Im trying to do a slider menu, i have a div with a tape background, all is working fine when it's animating to the left by the background-repeat, but when it is animating to the right and it get to the left border of the background it get disappears because background-repeat doesn't repeat to the left, just to the right.. There's way to make the background repeat to the left?
And the list inside the "slider" div doesn't move at the same velocity of "slider" div
Here is the HTML code
<!DOCTYPE html>
<html>
<head>
<title>Prueba</title>
<link type = "text/css" rel = "stylesheet" href = "PruebaIndex.css">
<script type = "text/javascript" src = "jquery-2.1.4.js"></script>
<script>
$(document).ready(function(){
var mode = 0; // 0 Left - 1 Right
autoSlider();
function autoSlider(){
mode = 0;
$("#slider").animate({left: "-=60px", width: "+=60px"}, 'slow', 'linear', autoSlider);
}
function slideLeft(){
mode = 1;
$("#slider").animate({left: "+=60px", width: "-=60px"}, 'slow', 'linear', slideLeft);
}
$("#slider").mouseover(function(){
$("#slider").stop();
});
$("#slider").mouseout(function(){
if(mode === 0)
autoSlider();
else
slideLeft();
});
$("#Left").mouseover(function(){
$("#slider").stop();
autoSlider();
});
$("#Right").mouseover(function(){
$("#slider").stop();
slideLeft();
});
});
</script>
</head>
<body>
<div id = "wrapper">
<div id = "slider">
<ul>
<li>1</li>
<li>2</li>
<li>3</li>
</ul>
</div>
<div id = "Left">
Left
</div>
<div id = "Right">
Right
</div>
</div>
</body>
</html>
And the CSS code
*{
padding: 0;
margin: 0;
}
#slider {
padding: 0;
left: 0px;
background-color: black;
background-image: url("http://s11.postimg.org/msh93rl8z/Tira_Fotografica.png");
background-repeat: repeat-x;
width: 800px;
height: 304px;
position: relative;
overflow: hidden;
}
#wrapper {
width: 800px;
height: 1000px;
margin: 0 auto;
text-align: center;
overflow: hidden;
}
#Left {
width: 100px;
height: 100px;
position: absolute;
color: white;
background-color: black;
margin-top: -200px;
margin-left: -100px;
}
#Right {
width: 100px;
height: 100px;
position: absolute;
color: white;
background-color: black;
margin-top: -200px;
margin-left: 800px;
}
#slider ul {
list-style: none;
}
#slider ul li {
display: inline-block;
width: 200px;
height: 200px;
position: relative;
background-color: white;
margin: 50px 10px 0px 0px;
}
I tried to put the code on JSFiddle but it doesn't run..
Sorry for my bad english
it works. see here: https://jsfiddle.net/cLv4hLfy/
take a look at the #slider element.
this values are annoying ;-)
<div style="left: -5863.5px; width: 6663.8px; overflow: hidden;" id="slider">
left is decreasing and width is getting bigger and bigger.
when the slider goes to the opposite direction left gets bigger and width convergates to 0px.
[EDIT]: so the background is not animated. the div is animated. what about fix the div and animate something in the div. you could do something also with background position when its repeated.
Related
I have am restricting the body to be the viewport's height and setting overflow: hidden on it. I am using jQuery to slide in a div that is absolutely positioned outside of the viewable area. The div that slides in is larger than the viewport and I would like for its contents to be scrollable within the viewport window.
Here's my fiddle: https://jsfiddle.net/hvew0qx4/1/
HTML:
<div class='buttons'>
<button id="toggle-results">Show Results</button>
</div>
<div class="map general-styling"></div>
<div id="results-area" class='movable'>
<div class="results general-styling"></div>
</div>
CSS:
body {
height: 100vh;
overflow: hidden;
position: relative;
}
.general-styling {
box-sizing: border-box;
width: 100%;
border-width: 10px;
border-style: solid;
}
.movable {
transition: all 0.3s ease;
position: absolute;
z-index: 44;
width: 100vw;
min-height: 100vh;
background-color: white;
overflow-y: scroll;
}
.map {
background-color: red;
border-color: pink;
height: 100vh;
}
.results {
background-color: blue;
border-color: orange;
height: 1000px;
}
.buttons {
position: absolute;
z-index: 1000;
top: 40px;
right: 40px;
}
JavaScript:
var $toggleResultsBtn = $('#toggle-results');
var $resultsArea = $('#results-area');
var $body = $('body');
$('.movable').css('top', $body.height());
$toggleResultsBtn.on('click', function(){
$toggleResultsBtn.text(function(i, text){
return text === "Show Results" ? "Hide Results" : "Show Results";
});
$resultsArea.css('top', function(i, value){
return value === '0px' ? $body.height() : '0px';
});
});
Set the height of the inner div to that of its container, and then add the property overflow-y: scroll to it.
Like so:
.container {
height: 200px;
overflow: hidden;
}
.elem {
height: 200px;
overflow-y: scroll;
}
If you want the div to scroll down at least 1000px (you want a scrollbar without any content in your div), you may want the outer div to have overflow-y set to scroll, like so:
.container {
height: 200px;
overflow-y: scroll;
}
.elem {
height: 1000px;
}
EDIT: I played around with your fiddle, and it looks like the biggest thing holding you back from what you are looking for is that you are using min-height for your .moveable div.
Change it to:
.movable {
transition: all 0.3s ease;
position: absolute;
z-index: 44;
width: 100vw;
height: 100vh; /* Change was made on this line */
background-color: white;
overflow-y: scroll;
}
min-height allows your div to grow. You clearly don't want that here, since if the div can grow, there is no need for scrolling.
EDIT 2: Added bonus - to get the scrollbar back from the edge of the screen, override the default margin given to the body:
body {
margin: 0;
}
EDIT 3: Here's an updated JSFiddle: https://jsfiddle.net/anishgoyal/hvew0qx4/4/
Lets say I have a div with images, however not all have space to be displayed at same the time, so I used CSS property white-space: nowrap and overflow: hidden, so elements don't break into new lines or expand over div.
Now I need JavaScript technique that will allow me to move them left or right so user can reach these not visible images aswell. Think of it as a slider.
It should have two navigation buttons, left and right, by pressing each, images move in specific direction. Movement should be animated (not moving instantly, instead, they should move over specific period, frame by frame)
Here is jsfiddle demo: http://jsfiddle.net/rfLffev7/
(red and green div represent a button that should trigger functions)
HTML:
<div id="container">
<div id="left"></div>
<div id="track">
<img src="">
<img src="">
<img src="">
<img src="">
<img src="">
<img src="">
<img src="">
<img src="">
</div>
<div id="right"></div>
</div>
CSS:
#container {
width: 600px;
height: 200px;
margin: 10px auto;
}
#left {
width: 50px;
height: 200px;
float: left;
background: #500;
}
#track {
width: 500px;
height: 200px;
float: left;
background: #333;
white-space: nowrap;
overflow: hidden;
}
#track img {
width: 100px;
height: 100px;
border: 1px solid #fff;
margin-top: 50px;
margin-left: 10px;
}
#right {
width: 50px;
height: 200px;
float: left;
background: #050;
}
I would use absolute positioning for that as the CSS will be simpler. For the JavaScript, it's quite simple.
Here, I subtract 116px from the "margin-left" to move #track to the left and add 116px to #track to move it back to the right. I have not added any "stops" at either end, so in theory you could keep scrolling indefinitely.
document.getElementById("left").onclick = function(){
var currentPlace = parseInt(document.getElementById("track").style.marginLeft) || 0;
document.getElementById("track").style.marginLeft = (currentPlace - 116) + "px"
}
document.getElementById("right").onclick = function(){
var currentPlace = parseInt(document.getElementById("track").style.marginLeft) || 0;
document.getElementById("track").style.marginLeft = (currentPlace + 116) + "px"
}
Here's a working example (using absolute positioning): http://jsfiddle.net/rfLffev7/1/
I also added an additional :nth-child(even) class to make it more obvious that the images are moving:
#track img:nth-child(even) {
border: 1px solid #f00;
}
You can move the inner track using margins. For example, check the element for its margin value, then for the size of the image (or whatever distance you want to move the track), then add those two values together, then apply the new value to the track.
$('#right').click(function(){
var moveDistance = $('#track').find('img').width()
var moved = $('#track').css('marginLeft');
var moveIt = moveDistance - parseInt(moved)
$('#track').css('marginLeft', -moveIt);
});
I have updated your example with what I mean. The green button is rigged to move the distance of 1 image + the previous value of the element margin.
http://jsfiddle.net/rfLffev7/4/
You'll also need to make a few changes to your css to keep the other elements positions.
#container {
width: 600px;
height: 200px;
margin: 10px auto;
overflow:hidden;
position:relative;
}
#left {
width: 50px;
height: 200px;
left:0;
background: #500;
position:absolute;
z-index:1;
}
#track {
width: auto;
height: 200px;
float: left;
background: #333;
white-space: nowrap;
overflow: hidden;
position:absolute;
left:50px;
}
#track img {
width: 100px;
height: 100px;
border: 1px solid #fff;
margin-top: 50px;
margin-left: 10px;
}
#track img:nth-child(even) {
border: 1px solid #f00;
}
#right {
width: 50px;
height: 200px;
background: #050;
position:absolute;
right:0;
}
Im creating a page where my footer is growing on a certain event.
My problem is to make the footer grow according to how much space i got.
See my code or jsFiddle. I want the gray footer to grow all the way up to the colored elements with dynamic height (instead of like now, to 20%).
I guess i could count all the elements height above but that doesn't sound like a good solution.
jsFiddle here
<html>
<head>
<style type="text/css">
body #pagePlaceHolderOuter {
background: #FFFFFF;
height: 100%;
left: 0;
position: absolute;
top: 0;
width: 100%;
}
body #pagePlaceHolderOuter #pagePlaceHolderInner {
height: 100%;
margin: 0 auto;
max-width: 1000px;
min-width: 700px;
width: 70%;
position: relative;
}
body #pagePlaceHolderOuter #pagePlaceHolderInner .div1 {
width: 100%;
height: 100px;
background: blue;
}
body #pagePlaceHolderOuter #pagePlaceHolderInner .div2 {
width: 100%;
height: 120px;
background: green;
}
body #pagePlaceHolderOuter #pagePlaceHolderInner .div3 {
width: 100%;
height: 60px;
background: red;
}
body #pagePlaceHolderOuter #pagePlaceHolderInner .footer {
background: gray;
bottom: 0;
height: 10%;
position: absolute;
width: 100%;
}
</style>
</head>
<body>
<script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script>
<script>
$("#btn").click(function () {
$('body #pagePlaceHolderOuter #pagePlaceHolderInner .footer').css('height', '20%');
});
</script>
<div id="pagePlaceHolderOuter">
<div id="pagePlaceHolderInner">
<button type="button" id="btn">Click Me!</button>
<div class="div1">I have a dynamic height</div>
<div class="div2">I have a dynamic height</div>
<div class="div3">I have a dynamic height</div>
<div class="footer">Footer</div>
</div>
</div>
</body>
</html>
Instead of calculating the space of all the elements before, you can simply calculate the height of the most previous one and find the offset().top of that element. Using this approach I calculated the space (you have to make sure in your HTML the footer is directly after the previous element or slightly restructure my jQuery) and essentially you just toggle it between the default value and the default value + the space. Updated jsFiddle
$("#btn").click(function (e) {
var prev = $('.footer').prev(),
winHeight = $(window).height(),
calcTop = $('.footer').height() == Math.round(winHeight / 10) ?
(winHeight - prev.offset().top - prev.height()) : "10%";
$('body #pagePlaceHolderOuter #pagePlaceHolderInner .footer').css({
'height': calcTop
});
});
On a side note I used CSS transitions to "animate" the change, not jQuery for performance issues and for ease of editablity
If you just want the position to change, not the height, you can do it by toggling the bottom value instead. Demo of that here
What I am doing wrong?
When you click on class divtop, it should show a div popup in the middle of the page. At that time back page should become not clickable. escape or a button in popup will close it.
<html lang="en" class=" en">
<head>
<title>My Test Popup</title>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<style type="text/css">
.divtop
{
width: 800px;
height: 300px;
border:solid;
}
.divbottom
{
top: 400px;
}
.localmenu {
border: 1px solid black;
background: #fff;
margin-left : auto;
top: 50px; width: 300px;
padding-top: 25px;
margin-top: 100px;
height: 150px;
}
.appContent{
width: 800px;
border:solid;
height: 600px;
display: block;
margin-left: auto;
margin-right: auto;
}
.maincontent{
width: 100%;
}
</style>
</head>
<body>
<div class="appContent" >
<div class="maincontent" >
<div class="divtop" >Top</div>
<div class="divtop divbottom" >Bottom</div>
</div>
<div id="popup" style="width : 100%; height: 600px;display: none;">
<div class='localmenu'>
Text in Div Popup<br/>
<button id="btnHide">Close</button><br/>
</div>
</div>
</div>
<script>
$(document).ready(function() {
$('.divtop').click(function() {
$('#popup').show().css("top", "500px").animate({top: 50}, 200);
$('.mainContent').css("background-color", "grey");
});
$('#btnHide').click(function() {
$('#popup').hide();
});
});
</script>
</body>
</html>
Fiddle
I added some CSS to your #popup and it's now all in the CSS (not inline in the html). Changed also your jQuery animate to 50px, instead of just 50.
I think you have small adjustments to do to the CSS, like in .localmenu I'm not sure why you have both padding-top: 25px; margin-top: 100px;.
CSS
#popup {
position:absolute;
display: none;
float: left;
left:30%;
z-index:1;
}
#popoverlay {
position: fixed;
display:none;
top: 0;
left: 0;
width: 100%;
height: 100%;
background-color: #000;
opacity: 0.5;
}
jQuery
$(document).ready(function () {
$('.divtop').click(function () {
$('#popoverlay').show();
$('#popup').show().css("top", "500px").animate({
top: "50px"
}, 200);
$('.mainContent').css("background-color", "grey");
});
$('#btnHide').click(function () {
$('#popup').hide();
$('#popoverlay').hide();
});
});
HTML
<div class="appContent">
<div class="maincontent">
<div class="divtop">Top</div>
<div class="divtop divbottom">Bottom</div>
</div>
<div id="popup">
<div class='localmenu'>Text in Div Popup
<br/>
<button id="btnHide">Close</button>
<br/>
</div>
</div>
</div>
To get it to work properly, even if there is a vertical scroll bar, you have to use position "fixed". Place popup as a direct child of body and make it's position: fixed, and width and height 100%. Place localmenu as a direct child of body as well. Working example at jsbin.
Html:
<div id="popup">
<!--// This is to stop the user from interacting with the content in the back
// and to give a visual clue about that
-->
</div>
<div class='localmenu'>
<div>
Text in Div Popup<br/>
<button id="btnHide">Close</button><br/>
</div>
</div>
<div class="appContent" >
<div class="maincontent" >
<div class="divtop" >Top</div>
<div class="divtop divbottom" >Bottom</div>
</div>
</div>
CSS:
//Use opacity to give a visual clue. Please note that this doesn't work in -all- browsers
#popup {
position: fixed;
width: 100%;
height: 100%;
display: none;
background: black;
opacity: .5;
top: 0;
left: 0;
}
//This is just to be able to center the actual menu
.localmenu {
top: 20%;
left: 0;
width: 100%;
position: fixed;
height: 150px;
display: none;
}
.localmenu > div {
border: 1px solid blue;
background: #fff;
margin-left : auto;
margin-right: auto;
width: 300px;
height: 150px;
}
Javascript: (This is mostly the same, although I removed the animate, because I don't know exactly how it works and it needs to end at 'top: 0'. As localmenu and popup are seperate, we show them seperate as well.)
$(document).ready(function() {
$('.divtop').click(function() {
$('#popup').show().animate(200);
$('.localmenu').show();
//$('.mainContent').css("background-color", "grey");
});
$('#btnHide').click(function() {
$('#popup').hide();
$('.localmenu').hide();
});
});
To block the div tags at the back from being clickable:
Add a div with the following style in your HTML. Im gonna call it overlay.
.overlay {
width: 100%;
height: 100%;
background-color: #000;
left: 0;
opacity: .8;
position: absolute;
top: 0;
z-index: 10000;
display: none;
}
This will essentially cover up your page when shown up.
To center your popup:
I added some extra styles to #popup and removed some from .localmenu. You were missing position: absolute and z-index, added those in. (z-index of popup must be > z-index of overlay)
#popup {
background: #fff;
position :absolute;
left : 40%;
width : 300px;
height: 600px;
height: 150px;
display: none;
z-index: 10001;
}
.localmenu
{
border: 1px solid black;
}
Then, in your JS,
In your animate method, I changed 50px to 30% to center div#popup
Added code to hide and show .overlay along with #popup.
After the changes,
$(document).ready(function () {
$('.divtop').click(function () {
$('#popup').show().css("top", "500px").animate({
top: "30%"
}, 200);
$('.overlay').show();
});
$('#btnHide').click(function () {
$('#popup,.overlay').hide();
});
});
Demo
http://jsbin.com/olasog/1
Code
http://jsbin.com/olasog/1/edit
Try this:
$(document).ready(function() {
$('.divtop').click(function() {
var div = $('.appContent');
$('.localmenu').css({'margin': '200px auto'});
$('#popup').show().css({top: "500px", position: 'absolute', width: div.width(), height: div.height()}).animate({top: 0}, 200);
$('.mainContent').css("background-color", "grey");
});
$('#btnHide').click(function() {
$('.mainContent').css("background-color", "");
$('#popup').hide();
});
});
I'm trying to do what many have asked before, but even after trying everything I still can't get the results I want.
I have an image 600px by 1600px, 4 images of 600px by 400px in a vertical line. I want to show 600px by 400px of the image at any one time. Ideally I would be able to hover over an element somewhere on my page and move the image upwards to reveal the other portions of the 600px by 400px image. In effect, I'd have 4 images viewable by hovering over 4 the elements.
I've tried various css3 and jquery solution but none have worked. I would appreciate any help with this.
HTML
<div class="mainimage">
<div class="buttonsection">
<div class="button1">Button 1</div>
<div class="button2">Button 2</div>
<div class="button3">Button 3</div>
<div class="button4">Button 4</div>
</div><!--end of buttonsection-->
<div class="rollingimage">
<img src="IMG/four-pics.png">
</div><!--end of rollingimage-->
</div><!--end of mainimage-->
</div><!--end of main content-->
CSS
.mainimage {
position: relative;
top: 0px;
left: 0px;
width: 900px;
height: 400px;
border: 2px solid #E78F25;
margin: 0 10px 20px 0;
}
.buttonsection {
width: 290px;
height: 400px;
position: relative;
float: left;
}
.button1,
.button2,
.button3,
.button4 {
display: inline;
height: 98px;
width: 290px;
border: 1px solid #E78F24;
text-align: center;
float: left;
}
.rollingimage {
width: 598px;
height: 400px;
position: relative;
overflow: hidden;
top: 0px;
left: 0px;
float: right;
}
jquery
$(document).ready(function(){
$(".button1").hover(function(){
$('.rollingimage').stop().animate({'top': '-200px'}, 1500);
});
});
Here is the jsfidle: http://jsfiddle.net/dirtyd77/jCvYm/1/
Thanks yet again
Gary
Just for fun, no JS:
http://jsfiddle.net/coma/MTWdb/5/
HTML
<div id="foo">
Button 1
Button 2
Button 3
Button 4
<div></div>
</div>
CSS
#foo {
width: 400px;
border: 2px solid #E78F25;
position: relative;
}
#foo > div {
position: absolute;
top: 0;
right: 0;
bottom: 0;
width: 200px;
background: #fff url(http://placekitten.com/600/1600) no-repeat 0 0;
transition: background-position .5s;
}
#foo > a {
display: block;
width: 200px;
line-height: 100px;
text-align: center;
text-decoration: none;
}
#foo > a + a {
border-top: 1px solid #E78F25;
}
#foo > a:nth-child(1):hover ~ div {
background-position: 0 0;
}
#foo > a:nth-child(2):hover ~ div {
background-position: 0 -400px;
}
#foo > a:nth-child(3):hover ~ div {
background-position: 0 -800px;
}
#foo > a:nth-child(4):hover ~ div {
background-position: 0 -1200px;
}
You need to change the positioning of the image inside the div, not the div itself. To animate my example, you could add CSS transitions for better performance than JS animations.
http://jsfiddle.net/jCvYm/8/
$('.rollingimage').find('img')
As Dom mentioned, the jsFiddle you provided didn't reference the jQuery library. It also didn't included any actual images, and only contained code for one of the three buttons. I doubt those were the original problems you were having, though. (The missing reference to jQuery might have been.)
Once I had those straightened out, I noticed that hovering the button caused the picture to slide out of the screen, instead of scrolling. The simplest way to fix that is to move the img element, instead of moving the div. (The more natural way would be to change the scroll position of the div, but I don't recall how to do that off the top of my head.)
Added CSS:
.rollingimage img {
position: relative;
}
New JS:
$(document).ready(function(){
$(".button1").hover(function(){
$('.rollingimage img').stop().animate({'top': '0px'}, 1500);
});
$(".button2").hover(function(){
$('.rollingimage img').stop().animate({'top': '-400px'}, 1500);
});
$(".button3").hover(function(){
$('.rollingimage img').stop().animate({'top': '-800px'}, 1500);
});
$(".button4").hover(function(){
$('.rollingimage img').stop().animate({'top': '-1200px'}, 1500);
});
});
jsFiddle: http://jsfiddle.net/jCvYm/6/