total number of DIVs. If it is, the sliding motion is inverted and all DIV's will return to the left. In the same manner, if the clicked element is not the current DIV, it will not move. if it is, it will move back to the left. When all DIV's have been move back in default position, ou counter is reset and our "current" classname is reassigned to the very first DIV.
The resize function is not optimal, but it deals with any responsive issue you could face. It will reset all DIVs to the left and recalculate the offset, so that each DIV never slide offscreen. Needs a little work, but it's better than nothing for now.
JQUERY:
var $boxWidth;
var $screenWidth;
var $offsetRight;
var $count = 0;
$(function () {
$boxWidth = $('.box-item').width();
$screenWidth = $('.box-container').width();
$offsetRight = $screenWidth - ($boxWidth*$('.box-item').length);
$('.box-item').css('right',$offsetRight);
$('.box-item').click(function(event) {
if($(this).hasClass('current')){
if($count < $('.box-item').length){
$(this).animate({
right: "0px",
}, 2000, function(){
$count++;
$(this).removeClass('current');
if($count < $('.box-item').length){
$(this).next().addClass('current');
}
else{
$(this).addClass('current');
}
});
}
else{
$(this).animate({
right: $offsetRight,
}, 2000, function(){
$count++;
$(this).removeClass('current');
console.log($count);
if($count < ($('.box-item').length*2)){
$(this).prev().addClass('current');
}
else{
$(this).addClass('current');
$count = 0;
}
});
}
}
});
window.onresize = myResize;
myResize();
});
function myResize(){
$screenWidth = $('.box-container').width();
$offsetRight = $screenWidth - ($boxWidth*$('.box-item').length);
$('.box-item').each(function(){
$(this).css('right',$offsetRight);
});
$('.box-item').eq(0).addClass('current');
$count = 0;
}

Partially exposed div to slide up when image is clicked

this might be a weird one but what I am trying to do is make a div slide up from the bottom of the screen when someone clicks an image. To paint this clearer, imagine the Windows desktop, and if you click the start menu image/icon, instead of the start menu popping up from the button, the entire start menu bar would slide up exposing the entire div.
What I'm doing now (forgive me as I have just learned JS and jQuery from codecademy) is using the slideUp function. However, this is causing the div to slide down out of sight instead of up, exposing the entire div. The goal is that when you click the button the div slides up, and if you click the button again (or anywhere outside the div) it'll slide back down leaving the top 60px exposed like before.
Here's my JS/jQuery code:
$('#start').click(function() {
$('#nav').slideUp('slow');
});
My HTML
<div id="nav" class="nav">
<img id="start" src="img/btn_start.png">
</div>
My CSS
* {
padding: 0px;
margin: 0px;
}
body {
width: 100%;
font-family: Helvetica;
}
.nav {
width: 100%;
min-width: 100%;
height: 500px;
background: #000;
color: #fff;
position: absolute;
bottom: -440px;
text-align: center;
padding: 5px;
box-sizing: border-box;
overflow: auto;
}
.nav ul li {
display: inline;
}
.nav li {
padding: 20px;
margin-top: 80px;
position: relative;
top: 50%;
transform: translateY(-50%);
}
#start {
float: left;
}
Thanks, and I hope this isn't too ridiculous.

Instead of slideUp you should use
$('#start').click(function() {
$('#nav').animate({bottom: "0px"}, 1200);
});
...which will smoothly animate from the current location until the bottom is at 0px (i.e. aligned with the bottom of the containing element).
For even smoother results, checkout velocity.js (http://julian.com/research/velocity/), which does even smoother animation by synchronising with browser frame updates.
JsFiddle here: http://jsfiddle.net/11r46jnm/
You can also do this with CSS transitions instead. For stuff like this I like to hook my CSS into data attributes on the HTML:
<div id="nav" class="nav" data-nav-state="collapsed">
<img id="start" src="img/btn_start.png">
</div>
...use javascript to change the attributes...
$('#start').click(function() {
//toggle the nav element between two states
var currentState = $('#nav').attr("data-nav-state");
var newState = "collapsed";
if ( currentState === "collapsed" ) {
newState = "expanded";
}
$('#nav').attr("data-nav-state", newState);
});
Finally we use CSS to set the positions of the two states, and to ensure that transition is smooth. CSS transitions have much better performance than jQuery, so I recommend using them if you can:
#nav[data-nav-state=collapsed] {
bottom: -440px;
}
#nav[data-nav-state=expanded] {
bottom: 0px;
}
#nav {
transition: bottom 1.2s ease;
}
See this jsFiddle for a demo: http://jsfiddle.net/Lv2saepy/1/

Make element fit it's entire parent

I am creating an advanced administration panel, and I'm playing the part of editing items, I like it when I clicked to edit an item he would fill the entire space of its parent, however I have no idea how to make the element back to its original position with animation, any idea how to do this? I tried this so far:
Here is a pen: http://codepen.io/anon/pen/WvGONp
HTML
<div id="container">
<div class="single-item">
<div class="title">home</div>
<a class="edit" href="#"></a>
</div>
<div class="single-item">
<div class="title">Gallery</div>
<a class="edit" href="#"></a>
</div>
<div class="single-item">
<div class="title">Contact</div>
<a class="edit" href="#"></a>
</div>
</div>
SCSS
* {
margin: 0;
padding: 0;
border: 0;
box-sizing: border-box;
}
html, body, #container {
height: 100%;
min-height: 100%;
}
#container{
& > .single-item{
position: relative;
background-color: #d9d9d9;
border-radius: 2px;
margin-bottom: 15px;
padding: 15px;
z-index: 1;
& > .edit{
display: block;
position: absolute;
background-color: #000;
top: 15px;
right: 15px;
width: 20px;
height: 20px;
}
&.active{
z-index: 2;
}
}
}
Javascript
$("#container").on("click", ".edit", function(e){
e.preventDefault();
var el = $(this);
var elParent = el.closest(".single-item");
var curElTop = elParent.position().top;
var curElLeft = elParent.position().left;
elParent.toggleClass("active", function(){
elParent.css({
position: "absolute",
top: curElTop,
left: curElLeft
}).animate({
top: 0,
right: 0,
bottom: 0,
left: 0
});
});
});

CSS3 transition will help you create smooth animation for full screen width & height.
But if still for some reason, you want to do it in jQuery, here is the solution :
While clicking second time on the "edit" button, you just have to say :
$("<element_reference>").removeAttr("style");
It will remove the styles what was applied previously, get back the element to its normal view.
Or you can also change the position from "absolute" to "static", both will give you the same result. Refer this question for animating position using jQuery.
Hope it helps.

I've discovered the easiest way to do things like this is:
Put CSS transition properties on the item.
Make a new class that you add onto the item when it's clicked, to make it fullscreen. Take off the class when the item is closed.
CSS transitions tend to be faster and smoother.