JavaScript Regex URL extract domain only

JavaScript Regex URL extract domain only - javascript

Currently I can extract the 'domain' from any URL with the following regex:
/^(?:https?:\/\/)?(?:[^#\n]+#)?(?:www\.)?([^:\/\n\?\=]+)/im
However I'm also getting subdomain's too which I want to avoid. For example if I have sites:
www.google.com
yahoo.com/something
freds.meatmarket.co.uk?someparameter
josh.meatmarket.co.uk/asldf/asdf
I currently get:
google.com
yahoo.com
freds.meatmarket.co.uk
josh.meatmarket.co.uk
Those last two I would like to exclude the freds and josh subdomain portion and extract only the true domain which would just be meatmarket.co.uk.
I did find another SOF that tries to solve in PHP, unfortunately I don't know PHP. is this translatable to JS (I'm actually using Google Script FYI)?
function topDomainFromURL($url) {
$url_parts = parse_url($url);
$domain_parts = explode('.', $url_parts['host']);
if (strlen(end($domain_parts)) == 2 ) {
// ccTLD here, get last three parts
$top_domain_parts = array_slice($domain_parts, -3);
} else {
$top_domain_parts = array_slice($domain_parts, -2);
}
$top_domain = implode('.', $top_domain_parts);
return $top_domain;
}

So, you need firstmost hostname stripped from your result, unless there only two parts already?
Just postprocess your result from first match with regexp matching that condition:
function domain_from_url(url) {
var result
var match
if (match = url.match(/^(?:https?:\/\/)?(?:[^#\n]+#)?(?:www\.)?([^:\/\n\?\=]+)/im)) {
result = match[1]
if (match = result.match(/^[^\.]+\.(.+\..+)$/)) {
result = match[1]
}
}
return result
}
console.log(domain_from_url("www.google.com"))
console.log(domain_from_url("yahoo.com/something"))
console.log(domain_from_url("freds.meatmarket.co.uk?someparameter"))
console.log(domain_from_url("josh.meatmarket.co.uk/asldf/asdf"))
// google.com
// yahoo.com
// meatmarket.co.uk
// meatmarket.co.uk

Try this:
https?:\/\/(www\.)?[-a-zA-Z0-9#:%._\+~#=]{2,256}\.([a-z]{2,6}){1}

Try to replace www by something else:
/^(?:https?:\/\/)?(?:[^#\n]+#)?(?:[^.]+\.)?([^:\/\n\?\=]+)/im
EDIT:
If you absolutely want to preserve the www into your regex, you could try this one:
/^(?:https?:\/\/)?(?:[^#\n]+#)?(?:www\.)?(?:[^.]+\.)?([^:\/\n\?\=]+)/im

export const extractHostname = url => {
let hostname;
// find & remove protocol (http, ftp, etc.) and get hostname
if (url.indexOf("://") > -1)
{
hostname = url.split('/')[2];
}
else
{
hostname = url.split('/')[0];
}
// find & remove port number
hostname = hostname.split(':')[0];
// find & remove "?"
hostname = hostname.split('?')[0];
return hostname;
};
export const extractRootDomain = url => {
let domain = extractHostname(url),
splitArr = domain.split('.'),
arrLen = splitArr.length;
// extracting the root domain here
// if there is a subdomain
if (arrLen > 2)
{
domain = splitArr[arrLen - 2] + '.' + splitArr[arrLen - 1];
// check to see if it's using a Country Code Top Level Domain (ccTLD) (i.e. ".me.uk")
if (splitArr[arrLen - 2].length === 2 && splitArr[arrLen - 1].length === 2)
{
//this is using a ccTLD
domain = splitArr[arrLen - 3] + '.' + domain;
}
}
return domain;
};

This is what I've come up with. I don't know how to combine the two match rules into a single regexp, however. This routine won't properly process bad domains like example..com. It does, however, account for TLDs that are in the variety of .xx, .xx.xx, .xxx, or more than 4 character TLDs on the end. This routine will work on just domain names or entire URLs, and the URLs don't have to have the http or https protocol -- it could be ftp, chrome, and others.
function getRootDomain(s){
var sResult = ''
try {
sResult = s.match(/^(?:.*\:\/?\/)?(?<domain>[\w\-\.]*)/i).groups.domain
.match(/(?<root>[\w\-]*(\.\w{3,}|\.\w{2}|\.\w{2}\.\w{2}))$/).groups.root;
} catch(ignore) {}
return sResult;
}
So basically, the first routine strips out any potential stuff before the ://, if that exists, or just a :, if that exists. Next, it looks for all non-word boundary stuff except allows the dash and period like you'd potentially see in domains. It labels this into a named capture group called domain. It also prevents the domain match from including a port such as :8080 as an example. If given an empty string, it just returns an empty string back.
From there, we then do another pass on this and instead of looking from the left-to-right like you would with the preceding ^ symbol, we use the ending $ symbol, working right-to-left, and allow only 4 conditions on the end: .xx.xx, .xx, .xxx, or more than .xxx (such as 4+ character TLDs), where x is a non-word boundary item. Note the {3,} -- that means 3 or more of something, which is why we handle the TLDs that are 3 or more characters too. From there, we allow for a non-word boundary in front of that which may include dashes and periods.
EDIT: Since posting this answer, I learned how to combine the full domain and the root part into one single RegExp. However, I'll keep the above for reasons where you may want to get both values, although the function only returned the root (but with a quick edit, could have returned both full domain and root domain). So, if you just want the root alone, then you could use this solution:
function getRootDomain(s){
var sResult = ''
try {
sResult = s.match(/^(?:.*?:\/\/)?.*?(?<root>[\w\-]*(?:\.\w{2,}|\.\w{2}\.\w{2}))(?:[\/?#:]|$)/).groups.root;
} catch(ignore) {}
return sResult;
}

Related

Javascript return true if a string contains subdomain

I have an API that returns a domain to my front end.
This domain is the string format.
For eg: "google.com" / "google.co.ok"
or "test.google.com"/ "test.google.co.ok:
Notice that the string does not contain any protocol.
I want to write a method that parses the string and returns true if the string contains a subdomain.
In the above 2 examples, the method should return true for test.google.com or test.google.co.ok
EDIT: If it were python, i would write something like below. But hoping something similat was available in JS.
from tld import get_tld, get_fld
get_tld("www.google.co.uk", fix_protocol=True)
# 'co.uk'
get_fld("www.google.co.uk", fix_protocol=True)
# 'google.co.uk'

There are multiple JavaScript libraries available that can be used the same way you're using tld. psl is older but still has millions of weekly downloads.
You could use psl and implement something like this:
import { parse } from "psl";
function hasSubdomain(str) {
const { subdomain } = parse(str);
return subdomain !== null;
}
hasSubdomain("www.google.com") // true
hasSubdomain("google.co.uk") // false
Feel free to clone and edit this example on RunKit as you see fit.

Sure thing. Since there's no protocol, maybe something like:
"word.domain.com"
.split(".").length > 2 // true
"domain.com"
.split(".").length > 2 // false
"www.domain.co.uk"
.split(".").length > 2 // uh-oh
You'll likely need to parse out "www" and second-level domains (".co", ".gc", etc).

You can use RegExp to perform string manipulation. Please take a look at the following snippet and run the code and see the results from different test cases covering most of the possibilities. Let me know if it's helpful.
function subDomain(url) {
// REMOVE LEADING AND TRAILING WHITE SPACE
url = url.replace(new RegExp(/^\s+/), ""); // START
url = url.replace(new RegExp(/\s+$/), ""); // END
// CONVERT BACK SLASHES TO FORWARD SLASHES
url = url.replace(new RegExp(/\\/g), "/");
// REMOVES 'www.' FROM THE START OF THE STRING
url = url.replace(new RegExp(/^www\./i), "");
// REMOVE STRING FROM FIRST FORWARD SLASH ON
url = url.replace(new RegExp(/\/(.*)/), "");
// REMOVES '.??.??' OR '.???.??' FROM END - e.g. '.CO.UK', '.COM.AU'
if (url.match(new RegExp(/\.[a-z]{2,3}\.[a-z]{2}$/i))) {
url = url.replace(new RegExp(/\.[a-z]{2,3}\.[a-z]{2}$/i), "");
// REMOVES '.??' or '.???' or '.????' FROM END - e.g. '.US', '.COM', '.INFO'
} else if (url.match(new RegExp(/\.[a-z]{2,4}$/i))) {
url = url.replace(new RegExp(/\.[a-z]{2,4}$/i), "");
}
// CHECK TO SEE IF THERE IS A DOT '.' LEFT
var subDomain = url.match(new RegExp(/\./g)) ? true : false;
return subDomain;
}
const subdomainInput = "test.google.com";
const subdomainInputWithPath = "test.google.com/test";
const subdomainInputWithPathWithWS = " test.google.com ";
const subdomainInputWithWS = " test.google.com ";
const subdomainInputWithQueryString = "test.google.com/test?token=33333";
const noSubInput = "google.com"
const noSubInputWithPath = "google.com/search"
const noSubInputWithPathWithQueryString = "google.com/search?token=ttttttt"
console.log("Test Run\n")
conosle.log("With subdomain test cases")
console.log(`subdomainInput: ${subDomain(subdomainInput)}`);
console.log(`subdomainInputWithPath: ${subDomain(subdomainInputWithPath)}`);
console.log(`subdomainInputWithWS: ${subDomain(subdomainInputWithWS)}`);
console.log(`subdomainInputWithPathWithWS: ${subDomain(subdomainInputWithPathWithWS)}`);
console.log(`subdomainInputWithQueryString: ${subDomain(subdomainInputWithQueryString)}`);
conosle.log("Without subdomain test cases")
console.log(`noSubInput: ${subDomain(noSubInput)}`);
console.log(`noSubInput: ${subDomain(noSubInput)}`);
console.log(`noSubInputWithPath: ${subDomain(noSubInputWithPath)}`);
console.log(`noSubInputWithPathWithQueryString: ${subDomain(noSubInputWithPathWithQueryString)}`);
return(subDomain);
}

Validate domain name string with Javascript only .com and .net allowed

I have a function that validates domain names perfectly, but I need it to validate only ".com" and ".net'"s.
So a string "abcdefghi.co" or "abcdefghi.org" would be invalid.
Please give me a hand modifying the reg.
function frmValidate( domain ) {
if (/^[a-zA-Z0-9][a-zA-Z0-9-]{1,61}[a-zA-Z0-9](?:\.[a-zA-Z]{2,})+$/.test(domain)) {
//alert("Valid Domain Name");
return true;
} else {
//alert("Enter Valid Domain Name");
return false;
}
}

Because you only want to permit one . (followed by .com or .net), don't repeat the (?:\. ... group - instead, just match \., followed by a group that alternates between com and net. You may also simplify the pattern by using the case-insensitive flag /i:
/^[a-z0-9][a-z0-9-]{1,61}[a-z0-9]\.(?:com|net)$/i
const input = prompt('Domain to test?');
console.log(
/^[a-z0-9][a-z0-9-]{1,61}[a-z0-9]\.(?:com|net)$/i
.test(input)
);

The regex is currently testing if there's "." followed by 2 or more characters at the end.
Change it to ^[a-zA-Z0-9][a-zA-Z0-9-]{1,61}[a-zA-Z0-9](?:.(com|net))+$ and it will match only .com and .net domains
https://regexr.com/49fcn

// 1) there could be more than one dot in a valid domain name,
// since subdomains don't make domain names invalid;
// 2) for the dot(s) placement, don't use some reg ex wizardry
// that will confuse and confound the next support guy
// (even if that's only you six months later)
function frmValidate( domain ) {
// since domain could have subdomain like qwe.asd.zxc,
// parse into substrings at "."
var dParts = domain.split('.');
// capture tld from end of list
var tld = dParts[dParts.length - 1];
// determine whether tld is "com" or "net"
var isValid = ('com' === tld) || ('net' === tld);
// for testing
// alert('top level domain is: ' + tld + ' and is ' + (isValid?'':'NOT ') + 'valid');
// advise caller
return isValid;
};

How to get domain from email address in Javascript?

I want to get the domain part from an email address, in Javascript. It's easy to extract the domain from an email like via split: "joe#example.com", which is example.com.
However, emails also come in forms like "joe#subdomain1.example.com.uk", of which the domain is example.com.uk, instead of subdomain1.example.com.uk. The problem here is that subdomain1 can be mistakenly considered as part of the domain.
How do I do this reliably?

That is really not a trivial problem as it might seem at first glance.
Luckily there are libs that solves this, tld-extract is a popular choice which uses Mozilla's Public Suffix List (a volunteer based list). The usage is
var parser = require('tld-extract');
console.log( parser("www.google.com") );
console.log( parser("google.co.uk") );
/**
* >> { tld: 'com', domain: 'google.com', sub: 'www' }
* >> { tld: 'co.uk', domain: 'google.co.uk', sub: '' }
*/
To extract the server address part from email address first split by # character like this
const email = "john#sub.domain.com"
const address = email.split('#').pop()
const domain = parser(address).domain
See more in depth discussion about the problem solution check the README of a similar python library.
tldextract on the other hand knows what all gTLDs and ccTLDs look like
by looking up the currently living ones according to the Public Suffix
List (PSL). So, given a URL, it knows its subdomain from its domain,
and its domain from its country code.
Make sure to learn about the list on Public Suffix List website and understand it is based on volunteer work and might not be exhaustive at all time.
The Public Suffix List is a cross-vendor initiative to provide an
accurate list of domain name suffixes, maintained by the hard work of
Mozilla volunteers and by submissions from registries, to whom we are
very grateful.
Since there was and remains no algorithmic method of finding the
highest level at which a domain may be registered for a particular
top-level domain (the policies differ with each registry), the only
method is to create a list. This is the aim of the Public Suffix List.

I agree that the best solution for this problem would be to use a library, like what was suggested in https://stackoverflow.com/a/49893282/2735286.
Yet if you have a long enough list with top level domains and subdomains, you could write some code which extracts whatever characters are found after the '#' sign and then from the domain you try to find out whether you have a top level or subdomain. When you know if you are dealing with a top level domain you know where you can find the main domain name and so everything before it must be a subdomain. The same applies to the subdomain.
This is a naive implementation, but you could try this:
// TODO: needs to have an exhaustive list of top level domains
const topLevelDomains = ["com", "org", "int", "gov", "edu", "net", "mil"];
// TODO: Needs an exhaustive list of subdomains
const subdomains = ["co.uk", "org.uk", "me.uk", "ltd.uk", "plc.uk"];
function extract(str) {
const suffix = str.match(/.+#(.+)/);
if (suffix) {
const groups = suffix.pop().split(".");
const lastPart = groups[groups.length - 1];
if (isSubDomain(groups[groups.length - 2] + "." + lastPart)) {
console.log("Sub domain detected in: " + groups);
if (groups.length > 3) {
console.log("Possible subdomain: " + groups.splice(0, groups.length - 3));
console.log();
}
} else if (isTopLevelDomain(lastPart)) {
console.log("Top level domain detected in: " + groups);
if (groups.length > 2) {
console.log("Possible subdomain: " + groups.splice(0, groups.length - 2));
console.log();
}
}
}
}
function isTopLevelDomain(lastPart) {
return (topLevelDomains.find(s => s === lastPart));
}
function isSubDomain(lastPart) {
return (subdomains.find(s => s === lastPart));
}
extract("joe#example.com");
extract("joe#subdomain1.example.co.uk");
extract("joe#subdomain2.example.edu");
extract("joe#subdomain3.example.ltd.uk");
extract("joe#test.subdomain3.example.plc.uk");
Please challenge the logic, if I got this wrong.

// Not a proper solution because of email pattern is not fixed. Use below if it is appropriate solution according to your problem .
jQuery( document ).ready(function() {
//var input = 'joe#subdomain1.com';
var input = 'joe#subdomain1.example.com.uk';
var first_split = input.split("#")[1];
var second_split = first_split.split(".");
if(second_split.length == 2) {
console.log('domain is : '+first_split);
} else if(second_split.length > 2) {
var str = first_split.substring(first_split.indexOf(".") + 1);
console.log('domain is : '+str);
}
});

regex detect url and prepend http:// [duplicate]

This question already has answers here:
Adding http:// to all links without a protocol
(4 answers)
Closed 8 years ago.
I would like to detect url's that are entered in a text input. I have the following code which prepends http:// to the beginning of what has been entered:
var input = $(this);
var val = input.val();
if (val && !val.match(/^http([s]?):\/\/.*/)) {
input.val('http://' + val);
}
How would I go about adapting this to only append the http:// if it contains a string followed by a tld? At the moment if I enter a string for example:
Hello. This is a test
the http:// will get appended to hello, even though it's not a url. Any help would be greatly appreciated.

This simple function works for me. We don't care about the real existence of a TLD domain to gain speed, rather we check the syntax like example.com.
Sorry, I've forgotten that VBA trim() is not intrinsic function in js, so:
// Removes leading whitespaces
function LTrim(value)
{
var re = /\s*((\S+\s*)*)/;
return value.replace(re, "$1");
}
// Removes ending whitespaces
function RTrim(value)
{
var re = /((\s*\S+)*)\s*/;
return value.replace(re, "$1");
}
// Removes leading and ending whitespaces
function trim(value)
{
return LTrim(RTrim(value));
}
function hasDomainTld(strAddress)
{
var strUrlNow = trim(strAddress);
if(strUrlNow.match(/[,\s]/))
{
return false;
}
var i, regex = new RegExp();
regex.compile("[A-Za-z0-9\-_]+\\.[A-Za-z0-9\-_]+$");
i = regex.test(strUrlNow);
regex = null;
return i;
}
So your code, $(this) is window object, so I pass the objInput through an argument, using classical js instead of jQuery:
function checkIt(objInput)
{
var val = objInput.value;
if(val.match(/http:/i)) {
return false;
}
else if (hasDomainTld(val)) {
objInput.value = 'http://' + val;
}
}
Please test yourself: http://jsfiddle.net/SDUkZ/8/

The best solution i have found is to use the following regex:
/\.[a-zA-Z]{2,3}/
This detects the . after the url, and characters for the extension with a limit of 2/3 characters.
Does this seem ok for basic validation? Please let me know if you see any problems that could arise.
I know that it will detect email address's but this wont matter in this instance.

You need to narrow down your requirements first as URL detection with regular expressions can be very tricky. These are just a few situations where your parser can fail:
IDNs (госуслуги.рф)
Punycode cases (xn--blah)
New TLD being registered (.amazon)
SEO-friendly URLs (domain.com/Everything you need to know about RegEx.aspx)
We recently faced a similar problem and what we ended up doing was a simple check whether the URL starts with either http://, https://, or ftp:// and prepending with http:// if it doesn't start with any of the mentioned schemes. Here's the implementation in TypeScript:
public static EnsureAbsoluteUri(uri: string): string {
var ret = uri || '', m = null, i = -1;
var validSchemes = ko.utils.arrayMap(['http', 'https', 'ftp'], (i) => { return i + '://' });
if (ret && ret.length) {
m = ret.match(/[a-z]+:\/\//gi);
/* Checking against a list of valid schemes and prepending with "http://" if check fails. */
if (m == null || !m.length || (i = $.inArray(m[0].toLowerCase(), validSchemes)) < 0 ||
(i >= 0 && ret.toLowerCase().indexOf(validSchemes[i]) != 0)) {
ret = 'http://' + ret;
}
}
return ret;
}
As you can see, we're not trying to be smart here as we can't predict every possible URL form. Furthermore, this method is usually executed against field values we know are meant to be URLs so the change of misdetection is minimal.
Hope this helps.

Trying to Validate URL Using JavaScript

I want to validate a URL and display message. Below is my code:
$("#pageUrl").keydown(function(){
$(".status").show();
var url = $("#pageUrl").val();
if(isValidURL(url)){
$.ajax({
type: "POST",
url: "demo.php",
data: "pageUrl="+ url,
success: function(msg){
if(msg == 1 ){
$(".status").html('<img src="images/success.gif"/><span><strong>SiteID:</strong>12345678901234456</span>');
}else{
$(".status").html('<img src="images/failure.gif"/>');
}
}
});
}else{
$(".status").html('<img src="images/failure.gif"/>');
}
});
function isValidURL(url){
var RegExp = /(ftp|http|https):\/\/(\w+:{0,1}\w*#)?(\S+)(:[0-9]+)?(\/|\/([\w#!:.?+=&%#!\-\/]))?/;
if(RegExp.test(url)){
return true;
}else{
return false;
}
}
My problem is now it will show an error message even when entering a proper URL until it matches regular expression, and it return true even if the URL is something like "http://wwww".
I appreciate your suggestions.

Someone mentioned the Jquery Validation plugin, seems overkill if you just want to validate the url, here is the line of regex from the plugin:
return this.optional(element) || /^(https?|ftp):\/\/(((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\(\)\*\+,;=]|:)*#)?(((\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.(\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.(\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.(\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5]))|((([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.)+(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.?)(:\d*)?)(\/((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\(\)\*\+,;=]|:|#)+(\/(([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\(\)\*\+,;=]|:|#)*)*)?)?(\?((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\(\)\*\+,;=]|:|#)|[\uE000-\uF8FF]|\/|\?)*)?(\#((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\(\)\*\+,;=]|:|#)|\/|\?)*)?$/i.test(value);
Here is where they got it from: http://projects.scottsplayground.com/iri/
Pointed out by #nhahtdh This has been updated to:
// Copyright (c) 2010-2013 Diego Perini, MIT licensed
// https://gist.github.com/dperini/729294
// see also https://mathiasbynens.be/demo/url-regex
// modified to allow protocol-relative URLs
return this.optional( element ) || /^(?:(?:(?:https?|ftp):)?\/\/)(?:\S+(?::\S*)?#)?(?:(?!(?:10|127)(?:\.\d{1,3}){3})(?!(?:169\.254|192\.168)(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})).?)(?::\d{2,5})?(?:[/?#]\S*)?$/i.test( value );
source: https://github.com/jzaefferer/jquery-validation/blob/c1db10a34c0847c28a5bd30e3ee1117e137ca834/src/core.js#L1349

It's not practical to parse URLs using regex. A full implementation of the RFC1738 rules would result in an enormously long regex (assuming it's even possible). Certainly your current expression fails many valid URLs, and passes invalid ones.
Instead:
a. use a proper URL parser that actually follows the real rules. (I don't know of one for JavaScript; it would probably be overkill. You could do it on the server side though). Or,
b. just trim away any leading or trailing spaces, then check it has one of your preferred schemes on the front (typically ‘http://’ or ‘https://’), and leave it at that. Or,
c. attempt to use the URL and see what lies at the end, for example by sending it am HTTP HEAD request from the server-side. If you get a 404 or connection error, it's probably wrong.
it return true even if url is something like "http://wwww".
Well, that is indeed a perfectly valid URL.
If you want to check whether a hostname such as ‘wwww’ actually exists, you have no choice but to look it up in the DNS. Again, this would be server-side code.

function validateURL(textval) {
var urlregex = /^(https?|ftp):\/\/([a-zA-Z0-9.-]+(:[a-zA-Z0-9.&%$-]+)*#)*((25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]?)(\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9]?[0-9])){3}|([a-zA-Z0-9-]+\.)*[a-zA-Z0-9-]+\.(com|edu|gov|int|mil|net|org|biz|arpa|info|name|pro|aero|coop|museum|[a-zA-Z]{2}))(:[0-9]+)*(\/($|[a-zA-Z0-9.,?'\\+&%$#=~_-]+))*$/;
return urlregex.test(textval);
}
This can return true for URLs like:
http://stackoverflow.com/questions/1303872/url-validation-using-javascript
or:
http://regexlib.com/DisplayPatterns.aspx?cattabindex=1&categoryId=2

I written also a URL validation function base on rfc1738 and rfc3986 to check http and https urls. I try to hold this modular, so it can be better maintained and adapted to own requirements.
The RegExp in one line is show at end of this post.
The RegExp accept HTTP and HTTPS URLs with some international domain or IPv4 number. IPv6 is not supported yet.
window.isValidURL = (function() {// wrapped in self calling function to prevent global pollution
//URL pattern based on rfc1738 and rfc3986
var rg_pctEncoded = "%[0-9a-fA-F]{2}";
var rg_protocol = "(http|https):\\/\\/";
var rg_userinfo = "([a-zA-Z0-9$\\-_.+!*'(),;:&=]|" + rg_pctEncoded + ")+" + "#";
var rg_decOctet = "(25[0-5]|2[0-4][0-9]|[0-1][0-9][0-9]|[1-9][0-9]|[0-9])"; // 0-255
var rg_ipv4address = "(" + rg_decOctet + "(\\." + rg_decOctet + "){3}" + ")";
var rg_hostname = "([a-zA-Z0-9\\-\\u00C0-\\u017F]+\\.)+([a-zA-Z]{2,})";
var rg_port = "[0-9]+";
var rg_hostport = "(" + rg_ipv4address + "|localhost|" + rg_hostname + ")(:" + rg_port + ")?";
// chars sets
// safe = "$" | "-" | "_" | "." | "+"
// extra = "!" | "*" | "'" | "(" | ")" | ","
// hsegment = *[ alpha | digit | safe | extra | ";" | ":" | "#" | "&" | "=" | escape ]
var rg_pchar = "a-zA-Z0-9$\\-_.+!*'(),;:#&=";
var rg_segment = "([" + rg_pchar + "]|" + rg_pctEncoded + ")*";
var rg_path = rg_segment + "(\\/" + rg_segment + ")*";
var rg_query = "\\?" + "([" + rg_pchar + "/?]|" + rg_pctEncoded + ")*";
var rg_fragment = "\\#" + "([" + rg_pchar + "/?]|" + rg_pctEncoded + ")*";
var rgHttpUrl = new RegExp(
"^"
+ rg_protocol
+ "(" + rg_userinfo + ")?"
+ rg_hostport
+ "(\\/"
+ "(" + rg_path + ")?"
+ "(" + rg_query + ")?"
+ "(" + rg_fragment + ")?"
+ ")?"
+ "$"
);
// export public function
return function (url) {
if (rgHttpUrl.test(url)) {
return true;
} else {
return false;
}
};
})();
RegExp in one line:
var rg = /^(http|https):\/\/(([a-zA-Z0-9$\-_.+!*'(),;:&=]|%[0-9a-fA-F]{2})+#)?(((25[0-5]|2[0-4][0-9]|[0-1][0-9][0-9]|[1-9][0-9]|[0-9])(\.(25[0-5]|2[0-4][0-9]|[0-1][0-9][0-9]|[1-9][0-9]|[0-9])){3})|localhost|([a-zA-Z0-9\-\u00C0-\u017F]+\.)+([a-zA-Z]{2,}))(:[0-9]+)?(\/(([a-zA-Z0-9$\-_.+!*'(),;:#&=]|%[0-9a-fA-F]{2})*(\/([a-zA-Z0-9$\-_.+!*'(),;:#&=]|%[0-9a-fA-F]{2})*)*)?(\?([a-zA-Z0-9$\-_.+!*'(),;:#&=\/?]|%[0-9a-fA-F]{2})*)?(\#([a-zA-Z0-9$\-_.+!*'(),;:#&=\/?]|%[0-9a-fA-F]{2})*)?)?$/;

In a similar situation I got away with this:
someUtils.validateURL = function(url) {
var parser = document.createElement('a');
try {
parser.href = url;
return !!parser.hostname;
} catch (e) {
return false;
}
};
i.e. why invent the wheel if browsers can do it for you? But, of course, this will only work in the browser.
there are various parts of parsed URL exactly how browser would interpret it:
parser.protocol; // => "http:"
parser.hostname; // => "example.com"
parser.port; // => "8080"
parser.pathname; // => "/path/"
parser.search; // => "?search=test"
parser.hash; // => "#hash"
parser.host; // => "example.com:3000"
Using these you can improve your validating function depending on the requirements. The only drawback is that it will accept relative URLs and use current page server's host and port. But you can use it for your advantage, by re-assembling the URL from parts and always passing it in full to your AJAX service.
What validateURL won't accept is invalid URL, e.g. http:\:8883 will return false, but :1234 is valid and is interpreted as http://pagehost.example.com/:1234 i.e. as a relative path.
UPDATE
This approach is no longer working with Chrome and other WebKit browsers. Even when URL is invalid, hostname is filled with some value, e.g. taken from base. It still helps to parse parts of URL, but will not allow to validate one.
Possible better no-own-parser approach is to use var parsedURL = new URL(url) and catch exceptions. See e.g. URL API. Supported by all major browsers and NodeJS, although still marked experimental.

best regex I found from http://angularjs.org/
var urlregex = /^(ftp|http|https):\/\/(\w+:{0,1}\w*#)?(\S+)(:[0-9]+)?(\/|\/([\w#!:.?+=&%#!\-\/]))?$/;

This is what worked for me:
function validateURL(value) {
return /^(https?|ftp):\/\/(((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\(\)\*\+,;=]|:)*#)?(((\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.(\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.(\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.(\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5]))|((([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.)+(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.?)(:\d*)?)(\/((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\(\)\*\+,;=]|:|#)+(\/(([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\(\)\*\+,;=]|:|#)*)*)?)?(\?((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\(\)\*\+,;=]|:|#)|[\uE000-\uF8FF]|\/|\?)*)?(\#((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\(\)\*\+,;=]|:|#)|\/|\?)*)?$/i.test(value);
}
from there is is just a matter of calling the function to get a true or false back:
validateURL(urltovalidate);

I know it's quite an old question but since it does not have any accepted answer, I suggest you to use the URI.js framework: https://github.com/medialize/URI.js
You can use it to check for malformed URI using a try/catch block:
function isValidURL(url)
{
try {
(new URI(url));
return true;
}
catch (e) {
// Malformed URI
return false;
}
}
Of course it will consider something like "%#" as a well formed relative URI... So I suggest you read the URI.js API to perform more checks, for example if you want to make sure that the user entered a well formed absolute URL you may do like this:
function isValidURL(url)
{
try {
var uri = new URI(url);
// URI has a scheme and a host
return (!!uri.scheme() && !!uri.host());
}
catch (e) {
// Malformed URI
return false;
}
}

Import in an npm package like
https://www.npmjs.com/package/valid-url
and use it to validate your url.

You can use the URL API that is recently standard. Browser support is sketchy at best, see the link. new URL(str) is guaranteed to throw TypeError for invalid URLs.
As stated above, http://wwww is a valid URL.

The URL API can be used to validate the structure of a URL string.
An error is thrown when trying to serialise an invalid URL string into a URL object. This could be abstracted into a helper function (Typescript snippet below):
function isValidURL(URL: string) : boolean {
try {
new URL(string);
return true;
} catch (err) { return false; }
}
isValidURL('https://www.google.com'); // returns true
isValidURL('localhost:3000'); // returns true
isValidURL('not-a-valid-url'); // returns false
isValidURL('google.com'); // returns false (see footnote)
If you strictly want HTTP / web links to be valid, we can simply add a condition to the return statement:
...
const url = new URL(string);
return url.protocol === 'https:' || url.protocol === 'http:';
...
Granted, this approach comes with a few caveats:
No support for the URL API in Internet Explorer (could be fixed with a polyfill)
Without additional checks, URLs without either a protocol or port are seen as invalid (e.g. google.com is invalid but google.com:3000 is OK). This may be an unintended behaviour for some usecases.

If you're looking for a more reliable regex, check out RegexLib. Here's the page you'd probably be interested in:
http://regexlib.com/Search.aspx?k=url
As for the error messages showing while the person is still typing, change the event from keydown to blur and then it will only check once the person moves to the next element.

var RegExp = (/^HTTP|HTTP|http(s)?:\/\/(www\.)?[A-Za-z0-9]+([\-\.]{1}[A-Za-z0-9]+)*\.[A-Za-z]{2,40}(:[0-9]{1,40})?(\/.*)?$/);

My solution:
function isValidUrl(t)
{
return t.match(/^(http|https|ftp):\/\/(([A-Z0-9][A-Z0-9_-]*)(\.[A-Z0-9][A-Z0-9_-]*)+)(:(\d+))?\/?/i)
}

Demo : http://jsbin.com/uzimeb/1/edit
function checkURL(value) {
var urlregex = new RegExp("^(http|https|ftp)\://([a-zA-Z0-9\.\-]+(\:[a-zA-Z0-9\.&%\$\-]+)*#)*((25[0-5]|2[0-4][0-9]|[0-1]{1}[0-9]{2}|[1-9]{1}[0-9]{1}|[1-9])\.(25[0-5]|2[0-4][0-9]|[0-1]{1}[0-9]{2}|[1-9]{1}[0-9]{1}|[1-9]|0)\.(25[0-5]|2[0-4][0-9]|[0-1]{1}[0-9]{2}|[1-9]{1}[0-9]{1}|[1-9]|0)\.(25[0-5]|2[0-4][0-9]|[0-1]{1}[0-9]{2}|[1-9]{1}[0-9]{1}|[0-9])|([a-zA-Z0-9\-]+\.)*[a-zA-Z0-9\-]+\.(com|edu|gov|int|mil|net|org|biz|arpa|info|name|pro|aero|coop|museum|[a-zA-Z]{2}))(\:[0-9]+)*(/($|[a-zA-Z0-9\.\,\?\'\\\+&%\$#\=~_\-]+))*$");
if (urlregex.test(value)) {
return (true);
}
return (false);
}

I have found a great resource for comparing different solutions:
https://mathiasbynens.be/demo/url-regex
According to that page, only solution from diegoperini passes all tests. Here is that regex:
_^(?:(?:https?|ftp)://)(?:\S+(?::\S*)?#)?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\x{00a1}-\x{ffff}0-9]+-?)*[a-z\x{00a1}-\x{ffff}0-9]+)(?:\.(?:[a-z\x{00a1}-\x{ffff}0-9]+-?)*[a-z\x{00a1}-\x{ffff}0-9]+)*(?:\.(?:[a-z\x{00a1}-\x{ffff}]{2,})))(?::\d{2,5})?(?:/[^\s]*)?$_iuS

I checked a lot of url validators in google and no one works for me. For example I'd like to see valid on links like 'aa.com'. I like silly check for dot sign in string.
function isValidUri(str) {
var dotIndex = str.indexOf('.');
return (dotIndex > 0 && dotIndex < str.length - 2);
}
It should not stay on beginning and end of string (for now we don't have top level domain names with one character).

Here's a regular expression which might fit the bill (it's very long):
/^(?:\u0066\u0069\u006C\u0065\u003A\u002F{2}(?:\u002F{2}(?:(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D\u002E\u005F\u007E\u0021\u0024\u0026\u0027\u0028\u0029\u002A\u002B\u002C\u003B\u003D]|\u0025[\u0030-\u0039\u0041-\u0046\u0061-\u0066][\u0030-\u0039\u0041-\u0046\u0061-\u0066])*\u0040)?(?:\u005B(?:(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){6}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035]))|\u003A{2}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){5}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035]))|(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4})?\u003A{2}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){4}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035]))|(?:(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A)?[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4})?\u003A{2}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){3}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035]))|(?:(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){0,2}[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4})?\u003A{2}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){2}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035]))|(?:(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){0,3}[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4})?\u003A{2}[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035]))|(?:(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){0,4}[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4})?\u003A{2}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035]))|(?:(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){0,5}[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4})?\u003A{2}[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){0,6}[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4})?\u003A{2})\u005D|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])|(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039](?:(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D]+)?[\u0041-\u005A\u0061-\u007A\u0030-\u0039])?|(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039](?:(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D]+)?[\u0041-\u005A\u0061-\u007A\u0030-\u0039])?\u002E)+[\u0041-\u005A\u0061-\u007A\u0030-\u0039](?:(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D]+)?[\u0041-\u005A\u0061-\u007A\u0030-\u0039])?))(?:\u003A(?:\u0030-\u0035\u0030-\u0039{0,4}|\u0036\u0030-\u0034\u0030-\u0039{3}|\u0036\u0035\u0030-\u0034\u0030-\u0039{2}|\u0036\u0035\u0035\u0030-\u0032\u0030-\u0039|\u0036\u0035\u0035\u0033\u0030-\u0035))?(?:\u002F(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D\u002E\u005F\u007E\u0021\u0024\u0026\u0027\u0028\u0029\u002A\u002B\u002C\u003B\u003D\u003A\u0040]|\u0025[\u0030-\u0039\u0041-\u0046\u0061-\u0066][\u0030-\u0039\u0041-\u0046\u0061-\u0066])*)*|\u002F(?:(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D\u002E\u005F\u007E\u0021\u0024\u0026\u0027\u0028\u0029\u002A\u002B\u002C\u003B\u003D\u003A\u0040]|\u0025[\u0030-\u0039\u0041-\u0046\u0061-\u0066][\u0030-\u0039\u0041-\u0046\u0061-\u0066])+(?:\u002F(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D\u002E\u005F\u007E\u0021\u0024\u0026\u0027\u0028\u0029\u002A\u002B\u002C\u003B\u003D\u003A\u0040]|\u0025[\u0030-\u0039\u0041-\u0046\u0061-\u0066][\u0030-\u0039\u0041-\u0046\u0061-\u0066])*)*)?|(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D\u002E\u005F\u007E\u0021\u0024\u0026\u0027\u0028\u0029\u002A\u002B\u002C\u003B\u003D\u003A\u0040]|\u0025[\u0030-\u0039\u0041-\u0046\u0061-\u0066][\u0030-\u0039\u0041-\u0046\u0061-\u0066])+(?:\u002F(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D\u002E\u005F\u007E\u0021\u0024\u0026\u0027\u0028\u0029\u002A\u002B\u002C\u003B\u003D\u003A\u0040]|\u0025[\u0030-\u0039\u0041-\u0046\u0061-\u0066][\u0030-\u0039\u0041-\u0046\u0061-\u0066])*)*)|[\u0041-\u005A\u0061-\u007A][\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002B\u002D\u002E]*\u003A(?:\u002F{2}(?:(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D\u002E\u005F\u007E\u0021\u0024\u0026\u0027\u0028\u0029\u002A\u002B\u002C\u003B\u003D]|\u0025[\u0030-\u0039\u0041-\u0046\u0061-\u0066][\u0030-\u0039\u0041-\u0046\u0061-\u0066])*\u0040)?(?:\u005B(?:(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){6}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035]))|\u003A{2}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){5}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035]))|(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4})?\u003A{2}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){4}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035]))|(?:(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A)?[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4})?\u003A{2}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){3}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035]))|(?:(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){0,2}[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4})?\u003A{2}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){2}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035]))|(?:(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){0,3}[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4})?\u003A{2}[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035]))|(?:(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){0,4}[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4})?\u003A{2}(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035]))|(?:(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){0,5}[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4})?\u003A{2}[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}|(?:(?:[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4}\u003A){0,6}[\u0030-\u0039\u0041-\u0046\u0061-\u0066]{1,4})?\u003A{2})\u005D|(?:(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])\u002E){3}(?:[\u0030-\u0039]|[\u0031-\u0039][\u0030-\u0039]|\u0031[\u0030-\u0039]{2}|\u0032[\u0030-\u0034][\u0030-\u0039]|\u0032\u0035[\u0030-\u0035])|(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039](?:(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D]+)?[\u0041-\u005A\u0061-\u007A\u0030-\u0039])?|(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039](?:(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D]+)?[\u0041-\u005A\u0061-\u007A\u0030-\u0039])?\u002E)+[\u0041-\u005A\u0061-\u007A\u0030-\u0039](?:(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D]+)?[\u0041-\u005A\u0061-\u007A\u0030-\u0039])?))(?:\u003A(?:\u0030-\u0035\u0030-\u0039{0,4}|\u0036\u0030-\u0034\u0030-\u0039{3}|\u0036\u0035\u0030-\u0034\u0030-\u0039{2}|\u0036\u0035\u0035\u0030-\u0032\u0030-\u0039|\u0036\u0035\u0035\u0033\u0030-\u0035))?(?:\u002F(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D\u002E\u005F\u007E\u0021\u0024\u0026\u0027\u0028\u0029\u002A\u002B\u002C\u003B\u003D\u003A\u0040]|\u0025[\u0030-\u0039\u0041-\u0046\u0061-\u0066][\u0030-\u0039\u0041-\u0046\u0061-\u0066])*)*|\u002F(?:(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D\u002E\u005F\u007E\u0021\u0024\u0026\u0027\u0028\u0029\u002A\u002B\u002C\u003B\u003D\u003A\u0040]|\u0025[\u0030-\u0039\u0041-\u0046\u0061-\u0066][\u0030-\u0039\u0041-\u0046\u0061-\u0066])+(?:\u002F(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D\u002E\u005F\u007E\u0021\u0024\u0026\u0027\u0028\u0029\u002A\u002B\u002C\u003B\u003D\u003A\u0040]|\u0025[\u0030-\u0039\u0041-\u0046\u0061-\u0066][\u0030-\u0039\u0041-\u0046\u0061-\u0066])*)*)?|(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D\u002E\u005F\u007E\u0021\u0024\u0026\u0027\u0028\u0029\u002A\u002B\u002C\u003B\u003D\u003A\u0040]|\u0025[\u0030-\u0039\u0041-\u0046\u0061-\u0066][\u0030-\u0039\u0041-\u0046\u0061-\u0066])+(?:\u002F(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D\u002E\u005F\u007E\u0021\u0024\u0026\u0027\u0028\u0029\u002A\u002B\u002C\u003B\u003D\u003A\u0040]|\u0025[\u0030-\u0039\u0041-\u0046\u0061-\u0066][\u0030-\u0039\u0041-\u0046\u0061-\u0066])*)*)(?:\u003F(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D\u002E\u005F\u007E\u0021\u0024\u0026\u0027\u0028\u0029\u002A\u002B\u002C\u003B\u003D\u003A\u0040\u002F\u003F]|\u0025[\u0030-\u0039\u0041-\u0046\u0061-\u0066][\u0030-\u0039\u0041-\u0046\u0061-\u0066])*)?(?:\u0023(?:[\u0041-\u005A\u0061-\u007A\u0030-\u0039\u002D\u002E\u005F\u007E\u0021\u0024\u0026\u0027\u0028\u0029\u002A\u002B\u002C\u003B\u003D\u003A\u0040\u002F\u003F]|\u0025[\u0030-\u0039\u0041-\u0046\u0061-\u0066][\u0030-\u0039\u0041-\u0046\u0061-\u0066])*)?)$/
There are some caveats to its usage, namely it does not validate URIs which contain additional information after the user name (e.g. "username:password"). Also, only IPv6 addresses can be contained within the IP literal syntax and the "IPvFuture" syntax is currently ignored and will not validate against this regular expression. Port numbers are also constrained to be between 0 and 65,535. Also, only the file scheme can use triple slashes (e.g. "file:///etc/sysconfig") and can ignore both the query and fragment parts of a URI. Finally, it is geared towards regular URIs and not IRIs, hence the extensive focus on the ASCII character set.
This regular expression could be expanded upon, but it's already complex and long enough as it is. I also cannot guarantee it's going to be "100% accurate" or "bug free", but it should correctly validate URIs for all schemes.
You will need to do additional verification for any scheme-specific requirements or do URI normalization as this regular expression will validate a very broad range of URIs.

Try edit your isValidURL function as follows:
function isValidURL(url) {
var encodedURL = encodeURIComponent(url);
var isValid = false;
$.ajax({
url: "http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20html%20where%20url%3D%22" + encodedURL + "%22&format=json",
type: "get",
async: false,
dataType: "json",
success: function(data) {
isValid = data.query.results != null;
},
error: function(){
isValid = false;
}
});
return isValid;
}
This should do the trick.

Develop Reference

JavaScript is the programming language of the Web.

JavaScript Regex URL extract domain only - javascript

Try this: https?:\/\/(www\.)?[-a-zA-Z0-9#:%._\+~#=]{2,256}\.([a-z]{2,6}){1}

Try to replace www by something else: /^(?:https?:\/\/)?(?:[^#\n]+#)?(?:[^.]+\.)?([^:\/\n\?\=]+)/im EDIT: If you absolutely want to preserve the www into your regex, you could try this one: /^(?:https?:\/\/)?(?:[^#\n]+#)?(?:www\.)?(?:[^.]+\.)?([^:\/\n\?\=]+)/im

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regex detect url and prepend http:// [duplicate]

Trying to Validate URL Using JavaScript

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