I am showing a set of products via shortcode in WordPress. The display has an image and button.
Problem: Only the photo contains the link to single product page. The associated button does not have the link to the single product page.
This is the current code:
<div class="display-products">
<div class="wpb_wrapper">
<div class="displayProduct-shortcode displayProduct-Container">
<div class="product_grid dp-section dp-group woocommerce" id="displayProduct">
<div class="dp_product_item dp-col dp-col_1_of_6 firstcol">
<div class="dp_images">
<a class="dp-product-image" title="Custom Made Wedding Cabinet" href="yahoo.com">
<div class="he-wrap tpl1">
<div class="dp-img-wrapper"> <img width="192" height="264" alt="#" class="attachment-display_product_thumbnail size-display_product_thumbnail wp-post-image" src="img_src"> </div>
</div> <span data-id="696" class="dpquickview dp_quickview_button"><img src="img_src"></span> </a>
</div>
<div class="dp-product-information clearfix">
<h2 class="product-name">
<a title="Custom Made Wedding Cabinet" href="#">Custom Made Wedding Cabinet</a>
</h2>
<div class="dp-stock"></div>
<div class="dp-grid-button"> <a class="single_add_to_cart_button button alt db_customButton" href="#">READ MORE</a> </div>
<div style="clear: both;"></div>
</div>
</div>
</div>
</div>
</div>
</div>
Desired Output: I want to somehow iterate over each .single_add_to_cart_button and copy the link of every product-name to each READ MORE button
This is my current jquery code:
j('.display-products .displayProduct-shortcode .dp-product-information .dp-grid-button .single_add_to_cart_button').each(function() {
var getProductLink = j('.display-products .displayProduct-shortcode .dp-product-information .product-name > a').attr('href');
j(this).attr('href', getProductLink);
});
Set the href attribute value using the elements context. Use closest() to traverse up to dp-product-information element then find the desired anchor element the read its attribute and set the value.
Use
j('.display-products .displayProduct-shortcode .dp-product-information .dp-grid-button .single_add_to_cart_button').attr('href', function(){
return j(this).closest('.dp-product-information').find('.product-name>a').attr('href');
});
$(function() {
$('.dp-product-information .dp-grid-button .single_add_to_cart_button').attr('href', function() {
return $(this).closest('.dp-product-information').find('.product-name > a').attr('href');
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="dp-product-information clearfix">
<h2 class="product-name">
<a title="Custom Made Wedding Cabinet" href="#Test">Custom Made Wedding Cabinet</a>
</h2>
<div class="dp-stock"></div>
<div class="dp-grid-button">
<a class="single_add_to_cart_button button alt db_customButton" href="#">READ MORE</a>
</div>
<div style="clear: both;"></div>
</div>
Instead of assigning value for the different buttons with the links I would like to suggest you to use a common class (if you can) then trigger the click event for them:
$('.selector').on('click',function(){
$('.a-selector').trigger('click');
});
Related
I have started some blogs using Weebly now I want to do several changes to the blog UI, everything went well until I wanted to do this. I wanted to get the image path from the image inside blog-content and set it on the blog-post-image. In my head, this jquery looks logical, but somewhere error lays.
Few things to care about, I should use each because there are many of the blog posts and I cannot use ids because of the same reason, cannot use the same id multiple times.
HTML:
$('.blog-post-image').each(function() {
var $me = $(this);
var blogPostImage = $me.siblings('.blog-content').children('img').attr('src');
$me.attr('src', blogPostImage);
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="blog-post-746510653886732592" class="blog-post">
<div class="blog-header">
<div class="blog-post-container">
<h2 class="blog-title">
</h2>
<p class="blog-date">
<span class="date-text">
15/6/2021
</span>
</p>
<div>
<img class="blog-post-image" />
</div>
</div>
</div>
<div class="blog-content">
<div>
<div class="wsite-image wsite-image-border-none " style="padding-top:10px;padding-bottom:10px;margin-left:0;margin-right:0;text-align:center">
<a>
<img src="/uploads/7/7/9/0/77909082/820610853.jpg" alt="Picture" style="width:100%;max-width:1100px">
</a>
<div style="display:block;font-size:90%">
</div>
</div>
</div>
.blog-post-image doesn't have any siblings. Siblings are immediate children of the same parent element, but there are no other elements in the div containing <img class="blog-post-image" />.
You need to go up to the .blog-header to get its sibling.
Also, instead of using .each(), you can use a function in .attr(). It automatically loops, and assigns the return value to the attribute.
$('.blog-post-image').attr('src', function() {
return $(this).closest('.blog-header').siblings('.blog-content').find('img').attr('src');
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="blog-post-746510653886732592" class="blog-post">
<div class="blog-header">
<div class="blog-post-container">
<h2 class="blog-title">
</h2>
<p class="blog-date">
<span class="date-text">
15/6/2021
</span>
</p>
<div>
<img class="blog-post-image" />
</div>
</div>
</div>
<div class="blog-content">
<div>
<div class="wsite-image wsite-image-border-none " style="padding-top:10px;padding-bottom:10px;margin-left:0;margin-right:0;text-align:center">
<a>
<img src="/uploads/7/7/9/0/77909082/820610853.jpg" alt="Picture" style="width:100%;max-width:1100px">
</a>
<div style="display:block;font-size:90%">
</div>
</div>
</div>
Two things:
1.) .blog-content is not a sibling of .blog-post-image
2.) .children() only looks one level deep to find the element you are looking for.
What you need to do is traverse upwards to find a sibling of .blog-content and then use the .find() function to do a deep search of the given DOM node to find what you're looking for.
$('.blog-post-image').each(function() {
var me = $(this);
var blogPostImage = me.parent().parent().parent().siblings('.blog-content').find('img').attr('src');
me.attr('src', blogPostImage);
});
<head>
<script src="https://code.jquery.com/jquery-3.6.0.min.js"></script>
</head>
<body>
<div id="blog-post-746510653886732592" class="blog-post">
<div class="blog-header">
<div class="blog-post-container">
<h2 class="blog-title">
</h2>
<p class="blog-date">
<span class="date-text">15/6/2021</span>
</p>
<div>
<img class="blog-post-image" />
</div>
</div>
</div>
<div class="blog-content">
<div>
<div class="wsite-image wsite-image-border-none " style="padding-top:10px;padding-bottom:10px;margin-left:0;margin-right:0;text-align:center">
<a>
<img src="/uploads/7/7/9/0/77909082/820610853.jpg" alt="Picture" style="width:100%;max-width:1100px">
</a>
<div style="display:block;font-size:90%">
</div>
</div>
</div>
</div>
</div>
</body>
I have one tabular structure using div, where am showing data. If i will click on one row then am hiding that row and showing some content in place of that. It is similar like google inbox concept, where on click of on row it will show the mail content there only.
But in inbox on click on another email it first hiding the already expanded email content and then showing the other one. In my case am able to show the content on click of the row but unable to hide already shown content div.
This is my code, I have used ng-show and ng-hide along with ng-click.
<div class="surveyList" ng-repeat="survey in allSurveys">
<span class="checkbox" ng-hide="showDetails"></span>
<div class="toogleSurvey" ng-mouseover="hoverIn()" ng-mouseleave="hoverOut()" ng-click="showDetails=!showDetails" ng-hide="showDetails">
<div>{{survey.Name}}</div>
<div>{{survey.Type}}</div>
<div class="hidden-xs">{{survey.SurveyReference}}</div>
<div class="hidden-xs">{{survey.CreatedDate}}</div>
<div class="hidden-xs SurveyLastChild">{{survey.Status}}</div>
<div class="hidden-xs surveyListTool" ng-show="hoverEdit">
<a class="editSurvey"><img src="images/edit_normal.png" /></a>
<a class="deleteSurvey"><img src="images/delete_normal.png" /></a>
<a class="exportSurvey"><img src="images/export_normal.png" /></a>
<a class="menuSurvey"><img src="images/menu_normal.png" /></a>
</div>
</div>
<div class="surveyDetailsBox" ng-show="showDetails" ng-click="showDetails=!showDetails">
<div class="surveyDetailHead">
<p class="surveyTitle">{{survey.Name}}</p>
<div class="surveyDetailHeadTool">
<a class="editSurvey"><img src="images/edit_normal.png" /></a>
<a class="deleteSurvey"><img src="images/delete_normal.png" /></a>
<a class="exportSurvey"><img src="images/export_normal.png" /></a>
<a class="menuSurvey"><img src="images/menu_normal.png" /></a>
</div>
</div>
</div>
</div>
On click on div.toogleSurvey am showing div.surveyDetailsBox and it goes reverse also.
Check
var app = angular.module("myapp", []);
app.controller("myctrl", ['$scope', function($scope) {
}]);
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="myapp">
<div ng-controller="myctrl">
<div>
<div class="toogleSurvey" ng-mouseover="hoverIn()" ng-mouseleave="hoverOut()" ng-click="showDetails=!showDetails" ng-hide="showDetails">
Click on toogleSurvey
</div>
<div class="surveyDetailsBox" ng-show="showDetails" ng-click="showDetails=!showDetails">
Click on surveyDetailsBox
</div>
</div>
</div>
Try doing this way.
use ng-click and call a controller function passing the survey object like
<div class="toogleSurvey" ng-click="showSurveyDetailsBox(survey)">
and in your controller
$scope.showSurveyDetailsBox = function(surveyobj)
{
$scope.surveyobjectForDetailsBox = surveyobj;
$scope.showSurveyDetails = true;
}
i want to get the attr href of an above link beside the one i press wich is the last link from productinfo div class. I tryed with closest but it gets me the same link i press and i want the above one. The link i want to store in produs_href is the link from first href under productinfo class. Here is my code:
<div class="col-sm-4 produse"><!--PRODUS-->
<div class="product-image-wrapper">
<div class="single-products">
<div class="productinfo text-center">
<img src="/images/produse/'.$recomand['ID_Produs'].'/'.$recomand['Poza'].'" alt="" />
<h2 style="text-decoration: line-through;">'.$recomand['Pret'].' lei </h2><h2>'.$recomand['Pret_Nou'].' lei </h2>
<p>'.$recomand['Nume_Prod'].' '.$recomand['Gramaj'].' '.$tip.'</p>
<i class="fa fa-shopping-cart"></i>Adaugă în coș
</div>
</div>
</div>
</div>
jquery
<script>
$(".cos").click(function(e){
e.preventDefault();
var href = $(this).attr('href');
var produs_href = $(this).closest('a').attr('href');
$.getJSON(href, function(data) {
$.each(data, function(key, val) {
$("#cnt").empty();
$("#test").append('<li>' + val.nume + '</li>')
$("#cnt").append('' + val.cnt +'')
});
});
$(\'#detalii_prod\').modal('show');
alert(produs_href);
});
</script>
Use prev. This method gets the immediately preceding sibling.
$(this).prev().attr('href');
EDIT
From your comments, the code that would do the trick is
$(this).closest('.productinfo').find('a:first').attr('href');
You can use the .prev
var link = $(this).prev().attr('href');
and now you can use link.
you can use like this
$(this).prev("a").attr("href");
and more help:
Get the href value of a previous HTML anchoer, <a>, using jQuery
$(".cos").click(function(e){
e.preventDefault();
var text = $(this).parent().find('a:first').attr('href');
alert(text);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="col-sm-4 produse">
<!--PRODUS-->
<div class="product-image-wrapper">
<div class="single-products">
<div class="productinfo text-center"> <img src="img/Penguins.jpg" height="50" width="50" alt="" />
<h2 style="text-decoration: line-through;">Hello there</h2>
<h2>Anto</h2>
<a href="link produs">
<p>Angeline</p>
</a> <i class="fa fa-shopping-cart"></i>Test </div>
</div>
</div>
</div>
try this
$(this).parent().find('a:first').attr('href');
Try with .eq() method.
$(this).parent().find('a').eq(0).attr('href');
Hope this helps you...
When storing DOM elements in a javascript variable prior to appending them to the actual DOM is there a way with jQuery to select elements inside the variable?
For example,
I have a list of tweets on my page. Every time I click a refresh button I append a new tweet to the list below.
I add the new tweet like follows:
new tweet
<li class="tweet normal-tweet" data-user-name="Dorothy">
<div class="image">
<img height="48" width="48" src="http://twitter.com/api/users/profile_image?screen_name=Dorothy" alt="" />
</div>
<div class="content">
<div class="user">
<a class="user-name" href="http://twitter.com/Dorothy" title="Dorothy">Dorothy</a>
<div class="full-name"></div>
</div>
<div class="text">Once in a lullaby</div>
<div class="time-stamp" data-time="1322631934000">1322631934000</div>
</div>
</li>
Inside each tweet on the page, not the new tweet yet, I use jQuery to append some elements.
I have:
var actionsMarkup =
"<div class='actions'>
<span class='favorite'>Favorite</span>
<span class='retweet'>Retweet</span>
<span class='reply'>Reply</span>
</div>";
and I append it to the element with the .content class
$(actionsMarkup).appendTo('#tweets .tweet .content');
Now, when I make a new tweet I do the following:
$(document).on('click', '.refresh', function() {
newTweet = $(<new tweet code from above>);
actionsMark = $(actionsMarkup);
$(newTweet.appendTo('#tweets');
I need to be able to append the actionsMark contents to the div with class .content. However, I can't just reapply my prior statement of
$(actionsMarkup).appendTo('#tweets .tweet .content');
because that puts the markup on all .content divs again, even if it is already there.
Is there a way for me to use selectors to access the DOM nodes in my newTweet variable before I append it to the document object?
I am thinking something like
$(actionsMarkup).appendTo( newTweet, '.content');
If there is no way with selectors to do this then what are some other quick ways?
List of Tweets and Tweet container
<ul id="tweets" class="normal-tweet show-promoted-tweets">
<li class="tweet promoted-tweet" data-user-name="Dorothy">
<div class="image">
<img height="48" width="48" src="http://twitter.com/api/users/profile_image?screen_name=Dorothy" alt="" />
</div>
<div class="content">
<div class="user">
<a class="user-name" href="http://twitter.com/Dorothy" title="Dorothy">Dorothy</a>
<div class="full-name">Dorothy</div>
</div>
<div class="text">Somewhere over the rainbow</div>
<div class="time-stamp" data-time="1322631934000">3 minutes ago</div>
</div>
</li>
<li class="tweet promoted-tweet" data-user-name="lion">
<div class="image">
<img height="48" width="48" src="http://twitter.com/api/users/profile_image?screen_name=lion" alt="" />
</div>
<div class="content">
<div class="user">
<a class="user-name" href="http://twitter.com/lion" title="lion">lion</a>
<div class="full-name">Lion</div>
</div>
<div class="text">Way up high,</div>
<div class="time-stamp" data-time="1322631934000">17 minutes ago</div>
</div>
</li>
<li class="tweet normal-tweet" data-user-name="scarecrow">
<div class="image">
<img height="48" width="48" src="http://twitter.com/api/users/profile_image?screen_name=scarecrow" alt="" />
</div>
<div class="content">
<div class="user">
<a class="user-name" href="http://twitter.com/scarecrow" title="scarecrow">scarecrow</a>
<div class="full-name">Scarecrow</div>
</div>
<div class="text">And the dreams that you dreamed of,</div>
<div class="time-stamp" data-time="1322631934000">32 minutes ago</div>
</div>
</li>
</ul>
You can use .last(), to select the last element after you append your new tweet, like below:
$(document).on('click', '.refresh', function() {
newTweet = $(<new tweet code from above>);
$(newTweet).appendTo('#tweets');
var actionsMarkup =
"<div class='actions'>
<span class='favorite'>Favorite</span>
<span class='retweet'>Retweet</span>
<span class='reply'>Reply</span>
</div>";
$("#tweets .tweet").last().find(".content").append(actionsMarkup);
});
if you insist to use appendTo(), you can try using :last-child:
$(actionsMarkup).appendTo('#tweets .tweet:last-child .content');
I was looking to see if you can do the same thing, found this question but the existing answer is not useful in my case as i would like to alter the element before adding.
You can create a new dom element in a variable with jQuery and do operations on it as if it is already in the dom before appending it.
Example:
var newTweet = $('<div></div>');
newTweet.addClass('tweet');
newTweet.append('<span class="username"></span>');
newTweet.find('span.username').html('John Doe');
$('body').append(newTweet);
the following will be appended to the body:
<div class="tweet"><span class="username">John Doe</span></div>
Very handy if you are building a reusable interface element (like a dialogue box) with multiple options.
I am new to jQuery and am trying to write a script that will run through a menu list and display the correct background image based on the menu item. The menu list is going to be randomly populated so a script is necessary to load the correct image.
The problem is that the attribute where I am able to see which item the menu belongs to is not on the list item itself but on a div contained inside the list item. My question is is it possible to select a child element of the already selected element ?
E.g (the menuli a segment)
$(document).ready( function() {
$(menuli).each( function(index) {
$itemnumber = $(menuli a).attr("href");
switch($itemnumber) {
case 1:
$(this).css("background-image", "image01.jpg");
break;
}
});
});
This is more or less the script I am trying to get, where each list item is iterated through and depending on the href of the link inside the list item a background image is set to that list item.
EDIT
Here is my html:
<div id="divMenuSportGSXSports">
<div class="VociMenuSportG">
<div class="ImgSport" style="background-image:url(../ImgSport.ashx?IDBook=53&IDSport=468&Antepost=0&)">
<img src="buttons_void.png">
</div>
<div class="NomeSport">
<a id="h_w_PC_cSport_repSport_ctl00_lnkSport" href="/Sport/Groups.aspx?IDSport=468&Antepost=0">
<span title="SOCCER">SOCCER</span>
</a>
</div>
</div>
<div class="VociMenuSportG">
<div class="ImgSport" style="background-image:url(../ImgSport.ashx?IDBook=53&IDSport=520&Antepost=0&)">
<img src="buttons_void.png">
</div>
<div class="NomeSport">
<a id="h_w_PC_cSport_repSport_ctl01_lnkSport" href="/Sport/Groups.aspx?IDSport=520&Antepost=0">
<span title="BASEBALL">BASEBALL</span>
</a>
</div>
</div>
<div class="VociMenuSportG">
<div class="ImgSport" style="background-image:url(../ImgSport.ashx?IDBook=53&IDSport=544&Antepost=0&)">
<img src="buttons_void.png">
</div>
<div class="NomeSport">
<a id="h_w_PC_cSport_repSport_ctl02_lnkSport" href="/Sport/Groups.aspx?IDSport=544&Antepost=0">
<span title="CRICKET">CRICKET</span>
</a>
</div>
</div>
<div class="VociMenuSportG">
<div class="ImgSport" style="background-image:url(../ImgSport.ashx?IDBook=53&IDSport=525&Antepost=0&Tema=Supabets)">
<img src="buttons_void.png">
</div>
<div class="NomeSport">
<a id="h_w_PC_cSport_repSport_ctl03_lnkSport" href="/Sport/Groups.aspx?IDSport=525&Antepost=0">
<span title="BASKETBALL">BASKETBALL</span>
</a>
</div>
</div>
<div class="VociMenuSportG">
<div class="ImgSport" style="background-image:url(../ImgSport.ashx?IDBook=53&IDSport=534&Antepost=0&)">
<img src="buttons_void.png">
</div>
<div class="NomeSport">
<a id="h_w_PC_cSport_repSport_ctl04_lnkSport" href="/Sport/Groups.aspx?IDSport=534&Antepost=0">
<span title="ICE HOCKEY">ICE HOCKEY</span>
</a>
</div>
</div>
<div class="VociMenuSportG">
<div class="ImgSport" style="background-image:url(../ImgSport.ashx?IDBook=53&IDSport=523&Antepost=0&)">
<img src="buttons_void.png">
</div>
<div class="NomeSport">
<a id="h_w_PC_cSport_repSport_ctl05_lnkSport" href="/Sport/Groups.aspx?IDSport=523&Antepost=0">
<span title="TENNIS">TENNIS</span>
</a>
</div>
</div>
</div>
Yes you can, use find
var parentElement = $('#someElement');
var childElement = parentElement.find('.child'); //where .child should be your child selector
Where as example code is not clear, I just gave answer to your question.
try to change this:
$(this).css("background-image", "image01.jpg");
to this:
$(this).children("div").css("background-image", "image01.jpg");
If you want to target the direct child of the element, better to use children() than find()
Please refer to this: What is fastest children() or find() in jQuery?