Develop Reference

Unique comment section per dynamic modal

I have a webpage with dynamically loaded cards that pop up into individual modals to display more data. These modals all have their unique id in order to pop up the correct one.
I am attempting to put a unique comment section for each modal. What I have implemented works only for the first modal & doesnt even show the comments on the second modal onwards.
I would appreciate some direction in how to make them display per modal & how to make them unique. I am assuming I echo $test[id] just like I used for the modals. Need a little assistance in script side of things.
<div id="myModal<?php echo $test['id']; ?>" class="modal">
<div class="modal-content">
<div class="container">
<form method="POST" id="comment_form">
<input type="hidden" id="id" name="id" value="<?php echo $test['id']; ?>">
<div class="form-group">
<input type="text" name="comment_name" id="comment_name" class="form-control" placeholder="Enter Name" />
</div>
<div class="form-group">
<textarea name="comment_content" id="comment_content" class="form-control" placeholder="Enter Comment" rows="5"></textarea>
</div>
<div class="form-group">
<input type="hidden" name="comment_id" id="comment_id" value="0" />
<input type="submit" name="submit" id="submit" class="btn btn-info" value="Submit" />
</div>
</form>
<span id="comment_message"></span>
<br />
<div id="display_comment<?php echo $test['id']; ?>"></div>
</div>
</div>
</div>
<script>
var data = 1;
$(document).ready(function(){
$('#comment_form').on('submit', function(event){
event.preventDefault();
var form_data = $(this).serialize();
$.ajax({
url:"add_comment.php",
method:"POST",
data:form_data,
dataType:"JSON",
success:function(data)
{
if(data.error != '')
{
$('#comment_form')[0].reset();
$('#comment_message').html(data.error);
$('#comment_id').val('0');
load_comment();
}
}
})
});
load_comment();
function load_comment()
{
$.ajax({
url:"fetch_comment.php",
method:"POST",
success:function(data)
{
$('#display_comment').html(data);
}
})
}
$(document).on('click', '.reply', function(){
var comment_id = $(this).attr("id");
$('#comment_id').val(comment_id);
$('#comment_name').focus();
});
});
</script>
UPDATE:
Going with the response received, I made certain changes & noticed that even though the comment form is visible on all modals, the posted comments itself
only appear on the first modal. With a bit of hardcoding I am able to tell that the display_comment(id) in html & script needs to be same. The HTML id updates as per console, but I am unable to pass the correct id to $('#display_comment'+myData1).html(data); (it is always 1).
<div id="myModal<?php echo $test['id']; ?>" class="modal">
<div class="modal-content">
<div class="container">
<form method="POST" id="comment_form">
<input type="hidden" id="id" name="id" value="<?php echo $test['id']; ?>">
<div class="form-group">
<input type="text" name="comment_name" id="comment_name" class="form-control" placeholder="Enter Name" />
</div>
<div class="form-group">
<textarea name="comment_content" id="comment_content" class="form-control" placeholder="Enter Comment" rows="5"></textarea>
</div>
<div class="form-group">
<input type="hidden" name="comment_id" id="comment_id" value="0" />
<input type="submit" name="submit" id="submit" class="btn btn-info" value="Submit" />
</div>
</form>
<span id="comment_message"></span>
<br />
<div id="display_comment<?php echo $test['id']; ?>"></div>
</div>
<div id="dom-target" style="display: none;" data-id="<?php echo htmlspecialchars($test['id']);?>">
<?php
echo htmlspecialchars($test['id']);
?>
</div>
</div>
<script>
$(document).ready(function(){
$('#comment_form').on('submit', function(event){
event.preventDefault();
var form_data = $(this).serialize();
$.ajax({
url:"add_comment.php",
method:"POST",
data:form_data,
dataType:"JSON",
success:function(data)
{
if(data.error != '')
{
$('#comment_form')[0].reset();
$('#comment_message').html(data.error);
$('#comment_id').val('0');
load_comment();
}
}
})
});
load_comment();
function load_comment()
{
var myData1 = $("#dom-target").data("id");
console.log('#display_comment'+myData1);
$.ajax({
url:"fetch_comment.php",
method:"POST",
success:function(data)
{
$('#display_comment'+myData1).html(data);
}
})
}
$(document).on('click', '.reply', function(){
var comment_id = $(this).attr("id");
$('#comment_id').val(comment_id);
$('#comment_name').focus();
});
});
</script>
I have also tried the following & simply receive undefined as the value in console for myData2:
$.ajax({
url:"fetch_comment.php",
method:"POST",
data: {
myData2: $("#dom-target").data("id")
},

you should loop all the content according to your $test['id'].
each loop will generate each $test['id'], modals, form.
therefore, you will have multiple form according to each modals.
regarding the name of the input box (name="comment_id","comment_name" etc), just use the same name, as this will affect your backend on how you will process those input ($_POST['']).
this shouldn't be an issue if you area using same input name as user can only submit 1 form on each request.
just the value will be changing based on the form.

Select option ajax inside modal

I have problem with my modal, I have modal and inside my modal I have selecoption factory which my select using ajax jQuery like this
$('#fFactory').change(function(e) {
$.ajax({
type: "POST",
url: host + "budget/FFactory",
data: dataString,
cache: false,
success: function(data) {
console.log($("#fFactory").html(data));
}
});
});
But my problem is, my select option wont work inside modal. How do I trigger my select option inside modal??
My html :
<?php
$json = array();
if($data['title']=='additem')
{
$json['title'] = 'Add Item';
}
else
{
$json['title'] = 'Add Item';
}
$json['body'] = '<div class="row">
<div class="col-sm-12">
<div class="form-group">
<label for="exampleInputEmail1">
Factory
</label>
<select id="fFactory" class="form-control input-sm">
</select>
</div>
<div class="form-group">
<label for="exampleInputPassword1">
Password
</label>
<input type="password" class="form-control" id="exampleInputPassword1" placeholder="Password">
</div>
</div>
</div>';
$json['footer'] = '<button type="button" class="btn btn-primary btn-o modal-close pull-left" data-dismiss="modal">
close
</button>';
// var_dump($json);
echo json_encode($json);
?>
I'm using json. On jQuery when active modal
$('#addbudget').click(function(){
var code = "";
var modal = $('.bs-modal-lg');
var modalData = jQuery.parseJSON(ajaxPOST(code,'budget/form/additem',null,true));
modal.find('.modal-title').html(modalData.title);
modal.find('.modal-body').html(modalData.body);
modal.find('.modal-footer').html(modalData.footer);
modal.modal('show');
});
UPDATE :
How silly I am, I was wrong on json, I forgot have to add function init: on jQuery now it works. I'm so sorry about silly I am. Thanks for all who helping me again :)

Ajax success function not working on the second time

Aim: Continue to display any form validation errors through json callback
Problem: When I submit on the form with invalid input it shows an error message in a div element. If all inputs are valid it will process the ajax request and show a success message in a div element. After which, the form resets but the modal remain open. When I try to again validate the input in doesn't show any error message. When I try to test the valid input still the same no message shown.
In short: Ajax success function not working on the second time.
Here's my code:
Bootstrap Modal (where my form inputs placed)
<div class="modal fade" id='frmModal'>
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button class='close' data-dismiss='modal'>×</button>
<h4 class='title'>Add new data</h4>
</div>
<div class="modal-body">
<?php echo form_open('Employee/save',array('id'=>'frm', 'class'=>'form-horizontal')); ?>
<div id="message"></div>
<div class="form-group">
<label for='fname' class='col-md-3 control-label'>First Name:</label>
<div class="col-md-9">
<input type="text" name="fname" id='fname' class='form-control' placeholder='First Name...'>
</div>
</div>
<div class='form-group'>
<label for='lname' class='col-md-3 control-label'>Last Name:</label>
<div class="col-md-9">
<input type="text" name="lname" id='lname' class='form-control' placeholder='Last Name...'>
</div>
</div>
<div class='form-group'>
<label for='age' class='col-md-3 control-label'>Age:</label>
<div class="col-md-9">
<input type="text" name="age" id='age' class='form-control' placeholder='Age...'>
</div>
</div>
</div>
<div class="modal-footer">
<button class="btn btn-primary action" type='submit'><i class='glyphicon glyphicon-floppy-disk'></i> Save Data</button>
</div>
<?php echo form_close(); ?>
</div>
</div>
</div>
</div>
Jquery Code:
$(document).on('submit','#frm',function(e){
e.preventDefault();
var form = $('#frm');
$.ajax({
url: form.attr('action'),
type: 'POST',
dataType: 'json',
encode: true,
data: form.serialize(),
success: function(data) {
if (!data.success) {
if (data.errors) {
$('#message').html(data.errors).addClass('alert alert-danger');
}
} else {
reloadData();
$('#message').html("<span class='glyphicon glyphicon-ok'></span> " + data.message).removeClass('alert alert-danger').addClass('alert alert-success');
setTimeout(function() {
$("#message").fadeTo(500, 0).slideUp(500, function() {
$(this).remove();
});
}, 3000);
$('#frm')[0].reset();
}
}
});
});
CodeIgniter Controller:
$this->form_validation->set_rules('fname','First Name', 'required|trim');
$this->form_validation->set_rules('lname','Last Name', 'trim|required');
$this->form_validation->set_rules('age','Age', 'trim|numeric|required');
if($this->form_validation->run()===FALSE)
{
$info['success'] = false;
$info['errors'] = validation_errors();
}
else
{
$info['success'] = true;
$data = array(
"firstname" => $this->input->post('fname'),
"lastname" => $this->input->post('lname'),
"age" => $this->input->post('age'),
);
$this->Employee_model->save('ci_table', $data);
$info['message'] = 'Successfully saved data';
}
$this->output->set_content_type('application/json')->set_output(json_encode($info));
}

I think I understand... The form still works but the messages do not appear? If so then try the below...
You are removing the #message element instead of clearing it... try:
$("#message").fadeTo(500, 0).slideUp(500, function() {
$(this).empty();
This way you are emptying the #message element instead of removing it completely..

form submitting twice via ajax POST

Inserting into mysql using php file called via AJAX. Before insert statement php code performs select query to find duplicate records and continue to insert statement.
Issue: When calling php file from ajax. it executed twice and getting response as duplicate record.
well i tried error_log from insert function its called twice.
Trigger point of form validation
$("#load-modal").on("click","#addcountryformsubmitbtn",function(e){
e.preventDefault();
var $form = $("#addcountryform"), $url = $form.attr('action');
$form.submit();
});
This is how form submitted after validation:
}).on('success.form.bv', function(e){
e.preventDefault();
var $form = $("#addcountryform"), $url = $form.attr('action');
$.post($url,$form.serialize()).done(function(dte){ $("#load-modal").html(dte); });
});
using bootstrapvalidator, Core PHP, mysqli, Chrome Browser.
Actual JS:
$(document).ready(function() {
$php_self_country="<?php echo $_SERVER['PHP_SELF']."?pg=countrycontent"; ?>";
$("#country-content").load($php_self_country,loadfunctions);
$("#country-content").on( "click", ".pagination a", function (e){
e.preventDefault();
$("#country-loading-div").show();
var page = $(this).attr("data-page");
$("#country-content").load($php_self_country,{"page":page}, function(){
$("#country-loading-div").hide();
loadfunctions();
});
});
$("#country-content").on("click","#closebtn",function(e){
e.preventDefault();
$("#country-content").load($php_self_country,loadfunctions);
});
});
function loadfunctions(){
$("[data-toggle='tooltip']").tooltip();
$("#country-content").on("click","#addcountrybtn, #addcountrylargebtn",function(e){
e.preventDefault();
$.ajax({
url: $php_self_country,
type: "POST",
data: { 'addcountry':'Y' },
dataType: "html",
cache: false
}).done(function(msg){
$("#load-modal").html(msg);
$("#load-modal").modal('show');
$('input[type="radio"]').iCheck({ checkboxClass: 'icheckbox_minimal', radioClass: 'iradio_minimal' });
modalvalidation();
}).fail(function() {
$("#load-modal").html( "Request Failed. Please Try Again Later." );
});
});
$("#country-content").on("click",".tools a",function(e){
e.preventDefault();
var recordid = $(this).attr("record-id");
$.ajax({
url: $php_self_country,
type: "POST",
data: { 'modifycountry':recordid },
dataType: "html",
cache: false
}).done(function(msg){
$("#load-modal").html(msg);
$("#load-modal").modal('show');
$('input[type="radio"]').iCheck({ checkboxClass: 'icheckbox_minimal', radioClass: 'iradio_minimal' });
modalvalidation();
}).fail(function() {
$("#load-modal").html( "Request Failed. Please Try Again Later." );
});
});
$("#load-modal").on("click","#addcountryformsubmitbtn",function(e){
e.preventDefault();
var $form = $("#addcountryform"), $url = $form.attr('action');
$form.submit();
});
$("#load-modal").on("hide.bs.modal", function () {
window.location.href=$php_self_country_pg;
});
}
function modalvalidation(){
$('#addcountryform').bootstrapValidator({
message: 'This value is not valid',
feedbackIcons: {
valid: 'glyphicon glyphicon-ok',
invalid: 'glyphicon glyphicon-remove',
validating: 'glyphicon glyphicon-refresh'
},
fields: {
[-------Validation part comes here----------]
}
}).on('success.form.bv', function(e){
e.preventDefault();
var $form = $("#addcountryform"), $url = $form.attr('action');
$.post($url,$form.serialize()).done(function(dte){ $("#load-modal").html(dte); });
});
}
HTML
this html is called on button click addcountrybtn via AJAX and write in to div load-modal which is in base html file.
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>
<h4 class="modal-title"><i class="fa fa-exchange"></i> <?php echo COUNTRYLABEL; ?></h4>
</div>
<div class="modal-body">
<form role="form" method="POST" action="self.php" name="addcountryform" id="addcountryform" class="form-horizontal">
<div class="form-group">
<div class="col-xs-3">
<label for="countryname" class="pull-right">Country Name</label>
</div>
<div class="col-xs-9">
<div class="lnbrd">
<input type="text" class="form-control" name="countryname" placeholder="Enter Country Name">
</div>
</div>
</div>
<div class="form-group">
<div class="col-xs-3">
<label for="crncyname" class="pull-right">Currency Name</label>
</div>
<div class="col-xs-9">
<div class="lnbrd">
<input type="text" class="form-control" name="crncyname" placeholder="Enter Currency Name">
</div>
</div>
</div>
<div class="form-group">
<div class="col-xs-3">
<label for="crncycode" class="pull-right">Currency Code</label>
</div>
<div class="col-xs-9">
<div class="lnbrd">
<input type="text" class="form-control" name="crncycode" placeholder="Enter Currency Code">
</div>
</div>
</div>
<div class="form-group">
<div class="col-xs-3">
<label for="forrate" class="pull-right">Foreign Currency Rate<?php echo isset($icon)?$icon:''; ?></label>
</div>
<div class="col-xs-9">
<div class="lnbrd">
<input type="text" class="form-control" name="forrate" placeholder="Enter Foreign Currency Rate.">
</div>
</div>
</div>
<div class="form-group">
<div class="col-xs-3">
<label for="taxpercent" class="pull-right">Tax %</label>
</div>
<div class="col-xs-9">
<div class="lnbrd">
<input type="text" class="form-control" name="taxpercent" placeholder="Enter Tax Percentage">
</div>
</div>
</div>
</form>
</div>
<div class="modal-footer clearfix">
<button type="button" class="btn btn-danger pull-right" id="addcountryformsubmitbtn">Add</button>
</div>
</div>
Note:- in Database point of view code works as expected.

Couple of things that I have seen could possibly be the cause.
If you are using IE, I have seen that perform a GET immediately before doing a POST (to the same URL, with the same data being sent over), so it could be worth trying to check for that on your server (and ignore the GET)
Something else it maybe to add the following to the end of your button click events after the AJAX call (actually, normally I'd put the first line at the top with the prevent default, and the return statement obviously goes very last)...
e.stopImmediatePropagation();
return false;

get data From Bootstrap 3 modal form with jquery ajax

i wrote this to get form data and post it to a php page and do some proccess and get back a result to me,i start with getting post data from my bootstrap modal form and i found that the script can't take values from modal form,because the php part i can't upload it to fiddle or somewhere else.
i upload it on my server for rapid review
click on compose;
complete the fields
and when Send button clicked it expect to modal form sent some value to jquery ajax(on submit) but nothing sent from modal inputs to ajax and the whole $_POST array remain null,and whats going on?
hours and hours i searched for doc's and example's,but i couldn't found any answer,some examples works with bootstrap 2,and nothing for the bootstrap 3.
bootstrap 3.3.1,jquery 2.1.1
here is the modal code:
<div class="modal fade" id="largeModal" tabindex="-1" role="dialog" aria-labelledby="largeModal" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>
<h4 class="modal-title" id="myModalLabel">Compose</h4>
</div>
<div class="modal-body">
<form id="sendmail" data-async method="post" role="form" class="form-horizontal">
<div class="form-group">
<label class="col-sm-2" for="inputTo">To</label>
<div class="col-sm-10">
<input type="email" class="form-control" id="inputTo" placeholder="comma separated list of recipients">
</div>
</div>
<div class="form-group">
<label class="col-sm-2" for="inputSubject">Subject</label>
<div class="col-sm-10">
<input type="text" class="form-control" id="inputSubject" placeholder="subject">
</div>
</div>
<div class="form-group">
<label class="col-sm-12" for="inputBody">Message</label>
<div class="col-sm-12">
<textarea class="form-control" id="inputBody" rows="18"></textarea>
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
<button type="submit" class="btn btn-primary" value="Submit">Send</button>
<div id='response'></div>
</div>
</form>
</div>
</div>
</div>
jQuery:
$(document).ready(function () {
$('#sendmail').submit(function () {
$('#response').html("<b>Loading response...</b>");
$.ajax({
type: 'POST',
url: 'proccess.php',
data: $(this).serialize()
})
.done(function (data) {
$('#response').html(data);
})
.fail(function () {
alert("Posting failed.");
});
return false;
});
});
Simple PHP Code:
print_r($_POST);

In your code, this which is provided inside the $.ajax method's object refers ajax object. And it seems that you need to refer to the form from which you have to get the data and serialise it and send it into AJAX request.
Try following code,
$(document).ready(function () {
$('#sendmail').submit(function () {
var that = this;
$('#response').html("<b>Loading response...</b>");
$.ajax({
type: 'POST',
url: 'proccess.php',
data: $(that).serialize()
})
.done(function (data) {
$('#response').html(data);
})
.fail(function () {
alert("Posting failed.");
});
return false;
});
});
here I have referred the form object this by assigning it to that