Are there any possibilities to use "goto" inside switch statement in javascript? - javascript

This is my example program in JS. I have to iterate or loop inside the switch statement. So I have used goto, but it doesn't working.
Are there any other options to loop this or is my syntax wrong?
var input = 1;
switch (input)
{
case 1:
...
break;
case 2:
...
break;
case 3:
...
if (..) { }
else
{
goto case 2;
}
break;
default:
alert("No Return");
break;
}

Are there any possibilities to use "goto" inside switch statement in javascript?
No, there are no possibilities to use "goto" inside switch statement, or anywhere else, since JavaScript has no such statement.
To solve your problem, as suggested in a comment, organize your cases (moving 3 above 2) so you can use fall-through:
var input = 1;
switch (input)
{
case 1:
...
break;
case 3:
...
if (..) { ...; break; }
// fall through to case 2
case 2:
...
break;
default:
alert("No Return");
break;
}
In this case, make sure to comment the fall-through so people looking at your code don't think it's a bug. You may also need to add a hint so that your linter does not complain.
Or, just put the logic common to 2 and 3 in a little function:
function someLogicFor2Or3() { ... }
case 2:
someLogicFor2OrMaybe3();
break;
case 3:
...
if (..) { }
else someLogicFor2OrMaybe3();
break;

I have used the following technique to do this :
var input = 1;
while (1) {
switch (input) {
case 1:
...
break; // switch
case 2:
...
break; // switch
case 3:
...
if (..) { }
else {
input = 2; // goto case 2;
continue; // while
}
break; // switch
default:
alert ("No Return");
break; // switch
}
break; // while
}

Related

Make specific case execute last in switch

I need to make a case execute at the last. Any ideas?
$.each(dataNames, function (varName, itemVal) {
switch (varName)
{
case "afshin":
alert('afshin');
break;
case "saeed":
alert('saeed');
break;
case "larry":
alert('larry');
break;
case "abc":
alert('abc');
break;
default:
alert('Default case');
break;
}
});
from the code above i need the case 'abc' to get executed at the last of all cases as i'm manipulating some code which has to execute from the other cases.
FYI, dataNames is a JSON object

Is it possible to have multiple switch cases in one switch case?

Is it possible to make like a two layer switch case? Say I have two expressions, that inside the the first case it looks for the second expression? I have googled but I have not found anything that I look for.
switch (Middle, Direction) {
case true:
case 'left':
code block
break;
case 'right':
code block
break;
break;
case false:
case 'left':
code block
break;
case 'right':
code block
break;
break;
default:
code block
}
Yes, you have to use individual, complete switches:
switch (Middle) {
case true:
switch (Direction) {
case 'left':
//code block
break;
case 'right':
//code block
break;
}
break;
case false:
switch (Direction) {
case 'left':
//code block
break;
case 'right':
//code block
break;
}
break;
default:
//code block
}
Note that in the above, if Direction isn't 'left' or 'right' but Middle is true or false (which, if it's really a boolean, it must be), then no default code is run as the subordinate switches don't have defaults.
Alternately, you might combine Middle and Direction, which makes it easier to use a default for non-matching cases:
switch (Middle+'|'+Direction) {
case 'true|left':
//code block
break;
case 'true|right':
//code block
break;
case 'false|left':
//code block
break;
case 'false|right':
//code block
break;
default:
//code block
}
Or look at a dispatch object:
var actions = {
"true|left": function() {
// code for Middle = true, Direction = left
},
"true|right": function() {
// code for Middle = true, Direction = right
},
"false|left": function() {
// code for Middle = false, Direction = left
},
"false|right": function() {
// code for Middle = false, Direction = right
},
"default": function() {
// code for the default
}
};
(actions[Middle+"|"+Direction] || actions.default)();
...though in this specific case it doesn't buy you much of anything over a switch.
Just use another switch in your case.

How to execute somethnig `finally` in Javascript swich-case statement?

In javascript switch statements, I would like to execute some function if any one of the case is satisified:
switch (myVar){
case 0:
do_something_0();
break;
case 1:
do_something_1();
break;
// I want to execute myFunc() if myVar === 1 or myVar === 2
}
I came up with the idea of having auxiliary variable haveMatched, like this.
var haveMatched=false;
switch (myVar){
case 0:
do_something_0();
haveMatched=true;
break;
case 1:
do_something_1();
haveMatched=true;
break;
}
if (haveMatched){
do_finally();
}
I think there might be better way of achieving this (for example, I would've tried the similar way if I hadn't known about the default: keyword). Am I doing it right, or am I missing something?
If you rewrite your code to include a default case you don't have to include haveMatched = true in every case.
var haveMatched=true;
switch (myVar){
case 0:
do_something_0();
break;
case 1:
do_something_1();
break;
default:
haveMatched = false;
}
if (haveMatched){
do_finally();
}
Why not put the function in the case:
switch (myVar){
case 0:
do_something_0();
do_finally();
break;
case 1:
do_something_1();
do_finally();
break;
}
Include the function in every case block, you don't need a flag...
switch (myVar){
case 0:
do_something_0();
do_finally();
break;
case 1:
do_something_1();
do_finally();
break;
}
this is a workaround:
try {
switch (option) {
case 0:
console.log("option 0");
break;
case 1:
console.log("option 1");
break;
default:
}
} catch (err) {
throw err;
} finally {
doActionFinally();
}

switch between functions with checkboxes?

I'm trying to simplify some information on my play-site.
There are two dif. user-types, students and others.
Many places and stores offer a discount to students, and I would therefore make this accessible with a checkbox that changes some of the scripts.
This Is my example (simplifyed as good as i could):
<head>
<script TYPE="text/javascript" SRC="script/script_uteplasser.js"></script>
</head>
<body>
<form action="">
<input type="checkbox" id="checkbox_student" onclick="student();"><span>I'm A student!</span></input></form>
(...)
</body>
javascript (script_uteplasser):
//--------------------SAMFUNDET---------------------
samfundet = "...blablablabla..." + cc_samfundet() + "...blablablabla...";
//----INNGANGSAV. SAMFUNDET----
var checkbox1 = document.getElementById("checkbox_student");
function student(){
if (checkbox1.checked){
function cc_samfundet(){var d=new Date(); var theDay=d.getDay(); switch (theDay) { case 1: return "Free"; break; case 2: return "Free"; break; case 3: return "Free"; break; case 4: return "Free"; break; case 5: return "Free"; break; case 6: return "Free"; break; case 0: return "Free";}}
}
else{
function cc_samfundet(){var d=new Date(); var theDay=d.getDay(); switch (theDay) { case 1: return "100,-"; break; case 2: return "100,-"; break; case 3: return "100,-"; break; case 4: return "100,-"; break; case 5: return "100,-"; break; case 6: return "100,-"; break; case 0: return "100,-";}}
}
}
//-------------------------------------------------
This doesn't kill the script, but isn't returning any information either.
Why do you want to redefine function ?
You can check in your function if checkbox is checked. If you want really to redefine function use this code :
//declare your function :
function cc_samfundet () {
//...
}
//or :
var cc_samfundet2 = function () { /* ... */ };
//redefine your function :
cc_samfundet = function () {
//...
}
//or with an existing function :
cc_samfundet = cc_samfundet2;
It doesn't return anything because you're only defining your function(s) in your evaluation. If you add a second pair of parentheses afterwards, it should work how you intend.
That said, this is a really poor design pattern. First of you don't really need to make what you're doing functions here. Second is creating the same named function twice with completely separate logic - that pretty much brakes every good programming principle.
Update: Here is something to point you in the right direction,
var checkbox1 = document.getElementById("checkbox_student");
// Assuming this function should do something else too?
function student() {
cc_samfundet(checkbox1.checked);
}
var cc_samfundet = function (isStudent) {
var d = new Date();
var theDay = d.getDay();
switch (theDay) {
case 1:
return isStudent ? "Free" : "100,-";
// and so on
}
}

javascript switch(true)

Hi i am trying to handle an ajax json response
here is my code
success: function (j) {
switch(true)
{
case (j.choice1):
alert("choice2");
break;
case (j.choice2):
alert("choice2");
break;
default:
alert("default");
break;
}
}
based on what j is return i do my action BUT i keep getting the default.
I have alert the j values and come correct.Some how case (j.choice1) case (j.choice2) is not working.
I tried case (j.choice1!="") (j.choice2!="") But in this scenario i keep getting the first choice.
What am i missing
It works for me:
var a = 0, b = true;
switch(true) {
case a:
console.log('a');
break;
case b:
console.log('b');
break;
}
However, the case labels must be equal to true, not just implicitly true.
Also, only the first case that evaluates to true will execute.
SOLVED
Based on SLaks answer i modify the code as below
if(j.choice1){ var choice1=true;} else { var choice1=false;}
if(j.choice2){ var choice2=true;} else { var choice2=false;}
switch(true)
{
case choice1:
alert("choice1");
break;
case choice2:
alert("choice2");
break;
default:
alert("default");
break;
}
For all asking why switch and not if.
Switch will execute only 1 statement, but if can execute more than 1 if any mistake come form response (for example if set choice1 and choice 2 the if will alert both but switch will alert only choice1).
The response expecting as choice has to do with credit card charge to bank so i want to ensure that only 1 action will exetute
Thank to all
You need to read up on the switch statement. You should not be switching on a constant value.
It appears that you need to use if statements, as you don't really want to be switching on your j value:
success: function (j) {
if (j.choice1)
{
alert("choice1");
break;
}
if (j.choice2)
{
alert("choice2");
break;
}
alert("default");
}
}
In a case like this, a better way to do this is probably something like:
success: function (j) {
if(j.choice1 || j.choice2) {
alert("choice2");
} else {
alert("default");
}
}
Why not use an object literal instead of a switch(true) ?
const j= {
choice1: false,
choice2: true
};
const map = {
true: 'default',
...(j.choice1 ? {[`${j.choice1}`]: 'choice1'} :{}),
...(j.choice2 ? {[`${j.choice2}`]: 'choice2'} :{})
}['true']
console.log(map) // 'choice2'

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