Develop Reference

How to make the div editable to textarea and upload/delete existing images

I have a website where user can upload images, name and description. I am saving it in mysql and fetching that information to show on my website. That's what my below code does, let the user enter those information (image and text) and show it on the website when they click submit button.
My question is how can I make the div (that shows images, name and desc) to editable when user clicks the edit button (so change that same div to textarea or something that is editable) and for images should have an cross mark near the image when clicked on edit button, so user can delete it and upload button to upload more images.
What I have done: I try to use javascript to get the value of div and use that to change it to textarea, but it says the value is undefined for the grid div.
So, how can I make my div editable as explained above, as what I have try so far is not complete, so is there any better way to make the div editable same way I explained above so user can edit text and upload or delete images?
My code:
<?php
require "database.php"; // connecting to database
session_start();
global $username;
$username = $_SESSION['userUsername'].$_SESSION['userId']; //fetching the username
$image = "userPos/$username"; //fetching image posted by specific user
function listFolderFiles($dir, $username){
<!-- The div my_class is getting the images from local storage
that was initially uploaded by user in the website
(and we stored it in the local storage) to display them on the website -->
echo '<div class="my_class">';
$ffs = scandir($dir);
unset($ffs[array_search('.', $ffs, true)]);
unset($ffs[array_search('..', $ffs, true)]);
// prevent empty ordered elements
if (count($ffs) < 1)
return;
foreach($ffs as $ff){
$s = "'<li>'.$ff";
$saving = "$dir/$ff";
$string = "$saving";
global $string_arr;
$string_arr = (explode("/",$string));
$sav;
$sav = '<li>'.$ff;
global $sa;
$sa = "$ff";
echo '<div class="imagess">';
if(is_file($saving)) {
echo '
<div class="images">
<img src="'.$saving.' " width="100" height="100" alt="Random image" class="img-responsive" />
</div>
' ;
}
echo `</div>`;
if(is_dir($dir.'/'.$ff)) listFolderFiles($dir.'/'.$ff, $username);
}
echo `</div>`;
require "database.php";
<!--Here we are fetching the name and description
that was entered by user on the website
and displaying them on the website now-->
$username = $_SESSION['userUsername'].$_SESSION['userId'];
$sql = "SELECT * FROM `_desc` WHERE `username` = '$username' AND `id` = '$string_arr[2]';";
$result = mysqli_query($conn, $sql);
$resultCheck = mysqli_num_rows($result);
if($resultCheck > 0) {
echo '</br>';
while($row = mysqli_fetch_assoc($result) ) {
//name and desc
echo '<div class="grid">' . '<h2>' . $row["_name"] . '</h2>' . '</div>';
echo '<div class="grid2">' . '<p>' . $row["_desc"] . '</p>' . '</div>';
}
<!--Here I am trying when user click on edit button it should
change that div to editable textarea so user can edit
and save it or delete the whole div-->
echo '<button onClick="editName()" class="btn btn-info">
Edit</button>';
echo '<a href="deleteUserInfo.php?edit= '.
$row["id"].'"class="btn btn-danger ">Delete</a>';
}
echo '</div>';
}
listFolderFiles($image, $username);
?>
<script>
function editName() {
console.log("calling");
var divName = $("grid").html();
console.log(divName); //value is undefined here
var editableName = $("<textarea />");
editableName.val(divName);
$("grid").replaceWith(editableName);
editableName.focus();
editableName.blur(saveName);
}
function saveName() {
var htmlName = $(editableName).html();
var viewableText = $("<div>");
viewableText.html(htmlName);
$(editableName).replaceWith(viewableText);
$(viewableText).click(editName);
}
</script>
</body>
</html>

It is quite simple, you should use contenteditable attribute available and set that value to true. This will make the div element editable.
Like this,
<div class="grid" contenteditable="true">I am editable!</div>
In your case, you should use a function to select the element and set the attribute to true. And for the div element on clicking the type='file' input tag, you can write function that will delete the file that is previously uploaded and upload the new file. I would recommend you to research before posting a question in the community as you might get negative impacts on such questions. Hope it helps! Happy coding!!

When the user clicks the edit button, set the contenteditable attribute to true on the target element and set the focus to that element.
function editName() {
$("grid").attr("contenteditable", true);
$("grid").focus();
$("grid").blur(saveName);
}

Expanding the content by click it

When i click the more. I wanted the content should expand. I my page i have about 10 question with more option. The question content is coming through the php script.
<?php
$result = mysqli_query($conn, $query) or die("error: " . mysqli_error($conn));
//fetch the data.
if (mysqli_num_rows($result) > 0) {
while($data = mysqli_fetch_assoc($result)) {
$question = $data['question'];
echo "<span class=\"spanstyle\" id=\"fullquestion\">" . substr($question, 0, 170);
echo "...more</span><br>";
}
}
?>
I try to do that by javascript. ContectExpand() fire of when i click.
<script>
function contentExpand() {
var question = <?php echo $question; ?>;
document.getElementById("content").innerHTML = question;
}
</script>
Problem is, $question is changing the value as it is inside the loop. It doesn't have a fixed value.
Also I want to know that I can do that only along with php without javascipt.

For my solution you need some sort of $data['id'], which is unique for each question.. I think it cannot be done only in PHP, but you should try to use jQuery, it makes javascript much easier
<?php
$result = mysqli_query($conn, $query) or die("error: " . mysqli_error($conn));
//fetch the data.
if (mysqli_num_rows($result) > 0) {
while($data = mysqli_fetch_assoc($result)) {
$question = $data['question'];
echo "<span class='spanstyle' id='shortQuestion{$data['id']}'>" . substr($question, 0, 170).
"...<a href='#' onClick='return contentExpand({$data['id']});'>more</a></span>
<span class='spanstyle' id='longQuestion{$data['id']}'>{$data['question']}</span>
<br>";
}
}
?>
Javascript
<script>
function contentExpand( fullcontentId ) {
document.getElementById('shortQuestion'+fullcontentId).style.display = "none";
document.getElementById('longQuestion'+fullcontentId).style.display = "inline";
return false;
}
</script>

There are several issues with you code. Regarding your question, the most important are:
The while loop is generating several span elements with the same id.
The onClick function should content a reference to the element you want to expand.
You dind't include any code constraining the size of the span element, so there is nothing to be expanded.
How to fix them:
Modify the while loop
Create a $i variable that counts the rows and add it to the span id, to the link id and to the javascript function in this way:
$i = 0;
while($data = mysqli_fetch_assoc($result)) {
$i++;
$question = $data['question'];
echo "<span class='spanstyle' id='fullquestion_" . $i. "' >";
echo "<a href='#' id='link_" . $i . "' onClick='contentExpand(" . $i. ");'>more</a> ";
echo $question."</span><br>";
}
Create a javascript function that resize the span element:
You didn't tell us how you want to expand the content. There would be a lot of different ways to achieve it. This is just one that tries to respect your HTML markup, but surely not the best:
<script>
function contentExpand(id) {
var link = document.getElementById('link_'+id);
var span = document.getElementById('fullquestion_'+id);
if(link.innerHTML=='more')
{
link.innerHTML = 'less';
span.style.width = '100px';
}else{
link.innerHTML = 'more';
span.style.width = 'auto';
}
}
</script>
Modify the css of the span element:
A block element like a div would suit better anyway, but maybe you have very good reasons to use a span.
span {
white-space: nowrap;
overflow: hidden;
text-overflow: ellipsis;
text-align: right;
}
How to do it without javascript (just PHP):
It is certainly possible, but I guess you don't want to do it.
But if still you want to do so, generate the loop with just partial information about the related $question (as you do in the original code, substr($question, 0, 170)) but put the elements inside a form.
When the user click the more span element, submit the form to send from the client back to the server the information about the selected item.
Then, the PHP script would generate again the page but, this time, the selected item will load the full text of the question ($question instead of substr($question, 0, 170)).
So, you will have to make a new HTTP request call (that means to reload the page, AJAX is not an option if you don't want to use javascript).
Doing all this add a new layer of complexity and make it less efficient.
My advice is, if you don't have strong reasons to don't use javascript, use it.

cannot impliment infinite scroll with my code

I've read multiple examples on infinite scrolling, but I find it hard to implement it to my code. Here's the code, where data get shown from MySQL database :
<div class="container" align="center" style="margin-top:100px;margin-bottom:100px"><div class="row">
<?php
$result = mysql_query("SELECT * FROM batai WHERE svarbumas=1 ORDER BY id DESC");
while ($row = mysql_fetch_array($result))
{
extract($row);
$link=$row["linkas"];
echo "<div class='col-md-4'>";
$sites_html = file_get_contents($link);
$html = new DOMDocument();
#$html->loadHTML($sites_html);
$meta_og_img = null;
//Get all meta tags and loop through them.
foreach($html->getElementsByTagName('meta') as $meta) {
//If the property attribute of the meta tag is og:image
if($meta->getAttribute('property')=='og:image'){
//Assign the value from content attribute to $meta_og_img
$meta_og_img = $meta->getAttribute('content');
}
}
list($width, $height) = getimagesize($meta_og_img);
$skaicius = abs($width - $height);
if($width > $height) {
echo "<img src=\"$meta_og_img\" style='height:234px;margin-left:-33%' onclick='window.open(\"$link\", \"_blank\");'>";
}
else if($width < $height) {
if($skaicius < 100){
echo "<img src=\"$meta_og_img\" style='width:234px'
onclick='window.open(\"$link\", \"_blank\");'>";
}
else {
echo "<img src=\"$meta_og_img\" style='width:234px;margin-top:-33%'
onclick='window.open(\"$link\", \"_blank\");'>";
}
}
echo "</div>";
}
?>
Stored in the database is a link to, for example, a internet shop page. What the code does is it takes a image for facebook preview from the link stored in the db, which is tagged og:image and then positions it to center. The problem is that page tries to load every image and that takes a ton of time to load the page, thats why I want to somehow make it into a load on scroll page. Btw, Im using Bootstrap's grid system here. I hope you can help me. P.S. If you don't get what I mean because of my bad english, ask me and I'll try to answer it more clearly

Trying to show full size image from thumbnails retrieved using php and database

I'm trying to use thumbnails retrieved from database. PHP is working fine and displaying my thumbnails. I don't know how to get the id from database into the imageID for JavaScript function and getElementById, to display as full size when clicked. I can do straight JavaScript inline onsubmit in my code. The inline JavaScript is working; the thumbnail is being displayed, and when clicked a full size shows, but I want to use my database retrieved images to show the full size image when clicked. Do you think you can help me with my code?
<!DOCTYPE html>
<html lang="en">
<head>
<title></title>
<script type="text/javascript">
//function that shows full sized image of the thumbnail
function showImage(imageID) {
//first hide all images
document.getElementById('image1').style.display = 'none';
//then display the one that had its thumbnail clicked.
document.getElementById(imageID).style.display = '';
}
</script>
</head>
<body>
<h1></h1>
<?php
$host = "localhost";
$user = "root";
$pass = "";
$database = "travel1";
$conn = new mysqli($host, $user, $pass, $database);
if ($conn->connect_error)
die ("Unable to connect to database: " . $conn->connect_error );
$sql = "select * from what_to_do
where DESTINATION='NEW YORK CITY'";
$result = $conn->query($sql);
if ($result->num_rows >= 0) {
echo "<table>";
while($row = $result->fetch_assoc()) {
echo "<td>".$row["THUMBNAIL"]."</td>";
}
echo "</table>";
}
else {
echo "You have no destinations";
}
$conn->close();
?>
<p>
<img id="image1" alt="" src="images/NewYork/Pick7/9-11show.jpg"
style="display: none" />
</p>
<p>
<img alt="" src="="images/NewYork/Pick7/9-11thumb.JPG"style="width:100px;
height:100px" onclick="showImage('image1')" />
</p>

In this code the second img tag is closed prematurely, like src="something" etc etc. If that tag were properly formed, I think this should work?
Otherwise, you would just do something like " src="/blah" />
Hopefully that answers your question?
And then for the I onclick function just do essentially the same thing.

I'm going to presume a lot, but here goes!
The above answer is correct, you are prematurely closing an image tag at the bottom of your code, it should be like this:
<img alt="" src="images/NewYork/Pick7/9-11thumb.JPG" style="width:100px;
height:100px;" onclick="showImage('image1')" />
But otherwise there are a few other issues to address...
First, by typing in the specific name of the destination for each query on every page you'll be defeating the purpose in using a database! Just like you've mentioned, you need to use the ID and pull in the data accordingly.
To do this you need to define what the ID is by letting the user select the destination on a previous page/section(in your example a destination list might be appropriate with all the destinations in some kind of order, be that ascending or descending ect... PHP has a few different ways.)
So first, the query to sort by ID is:
SELECT * FROM travel1 order by id desc
and then to set the ID in the URL when the destination link is clicked, here's an example link using php to carry the ID to the next page:
more info
Once you get to the destination info page(that's what I'm calling your above code), filter your data so that you can access the specific destination by ID by firstly adding this to your page(after you've connected to the database that is):
<?php
if(isset($_GET['id'])){
$id = preg_replace('#[^0-9]#i', '',$_GET['id']);
$result = $con->query("SELECT * FROM travel1 WHERE id='$id' ");
while($rows = $result->fetch_assoc()) {
echo "<td>".$row["THUMBNAIL"]."</td>";
}
} else {
echo "We're having some issues...";
}
?>
The above code will pick up the database ID from your URL which was carried over from the previous page(your new destination list) and can be echoed out like your other links such as:
'echo "<td>".$row["THUMBNAIL"]."</td>";'
I hope this helped! =D

mysql loop to display images. Need help to pass/setting count for each image - javascript

I have a sql loop that displays images from a database. I then put all the paths of the images in a js array. Which i pass to an onClick function. Which works ok. But my question is can i pass or associate the count value after each iteration of the loop to the corresponding image
ie if i click on the first image "0" get passed to the function so i can use it to get the corrseponding image path from the array.
Thanks in advance for any help.
<script type="text/javascript">
var pathArray=new Array();
var count = -1;
</script>
<?php
while($row = mysqli_fetch_array($result))
{
?>
<script type="text/javascript">
path = '<?php echo $row['path'];?>';
pathArray.push(path);
count++;
</script>
<div id="displayimage"><img src="<?php echo $row['path'];?>" width="200px" height="156px" style="border:solid 2px white;margin-left:15px;" onclick="openImages(pathArray,count);"></div>
<?php
$i++;
if($i % 3 === 0)
{
echo "<br /><br /><br />";
}
}

All you have to do is put the server-side variable into the call to openImages:
onclick="openImages(<?php echo $i; ?>);"
Then, make the openImages function take an integer as the parameter (remove the others, they're not needed):
function openImages(i) {
alert(path[i]);
}
Alternatively, maybe it would be easier to simply send the path as the parameter? Then you could remove the script block from the loop entirely. (That is, assuming you don't have other uses for pathArray.)
onclick="openImages('<?php echo $row['path']; ?>')"