Develop Reference

How to set background color for all elements with the same class individually based on custom attribute

I have multiple elements with the class .hours and they all have a color attribute with a hex value like so: <div class="hours" color="#FFFFFF">.
How can I use jQuery to set the background color of all the elements individually so that the element over has the color #FFFFFF and the element <div class="hours" color="#666666"> gets the background color #666666?
My attempt: $('.hours').css('background-color', this.attr.color);

You can use .each to refer to every element and it's color attribute
$('.hours').each(function() {
let elem = $(this);
elem.css('background', elem.attr('color'));
});
.hours {
border: 1px solid black;
height: 100px;
width: 100px;
display: inline-block;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="hours" color="#FFFFFF"></div>
<div class="hours" color="#AAAAAA"></div>
<div class="hours" color="#444444"></div>

Pure JS solution (for this jQuery is rather ineffective in my opinion...):
document.querySelectorAll('.hours').forEach(function(el) {
el.style.backgroundColor = el.getAttribute('color');
});

try with this
$('.hours').each(function(){
var t = $(this);
t.css('background-color', t.attr('color'));
});
})

$(".hours").each(function(){
let $this= $(this);
let color=$this.attr("color");
$this.css("background-color", color);
});

Not really what you asked, but the same can be achieved without JS, just with pure CSS and custom properties:
<div style="--color: green"></div>
div {
--color: #e2001a; /* default color */
background-color: var(--color);
height: 40px;
}
Example: http://jsfiddle.net/e1fwtcdz/1

How can I access a DOM element with jQuery that I have "moved" around the page?

I have a page with two areas. There are boxes in each area. If the user clicks on a box in the top area, it gets moved to the bottom and vice versa. This works fine for the first movement. Theoretically, I should be able to move them back and forth between sections as I please.
Box HTML:
<div id="top-area">
<div class="top-box" id="blue-box"></div>
<div class="top-box" id="yellow-box"></div>
<div class="top-box" id="green-box"></div>
</div>
<hr/>
<div id="bottom-area">
<div class="bottom-box" id="red-box"></div>
<div class="bottom-box" id="gray-box"></div>
</div>
I use jQuery.remove() to take it out of the top section and jQuery.append() to add it to the other. However, when I try to move a box back to its original position, the event that I have created to move them doesn't even fire.
jQuery/JavaScript:
$(".top-box").on('click', function ()
{
var item = $(this);
item.remove();
$(this).removeClass("top-box").addClass("bottom-box");
$("#bottom-area").append(item);
});
$(".bottom-box").on('click', function ()
{
var item = $(this);
item.remove();
$(this).removeClass("bottom-box").addClass("top-box");
$("#top-area").append(item);
});
I have verified that the classes I am using as jQuery selectors are getting added/removed properly. I am even using $(document).on() to handle my event. How come my boxes are not triggering the jQuery events after they are moved once?
Please see the Fiddle: http://jsfiddle.net/r6tw9sgL/

Your code attaches the events on the page load to the elements that match the selector right then.
If you attach the listener to #top-area and #bottom-area and then use delegated events to restrict the click events to the boxes, it should work like you expect. See .on: Direct and Delegated Events for more information.
Use the below JavaScript:
$("#top-area").on('click', '.top-box', function ()
{
var item = $(this);
item.remove();
$(this).removeClass("top-box").addClass("bottom-box");
$("#bottom-area").append(item);
});
$("#bottom-area").on('click', '.bottom-box', function ()
{
var item = $(this);
item.remove();
$(this).removeClass("bottom-box").addClass("top-box");
$("#top-area").append(item);
});
Alternatively:
You could also change .on() to .live(), which works for "all elements which match the current selector, now and in the future." (JSFiddle)
JSFiddle

Here's another way you could work it:
function toBottom ()
{
var item = $(this);
item.remove();
item.off('click', toBottom);
item.on('click', toTop);
$(this).removeClass("top-box").addClass("bottom-box");
$("#bottom-area").append(item);
}
function toTop ()
{
var item = $(this);
item.remove();
item.off('click', toTop);
item.on('click', toBottom);
$(this).removeClass("bottom-box").addClass("top-box");
$("#top-area").append(item);
}
$(".top-box").on('click', toBottom);
$(".bottom-box").on('click', toTop);
#top-area, #bottom-area {
height: 100px;
border: 1px solid black;
padding: 10px;
}
.top-box::before {
content: "Top";
}
.bottom-box::before {
content: "Bottom";
}
#blue-box, #red-box, #yellow-box, #green-box, #gray-box {
width: 100px;
cursor: pointer;
float: left;
margin: 0 5px;
text-align: center;
padding: 35px 0;
}
#blue-box {
background-color: blue;
}
#red-box {
background-color: red;
}
#yellow-box {
background-color: yellow;
}
#green-box {
background-color: green;
}
#gray-box {
background-color: gray;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="top-area">
<div class="top-box" id="blue-box"></div>
<div class="top-box" id="yellow-box"></div>
<div class="top-box" id="green-box"></div>
</div>
<hr/>
<div id="bottom-area">
<div class="bottom-box" id="red-box"></div>
<div class="bottom-box" id="gray-box"></div>
</div>
This basically removes the listener that switched the object to bottom to a listener that switches the object to the top and viceversa.

Change CSS Property through JavaScript. (Uses ID's and Classes)

I'm trying to resize a panel using JavaScript to fit a small image into a panel, and struggling badly.
It's within the bold:
<body id="visCinemaTransRefund"><br>
<div id="content"><br>
<ul class="PayPanel" id="paymentDetails"><br>
Here's the CSS that needs modifying:
visCinemaTransRefund .PayPanel { width: 435px; }
How would I be able to modify with width of this panel?
I've also got a form I'm trying to resize within CSS:
visCinemaTransRefund FORM (width: 1005px;)

document.getElementById('paymentDetails').style.width = '1000px';

Have you tried using:
document.getElementById("paymentDetails").getElementsByClassName("PayPanel")[0].style.width="1000px"
Remember: getElementsByClassName return an array of elements, so using [0] you are indexing first element (and, of course, the only one).
Since getElementsById return a single elements, getElementsByClassName could be useless.

If you want to do this using CSS class :
HTML:
<div id="myDiv" class="medium"></div>
<button id="btn">Click me</button>
CSS:
#myDiv {
background-color: gray;
}
.medium {
height: 50px;
width: 50px;
}
.big {
height: 100px;
width: 100px;
}
JS:
document.getElementById("btn").onclick = function() {
var element = document.getElementById("myDiv"); // or document.getElementsByClassName("className")
if (element.className == "medium") {
document.getElementById("myDiv").className = "big";
} else {
document.getElementById("myDiv").className = "medium";
}
};
JSFIDDLE

Use the following code to change the width of tags by accessing HTML element from the DOM using getElement functions and setting width to it using setAttribute javaScript function.
document.getElementById("paymentDetails").setAttribute("style","width:500px;");
document.getElementById("visCinemaTransRefund").getElementsByTagName("form")[0].setAttribute("style","width:1000px;");

Using JavaScript:
document.getElementById('paymentDetails').style.width = '1000px';
Using JQuery:
$("paymentDetails").width(1000);
$("paymentDetails").css("width","1000px");

set a newly created div on top of the older divs

I have a bunch of divs inside a container. The position of the content divs is relative, because I want them to appear one below the other and their height is unknown.
These divs are created dynamically (appendchild) inside the container div. Now, each div appears on the end (bottom) of the stack but my requirement is that the divs have a "newest first" option too, that is, each new div appears on top, not on bottom of the content divs (if the user selects the "newest first" in the settings).
html:
<div class="container">
<div id="div1" class="content">aaa<br>aaa</div>
<div id="div2" class="content">bbb<br><br>bbb</div>
<div id="div3" class="content">ccc</div>
<div id="div4" class="content">ddd</div>
</div>
css:
.container {
position: absolute;
top: 10px;
left: 10px;
right: 10px;
bottom: 10px;
border: 1px solid red;
}
.content {
position: relative;
top: 0px;
left: 5px;
width: 200px;
height: auto;
border: 1px solid blue;
margin: 3px;
}
http://jsfiddle.net/jk559/1/
so I'd like the end-user visible order to be: div4, div3, div2, div1.
How can I achieve this? (css/js)
preferrably no jquery.
thanks in advice!

Pure css solution:
Use flexbox to achieve this.
.container {
display:flex;
flex-direction:column-reverse;
justify-content: flex-end;
align-content: flex-end;
}
Updated fiddle here.
Read more information here.

try this
theParent = document.getElementById("theParent");
theKid = document.createElement("div");
theKid.setAttribute("id","div5");
theKid.setAttribute("class","content");
theKid.innerHTML = 'eee';
// append theKid to the end of theParent
theParent.appendChild(theKid);
// prepend theKid to the beginning of theParent
theParent.insertBefore(theKid, theParent.firstChild);
Demo Fiddle http://jsfiddle.net/jk559/4/

You can easily do it with JQuery with the following function.
$('.container > div').each(function() {
$(this).prependTo(this.parentNode);
});
UPDATED FIDDLE
As you mentioned in the question, I will try to attain the expected output with the pure javascript.

You can insert content in the beginning simply using .prepend() .
$(".container").prepend("<div id='div5' class='content'>eee</div>");
Demo

JS FIDDLE UPDATED DEMO
Use prepend() to add as first child of an element
/* $( ".container" ).prepend( "Your div with id here" ); */
/* Example */
$( ".container" ).prepend( "<div id='div5' class='content' >div5 on top </div>" );

Take a look at this answer about reordering dom items.
Basically, you have to maintain a state that decides the ordering. When you insert items (see insertItem below) you append or prepend based on the state. When the user selects the newest first option (see newFirst below), you first reverse the dom elements and then flip the state so that subsequent insert happen at the right place.
var newFirst = false;
var list = document.getElementById('my-list');
function newFirst() {
var items = list.childNodes;
var itemsArr = [];
for (var i in items) {
if (items[i].nodeType == 1) { // get rid of the whitespace text nodes
itemsArr.push(items[i]);
}
}
itemsArr.reverse();
for (i = 0; i < itemsArr.length; ++i) {
list.appendChild(itemsArr[i]);
}
newFirst = !newFirst;
}
function insertItem(content) {
var item = document.createElement("div");
item.setAttribute("class","content");
item.innerHTML = content;
if(newFirst) {
list.insertBefore(item, list.firstChild);
} else {
list.appendChild(item);
}
}

try this :
$("div[id*=div]").sort(function(a,b){
if(a.id > b.id) {
return -1;
} else {
return 1;
}
}).each(function() {
var elem = $(this);
$(".container").append(elem);
});
this will sort your divs inside container like this : div4, div3, div2, div1
if you want change the order to : div1, div2, div3, div4 just change if(a.id > b.id) to if(a.id < b.id)
you can add a link called change order then call this code when you click on it

How to move an element into another element

I would like to move one DIV element inside another. For example, I want to move this (including all children):
<div id="source">
...
</div>
into this:
<div id="destination">
...
</div>
so that I have this:
<div id="destination">
<div id="source">
...
</div>
</div>

You may want to use the appendTo function (which adds to the end of the element):
$("#source").appendTo("#destination");
Alternatively you could use the prependTo function (which adds to the beginning of the element):
$("#source").prependTo("#destination");
Example:
$("#appendTo").click(function() {
$("#moveMeIntoMain").appendTo($("#main"));
});
$("#prependTo").click(function() {
$("#moveMeIntoMain").prependTo($("#main"));
});
#main {
border: 2px solid blue;
min-height: 100px;
}
.moveMeIntoMain {
border: 1px solid red;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="main">main</div>
<div id="moveMeIntoMain" class="moveMeIntoMain">move me to main</div>
<button id="appendTo">appendTo main</button>
<button id="prependTo">prependTo main</button>

My solution:
Move:
jQuery("#NodesToMove").detach().appendTo('#DestinationContainerNode')
copy:
jQuery("#NodesToMove").appendTo('#DestinationContainerNode')
Note the usage of .detach(). When copying, be careful that you are not duplicating IDs.

Use a vanilla JavaScript solution:
// Declare a fragment:
var fragment = document.createDocumentFragment();
// Append desired element to the fragment:
fragment.appendChild(document.getElementById('source'));
// Append fragment to desired element:
document.getElementById('destination').appendChild(fragment);
Check it out.

Try plain JavaScript: destination.appendChild(source);.
onclick = function(){ destination.appendChild(source) };
div {
margin: .1em;
}
#destination {
border: solid 1px red;
}
#source {
border: solid 1px gray;
}
<div id=destination>
###
</div>
<div id=source>
***
</div>

I just used:
$('#source').prependTo('#destination');
Which I grabbed from here.

If the div where you want to put your element has content inside, and you want the element to show after the main content:
$("#destination").append($("#source"));
If the div where you want to put your element has content inside, and you want to show the element before the main content:
$("#destination").prepend($("#source"));
If the div where you want to put your element is empty, or you want to replace it entirely:
$("#element").html('<div id="source">...</div>');
If you want to duplicate an element before any of the above:
$("#destination").append($("#source").clone());
// etc.

You can use:
To insert after,
jQuery("#source").insertAfter("#destination");
To insert inside another element,
jQuery("#source").appendTo("#destination");

You can use the following code to move the source to the destination:
jQuery("#source")
.detach()
.appendTo('#destination');
Try the working CodePen.
function move() {
jQuery("#source")
.detach()
.appendTo('#destination');
}
#source{
background-color: red;
color: #ffffff;
display: inline-block;
padding: 35px;
}
#destination{
background-color:blue;
color: #ffffff;
display: inline-block;
padding: 50px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="source">
I am source
</div>
<div id="destination">
I am destination
</div>
<button onclick="move();">Move</button>

If you want a quick demo and more details about how you move elements, try this link:
http://html-tuts.com/move-div-in-another-div-with-jquery
Here is a short example:
To move ABOVE an element:
$('.whatToMove').insertBefore('.whereToMove');
To move AFTER an element:
$('.whatToMove').insertAfter('.whereToMove');
To move inside an element, ABOVE ALL elements inside that container:
$('.whatToMove').prependTo('.whereToMove');
To move inside an element, AFTER ALL elements inside that container:
$('.whatToMove').appendTo('.whereToMove');

I need to move content from one container to another including all the event listeners. jQuery doesn't have a way to do it, but the standard DOM function appendChild does.
// Assuming only one .source and one .target
$('.source').on('click',function(){console.log('I am clicked');});
$('.target')[0].appendChild($('.source')[0]);
Using appendChild removes the .source* and places it into target including its event listeners: Node.appendChild() (MDN)

You may also try:
$("#destination").html($("#source"))
But this will completely overwrite anything you have in #destination.

You can use pure JavaScript, using appendChild() method...
The appendChild() method appends a node as the last child of a node.
Tip: If you want to create a new paragraph, with text, remember to
create the text as a Text node which you append to the paragraph, then
append the paragraph to the document.
You can also use this method to move an element from one element to
another.
Tip: Use the insertBefore() method to insert a new child node before a
specified, existing, child node.
So you can do that to do the job, this is what I created for you, using appendChild(), run and see how it works for your case:
function appendIt() {
var source = document.getElementById("source");
document.getElementById("destination").appendChild(source);
}
#source {
color: white;
background: green;
padding: 4px 8px;
}
#destination {
color: white;
background: red;
padding: 4px 8px;
}
button {
margin-top: 20px;
}
<div id="source">
<p>Source</p>
</div>
<div id="destination">
<p>Destination</p>
</div>
<button onclick="appendIt()">Move Element</button>

I noticed huge memory leak & performance difference between insertAfter & after or insertBefore & before .. If you have tons of DOM elements, or you need to use after() or before() inside a MouseMove event, the browser memory will probably increase and next operations will run really slow.
The solution I've just experienced is to use inserBefore instead before() and insertAfter instead after().

Dirty size improvement of Bekim Bacaj's answer:
div { border: 1px solid ; margin: 5px }
<div id="source" onclick="destination.appendChild(this)">click me</div>
<div id="destination" >...</div>

For the sake of completeness, there is another approach wrap() or wrapAll() mentioned in this article. So the OP's question could possibly be solved by this (that is, assuming the <div id="destination" /> does not yet exist, the following approach will create such a wrapper from scratch - the OP was not clear about whether the wrapper already exists or not):
$("#source").wrap('<div id="destination" />')
// or
$(".source").wrapAll('<div id="destination" />')
It sounds promising. However, when I was trying to do $("[id^=row]").wrapAll("<fieldset></fieldset>") on multiple nested structure like this:
<div id="row1">
<label>Name</label>
<input ...>
</div>
It correctly wraps those <div>...</div> and <input>...</input> BUT SOMEHOW LEAVES OUT the <label>...</label>. So I ended up use the explicit $("row1").append("#a_predefined_fieldset") instead. So, YMMV.

The .appendChild does precisely that - basically a cut& paste.
It moves the selected element and all of its child nodes.