jquery getJSON request with params - javascript

This is my js script :
$.getJSON(riceviPaginaPrincipale, {tipo: "Principale"}).done(function(data) {
$("#contenitorePaginePrincipali").empty();
$.each(data.risultato, function(){
$("#contenitorePaginePrincipali").append('<button class="btnMenu">'+this['Nome']+'</button>');
});
$("#contenitorePaginePrincipali").append('<button class="btnMenu" onclick="creaPagina()"> Crea nuova pagina </button>');
});
and this is my php script :
<?php
//It includes session script php and global variables
include('../../sessione.php');
$tipo = $_POST['tipo'];
if(!$conn){
mysqli_close($conn);
$_SESSION['error'] = "Connessione al database pagine fallita.";
}
else{
$comando = "select * from Pagine where Tipo='$tipo'";
$result = mysqli_query($conn, $comando);
$res = array();
while($row = mysqli_fetch_array($result)) {
array_push($res, array('Nome' => $row[2]));
}
$_SESSION['error'] = "Connessione al DataBase pagine riuscita, pagine recuperate.";
}
echo json_encode(array("risultato" => $res));
?>
but it doesn't work. I'm not receiving anything.

You are currently sending the server a GET request. Id imagine that this is then causing some error due to the lack of validation on the $tipo = $_POST['tipo'] line.
You should look into using the POST from jquery http://api.jquery.com/jquery.post/ and also ensure you validate your code
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
// post handling
}
Is a basic starting point.
You should also be checking your query you are sending to MySQL its open to SQL Injection. Look into using http://php.net/manual/en/book.pdo.php

Related

how to send a variable which have not just usual string, from Javascript to PHP and so to be able using in SQL query

I want to send my variable from javascript to PHP using post method that needs to be used in SQL query, but my variable value has a special character like " / " that server doesn't perform it,
it's my sample code:
js:
var my_var = "ok1 / ok2_4"; // its my table name in database
$.post(
"part/order/order_from_js.php",
{
name: my_var,
},
function(data) {
// using data ....
}
php:
<?php
session_start();
$db=mysqli_connect("localhost","user_db","","db_name");
$name = mysqli_real_escape_string($db, $_POST['name']);// this is my main problem somehow
$select_query = "SELECT * FROM $name";
$users_query = $db->query($select_query);
if ($users_query ->num_rows > 0) {
$i=0;
while($row = $users_query->fetch_assoc()) {
$array[$i]= $row;
$i=$i+1;
}
}
mysqli_close($db);
echo json_encode($array);
?>
I have an error and nothing will pass back to javascript. I want to persist using mysqli_real_escape_string for avoid SQL injection attack.

How to retrieve Data from Php while in Node.js

I just wanted to retrieve some PHP/Mysql stuff at the beginning of my app (authentication and x and y data) from the users which I later plan to emit to the app.js (one time at the beginning and once the user disconnects update x - y values).
So basically I have set up Nodes.js and understood that some stuff is not possible like before (e.g with plain php)
Where I already have a problem is the AJAX php request in the index.html of my nodes Server
Schema:
app.js: pull Data from the /Client/index.html (I think need to do it via sockets)
index.html: get or post data via Ajax to a php file and get the values of the database back to the index.html(JavaScript)
then send that data via sockets to the app.js
php: select mysql database
retrieve values from mysql
parse them via Json and make them available in the index.html file Nodes.js (Client)
Maybe somebody of you have a solution
Nodes.js /Client/index.html:
function checkuser(username, password) {
var myObj;
var xhttp = new XMLHttpRequest();
xhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
// Typical action to be performed when the document is ready:
myObj = xhttp.responseText;
var i = 0;
while (i <= myObj.length) {
//console.log("ASQL found and Auth Username:"+ myObj[i].username) ;
console.log(myObj.username);
i++;
}
}
};
xhttp.open("GET", "/client/is_user.php?username333=" + username + "&password333=" + password, true);
xhttp.send();
}
is_user.php:
<?php
require('config_sql.php');
$email = stripslashes($_GET['username333']);
$email = mysqli_real_escape_string($con,$email);
$password369 = stripslashes($_GET['password333']);
$password369 = mysqli_real_escape_string($con,$password369);
$query = "SELECT * FROM `users` WHERE email='$email'
and password='".md5($password369)."'";
$result = mysqli_query($con,$query) or die(mysql_error());
$response = array();
$rows = mysqli_num_rows($result);
while ($row_user= mysqli_fetch_assoc($result))
{
$response[] = $row;
}
$jsonData = json_encode($response);
echo $jsonData;
mysqli_close($con);
?>
atm is not retrieving the username form the created json on the php side.
If I console.log(myObj); it's showing the me complete php.file data as plain text if I want to retrieve the username from MySql its saying undefined.
Is the php Interpreter actually working when I post/get via Ajax in a Node.js environment?
Normally when I was programming with pure php all the request worked well.
Thank you in advance.
Check you code for recieving result from query:
$rows = mysqli_num_rows($result);
while ($row_user= mysqli_fetch_assoc($result))
{
$response[] = $row;
}
$jsonData = json_encode($response);
Should be so:
$rows = mysqli_num_rows($result);
while ($row_user= mysqli_fetch_assoc($result))
{
$response[] = $row_user;
}
$jsonData = json_encode($response);

AJAX function for retrieving postgres data not working

I have a simple AJAX function bound to a button that should execute a PostgreSQL query. However, when I click the button that I bound the ajax query to, all I get is the confirmation that the database connection was successful. Nothing seems to happen withe the ajax result (should be printing to console in the handleAjax() function. What am I doing wrong?
This is the javascript code (with jquery):
$(document).ready(function() {
function sendAjax() {
$.ajax({
url: "db/database.php",
success: function (result) {
handleAjax(result);
}
});
}
function handleAjax(result) {
console.log(result);
}
$("#submit-button").on("click", sendAjax);
});
And this it the contents of database.php:
<?php
function dbconn(){
ini_set('display_errors', 1); // Displays errors
//database login info
$host = 'localhost';
$port = 5432;
$dbname = 'sms';
$user = 'postgres';
$password = 'postgres';
// establish connection
$conn = pg_connect("host=$host port=$port dbname=$dbname user=$user password=$password");
if (!$conn) {
echo "Not connected : " . pg_error();
exit;
} else {
echo "Connected.";
}
}
$conn = dbconn();
$sql = "SELECT * FROM numbers;";
$result = pg_query( $sql ) or die('Query Failed: ' .pg_last_error());
$count = 0;
$text = 'error';
while( $row = pg_fetch_array( $result, null, PGSQL_ASSOC ) ) {
$text = $row['message'];
//echo $text;
}
pg_free_result( $result );
?>
The problem is in the database.php file, all you get is "Connected." because you don't print your result at the end. Ajax only receive the output of the php file.
So at the end of your php file you should add :
echo $text;
And you also should remove the echo "Connected.";
AJAX is not a magic wand that in magic way reads PHP code. Let's say AJAX is a user. So what does user do.
Open web page
Wait until PHP execute code and display data
Tells you what he sees
If you don't display anything, ajax can't tell you what he saw.
In thi's place is worth to say that the best way to communicate between PHP and AJAX is using JSON format.
Your code generally is good. All you have to do is to display your data. All your data is in your $text var. So let's convert your array ($text) to JSON.
header('Content-Type: application/json');
echo json_encode($text);
First you set content-type to json, so ajax knows that he reads json. Then you encode (convert) your PHP array to js-friendly format (JSON). Also delete unnecessary echoes like 'Conntected' because as I said, AJAX reads everything what he sees.
You should return $conn from dbconn()
if (!$conn) {
echo "Not connected : " . pg_error();
exit;
} else {
echo "Connected.";
return $conn;
}

"CLI has stopped working" when trying to select all from an Oracle Database using JQuery?

I am attempting to use JavaScript and Jquery to search a database. I have set up a generic query.php file so that I can pass in the database and query and have it return an array. For some reason, when I try to select all using the *, my PHP server crashes with:
I am using the built in server with PHP 7.0.2. I am attempting to retrieve information from a Oracle database.
Here is the post statement:
$.post(DB1.filename,
{sid: DB1.sid,
username: DB1.username,
password: DB1.password,
host: DB1.host,
port: DB1.port,
sql: query},
function(res){
if(res == -1){
res = errorCode(DATABASE_CONNECTION_ERROR);
} else {
var a = parseObject(res);
var t = parseTable(a);
elements[TABLE].element.innerHTML = t;
}
log(FILE_NAME, "RETRIEVED query ");
}
);
Here is the query.php:
<?php
/* This script will connect to a database and search the given SQL string.
If the connection cannot be established, it will return -1. Otherwise, it will return a JSON array.
*/
//Parameters
$sql = $_POST["sql"];
//Database Information
$user = $_POST["username"];
$pass = $_POST["password"];
$host = $_POST["host"];
$port = $_POST["port"];
$sid = $_POST["sid"];
$connection = "(DESCRIPTION = (ADDRESS = (PROTOCOL = TCP)(HOST = " . $host .")(PORT = " . $port . ")) (CONNECT_DATA = (SID = " . $sid . ")))";
//Establish connection
$conn = oci_connect($user, $pass, $connection);
//Check connection
if(!$conn){
echo -1;
} else {
//Query for the given SQL statement
$stRows = oci_parse($conn, $sql);
oci_execute($stRows);
oci_fetch_all($stRows, $res); //This is where the everything actually crashes
echo json_encode($res);
//Close the connection
oci_close($conn);
}
?>
So if I set the query as:
query = "select TABLE_NAME from ALL_TABLES";
everything works just fine. A table with a single column will be printed to the screen.
However, if I run:
query = "select * from ALL_TABLES";
I get the error above.
This happens regardless of which table I am attempting to connect to. My credentials are correct and I have tried different credentials as well. Any ideas why this is happening?
--UPDATE--
I tried hard coding the column names. I can select up to 8 columns before it crashes.There are 152 rows.
I circumvented the error by swapping the oci_fetch_all for oci_fetch_array as follows:
<?php
...
} else {
//Query for the given SQL statement
$stRows = oci_parse($conn, $sql);
oci_execute($stRows);
$res = array();
while($row = oci_fetch_array($stRows, OCI_NUM)){
$res[] = $row;
}
echo json_encode($res);
//Close the connection
oci_close($conn);
}
?>
This meant drastic changes to the function used to decode the JSON object array, but it does work. I will not mark this answer as correct though because I would very much like to know why my original code wasn't working...

Php, js redirecting after successful registering, It inserts the user but won't redirect

<?php
$con = mysqli_connect("localhost", "root", "", "" ) or die("Neuspjelo spajanje");
function InsertUser(){ global $con;
if(isset($_POST['sign_up'])){
$name = mysqli_real_escape_string($con, $_POST['u_name']);
$pass = mysqli_real_escape_string($con,$_POST['u_pass']);
$email = mysqli_real_escape_string($con,$_POST['u_email']);
$country = mysqli_real_escape_string($con,$_POST['u_country']);
$gender = mysqli_real_escape_string($con,$_POST['u_gender']);
$b_day = mysqli_real_escape_string($con,$_POST['u_birthday']);
$date = date("m-d-Y");
$status = "unverified";
$posts = "No";
$get_email = "select * from users where user_email='$email'";
$run_email = mysqli_query($con, $get_email);
$check = mysqli_num_rows($run_email);
$insert = "insert into users (user_name, user_pass, user_email, user_country, user_gender, user_b_day,
user_image, register_date, last_login, status, posts) values
('$name','$pass', '$email', '$country', '$gender', '$b_day', 'default.jpg',
'$date', '$date', '$status', '$posts')";
$run_insert = mysqli_query($con, $insert);
$result = mysql_query($insert);
if($result){
echo "<script>alert ('You're successfully registered!')</script>";
echo "<script>window.open('home.php', '_self')</script>";
}
}
}
?>
You can't echo javascript and run it in a page that's already loaded. This would need to be the result of an ajax call on the client side with your redirects occuring from your ajax callbacks.
If you're ok with ditching the alert, you can just issue a redirect from php:
header('Location: home.php');
To do it ajaxy:
$.ajax({
type: "GET",
url: "your_insert_user.php"
}).success(function(xhr) {
alert ("You're successfully registered!");
window.open('home.php', '_self');
}).fail(function (jqXHR, status, errorThrown) {
//something else here
});
But, why would you want to issue an ajax call just to redirect?
Additionally, you need to issue the appropriate responses from your insert script:
if ($result) { echo ""; } //issues a "200 OK"
else { header("HTTP/1.1 422 Unprocessable Entity"); } //fires the failure callback in ajax
I would pass a conditional GET or POST paramater to home.php with some value flag and display your message there.
Based on what you post above, you are dealing with two separate issues here.
You say "it inserts" so I'm assuming that means that the mysql query to insert the new row into your database completes successfully. Then you send some HTML code, containing a (somewhat mangled) Javascript snippet, to the browser, which is supposed to issue a redirect request to the client's web browser, which doesn't have the desired result, seeing as you write that it "won't redirect".
Keep in mind that redirection is performed by the browser, is dependent on the browser's capabilities and/or settings, and requires proper javascript in the first place.
How do properly request a redirect from the browser has been discussed before on SO.
First of all,remove this line $result = mysql_query($insert); then modify your code and add this, hope it will work:
$run_insert = mysqli_query($con, $insert);
if($run_insert){
echo "<script>alert ('You\'re successfully registered!')</script>";
echo "<script>window.open('home.php', '_self')</script>";
}

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