Adding a numeric value with an object - javascript

Can anyone explain me that what happens when I add a variable of type object with a numeric value?
I did the following in chrome dev console :
> //Denotes input in dev console
< //Denotes output
> var a={};
< undefined
> a
> Object {}
> a=a+1;
< "[object Object]1"
> a
< "[object Object]1"
> b=2
< 2
> a+b
< "[object Object]12"
Also note that within bracket First is lower-case object and 2nd is uppercase Object.
Thanks.

Rules for JavaScript and mixed-type operations are quite convoluted and depend on the operation, for example for + an extremely simplified description is:
If both are number then the arithmetic sum is performed
If any of the two is not a number then both are converted to string and concatenation is performed
The string conversion of an object (unless you defined what to do) is just "[object Object]" and that explains the results you described in the question.
Note that this is not the whole truth... things are much more convoluted and a full description require concepts like .toValue members, special cases for Date objects and so on. Moreover things are getting more and more complex as time passes (ES6 behavior for example requires introduction of concepts like distinction between "exoticToPrim" and "OrdinaryToPrimitive").
Unfortunately I am not kidding.
In case you want to understand better pay attention when writing test programs that you cannot trust the == operator to check what the result is because the rules for that equality operator are even more convoluted (bordering total madness, actually). == in Javascript is just a bug-hiding shelter and should have no place in any code (if strangely enough you really want what it does then implement that behavior explicitly and comment on why it is needed instead of just using ==).
Always use ===.

a = a+1
It first looks if a is a numerical value or not, if it is then the behaviour is normal mathematical operation.
Otherwise it typecast a in a string and proceed with normal string concatenation. The default conversion from an object to string is [object Object], so a+1 will be [object Object]1
Try doing stringify({});, it prints [object Object]

When you use plus operator object a converts to string using toString method. And then strings a and b concatenate

This is called as type coercion. variable a cannot be added with 1 technically. So it coerced to string and then get concatenated with the numeric 1.
var a = {} + 1; //[object object]1
//--> string form of {} will be [object object]
//--> + operator will use its overload concatenation when it is used over a string.
//--> The type of value returned after this operation will be a string.

You will love this one: https://youtu.be/20BySC_6HyY?t=1m26s It's all about JavaScript trying to correct your variable types. It has some crazy edge cases. e.g.
"+" is to "add" 2 strings to form new one or to add 2 numbers to make a "sum". What is in your situation - you are trying to change variable types to strings or numbers and make new string or number. Js decided to make new string:
var a = {}
// Output: Object {}
a.toString();
// Output: "[object Object]"
To learn more i highly recommend this:
http://jibbering.com/faq/notes/type-conversion/

Related

Socket on returning [Object Object] on browser console [duplicate]

I'm running this in node.js:
> x = { 'foo' : 'bar' }
{ foo: 'bar' }
> console.log(x)
{ foo: 'bar' }
undefined
> console.log("hmm: " + x)
hmm: [object Object]
undefined
What I don't understand is why console.log(x) "pretty-prints" the object, whereas string concatenation "ugly-prints" it. And more importantly, what's the best way to make it print hmm: { foo: 'bar' }?
The + x coerces the object x into a string, which is just [object Object]:
http://jsfiddle.net/Ze32g/
The pretty printing is a very nice and probably very complex underlying code that someone implemented as part of the console object and the log method.
Try this:
console.log("hmm: ", x);
The console.log function
'console.log' is an overloaded function that accepts a list of parameters that are either passed by copy (string|number|boolean) or by reference (everything else).
In the case of values passed by copy, the value is printed by casting it as a string.
In the case of values passed by reference, the value is pretty printed as the browser sees fit.
The + operator
The plus sign operator (+) is overloaded.
When both sides of the operator are numbers, the sum of the two operators is returned.
If either side of the operator is a string, then both sides will be cast as string and the concatenation of those two strings will be returned.
console.log("hmm: " + x);
is the same as writing
console.log(String("hmm: ") + String(x));
Solution
Prevent the implicit string casting by swapping the plus sign (+) with a comma (,)
console.log("hmm: ", x);
More Info
For a more in depth description of the 'console.log' function, see:
https://developer.mozilla.org/en-US/docs/DOM/console.log
For a more in depth description on the plus sign operator (+), see:
http://www.w3schools.com/js/js_operators.asp
Use JSON.stringify when printing an object with string appending
console.log("Haa"+JSON.stringify(x))
you can use console.log(JSON.stringify(yourObject)); to print your object. it work!
You have multiple options:
process.stdout.write('hmm: ')
console.dir(x)
Another...
var util = require('util')
process.stdout.write('hmm: ')
console.log(util.inspect(x, true, 10, true))
See util.inspect docs for more info.
Edit: Sorry, my mind thought I read Node.js. This is valid for Node.js only. So, I'll leave it for any Googlers.
Edit2: I'm not crazy, I just need sleep. You did write Node.js. I'm going to add it as a tag.

Why does [[]][0]++ work but []++ throws run-time exception?

Why does the first line work while the second line throws run-time exception?
The first line:
[[]][0]++; //this line works fine
The second line:
[]++; //this lines throws exception
[[]][0]++
is equivalent to
var tmp = [[]];
tmp[0] = tmp[0]+1;
tmp[0] is an empty array, which is cast to the number 0, which increments to 1.
This only works because <array>[<index>]++ looks valid. It takes some type juggling, but it gets there.
But []++ is outright invalid. There's no way to make it make sense.
[] = []+1;
The left-hand side here is indeed invalid. You can't assign to an empty array.
The ++ operator (or indeed any postfix operator) requires the operand to be a "reference" - that is, a value that can be assigned to. [] is a literal, so you can't assign to it. [[]][0] is a valid reference to an element of a temporary array.
0++; // not valid, `0` is a literal.
var a = [];
a++; // ok, `a` is assignable
This is a rare case in which Javascript does something that actually makes sense. Consider
x[3]++; // Valid
3++; // Not valid
If this make sense for you, then what is surprising about
[[]][0]++; // valid
[]++; // not valid
<array>[index] is "a place" that you can assign or increment. That's all. The fact that you can increment a[<expr>] doesn't imply that you can increment <expr>.
The absurd part is that you can use [] as an index, that has the meaning of converting the array to an empty string "" and then to the number 0, but this is the well known problem of absurd implicit conversions of Javascript. Those implicit conversion rules are a big wart of Javascript and for example imply that 1 == [1] or that both []==false and (![])==false.
Javascript is pure nonsense in a lot of places... but not really here.

What is the difference between String and new String? [duplicate]

Taken from MDN
String literals (denoted by double or single quotes) and strings
returned from String calls in a non-constructor context (i.e., without
using the new keyword) are primitive strings. JavaScript automatically
converts primitives to String objects, so that it's possible to use
String object methods for primitive strings. In contexts where a
method is to be invoked on a primitive string or a property lookup
occurs, JavaScript will automatically wrap the string primitive and
call the method or perform the property lookup.
So, I thought (logically) operations (method calls) on string primitives should be slower than operations on string Objects because any string primitive is converted to string Object (extra work) before the method being applied on the string.
But in this test case, the result is opposite. The code block-1 runs faster than the code block-2, both code blocks are given below:
code block-1 :
var s = '0123456789';
for (var i = 0; i < s.length; i++) {
s.charAt(i);
}
code block-2 :
var s = new String('0123456789');
for (var i = 0; i < s.length; i++) {
s.charAt(i);
}
The results varies in browsers but the code block-1 is always faster. Can anyone please explain this, why the code block-1 is faster than code block-2.
JavaScript has two main type categories, primitives and objects.
var s = 'test';
var ss = new String('test');
The single quote/double quote patterns are identical in terms of functionality. That aside, the behaviour you are trying to name is called auto-boxing. So what actually happens is that a primitive is converted to its wrapper type when a method of the wrapper type is invoked. Put simple:
var s = 'test';
Is a primitive data type. It has no methods, it is nothing more than a pointer to a raw data memory reference, which explains the much faster random access speed.
So what happens when you do s.charAt(i) for instance?
Since s is not an instance of String, JavaScript will auto-box s, which has typeof string to its wrapper type, String, with typeof object or more precisely s.valueOf(s).prototype.toString.call = [object String].
The auto-boxing behaviour casts s back and forth to its wrapper type as needed, but the standard operations are incredibly fast since you are dealing with a simpler data type. However auto-boxing and Object.prototype.valueOf have different effects.
If you want to force the auto-boxing or to cast a primitive to its wrapper type, you can use Object.prototype.valueOf, but the behaviour is different. Based on a wide variety of test scenarios auto-boxing only applies the 'required' methods, without altering the primitive nature of the variable. Which is why you get better speed.
This is rather implementation-dependent, but I'll take a shot. I'll exemplify with V8 but I assume other engines use similar approaches.
A string primitive is parsed to a v8::String object. Hence, methods can be invoked directly on it as mentioned by jfriend00.
A String object, in the other hand, is parsed to a v8::StringObject which extends Object and, apart from being a full fledged object, serves as a wrapper for v8::String.
Now it is only logical, a call to new String('').method() has to unbox this v8::StringObject's v8::String before executing the method, hence it is slower.
In many other languages, primitive values do not have methods.
The way MDN puts it seems to be the simplest way to explain how primitives' auto-boxing works (as also mentioned in flav's answer), that is, how JavaScript's primitive-y values can invoke methods.
However, a smart engine will not convert a string primitive-y to String object every time you need to call a method. This is also informatively mentioned in the Annotated ES5 spec. with regard to resolving properties (and "methods"¹) of primitive values:
NOTE The object that may be created in step 1 is not accessible outside of the above method. An implementation might choose to avoid the actual creation of the object. [...]
At very low level, Strings are most often implemented as immutable scalar values. Example wrapper structure:
StringObject > String (> ...) > char[]
The more far you're from the primitive, the longer it will take to get to it. In practice, String primitives are much more frequent than StringObjects, hence it is not a surprise for engines to add methods to the String primitives' corresponding (interpreted) objects' Class instead of converting back and forth between String and StringObject as MDN's explanation suggests.
¹ In JavaScript, "method" is just a naming convention for a property which resolves to a value of type function.
In case of string literal we cannot assign properties
var x = "hello" ;
x.y = "world";
console.log(x.y); // this will print undefined
Whereas in case of String Object we can assign properties
var x = new String("hello");
x.y = "world";
console.log(x.y); // this will print world
String Literal:
String literals are immutable, which means, once they are created, their state can't be changed, which also makes them thread safe.
var a = 's';
var b = 's';
a==b result will be 'true' both string refer's same object.
String Object:
Here, two different objects are created, and they have different references:
var a = new String("s");
var b = new String("s");
a==b result will be false, because they have different references.
If you use new, you're explicitly stating that you want to create an instance of an Object. Therefore, new String is producing an Object wrapping the String primitive, which means any action on it involves an extra layer of work.
typeof new String(); // "object"
typeof ''; // "string"
As they are of different types, your JavaScript interpreter may also optimise them differently, as mentioned in comments.
When you declare:
var s = '0123456789';
you create a string primitive. That string primitive has methods that let you call methods on it without converting the primitive to a first class object. So your supposition that this would be slower because the string has to be converted to an object is not correct. It does not have to be converted to an object. The primitive itself can invoke the methods.
Converting it to an full-blown object (which allows you to add new properties to it) is an extra step and does not make the string oeprations faster (in fact your test shows that it makes them slower).
I can see that this question has been resolved long ago, there is another subtle distinction between string literals and string objects, as nobody seems to have touched on it, I thought I'd just write it for completeness.
Basically another distinction between the two is when using eval. eval('1 + 1') gives 2, whereas eval(new String('1 + 1')) gives '1 + 1', so if certain block of code can be executed both 'normally' or with eval, it could lead to weird results
The existence of an object has little to do with the actual behaviour of a String in ECMAScript/JavaScript engines as the root scope will simply contain function objects for this. So the charAt(int) function in case of a string literal will be searched and executed.
With a real object you add one more layer where the charAt(int) method also are searched on the object itself before the standard behaviour kicks in (same as above). Apparently there is a surprisingly large amount of work done in this case.
BTW I don't think that primitives are actually converted into Objects but the script engine will simply mark this variable as string type and therefore it can find all provided functions for it so it looks like you invoke an object. Don't forget this is a script runtime which works on different principles than an OO runtime.
The biggest difference between a string primitive and a string object is that objects must follow this rule for the == operator:
An expression comparing Objects is only true if the operands reference
the same Object.
So, whereas string primitives have a convenient == that compares the value, you're out of luck when it comes to making any other immutable object type (including a string object) behave like a value type.
"hello" == "hello"
-> true
new String("hello") == new String("hello") // beware!
-> false
(Others have noted that a string object is technically mutable because you can add properties to it. But it's not clear what that's useful for; the string value itself is not mutable.)
The code is optimized before running by the javascript engine.
In general, micro benchmarks can be misleading because compilers and interpreters rearrange, modify, remove and perform other tricks on parts of your code to make it run faster.
In other words, the written code tells what is the goal but the compiler and/or runtime will decide how to achieve that goal.
Block 1 is faster mainly because of:
var s = '0123456789'; is always faster than
var s = new String('0123456789');
because of the overhead of object creation.
The loop portion is not the one causing the slowdown because the chartAt() can be inlined by the interpreter.
Try removing the loop and rerun the test, you will see the speed ratio will be the same as if the loop were not removed. In other words, for these tests, the loop blocks at execution time have exactly the same bytecode/machine code.
For these types of micro benchmarks, looking at the bytecode or machine code wil provide a clearer picture.
we can define String in 3-ways
var a = "first way";
var b = String("second way");
var c = new String("third way");
// also we can create using
4. var d = a + '';
Check the type of the strings created using typeof operator
typeof a // "string"
typeof b // "string"
typeof c // "object"
when you compare a and b var
a==b ( // yes)
when you compare String object
var StringObj = new String("third way")
var StringObj2 = new String("third way")
StringObj == StringObj2 // no result will be false, because they have different references
In Javascript, primitive data types such is string is a non-composite building block. This means that they are just values, nothing more:
let a = "string value";
By default there is no built-in methods like toUpperCase, toLowerCase etc...
But, if you try to write:
console.log( a.toUpperCase() ); or console.log( a.toLowerCase() );
This will not throw any error, instead they will work as they should.
What happened ?
Well, when you try to access a property of a string a Javascript coerces string to an object by new String(a); known as wrapper object.
This process is linked to concept called function constructors in Javascript, where functions are used to create new objects.
When you type new String('String value'); here String is function constructor, which takes an argument and creates an empty object inside the function scope, this empty object is assigned to this and in this case, String supplies all those known built in functions we mentioned before. and as soon as operation is completed, for example do uppercase operation, wrapper object is discarded.
To prove that, let's do this:
let justString = 'Hello From String Value';
justString.addNewProperty = 'Added New Property';
console.log( justString );
Here output will be undefined. Why ?
In this case Javascript creates wrapper String object, sets new property addNewProperty and discards the wrapper object immediately. this is why you get undefined. Pseudo code would be look like this:
let justString = 'Hello From String Value';
let wrapperObject = new String( justString );
wrapperObject.addNewProperty = 'Added New Property'; //Do operation and discard

Why does `{} + []` return a different result from `a = {} + []` in Javascript?

In (at least) Firefox Web Console and JSBin, I get
> {} + []
0
> a = {} + []
"[object Object]"
Node.js returns "[object Object]" in both cases. Which behavior is correct according to the spec? If the first, why?
On the browser console, when it isn't preceded by a = (or some other code that changes its context), {} is treated as a block, not an object literal.
Since the block is empty it does nothing, leaving + [].
The unary plus operator converts the array to a number, which is 0.
When using an operator against objects the javascript interpreter should cast the values to primitive using the valueOf method which in fact use the internal ToPrimitive function relaying type casting to object's internal [[DefaultValue]] method.
Your example with the plus operator is a bit tricky because the operator can acts both as math addition or string concatenation. In this case it concatenates string representations of the objects.
What is really happening behind the scene is:
a = {}.valueOf().toString() + [].valueOf().toString();
Since the array is empty the toString method returns an empty string, that's why the correct result should be [object Object] which is the return value from object.valueOf()toString().

Converting an int64 value to a Number object in JavaScript

I have a COM object which has a method that returns an unsigned int64 (VT_UI8) value. We have an HTML page which contains some JavaScript which can load the COM object and make the call to that method, to retrieve the value as such:
var foo = MyCOMObject.GetInt64Value();
This value can easily be displayed to the user in a message dialog using:
alert(foo);
or displayed on the page by:
document.getElementById('displayToUser').innerHTML = foo;
However, we cannot use this value as a Number (e.g. if we try to multiply it by 2) without the page throwing "Number expected" errors. If we check "typeof(foo)" it returns "unknown".
I've found a workaround for this by doing the following:
document.getElementById('displayToUser').innerHTML = foo;
var bar = parseInt(document.getElementById('displayToUser').innerHTML);
alert(bar*2);
What I need to know is how to make that process more efficient. Specifically, is there a way to cast foo to a String explicitly, rather than having to set some document element's innerHTML to foo and then retrieve it from that. I wouldn't mind calling something like:
alert(parseInt((string)foo) * 2);
Even better would be if there is a way to directly convert the int64 to a Number, without going through the String conversion, but I hold out less hope for that.
This:
alert(Number(String(foo)) * 2);
should do it (but see below), if your COM object implements toString (or valueOf with the "string" hint) correctly (and apparently it does, if your innerHTML trick works -- because when you assign foo to innerHTML, the same process of converting the COM object to a string occurs as with String(foo)).
From Section 15.5.1 of the 5th Edition ECMAScript spec:
When String is called as a function rather than as a constructor, it performs a type conversion.
And Section 15.7.1
When Number is called as a function rather than as a constructor, it performs a type conversion
It may be worth trying just Number(foo) * 2 to make sure, but I don't think it'll work (it seems like your COM object only handles conversion to String, not Number, which isn't surprising or unreasonable).
Edit If String(foo) is failing, try:
alert(Number("" + foo) * 2);
I'm very surprised that your innerHTML trick is working but String(foo) is throwing an error. Hopefully "" + foo will trigger the same implicit conversion as your innerHTML trick.
Edit Okay, this COM object is being very strange indeed. My next two salvos:
alert(("" + foo) * 2);
That uses all implicit conversions (adding an object to a string converts the object to a string; applying the * operator to a string converts it to a number).
Alternately, we can make the string->number conversion explicit but indirect:
alert(parseInt("" + foo) * 2);
Eek. Well if none of the explicit conversions are working because of the strange behaviour of the host object, let's try the implicit ones:
var n= +(''+foo);
I'm assuming you don't mind that the target type Number doesn't cover the full range of values of an int64 (it's a double, so you only get 52 bits of mantissa).
Matt, from the comments to other answers, I suspect you're running this code in some sort of loop. If so, make sure that you check the returned value for null before trying your conversions.
var foo = MyCOMObject.GetInt64Value();
if (foo == null) {
foo = 0; // Or something else
}

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