Click one link disables other in java script - javascript

Hello I would like to disable all other links except the clicked one after I click one of the links.
Here is my code so far:
JavaScript
$(".link-chart").click(function($e) {
if($(this).find(".link-selector-two").hasClass('red')) {
$('.link-selector-two', this).addClass('cssclass');
$('.link-selector-one', this).addClass('cssclass');
} else {
$('.link-selector-two', this).removeClass('cssclass');
}
});
HTML
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<a href="#" class="link-chart lx-link-chart">
<div class="link-selector-one">
<div class="link-selector-two red">One</div>
</div>
</a>
<a href="#" class="link-chart lx-link-chart">
<div class="link-selector-one">
<div class="link-selector-two red">Two</div>
</div>
</a>
So the idea is for example if I click the first link to disable the second one, if I click again the first link it will deselect the first link in the way it is working now so the second link will be available for selection again. The same option is for the second link if I click the second to disable the first one.
Any help will be welcome to let me know in which approach have to go.

You could do something like this:
JS
var $linkChart = $('.link-chart');
$linkChart.click(function(e) {
$linkChart.each(function() {
if (e.currentTarget !== this) {
$(this).toggleClass('disabled');
}
});
});
SCSS
.link-chart {
&.disabled {
pointer-events: none;
opacity: 0.25;
}
}
Here's a fiddle to show it in action. FYI, I added a third link so that you could see it'll work exactly the same for as many links as you want to add.

Related

Hide div and show another divs

I just want to show a div when someone click "add" button. If he clicks that "add" button again, needs to hide the current one and show another div. It also needs to show the approved div list on top area. If someone clicks the top area approved div, need to load the div again.
I try to hide and show on click but no luck. (I'm bit new to jquery and I know this is pretty basic code.)
Here is the fiddle Fiddle
$('.add-box').click(function() {
$('.test-div-2').show();
});
$('.add-box').click(function() {
$('.test-div-1').hide();
});
.test-div-1,
.test-div-2,
.test-div-3 {
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="test-div-1">1</div>
<div class="test-div-2">2</div>
<div class="test-div-3">3</div>
<a class="add-box">Add</a>
Do below things:-
1.Add jQuery library before your script code.
2.Wrap your code inside $(document).ready(function(){..}); (needed when script code is added above the HTML. if script code is added at the bottom of the page then wrapping is not needed).
3.Do show(),hide() in single click itself.
$(document).ready(function(){
$('.add-box').click(function() {
$('.test-div-2').show();
$('.test-div-1').hide();
});
});
.test-div-1,
.test-div-2,
.test-div-3{
display:none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="test-div-1">1</div>
<div class="test-div-2">2</div>
<div class="test-div-3">3</div>
<a class="add-box">Add</a>
Fiddle example:- https://jsfiddle.net/rrj1818a/
Note:-
If you want to show one-by-one then do like below:-
https://jsfiddle.net/87re6avo/
<div class="test-div active">1</div>
<div class="test-div">2</div>
<div class="test-div">3</div>
<a class="add-box">Add</a>
$('.add-box').click(function(e) {
e.preventDefault();
var $current = $('.test-div.active');
var $next = $current.next();
$current.removeClass('active');
if(!$next.length) {
$next = $('.test-div').first();
}
$next.addClass('active');
});

jQuery click fires on second click but not first

I've checked some other threads but can't seem to find a response that goes with my code. My issue is my click event only fires on the second click, at which point it works perfectly (second click opens, third click closes, fourth opens, etc...)
$('.expand-btn').click(function() {
var clicks = $(this).data('clicks');
if (clicks) {
$('.expand-wrapper').animate({
right: "0"
}, 500, function() {
});
} else {
$('.expand-wrapper').animate({
right: "-325px"
}, 500, function() {
});
}
$(this).data('clicks', !clicks);
});
EDIT: Here is my HTML code. It works like this jquery plugin where .expand-wrapper is the contact form which is hidden off screen and .expand-btn is the little flap that is on the side of the screen and clickable.
<div class="expand-wrapper">
<i class="fa fa-envelope-o" aria-hidden="true"></i> Contact
<div class="expand-form">
<?php echo do_shortcode('[contact-form-7 id="2173" title="Home 01 Request_no_title"]'); ?>
</div>
</div>
This sounds like an issue where your data-clicks attribute isn't initialized on your element (as you are setting it at the end of your first click and then it appears to work as expected).
Try initializing it on your .expand-btn element as follows :
<a href="#" class="expand-btn" data-clicks='false'>...</a>
Or if you have multiple expand button elements, you can initialize them when your page is loaded using jQuery :
$(function(){
$('.expand-btn').data('clicks',false);
});

Make an endless jQuery short and easy

I have an accordion on my WordPress website.
Usually it works fine, adding and removing classes when clicking the different tabs, but there is an issue with one of the accordions on the website: When clicking on one of the tabs - it doesn't close the rest of the opened tabs. So I added this code in and it works fine:
jQuery(document).ready(function($) {
$("#top11").click(function() {
$("#collapse202").removeClass("in");
$("#collapse203").removeClass("in");
});
$("#top12").click(function() {
$("#collapse201").removeClass("in");
$("#collapse203").removeClass("in");
});
$("#top13").click(function() {
$("#collapse201").removeClass("in");
$("#collapse202").removeClass("in");
});
});
I am sure that there is a way to make it shorter, could some one please explain how to do it more compact?
One way is to add data-id to each collapsed element. For example:
<div id="collapse201" data-id="top11"></div>
<div id="collapse202" data-id="top12"></div>
<div id="collapse203" data-id="top13"></div>
And of course you should use a class in your tabs just in case there are lots of tabs in your accordion:
<div id="top11" class="clickingTab"></div>
<div id="top12" class="clickingTab"></div>
<div id="top12" class="clickingTab"></div>
The JS code could look like this then:
jQuery(document).ready(function($) {
$(".clickingTab").click(function() {
var clickedId = $(this).attr("id");
$("element:not([data-id="+clickedId+"])").removeClass("in");
});
});
There of course could be more efficient ways to solve your problem. But for this particular question this could be the particular solution.
If your HTML look like that, you can use the next() function to target the next sibling element:
$("#top11, #top12, #top13").click(function() {
$("#top11, #top12, #top13").next().removeClass("in");
$(this).next().addClass("in");
});
.in {
color:red;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="top11">top11</div>
<div id="collapse201" class="in">collapse201</div>
<div id="top12">top12</div>
<div id="collapse202" class="in">collapse202</div>
<div id="top13">top13</div>
<div id="collapse203" class="in">collapse203</div>

How do I make this code work for each click?

I have h3 block's and on click of each of the block I am showing the section associated with it. It is actually something like accordion(hide and collapse). I have also given a drop icon to the h3 tags, means that when the block is opened the h3 should have a dropicon pointing downwards while others h3 should have there dropocons towards right. I am controlling this behaviour using backgroundPosition. I am using the jQuery visible condition to see if the particular block is visible then give its drop icon one background position and to the rest other. It works fine but only for first click. It doesn't work for second click; can somebody explain why? Here is my code:
if($(this).next().is(':visible')) {
$(this).css({'backgroundPosition':'0px 14px'});
}
else {
$("h3").css({'backgroundPosition':'0px -11px'});
}
UPDATED CODE:
$("h3").click(function() {
$(".tabs").hide();
$(this).next().show();
if($(this).next().is(':visible')) {
$(this).css({'backgroundPosition':'0px 14px'});
} else {
$("h3").css({'backgroundPosition':'0px -11px'});
}
})
If you wrap the whole block in a div it might make traversing easier.
Html:
<div class="drop-block">
<h3>Click this</h3>
<ul>
<li>Drop</li>
<li>it</li>
<li>like</li>
<li>it's</li>
<li>hot</li>
</ul>
</div>​
Jquery:
var dropper = $('.drop-block');
$(dropper).find('h3').click(function(){
$(this).toggleClass('active');
$(dropper).find('ul').toggle();
});​
Example
I Belive that you are looking for live
So it will be something like this:
$(element).live('click', function(){
if($(this).next().is(':visible')) {
$(this).css({'backgroundPosition':'0px 14px'});
}
else {
$("h3").css({'backgroundPosition':'0px -11px'});
}
}
Instead of editing the css of them, make a css class "open" (or similar), and then add / remove the class on the click to open / close.
It is much easier to debug by checking for the existence of a class than it is to check the css properties of something in JS.
Better make a class name for each situation and easly handle the action
$('h3').on('click', function(){
if($(this).hasClass('opened')) {
$(this).removeClass('opened');
}
else {
$(this).addClass('opened');
}
}
$(document).on('click', 'h3', function(e) {
$(".tabs").hide('slow');
$(this).css({'backgroundPosition':'0px 14px'});
if(!$(this).next().is(':visible'))
{
$("h3").css({'backgroundPosition':'0px -11px'});
$(this).next().show('slow');
}
});
You can remove 'slow' from show/hide if animation is not required
Here is an example.
It sounds like you need to bind click events to the h3 elements and toggle the visibility of the child elements:
$(function(){
$("h3").click(function(){
$(this).next(".tabs").toggle();
});
});
Example markup:
<h3>Item 1</h3>
<div class="tabs">
<h4>Option 1</h4>
<h4>Option 2</h4>
</div>
<h3>Item 2</h3>
<div class="tabs">
<h4>Option 1</h4>
<h4>Option 2</h4>
</div>
Here's a jsFiddle to demonstrate.

JQuery toggle Q&A: individual Q&As don't operate correctly unless you click on Open All/Close All first

I have a Q&A list with "Open All/Close All" at the top with individual open and close image buttons that toggle when clicked. That works fine.
Then follow individual Q&As, and each has its own open and close image.
If you click on "Open All/Close All" first, as soon as the page loads, and then click on the individual Q&A open/close images, all works fine. But if after page load you click on the individual Q&A open/close images, bypassing "Open All/Close All," they display the inappropriate open or close image.
Here is page code:
<div class="answersee"><span>Open All</span><img src="assets/open.gif" border="0" alt="" /></div>
<div class="answerhide"><span>Close All</span><img src="assets/close.gif" border="0" alt="" /></div>
<div class="qa">
<div><img src="open.gif" border="0" alt="" /><span class="question">Question.</span></div>
<div class="answer"><p>Answer.</p></div>
</div>
Here's the script (also uses Jquery):
$(function () {
$(".qa").click(function () {
$(this).find("div").next().slideToggle("fast");
if ($(this).find("div:eq(0)").find("img").attr("src") == "open.gif") {
$(this).find("div:eq(0)").find("img").attr("src", "close.gif");
}
else {
$(this).find("div:eq(0)").find("img").attr("src", "open.gif");
}
});
$(".answersee").click(function () {
$(".answer").show("fast");
$(".qa > div > img").attr("src", "close.gif");
$(".answerhide").show();
$(".answersee").hide();
})
$(".answerhide").click(function () {
$(".answer").hide("fast");
$(".qa > div > img").attr("src", "open.gif");
$(".answersee").show();
$(".answerhide").hide();
})
});
I don't think it's a CSS problem, or I'd include that code here. Do I need to initialize the script in some way? Or did I make a mistake in the above script?
Here's how I would do it.
Working Demo →
EDIT:
Update the code to have simple open/close link.
Code with comments which explains my approach:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<style>
body
{
font-family: "Verdana";
font-size: 12px;
}
.question
{
background-color: #ccc;
cursor: pointer;
padding: 5px;
margin-bottom: 10px;
border-bottom: 1px solid #000;
}
.answer {
padding: 5px;
}
</style>
<script>
$(document).ready(
function()
{
//Hide all the answers on page load.
$('.answer').hide();
//For all questions, add 'open'/'close' text.
//You can replace it with an image if you like.
//This way, you don't need to specify img tag in your HTML for each question.
$('.question')
.append(' <span>[ open ]</span>');
//Now there are two ways to toggle the visibility of answer.
//Either click on the question OR click on Open All / Close All link.
//To use the same code for both instances, we will create
//a function which will take the 'question' div and toggle the answer for it.
//Advantage of this approach is that the code to toggle the answer is in
//one place.
//By default, this function will try to toggle the status of the answer
//i.e. if it's visible, hide it otherwise show it.
//This function will take a second argument called 'showAnswer'.
//If this argument is passed, it overrides the toggle behavior.
//If 'showAnswer' is true, answer is shown.
//If it's false, answer is hidden.
//This second parameter will be used by the 'openAll', 'closeAll' links.
var toggleAnswer = function toggleAnswer(question, showAnswer)
{
//The way I have structured the HTML, answer DIV is right after
//question DIV.
var $answer = $(question).next('div');
//Animation callback, after the animation is done, we want to
//switch the 'text' to display what could the user do with the question.
//Once again, you can change this code to show open/close image.
var updateText = function()
{
var text = $answer.is(':visible') ? ' [close] ' : ' [open] ';
$(question).find('span').html(text);
}
var method = null;
if(arguments.length > 1)
{
//If the function was called with two arguments, use the second
//argument to decide whether to show or hide.
method = showAnswer === true ? 'show' : 'hide';
}
else
{
//Second argument was not passed, simply toggle the answer.
method = $answer.is(':visible') ? 'hide' : 'show';
}
$answer[method]('fast', updateText);
};
//On each question click, toggle the answer.
//If you have noticed, I didn't enclose both Q&A inside one DIV.
//The way you have done if user clicks on the answer, answer will collapse.
//This may not be desirable as user may want to copy the answer
//and he won't be able to.
$('.question').click(function(){ toggleAnswer(this);});
//We will reuse the same toggleAnswer method in openAll, closeAll
//handling. This way, if you want to change behavior of how the question/answers
//are toggled, you can do it in one place.
$('#openClose').click(
function()
{
var showAnswer = $(this).html().toLowerCase().indexOf('open') != -1 ? true : false;
$('.question').each(function() { toggleAnswer(this, showAnswer); });
$(this).html(showAnswer ? 'Close All' : 'Open All');
return false;
}
);
}
);
</script>
<html>
<head>
<title>simple document</title>
</head>
<body>
<a id='openClose' href='#'>Open All</a>
<br /><br />
<div class='question'>Question 1</div>
<div class='answer'>Answer 1</div>
<div class='question'>Question 2</div>
<div class='answer'>Answer 2</div>
<div class='question'>Question 3</div>
<div class='answer'>Answer 3</div>
</body>
</html>
You need to use the callbacks because your animation will not have finished by the time to check for which image is being shown.
$(".qa").click(function() {
$(this).find("div").next().slideToggle("fast", toggleImage);
}
function toggleImage(){
var $img = $(this).find("img");
$img.attr('src') == "open.gif" ? $img.attr('src', "close.gif") : $img.attr('src', "open.gif");
}
N.B There are better ways to do this but lets get you working first and then see if you want to refactor it some more.
Thank you for taking the time to provide this. I will try this later today and report back. In my version, I toggle the Open All/Close All feature. It's a cleaner look and easier to use, since you don't have to move your mouse.
Redsquare and Solution Yogi:
Thanks. I will reply again later and also post a working demo so you can see the problem more clearly. Sorry, I should have done that before.
Liz

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