Generating alphanumerical sequence javascript - javascript

I have written a terribly slow function for generating codes that go from AA000 to ZZ999 (in sequence not random). And I have concluded that there has to be a better way to do this. Any suggestions on how to make this faster?
function generateAlphaNumeric(){
theAlphabet = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'];
resultArrray = [];
resultArrray2 = [];
teller = 0;
for(i in theAlphabet){
for(x in theAlphabet){
resultArrray[teller] = theAlphabet[i] + theAlphabet[x];
teller++;
}
}
teller = 0;
for(x = 0; x<10; x++){
for(y = 0; y<10; y++){
for(z = 0; z<10; z++){
resultArrray2[teller] = x.toString() + y.toString() +z.toString();
teller++;
}
}
}
teller = 0;
finalArray = [];
for(index in resultArrray){
for(i in resultArrray2){
finalArray[teller] = resultArrray[index] + resultArrray2[i];
teller++;
}
}
//console.log(resultArrray);
//console.log(resultArrray2);
console.log(finalArray);
}

This should be considerably faster:
var theAlphabet = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O',
'P','Q','R','S','T','U','V','W','X','Y','Z'];
var theDigits = ['0','1','2','3','4','5','6','7','8','9'];
var result = [];
for (var i=0 ; i<26 ; i++) {
var prefix1 = theAlphabet[i];
for (var j=0 ; j<26; j++) {
var prefix2 = prefix1 + theAlphabet[j];
for(var x = 0; x<10; x++){
var prefix3 = prefix2 + theDigits[x];
for(var y = 0; y<10; y++){
var prefix4 = prefix3 + theDigits[y];
for(var z = 0; z<10; z++){
result.push(prefix4 + theDigits[z]);
}
}
}
}
}
Key ideas:
Generate everything in one run
Reuse partial strings as much as possible
However, I don't see how such an exhaustive list is useful. There are exactly 26 * 26 * 1000 different codes. So instead of maintaining an array with all codes it could make sense to simply build a function that generates the specific code requested:
function getCode(number) {
var z = number % 10;
number -= z; number /= 10;
var y = number % 10;
number -= y; number /= 10;
var x = number % 10;
number -= x; number /= 10;
var a = number % 26;
number -= a; number /= 26;
var b = number;
return theAlphabet[a] + theAlphabet[b] + theDigits[x] + theDigits[y] + theDigits[z];
}

function generate() {
var str = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ',
array = [];
for (var i = 0; i < str.length; i++) {
for (var j = 0; j < str.length; j++) {
for (var k = 0; k < 10; k++) {
for (var l = 0; l < 10; l++) {
for (var m = 0; m < 10; m++) {
ar.push(str[i] + str[j] + k + l + m);
}
}
}
}
}
return array;
}
console.log(generate());
This will generate a array of all the codes .. U can save that array and parse it easily using a loop.

Try this solution:
function generate() {
var str = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ',
ar = [];
for (var index1 = 0; index1 < str.length; index1++) {
for (var index2 = 0; index2 < str.length; index2++) {
for (var index3 = 0; index3 < 1000; index3++) {
ar.push(str[index1] + str[index2] + ('000' + index3).slice(-3));
}
}
}
return ar;
}
console.log(generate());

I didn't test it, but it should do the trick
function generateAlphaNumeric()
{
var theAlphabet = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'];
var result = [];
// Will take a random letter inside theAlphabet
// Math.floor(Math.random() * theAlphabet.length) will generate a random number between 0 and 25
var i = 0;
while(i<2)
{
var letter = theAlphabet[Math.floor(Math.random() * theAlphabet.length)];
result.push(letter);
i++;
}
i = 0;
while(i<3)
{
// Adds a random number between 0 and 9
result.push(Math.floor(Math.random() * 10));
i++;
}
return result;
}

From a computational complexity perspective, unfortunately this is the best you can do. From a sheer number of instructions perspective, you can do a bit better (as others have pointed out), but it's still going to be the same order of complexity (remember that constants / multipliers are irrelevant in big-O complexity). You can also optimize the storage a bit.
Think about it. Your array needs to have 26 * 26 * 10 * 10 * 10 members. This means you need to at least touch that many elements.
Let N = number of elements in the alphabet
Let M = number of elements in your digit queue
Best Case Order Complexity = O(N * N * M * M * M) (if all you had to do was assign values)
Best case storage complexity = same as above (you have to store all the codes)
Right now you are using the following operations:
for(i in theAlphabet){ // *O(N)*
for(x in theAlphabet){ // *O(N)*
resultArrray[teller] = theAlphabet[i] + theAlphabet[x];// *(O(1))*
}
}
for(x = 0; x<10; x++){ // O(M)
for(y = 0; y<10; y++){ // O(M)
for(z = 0; z<10; z++){ // O(M)
resultArrray2[teller] = x.toString() + y.toString() +z.toString(); // O(1) (technically this is O(length of x + y + z)
teller++;
}
}
}
for(index in resultArrray){ // O(N * N)
for(i in resultArrray2){ // O(M * M * M(
finalArray[teller] = resultArrray[index] + resultArrray2[i]; //O(1)
teller++;
}
}
So at the end of the day your order complexity is O(N * N * M * M * M), which is the best you can do.
The bigger question is why you want to generate all the codes at all. If all you want is to create a unique code per order number or something, you can make a state machine like:
function getNextCode(previousCode) {
// in here, just increment the previous code
}
If all you want is a random identifier, consider using a hash of the timestamp + something about the request instead.
If you don't care about uniqueness, you can always just generate a random code.
All of the above are O(1).

Related

How to write a number pattern generator program in JavaScript?

I have to make a pattern like this:
=========1=========
=======22122=======
====33322122333====
4444333221223334444
I have not found the logic yet. I tried to code it, but the output is different.
Here is the output of my working code snippet:
----1-----
---123----
--12345---
-1234567--
123456789-
function nomor3(input){
let temp = '';
for (let x = 1; x <= input; x++){
for (let y = input ; y > x; y--){
temp += "-";
}
for (let z = 1; z <= (x * 2) - 1; z++){
temp += z;
}
for (let k = input; k >= x; k--){
temp += "-";
}
temp += '\n';
}
return temp
}
console.log(nomor3(5));
The logic for each level - say 4th level - it begins with the digit of the level to the count of the digit, then one less and so on. So line 4 looks like 4444-333-22-1 and backwards (dashes added for demonstration).
So here we build each line like that, starting from the biggest so we know its length so we can center other lines with dashes. We use arrays here and reversing them because it's easier than strings. But lastly we join so we have a string.
function pyramide(level) {
var len = null;
var result = [];
while (level > 0) {
var arr = [];
for (var i = level; i > 1; i--) {
for (var repeat = 0; repeat < i; repeat++) {
arr.push(i)
}
}
var str_level = arr.join("") + "1" + arr.reverse().join("");
if (len === null) {
len = str_level.length;
}
while (str_level.length < len) {
str_level = "-" + str_level + "-";
}
result.push(str_level);
level--;
}
return result.reverse().join("\n");
}
console.log(pyramide(5))

Js Multi-dimensional Array setting value oddly

I've made a multidimensional array with Array constructor and Array.fill method.
I cannot figure out where the problem is, but this code doesn't work as I want.
function loadChunk(){
for(var x = 0; x< 3; x++){
for(var y= 0; y < 3; y++){
console.log(x+","+y);
console.log((world[x][y]).loaded);
if(!(world[x][y]).loaded){
world[x][y].loaded=true;
}
}
}
}
function createWorld(w, d){
var worldz = new Array(d * 2 + 1);
var world = new Array(w * 2 + 1);
world.fill(worldz);
for(var x = 0; x< w * 2+ 1; x++){
for(var z = 0; z < d * 2 + 1; z++){
world[x][z]= { loaded: false };
}
}
return world;
}
var world = createWorld(1, 1);
Start();
function Start(){
loadChunk();
}
You can see what is happening with console.
With my view, no true should be written on console.
The problem is, if I edit world[0][n],then world[1 or more][n] changes too.
Replace your createWorld function with this:
function createWorld(w, d){
var world = new Array(w * 2 + 1);
for(var x = 0; x< w * 2+ 1; x++){
// each item of the array requires a new instance
// you should not use fill method in this situation
world[x]=new Array(d * 2 + 1);
for(var z = 0; z < d * 2 + 1; z++){
world[x][z]= { loaded: false };
}
}
return world;
}
function loadChunk() {
for (var x = 0; x < 3; x++) {
for (var y = 0; y < 3; y++) {
console.log(x + "," + y, (world[x][y]).loaded);
if (!(world[x][y]).loaded) {
world[x][y].loaded = true;
}
}
}
}
function createWorld(w, d) {
var world = [];
for (var x = 0; x < w * 2 + 1; x++) {
world[x] = [];
for (var z = 0; z < d * 2 + 1; z++) {
world[x][z] = {loaded: false};
}
}
return world;
}
var world = createWorld(1, 1);
Start();
function Start() {
loadChunk();
}
The problem that you expirience is that you fill "rows" of world with the same array, so world[0] === world[1] && world[1] === world[2] because array variable worldz is holding a reference
The best way to learn your problem is doing next thing:
function createWorld(w, d){
var worldz = new Array(d * 2 + 1);
var world = new Array(w * 2 + 1);
world.fill(worldz);
for(var x = 0; x< w * 2+ 1; x++){
for(var z = 0; z < d * 2 + 1; z++){
world[x][z]= { loaded: false };
debugger;
}
}
return world;
}
And inspecting in chrome debugger what happens with world variable on a first step
The reason why a change of world[0][0] also changes world[1][0] and world[2][0] (same for other indecees of worldz) is that world.fill(worldz) makes all elements of world the same identical object (Array) worldz.
To avoid this every element of world should be a new Array like eg:
for(n=0,max=world.length;n<max;n++) {world[n] = new Array(d * 2 + 1);}

Create Javascript array with Javascript for loop

I have a series of information that I am looking to cut down to size by looping the information. Here is the original code that is working:
$('#M1s1').css({'visibility': M1s1v});
$('#M1s2').css({'visibility': M1s2v});
$('#M1s3').css({'visibility': M1s3v});
$('#M1s4').css({'visibility': M1s4v});
$('#M1s5').css({'visibility': M1s5v});
$('#M1s6').css({'visibility': M1s6v});
$('#M1s7').css({'visibility': M1s7v});
$('#M2s1').css({'visibility': M2s1v});
$('#M2s2').css({'visibility': M2s2v});
$('#M2s3').css({'visibility': M2s3v});
$('#M2s4').css({'visibility': M2s4v});
$('#M2s5').css({'visibility': M2s5v});
$('#M2s6').css({'visibility': M2s6v});
$('#M2s7').css({'visibility': M2s7v});
$('#M3s1').css({'visibility': M3s1v});
$('#M3s2').css({'visibility': M3s2v});
$('#M3s3').css({'visibility': M3s3v});
$('#M3s4').css({'visibility': M3s4v});
$('#M3s5').css({'visibility': M3s5v});
$('#M3s6').css({'visibility': M3s6v});
$('#M3s7').css({'visibility': M3s7v});
$('#M4s1').css({'visibility': M4s1v});
$('#M4s2').css({'visibility': M4s2v});
$('#M4s3').css({'visibility': M4s3v});
$('#M4s4').css({'visibility': M4s4v});
$('#M4s5').css({'visibility': M4s5v});
$('#M4s6').css({'visibility': M4s6v});
$('#M4s7').css({'visibility': M4s7v});
$('#M5s1').css({'visibility': M5s1v});
$('#M5s2').css({'visibility': M5s2v});
$('#M5s3').css({'visibility': M5s3v});
$('#M5s4').css({'visibility': M5s4v});
$('#M5s5').css({'visibility': M5s5v});
$('#M5s6').css({'visibility': M5s6v});
$('#M5s7').css({'visibility': M5s7v});
And here is the for loops that I created to try and cut down the length of code and possibility of typing errors:
// set smc array(#M1s1, #M1s2, #M1s3, etc.)
var smc = [];
for (m = 1; m < 6; m++) {
for (s = 1; s < 8; s++) {
var smc[] = '#M' + m + 's' + s;
}
}
// set smcv array(#M1s1v, #M1s2v, #M1s3v, etc.)
var smcv = [];
for (mv = 1; mv < 6; mv++) {
for (sv = 1; sv < 8; sv++) {
var smcv[] = '#M' + mv + 's' + sv + 'v';
}
}
// loop to set visibility of small circles
for (i = 0; i < 35; i++) {
$(smc[i]).css({'visibility': smcv[i]});
}
I am really new to javascript loops and feel like I may be overlooking something basic or even a syntax error of some kind but can't put a finger on what the problem is. Any direction or assistance would be greatly appreciated!
UPDATE
Here is the final solution to my problem:
//set smc array(#M1s1, #M1s2, #M1s3, etc.)
var smc = [];
for (m = 1; m < 6; m++) {
for (s = 1; s < 8; s++) {
smc.push('#M' + m + 's' + s);
}
}
//set smcv array(#Ms1v, #M1s2v, #M1s3v, etc.)
var smcv = [];
for (mv = 1; mv < 6; mv++) {
for (sv = 1; sv < 8; sv++) {
smcv.push('M' + mv + 's' + sv + 'v');
}
}
//loop to set visibility of small circles
for (i = 0; i < 35; i++) {
$(smc[i]).css({'visibility': window[smcv[i]]});
}
You can't push value to array using var smc[] = 'something'.
Use smc.push( 'something' )
Lets say the M1s1v,M1s2v,.... values are coming from a json variable, something like this:
var x = {
M1s1v : "hidden",
M1s2v : "visibile",
...
}
then you can cut-short the code to something like this:
for (m = 1; m < 6; m++) {
for (s = 1; s < 8; s++) {
$('#M' + m + 's' + s).css({'visiblity':x['M'+m+'s'+s+'v']});
}
}
Hope it helps.
Say you have a two dimensional array, 5 x 7 for M and s holding something that will evaluate to true/false (boolean, 0, 1, empty string...).
var data = [][];
...
for (var M=0; M < data.length; M++) {
for (var s=0; s < data[M].length; M++) {
$('#M' + (M+1) + 's' + (s+1)).css({'visibility': data[M][s] ? 'visible' : 'hidden'});
}
}
You could "optimize" by using hard coded numbers instead of the lengths if you were centian of the dimensions.

Shuffle array and prevent more than 2 in a row

I have an array being built like this:
var entries = ['L','L','L','L','L','L','L','L','L','L','R','R','R','R','R','R','R','R','R','R','M','M','M','M','M']
This means the array is always filled with 10 times L, 10 times R and 5 times M
The output I want to achieve is a randomly generated array, so I came up with the simple solution to just shuffle it with
function shuffle(o){
for(var j, x, i = o.length; i; j = Math.floor(Math.random() * i), x = o[--i], o[i] = o[j], o[j] = x);
return o;
}
The problem I have now is that there is a rule for the outcome, never have one of these letters more than 2 times in a row. So I thought I just use a do/while loop to shuffle until that criteria is met. But in my test runs this totally fails with long loops.
So my question is - what is the best way to build this array without depending on luck. My full program that fails is something like this
function shuffle(o){
for(var j, x, i = o.length; i; j = Math.floor(Math.random() * i), x = o[--i], o[i] = o[j], o[j] = x);
return o;
}
function createProgram(numShooters){
var programs = [];
for(var s = 0; s < numShooters; s++){
//Build array with L/R/M
for( d=0; d < 10; d++ ){
program.push('L');
program.push('R');
if(d < 5){
program.push('M');
}
}
// This will run way too long and is not reliable
//do{
// program = shuffle(program);
//}while(!checkProgram(program))
if(!checkProgram(program)){
console.log('invalid program at ' + s);
}
programs[s] = program;
}
return programs;
}
function checkProgram(program){
var len = program.length;
var last = null;
var dups = 0;
for(var i=0; i<len; len++){
if(program[i] == last){
dups++;
}else{
dups = 0;
}
if(dups == 2){
return false;
}
last = program[i];
}
return true;
}
createProgram(5);
Instead of just shuffle arrays and hope for one without duplicates, you can create them by picking characters by random and specifically avoid to pick the character that was picked previously.
If you keep track of how many there are left to pick of each character, you can control the odds for the character to pick so that the distribution is correct. If for example the first two characters are L, then there are 10 R and 5 M left to pick from (and 8 L, but they are excluded for the next pick), so there should be a 2 in 3 chance to pick an R and a 1 in 3 chance to pick and M.
This approach can run into a dead end, where the array can't be completed, so it has to start over. Running it a few hundred times I have seen something like a 10% overhead, so if you create five arrays you should by average see a retry every other time.
function createProgram(numShooters){
var programs = [];
for(var s = 0; s < numShooters; s++){
var chars = [ 'L', 'R', 'M' ];
var program;
do {
program = [];
var cnt = [ 10, 10, 5, 0 ]; // picks left
var prev = 3; // previous pick
var tot = 25; // total picks left
while (program.length < 25) {
// check for duplicates
var x = program.length >= 2 && program[program.length - 2] == program[program.length - 1] ? prev : 3;
// check if more picks are possible
if (tot - cnt[x] <= 0) {
console.log('invalid program ' + program);
break;
}
// pick from the possible
var r = Math.floor(Math.random() * (tot - cnt[x]));
// determine what character was picked
var c = 0;
while (c == x || r >= cnt[c]) {
if (c != x) r -= cnt[c];
c++;
}
program.push(chars[c]);
cnt[c]--;
tot--;
prev = c;
}
} while (program.length < 25);
programs[s] = program;
}
return programs;
}
console.log(createProgram(1).toString());
So this is the final solution I came up with, as commented Guffas solution also works nice and smooth. But after doing some tests mine is about 30% faster and more readable, but way longer so I'll accept Guffas - thanks to everybody for their input!
function createProgram(numShooters){
var programs = [];
for(var s = 0; s < numShooters; s++){
var program = buildProgram();
programs[s] = program;
}
return programs;
}
function buildProgram(){
var program = [];
var ls = fillArray('L',10);
var rs = fillArray('R',10);
var ms = fillArray('M',5);
//Use either L or R to mix into M - adds variation
var side = Math.random() > 0.5 ? ls : rs;
var otherSide = side == ls ? rs : ls;
var initProg = side.concat(ms);
initProg = shuffle(initProg);
var program = [];
//Correcting invalid positions as suggested
for(var p1 = 0; p1 < initProg.length; p1++){
if(p1 > 1 && initProg[p1-1] == initProg[p1-2] && initProg[p1-1] == initProg[p1]){
if(otherSide.length > 0){
program.push(otherSide.pop());
}else{
return buildProgram(); //impossible state, redo...
}
}
program.push(initProg[p1]);
}
//Fill into remaining other pos
for(var p2 = 0; p2 < otherSide.length; p2++){
program = addAtRandomPos(program,otherSide[p2]);
}
return program;
}
function addAtRandomPos(arr,chr){
var pos = getRandomInt( 0, arr.length - 1 );
var charCur = arr[pos];
var pprev = pos > 1 ? arr[pos-2] : null;
var prev = pos > 0 ? arr[pos-1] : null;
var next = pos < arr.length - 1 ? arr[pos] : null;
var nnext = pos < arr.length - 2 ? arr[pos+1] : null;
var str = pprev + prev + chr + next + nnext;
if(str.indexOf('MMM') !== -1 || str.indexOf('RRR') !== -1 || str.indexOf('LLL') !== -1){
return addAtRandomPos(arr,chr);
}else{
arr.splice(pos,0,chr);
}
return arr;
}
function getRandomInt (min, max) {
return Math.floor(Math.random() * (max - min + 1)) + min;
}
function fillArray(chr,num){
var arr = [];
for(i = 0; i < num; i++){
arr.push(chr);
}
return arr;
}

Javascript Loto Game

How can I check for matching numbers in this script, stuck here, I need to compare the array of user numbers with the array of lotto numbers and display how many numbers they got correct if any along with their prize value.
function numbers() {
var numbercount = 6;
var maxnumbers = 40;
var ok = 1;
r = new Array(numbercount);
for (var i = 1; i <= numbercount; i++) {
r[i] = Math.round(Math.random() * (maxnumbers - 1)) + 1;
}
for (var i = numbercount; i >= 1; i--) {
for (var j = numbercount; j >= 1; j--) {
if ((i != j) && (r[i] == r[j])) ok = 0;
}
}
if (ok) {
var output = "";
for (var k = 1; k <= numbercount; k++) {
output += r[k] + ", ";
}
document.lotto.results.value = output;
} else numbers();
}
function userNumbers() {
var usersNumbers = new Array(5);
for (var count = 0; count <= 5; count++) {
usersNumbers[count] = window.prompt("Enter your number " + (count + 1) + ": ");
}
document.lotto.usersNumbers.value = usersNumbers;
}
Here is a lotto numbers generator and a scoring system. I'm going to leave it to you to validate the user input.
function lottoGen(){
var lottoNumbers = [];
for(var k = 0; k<6; k++){
var num = Math.floor(Math.random()*41);
if(lottoNumbers.indexOf(num) != -1){
lottoNumbers.push(num);
}
}
return lottoNumbers;
}
function scoreIt(){
var usersNumbers = document.getElementsByName('usersNumbers').item(0);
usersNumbers = String(usersNumbers)
usersNumbers = usersNumbers.split(' ');
var matches = 0;
for(var i = 0; i<6; i++){
if(lottoNumbers.indexOf(usersNumbers[i]) != -1){matches++;}
}
return matches;
}
Hi I'm new to this and trying to learn off my own back so obviously I'm no expert but the code above makes a lot of sense to me, apart from the fact I can't get it to work.. I tried to console.log where it says RETURN so I could see the numbers but it just shows an empty array still. I assumed this was to do with it being outside the loop..
I've tried various ways but the best I get is an array that loops the same number or an array with 6 numbers but some of which are repeated..
function lottoGen(){
var lottoNumbers = [];
for(var k = 0; k<6; k++){
var num = Math.floor(Math.random()*41);
if(lottoNumbers.indexOf(num) != -1){
lottoNumbers.push(num);
}
}
return lottoNumbers;
}
Lotto JS: CODEPEN DEMO >> HERE <<
(function(){
var btn = document.querySelector("button");
var output = document.querySelector("#result");
function getRandom(min, max){
return Math.round(Math.random() * (max - min) + min);
}
function showRandomNUmbers(){
var numbers = [],
random;
for(var i = 0; i < 6; i++){
random = getRandom(1, 49);
while(numbers.indexOf(random) !== -1){
console.log("upps (" + random + ") it is in already.");
random = getRandom(1, 49);
console.log("replaced with: (" + random + ").");
}
numbers.push(random);
}
output.value = numbers.join(", ");
}
btn.onclick = showRandomNUmbers;
})();

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