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Is there any way to filter objects from array of objects that should include all selected values in javascript

Here i have skills array and employees array and i am trying to get the employees that includes all the skills that are included in skills array using reduce, filter or find method. I am trying to stored the filtered employees in filteredItems but got stuck in it.
filteredItems = Skills?.length>0 ?
Employees?.filter((item) => {
return item.Skills.find((ele) => {
return Skills.find((el) => {
if(el.value === ele.id){
return ele
}
})
})
}) : []
Below are the arrays mentioned.
Skills Array
[
{
"value": 6,
"label": "Marketing"
},
{
"value": 20,
"label": "Golang"
}
]
Employees Array
[
{
"name": "Hassan",
"id": 56,
"Skills": [
{
"id": 20,
"name": "Golang",
},
],
},
{
"name": "Haroon",
"id": 95,
"Skills": [
{
"id": 6,
"name": "Marketing",
},
{
"id": 20,
"name": "Golang",
},
],
},
]
For example, in above scenario of arrays it should return employee of id of 95 not return employee of id 56 because it includes skills but not all that are mention in skills array.

I found it easier to first encapsulate an array of skill IDs to search for.
let skillIds = Skills.map(s => s.value);
Then I filtered and compared the end result to the length of the skill Ids array:
let filteredItems = Skills?.length > 0 ?
Employees?.filter(item => item.Skills.filter( s =>
skillIds.includes(s.id)).length==skillIds.length): []
let Skills = [{
"value": 6,
"label": "Marketing"
}, {
"value": 20,
"label": "Golang"
}]
let Employees = [{
"name": "Hassan",
"id": 56,
"Skills": [{
"id": 20,
"name": "Golang",
}],
}, {
"name": "Haroon",
"id": 95,
"Skills": [{
"id": 6,
"name": "Marketing",
},
{
"id": 20,
"name": "Golang",
},
],
}, ]
let skillIds = Skills.map(s => s.value);
let filteredItems = Skills?.length > 0 ?
Employees?.filter(item => item.Skills.filter( s => skillIds.includes(s.id)).length==skillIds.length): []
console.log(filteredItems)

You could create another property in the employees array.. call it "QUalified". Default it to true, then set it to false when the employee doesn't have a skill in the skills array.
let arSkills = [
{
"value": 6,
"label": "Marketing"
},
{
"value": 20,
"label": "Golang"
}
];
let arEmp = [
{
"name": "Hassan",
"id": 56,
"Skills": [
{
"id": 20,
"name": "Golang",
},
],
},
{
"name": "Haroon",
"id": 95,
"Skills": [
{
"id": 6,
"name": "Marketing",
},
{
"id": 20,
"name": "Golang",
},
],
},
];
arEmp.forEach(ele =>{
ele.Qualified = true;
let arTmp = [];
for(let {id} of ele.Skills)
arTmp.push(id)
for(let {value} of arSkills)
if(!arTmp.includes(value))
ele.Qualified = false
});
let arQual = arEmp.filter((ele) =>{
return ele.Qualified
});
console.log(arQual);

How to get the respective JSON object based on id

how to get the respective nested JSON object based on Id. For example below is my complete JSON.
[
{
"id": 1,
"title": "ASD Headquarters",
"items": [
{
"id": 11,
"title": "San Jose",
"items": [
{
"id": 13,
"title": "Jensen Chapman's Team",
"items": [
{
"id": 14,
"title": "Jimmy John"
},
{
"id": 15,
"title": "Daniel Mills"
},
{
"id": 16,
"title": "Chris Boden"
}
]
}
]
},
{
"id": 12,
"title": "Irvine",
"items": [
{
"id": 23,
"title": "Tracey Chapman's Team",
"items": [
{
"id": 24,
"title": "San Jesus"
},
{
"id": 25,
"title": "Fat Albert"
},
{
"id": 26,
"title": "Connor McDavid"
}
]
}
]
},
{
"id": 30,
"title": "San Diego",
"items": [
{
"id": 31,
"title": "Duran Duran's Team",
"items": [
{
"id": 32,
"title": "Amberlynn Pinkerton"
},
{
"id": 33,
"title": "Tony Mejia"
},
{
"id": 34,
"title": "Richard Partridge"
},
{
"id": 35,
"title": "Elliot Stabler"
}
]
},
{
"id": 40,
"title": "Steely Dan's Team",
"items": [
{
"id": 36,
"title": "Tony Stark"
},
{
"id": 37,
"title": "Totally Rad"
},
{
"id": 38,
"title": "Matt Murdock"
},
{
"id": 39,
"title": "Stan Lee"
}
]
}
]
}
]
}
]
From the above json how do i filter only particular nested object which have id as 11 => {"id": 11} using underscore.js
Output which i required is : {
"id":11,
"title":"San Jose",
"items":[
{
"id":13,
"title":"Jensen Chapman's Team",
"items":[
{
"id":14,
"title":"Jimmy John"
},
{
"id":15,
"title":"Daniel Mills"
},
{
"id":16,
"title":"Chris Boden"
}
]
}
]
}

You can use a recursive algorithm to look for an object in the current array as well as the nested ones.
var data = [{"id":1,"title":"ASD Headquarters","items":[{"id":11,"title":"San Jose","items":[{"id":13,"title":"Jensen Chapman's Team","items":[{"id":14,"title":"Jimmy John"},{"id":15,"title":"Daniel Mills"},{"id":16,"title":"Chris Boden"}]}]},{"id":12,"title":"Irvine","items":[{"id":23,"title":"Tracey Chapman's Team","items":[{"id":24,"title":"San Jesus"},{"id":25,"title":"Fat Albert"},{"id":26,"title":"Connor McDavid"}]}]},{"id":30,"title":"San Diego","items":[{"id":31,"title":"Duran Duran's Team","items":[{"id":32,"title":"Amberlynn Pinkerton"},{"id":33,"title":"Tony Mejia"},{"id":34,"title":"Richard Partridge"},{"id":35,"title":"Elliot Stabler"}]},{"id":40,"title":"Steely Dan's Team","items":[{"id":36,"title":"Tony Stark"},{"id":37,"title":"Totally Rad"},{"id":38,"title":"Matt Murdock"},{"id":39,"title":"Stan Lee"}]}]}]}];
console.log(find(12, data));
function find(id, [head, ...tail]) {
if (!head)
return null;
return checkObj(id, head) || find(id, tail);
}
function checkObj(id, obj) {
return obj.id === id ? obj : find(id, obj.items || [])
}
This also uses parameter destructuring in order to conveniently separate the "head" of the array from its "tail".
It could also be done within a single function.
var data = [{"id":1,"title":"ASD Headquarters","items":[{"id":11,"title":"San Jose","items":[{"id":13,"title":"Jensen Chapman's Team","items":[{"id":14,"title":"Jimmy John"},{"id":15,"title":"Daniel Mills"},{"id":16,"title":"Chris Boden"}]}]},{"id":12,"title":"Irvine","items":[{"id":23,"title":"Tracey Chapman's Team","items":[{"id":24,"title":"San Jesus"},{"id":25,"title":"Fat Albert"},{"id":26,"title":"Connor McDavid"}]}]},{"id":30,"title":"San Diego","items":[{"id":31,"title":"Duran Duran's Team","items":[{"id":32,"title":"Amberlynn Pinkerton"},{"id":33,"title":"Tony Mejia"},{"id":34,"title":"Richard Partridge"},{"id":35,"title":"Elliot Stabler"}]},{"id":40,"title":"Steely Dan's Team","items":[{"id":36,"title":"Tony Stark"},{"id":37,"title":"Totally Rad"},{"id":38,"title":"Matt Murdock"},{"id":39,"title":"Stan Lee"}]}]}]}];
console.log(find(12, data));
function find(id, [head, ...tail]) {
if (!head)
return null;
if (head.id === id)
return head;
return find(id, head.items || []) || find(id, tail);
}

Return filtered array js

I have an Array of Objects, each containing Array and Objects, like so:
data = [{
"id": 10022,
"date": "2017-12-31T03:44:19.963808Z",
"bought_beats": [{
"id": 10034,
"beat": {
"id": 6334,
"name": "Glass",
"producer": {
"id": 23,
"display_name": "MadReal",
}
},
"license": {
"id": 10034,
"name": "Premium",
},
}, {
"id": 894,
"beat": {
"id": 6334,
"name": "Other Name",
"producer": {
"id": 25,
"display_name": "Other Name",
}
},
"license": {
"id": 10034,
"name": "Premium",
},
}]
}, {
"moredata": "stuff"
}]
And I need to filter the bought_beats property, and only return beat, if beat.producer.id === 23
This is what I have but it's clearly not working
data.forEach(order => {
return order.bought_beats.filter(item => item.beat.id === producerId)
})
===========
Edit1:
Trying this. It "works", but it also removed some properties (id & date) from each order object (which is each index of data), so I have objects that only contain the array of "bought_beats"
var res = data.map(item => item.bought_beats.filter(item => item.beat.producer.id === 23))
========
Edit2
This seems to be 1 solution, it maintains the array and object structure the same, while it removes those unwanted elements from the bought_beats array.
data.forEach(order => {
let elementToRemoveIndex = order.bought_beats.findIndex(item => item.beat.producer.id !== 23)
order.bought_beats.splice(elementToRemoveIndex, 1)
})
Thanks #Pac0 for the continuous help

use .find over data.bought_beats since its an array,
DEMO
var data = [{
"id": 10022,
"date": "2017-12-31T03:44:19.963808Z",
"bought_beats": [{
"id": 10034,
"beat": {
"id": 6334,
"name": "Glass",
"producer": {
"id": 23,
"display_name": "MadReal",
}
},
"license": {
"id": 10034,
"name": "Premium",
},
}, {
"id": 894,
"beat": {
"id": 6334,
"name": "Other Name",
"producer": {
"id": 25,
"display_name": "Other Name",
}
},
"license": {
"id": 10034,
"name": "Premium",
},
}]
}, {
"moredata": "stuff"
}];
var result = data.find(dat => dat.bought_beats.some(item => item.beat.producer.id === 23));
console.log(result);

If I understood correctly, this should be what you want :
// project each object to its bought_beats / beats part
var beatsArrays = data.filter(x => x.bought_beats).map(x => x.bought_beats);
// flatten the array of arrays of beats into a simple array of beats
var beats = [].concat.apply([],beatsArrays).map(x => x.beat);
// filter
var relevantBeats = beats.filter(item => item.producer.id === 23);
// serve with a cherry in a sugar-frost cocktail glass (happy new year ! )
console.log(relevantBeats);
Snippet :
data = [{
"id": 10022,
"date": "2017-12-31T03:44:19.963808Z",
"bought_beats": [{
"id": 10034,
"beat": {
"id": 6334,
"name": "Glass",
"producer": {
"id": 23,
"display_name": "MadReal",
}
},
"license": {
"id": 10034,
"name": "Premium",
},
}, {
"id": 894,
"beat": {
"id": 6334,
"name": "Other Name",
"producer": {
"id": 25,
"display_name": "Other Name",
}
},
"license": {
"id": 10034,
"name": "Premium",
},
}]
}, {
"moredata": "stuff"
}];
// project each object to its bought_beats / beats part
var beatsArrays = data.filter(x => x.bought_beats).map(x => x.bought_beats);
// flatten the array of arrays of beats into a simple array of beats
var beats = [].concat.apply([],beatsArrays).map(x => x.beat);
// filter
var relevantBeats = beats.filter(item => item.producer.id === 23);
// serve with a cherry in a sugar-frost cocktail glass (happy new year ! )
console.log(relevantBeats);

// for each order
data.forEach(order => {
// we loop thorugh the bought beats array
order.bought_beats.forEach((item, index) => {
// and if there's a beat from another producer, we remove it
if (item.beat.producer.id !== producerId) order.bought_beats.splice(index, 1)
})
})

Filter and clone object properties

I have 2 arrays of objects: itemsList and itemsFetched. All of the objects inside each array have the same structure (nr of key/values). One of those keys has the same 'meaning' but a different name (item_id on itemsList, id on itemsFetched ). Their values are the same.
I need to filter the itemsList array and leave only the objects that have the item_id value equal to the id value on itemsFetched. Then copy(add) the key/value count from each object on the itemsFetched array (which matches the item_id=id) to the filtered array.
I've a working code but I'm sure it isnt the best way to solve this problem. I've already asked something similar before (regarding the 'filter' part) which solved my problem, but since I had to add the 'count' part after the filtering, I ended up refactoring the whole thing.
itemsList (sample)
[
{
"id": 0,
"name": "Egg",
"img": "http://www.serebii.net/pokemongo/items/egg.png"
},
{
"id": 1,
"name": "Pokeball",
"img": "http://www.serebii.net/pokemongo/items/20pokeballs.png"
},
{
"id": 2,
"name": "Greatball",
"img": "http://www.serebii.net/pokemongo/items/greatball.png"
},
{
"id": 401,
"name": "Incense",
"img": "http://www.serebii.net/pokemongo/items/incense.png"
},
{
"id": 901,
"name": "Incubator (Unlimited)",
"img": "http://www.serebii.net/pokemongo/items/eggincubator.png"
}
]
itemsFetched (sample)
[
{
"item_id": 1,
"count": 50,
"unseen": true
},
{
"item_id": 401,
"count": 2,
"unseen": true
},
{
"item_id": 901,
"count": 1,
"unseen": true
}
]
resultArray (what I want in the end)
[
{
"id": 1,
"name": "Pokeball",
"count": 50,
"img": "http://www.serebii.net/pokemongo/items/20pokeballs.png",
},
{
"id": 401,
"name": "Incense",
"count": 2,
"img": "http://www.serebii.net/pokemongo/items/incense.png"
},
{
"id": 901,
"name": "Incubator (Unlimited)",
"count": 1,
"img": "http://www.serebii.net/pokemongo/items/eggincubator.png"
}
]
my current code (working)
let arr = [];
itemsFetched.forEach((item) => {
itemsList.forEach((item2) => {
if (item.item_id === item2.id) {
arr.push({
"id": item.item_id,
"name": item2.name,
"count": item.count,
"img": item2.img
});
}
});
});
PS: I'm able to use ES6/7 syntax/features.

You can use hash map to reduce Time complexitly, your algorithm is O(m*n), The follow is O(m+n+r)
const itemsMap = itemsList.reduce((map, item) => {
map[item.id] = item
return map
}, {})
const results = itemsFetched
.filter((item) => itemsMap.hasOwnProperty(item.item_id))
.map((item) => ({
id: item.item_id,
name: itemsMap[item.item_id].name,
count: item.count,
img: itemsMap[item.item_id].img,
}))

Use a for ... of loop (an ES6 feature) in conjunction with Array#map.
This makes it much easier to return the merged object the first time you find a match, which is a logically optimization because neither list should contain more than one entry with a given id.
const result = itemsFetched.map(data => {
for (let item of itemsList) {
if (data.item_id === item.id) {
return {
id: item.id,
name: item.name,
count: data.count,
img: item.img
}
}
}
})
Snippet:
const itemsList = [{
"id": 0,
"name": "Egg",
"img": "http://www.serebii.net/pokemongo/items/egg.png"
}, {
"id": 1,
"name": "Pokeball",
"img": "http://www.serebii.net/pokemongo/items/20pokeballs.png"
}, {
"id": 2,
"name": "Greatball",
"img": "http://www.serebii.net/pokemongo/items/greatball.png"
}, {
"id": 401,
"name": "Incense",
"img": "http://www.serebii.net/pokemongo/items/incense.png"
}, {
"id": 901,
"name": "Incubator (Unlimited)",
"img": "http://www.serebii.net/pokemongo/items/eggincubator.png"
}]
const itemsFetched = [{
"item_id": 1,
"count": 50,
"unseen": true
}, {
"item_id": 401,
"count": 2,
"unseen": true
}, {
"item_id": 901,
"count": 1,
"unseen": true
}]
const result = itemsFetched.map(data => {
for (let item of itemsList) {
if (data.item_id === item.id) {
return {
id: item.id,
name: item.name,
count: data.count,
img: item.img
}
}
}
})
console.log(result)

One way to improve is to use for..of statement instead of forEach for the inner loop. This helps break from the loop once the id matches. There is no direct way to break from forEach method.
let arr = [];
itemsFetched.forEach((item) => {
for (let item2 of itemsList) {
if (itemsFetched.item_id === itemsList.id) {
arr.push({
"id": itemsFetched.item_id,
"name": itemsList.name,
"count": itemsFetched.count,
"img": itemsList.img
});
break;
}
}
});

Like this?
var itemsList = [
{
"id": 0,
"name": "Egg",
"img": "http://www.serebii.net/pokemongo/items/egg.png"
},
{
"id": 1,
"name": "Pokeball",
"img": "http://www.serebii.net/pokemongo/items/20pokeballs.png"
},
{
"id": 2,
"name": "Greatball",
"img": "http://www.serebii.net/pokemongo/items/greatball.png"
},
{
"id": 401,
"name": "Incense",
"img": "http://www.serebii.net/pokemongo/items/incense.png"
},
{
"id": 901,
"name": "Incubator (Unlimited)",
"img": "http://www.serebii.net/pokemongo/items/eggincubator.png"
}
];
var itemsFetched = [
{
"item_id": 1,
"count": 50,
"unseen": true
},
{
"item_id": 401,
"count": 2,
"unseen": true
},
{
"item_id": 901,
"count": 1,
"unseen": true
}
]
let arr = [];
itemsFetched.forEach((item) => {
itemsList.forEach((item2) => {
if (item.item_id == item2.id) {
arr.push({
"id": item.item_id,
"name": item2.name,
"count": item.count,
"img": item2.img
});
}
});
});
console.log(arr);

Underscore filter array of object using like query

I have the below Json.
{
"results": [
{
"id": "123",
"name": "Some Name"
},
{
"id": "124",
"name": "My Name"
},
{
"id": "125",
"name": "Johnson Johnson"
},
{
"id": "126",
"name": "Mike and Mike"
},
{
"id": "201",
"name": "abc xyz"
},
{
"id": "202",
"name": "abc befd"
},
{
"id": "210",
"name": "jki yuiu"
},
{
"id": "203",
"name": "asdfui uiuu"
},
{
"id": "204",
"name": "sfdhu uiu"
},
{
"id": "205",
"name": "asdfui uyu"
}
]
}
Using Underscore i want to filter the above data using sql like query on id.
for example if pass "2" the json should be filtered and return a new json which contain id starting with 2, If i pass 20 it should return new json with id starting with 20
similar to sql like query and then return n results matching,
correction: I want the data starting with id 2 or whatever parameter i pass i need data starting with it

Try this
function getResult(keyToFilter, valueStartsWith){
return _.filter(results, function(d){ return d[keyToFilter].startsWith(valueStartsWith); })
}
getResult("name", "asdfui");
[{
"id": "203",
"name": "asdfui uiuu"
},
{
"id": "205",
"name": "asdfui uyu"
}]

What about Array.prototype.filter and Array.prototype.slice? (underscore has similar functions but why to use them when it can be solved with plain JS)
function sqlLikeFilter(data, id, maxn) {
return data.result.filter(function(x) { return x.id == id; }).slice(0, maxn);
}
console.log(sqlLikeFilter(yourData, 125, 1));

Try this
function(id){
var result = _.filter(results, function(value) {
return value.id === id
})
return result;
}